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Metalworking (rec.crafts.metalworking) Discuss various aspects of working with metal, such as machining, welding, metal joining, screwing, casting, hardening/tempering, blacksmithing/forging, spinning and hammer work, sheet metal work. |
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#1
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Hi all,
I'm trying to figure out if there is any benefit in adding a flywheel to a rotary phase convertor. I've heard varying opinions on the subject. Having thought about it myself, I've reached the following conclusions: (i) The sag in voltage on the third line is caused by the fact that it is not connected directly to the supply. The flywheel doesn't change this. Nor will it change the steady speed at which the rotor turns, so unless it has some averaging effect on a cycle-by-cycle basis which I haven't considered, it won't affect the quality of the three phase output when the convertor is running in a steady state. (ii) It might be an advantage when trying to plug reverse the load motor. As far as I can see (on the most simplistic level), the motor with the most kinetic energy will win. I can't seem to find any used flywheels to fit my motor, but I can get a brand new flywheel for £40. I'm not sure if it is worth it in order to satisfy my scientific curiousity. If I get a different motor, I can get a flywheel for next to nothing, but that will involve lots of effort, bartering and deals in order to get a motor which isn't quite so cool. Any opinions and arguments? Thoughts would be appreciated... Best wishes, Chris |
#2
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In article , Christopher Tidy says...
Hi all, I'm trying to figure out if there is any benefit in adding a flywheel to a rotary phase convertor. There is no experimental data on this subject as far as I can see. I have seen coherent, cogent arguments from respected folks that support both views - one that it will help, the other that it will hinder. Those who suggest a flywheel is bad say that rotary converters deliver transient power to the generated phase by allowing the rotor to slip, and a flywheel prevents this. Those who suggest a flywheel is good say that that flywheels store rotational energy and will this is made available to transient loads. Those two preceeding statements are pure paraphrase on my part, and I of course apologize if I have mis-represented anyones comments. But there's no empirical data out there as far as I can tell. It wouldn't be that hard to instrument and measure. Jim -- ================================================== please reply to: JRR(zero) at pkmfgvm4 (dot) vnet (dot) ibm (dot) com ================================================== |
#3
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Regarding plug reversing, I recently rewired an older BP head. I was surprised
to see considerable evidence of arcing near the contacts in the drum switch. I figured that plug reversing it was the reason - a LOT of current flows, and motors with all their inductance do NOT like current changes. So regardless of what you do with your phase convertor, I strongly suggest that you not plug reverse anything using a drum switch unless that switch is extremely heavily built. I know of no value in adding rotary mass. The armature of an idler motor is already quite a bit of rotary mass. GWE Christopher Tidy wrote: Hi all, I'm trying to figure out if there is any benefit in adding a flywheel to a rotary phase convertor. I've heard varying opinions on the subject. Having thought about it myself, I've reached the following conclusions: (i) The sag in voltage on the third line is caused by the fact that it is not connected directly to the supply. The flywheel doesn't change this. Nor will it change the steady speed at which the rotor turns, so unless it has some averaging effect on a cycle-by-cycle basis which I haven't considered, it won't affect the quality of the three phase output when the convertor is running in a steady state. (ii) It might be an advantage when trying to plug reverse the load motor. As far as I can see (on the most simplistic level), the motor with the most kinetic energy will win. I can't seem to find any used flywheels to fit my motor, but I can get a brand new flywheel for £40. I'm not sure if it is worth it in order to satisfy my scientific curiousity. If I get a different motor, I can get a flywheel for next to nothing, but that will involve lots of effort, bartering and deals in order to get a motor which isn't quite so cool. Any opinions and arguments? Thoughts would be appreciated... Best wishes, Chris |
#4
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Christopher Tidy wrote...
I'm trying to figure out if there is any benefit in adding a flywheel to a rotary phase convertor. A flywheel would reduce, not increase, the idler's ability to respond to load changes. When the electrical load on the idler increases, the idler's rate of rotation falls (I.e., the slip increases). This raises the current draw from the single phase source. The higher winding current increases the strength of the rotating magnetic field in the idler, which pushes the generated third leg voltage up. The upshot of all this is that the response rate of the third leg voltage to electrical load changes is inversely related to the inertia of the idler's armature. That's my understanding. Perhaps one of the old regulars can explain it better. Is Fitch still around? I seem to remember his doing some tests on this very thing a few years back. Jim |
#5
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![]() jim rozen wrote: In article , Christopher Tidy says... Hi all, I'm trying to figure out if there is any benefit in adding a flywheel to a rotary phase convertor. There is no experimental data on this subject as far as I can see. I have seen coherent, cogent arguments from respected folks that support both views - one that it will help, the other that it will hinder. Those who suggest a flywheel is bad say that rotary converters deliver transient power to the generated phase by allowing the rotor to slip, and a flywheel prevents this. Those who suggest a flywheel is good say that that flywheels store rotational energy and will this is made available to transient loads. Then maybe one needs a "dual-mass" flywheel like they are putting on the diesel pickups now. |
#6
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Jim Wilson wrote:
Thanks for all the responses. A flywheel would reduce, not increase, the idler's ability to respond to load changes. When the electrical load on the idler increases, the idler's rate of rotation falls (I.e., the slip increases). This raises the current draw from the single phase source. The higher winding current increases the strength of the rotating magnetic field in the idler, which pushes the generated third leg voltage up. The upshot of all this is that the response rate of the third leg voltage to electrical load changes is inversely related to the inertia of the idler's armature. I'm not sure about this. Yes, it will take longer for the rotor's speed to fall, but surely the stored energy will be dissipated by driving extra current through the load? Best wishes, Chris |
#7
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IMO, you need to lose the thinking of a RPC as being a form of generator.
It isn't. Think more of the RPC as a network in which parts of it rotate in order to supply current throughout. Part of the RPC is the load motor. The idler generates nothing without the load as part of a network. IMO, a flywheel on the idler cannot act as anything more than additional dynamic load on the network. It would be aprox. the same to put the flywheel on the load motor instead. Forget flywheels and spend the money on enhancing the idler-load network with proper capacitance. Complex current flows in all parts of the RPC. In simplistic terms, the idler-load current paths can be viewed as series resonant circuits. Such circuits are "tuned" via capacitance placed in series. Bob Swinney "Jim Wilson" wrote in message .net... Christopher Tidy wrote... I'm trying to figure out if there is any benefit in adding a flywheel to a rotary phase convertor. A flywheel would reduce, not increase, the idler's ability to respond to load changes. When the electrical load on the idler increases, the idler's rate of rotation falls (I.e., the slip increases). This raises the current draw from the single phase source. The higher winding current increases the strength of the rotating magnetic field in the idler, which pushes the generated third leg voltage up. The upshot of all this is that the response rate of the third leg voltage to electrical load changes is inversely related to the inertia of the idler's armature. That's my understanding. Perhaps one of the old regulars can explain it better. Is Fitch still around? I seem to remember his doing some tests on this very thing a few years back. Jim |
#8
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On 3 Jan 2006 13:58:38 -0800, jim rozen
wrote: In article , Christopher Tidy says... Hi all, I'm trying to figure out if there is any benefit in adding a flywheel to a rotary phase convertor. There is no experimental data on this subject as far as I can see. I have seen coherent, cogent arguments from respected folks that support both views - one that it will help, the other that it will hinder. Those who suggest a flywheel is bad say that rotary converters deliver transient power to the generated phase by allowing the rotor to slip, and a flywheel prevents this. Those who suggest a flywheel is good say that that flywheels store rotational energy and will this is made available to transient loads. Those two preceeding statements are pure paraphrase on my part, and I of course apologize if I have mis-represented anyones comments. But there's no empirical data out there as far as I can tell. It wouldn't be that hard to instrument and measure. Jim Some kinetic energy is necessary for the thing to work, but my bet is that the rotor has more than enough and more would not help. Kinetic energy is necessary for the idler to produce power in the third leg during parts of the cycle when less or none is being drawn from the mains. Energy is also stored in the magnetic field, but its ebb and flow is in quadrature with third leg power. This is a cycle-by-cycle event: it accelerates (accumulates energy) during part of each cycle and decelerates (gives up energy) during other parts of each cycle. The result is speed ripple, which would be greater for rotors with small moments of inertia. The power levels drawn and delivered are a function of slip speed which governs both stator current and induced emf -- back emf in the case of the driven windings and generated emf in the case of the third leg. As the third leg produces more countertorque from higher current flow thru it, the rotor will slow until slipspeed has increased to the point where enough power is drawn from the mains to regain equilibrium. Observers (Jerry and Fitch) have said they didn't note much change in idler slipspeed with varying loads. However, resolution of 1% or better would be necessary to see speed variations because the slip speed range from no load to full load in most induction motors is only a few percent at most. |
#9
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On Tue, 3 Jan 2006 22:53:42 +0000 (UTC), Christopher Tidy
wrote: Jim Wilson wrote: Thanks for all the responses. A flywheel would reduce, not increase, the idler's ability to respond to load changes. When the electrical load on the idler increases, the idler's rate of rotation falls (I.e., the slip increases). This raises the current draw from the single phase source. The higher winding current increases the strength of the rotating magnetic field in the idler, which pushes the generated third leg voltage up. The upshot of all this is that the response rate of the third leg voltage to electrical load changes is inversely related to the inertia of the idler's armature. I'm not sure about this. Yes, it will take longer for the rotor's speed to fall, but surely the stored energy will be dissipated by driving extra current through the load? Yes, but power is the rate of energy flow. The amount of power it can produce for the third leg (energy delivered per cycle) is a function of slip speed, and field strength hence stator current which is also a function of slip speed. |
#10
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In article , Robert Swinney says...
IMO, you need to lose the thinking of a RPC as being a form of generator. It isn't. Think more of the RPC as a network in which parts of it rotate in order to supply current throughout. Part of the RPC is the load motor. The idler generates nothing without the load as part of a network. IMO, a flywheel on the idler cannot act as anything more than additional dynamic load on the network. It would be aprox. the same to put the flywheel on the load motor instead. Forget flywheels and spend the money on enhancing the idler-load network with proper capacitance. Complex current flows in all parts of the RPC. In simplistic terms, the idler-load current paths can be viewed as series resonant circuits. Such circuits are "tuned" via capacitance placed in series. Granted this kind of tuning is the very *first* thing one would do before considering flywheels. I specifically recall Gary Coffman claiming they would reduce transient response, and yet there's a considerable group of well-informed individuals on the practical machinist board who say they improve matters. I have to say I find *both* sides to be persuasive, at least at the 'hand-waving' level. My suspicion is that flywheels probably help up to a point, if one models the rotor as having zero mass to start with. And that the optimum flywheel size will wind up being about one rotor unit in size! This is what a former boss of mine calls 'the schwarz law of the initial maximum.' Ie, if it works the first time you set it up, anything you do to it after that makes it work worse. :^) Jim -- ================================================== please reply to: JRR(zero) at pkmfgvm4 (dot) vnet (dot) ibm (dot) com ================================================== |
#11
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Robert Swinney wrote...
IMO, you need to lose the thinking of a RPC as being a form of generator. Hrm. Is this in response to my post, or Christopher's? I don't think I view a RPC as a generator at all. Perhaps it's more like a rotating transformer. snip It would be aprox. the same to put the flywheel on the load motor instead. Most of what you said seemed reasonable (I snipped all the unobjectionable parts), but this statement can only be true under limited conditions. There would be a large difference in performance between the two systems for example when plug reversing is used. Cheers, Jim |
#12
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![]() "Jim Wilson" wrote in message .net... Robert Swinney wrote... IMO, you need to lose the thinking of a RPC as being a form of generator. Hrm. Is this in response to my post, or Christopher's? I don't think I view a RPC as a generator at all. Perhaps it's more like a rotating transformer. snip It would be aprox. the same to put the flywheel on the load motor instead. Most of what you said seemed reasonable (I snipped all the unobjectionable parts), but this statement can only be true under limited conditions. There would be a large difference in performance between the two systems for example when plug reversing is used. Cheers, Jim FWIW, you might view a plug reverse of the load motor as the worst case flywheel effect. Bob Swinney |
#13
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The only reason I can see for a flywheel to be advantageous is if you
were spinning the rpc up by hand before cutting in the power to lessen the duration of high current draw. |
#14
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On 3 Jan 2006 16:04:40 -0800, jim rozen
wrote: In article , Robert Swinney says... IMO, you need to lose the thinking of a RPC as being a form of generator. It isn't. Think more of the RPC as a network in which parts of it rotate in order to supply current throughout. Part of the RPC is the load motor. The idler generates nothing without the load as part of a network. IMO, a flywheel on the idler cannot act as anything more than additional dynamic load on the network. It would be aprox. the same to put the flywheel on the load motor instead. Forget flywheels and spend the money on enhancing the idler-load network with proper capacitance. Complex current flows in all parts of the RPC. In simplistic terms, the idler-load current paths can be viewed as series resonant circuits. Such circuits are "tuned" via capacitance placed in series. Granted this kind of tuning is the very *first* thing one would do before considering flywheels. I specifically recall Gary Coffman claiming they would reduce transient response, and yet there's a considerable group of well-informed individuals on the practical machinist board who say they improve matters. I have to say I find *both* sides to be persuasive, at least at the 'hand-waving' level. My suspicion is that flywheels probably help up to a point, if one models the rotor as having zero mass to start with. And that the optimum flywheel size will wind up being about one rotor unit in size! This is what a former boss of mine calls 'the schwarz law of the initial maximum.' Ie, if it works the first time you set it up, anything you do to it after that makes it work worse. :^) We just call that syndrome "fix it 'til it's broke". Snarl |
#15
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On Tue, 3 Jan 2006 21:07:42 +0000 (UTC), Christopher Tidy
wrote: I can't seem to find any used flywheels to fit my motor, but I can get a brand new flywheel for £40. I'm not sure if it is worth it in order to satisfy my scientific curiousity. If I get a different motor, I can get a flywheel for next to nothing, but that will involve lots of effort, bartering and deals in order to get a motor which isn't quite so cool. I won't touch the theoretical discussions on this thread. However I thought I might mention that if you wanted to experiment cheaply I'm sure you can find a used cast iron pulley in large enough diameter to serve as your flywheel. Preferably a multi-groove pulley. Wayne Cook Shamrock, TX http://members.dslextreme.com/users/waynecook/index.htm |
#16
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According to Ignoramus29795 :
On Tue, 3 Jan 2006 21:07:42 +0000 (UTC), Christopher Tidy wrote: [ ... ] (ii) It might be an advantage when trying to plug reverse the load motor. As far as I can see (on the most simplistic level), the motor with the most kinetic energy will win. I am not sure why you think so. Would you clarify why you think that plug reversing a load motor would somehow slow down the idler motor. The idler, after all, spins with the frequency of the AC mains. I have read reports here of under-rated rotary converters actually reversing, instead of the load motor, when plug reversing. I think that the flywheel might indeed solve this problem. Enjoy, DoN. -- Email: | Voice (all times): (703) 938-4564 (too) near Washington D.C. | http://www.d-and-d.com/dnichols/DoN.html --- Black Holes are where God is dividing by zero --- |
#17
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On Tue, 3 Jan 2006 17:20:12 -0600, "Robert Swinney"
wrote: IMO, you need to lose the thinking of a RPC as being a form of generator. It isn't. Think more of the RPC as a network in which parts of it rotate in order to supply current throughout. Part of the RPC is the load motor. The idler generates nothing without the load as part of a network. Sure it does. With the idler spinning, a voltage is generated in the third leg that is in quadrature to line voltage, even if there are no capacitors anywhere. Transformer action can not produce a quadrature voltage so it must be (and is) generated by the rotating rotor field -- which always is in quadrature with the stator field. IMO, a flywheel on the idler cannot act as anything more than additional dynamic load on the network. It would be aprox. the same to put the flywheel on the load motor instead. Forget flywheels and spend the money on enhancing the idler-load network with proper capacitance. Complex current flows in all parts of the RPC. In simplistic terms, the idler-load current paths can be viewed as series resonant circuits. If there are capacitors. But idlers without any run caps still work. In fact, they work quite well if they're large enough. |
#18
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I agree, using large motors simplifies everything! You get the
advantage of great kinetic energy with very understressed component parts. I favor a pony to "spin up" the first started (should be largest by 1.5) motor. |
#19
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Since the running idler and load motors are directly connected in parallel,
wouldn't plug reversing with identical motors and no mechanical load have an equal chance of reversing either motor? When running free, it seems to me that either motor could be considered to be the source or load for the third phase leg. I tend to believe that the idler requires more mechanical inertia than the load to maintain the best functioning. If an induction motor does not "generate", is induced counter EMF imaginary and the use of common induction motors as generators impossible? There are many ways to understand and describe how things work and I like to think of the RPC as simply a running induction motor with the magnetized rotor inducing EMF not only into the line energized windings (counter EMF) but also into the unenergized and phase displaced windings. Note that, when disconnected and still turning, an induction motor still has voltage across its windings and loading this voltage with "braking" resistors will mechanically load the rotor. I do not claim that this is the only way to describe it or that any description can change the operating principles involved. Don Young "Christopher Tidy" wrote in message ... Hi all, I'm trying to figure out if there is any benefit in adding a flywheel to a rotary phase convertor. I've heard varying opinions on the subject. Having thought about it myself, I've reached the following conclusions: (i) The sag in voltage on the third line is caused by the fact that it is not connected directly to the supply. The flywheel doesn't change this. Nor will it change the steady speed at which the rotor turns, so unless it has some averaging effect on a cycle-by-cycle basis which I haven't considered, it won't affect the quality of the three phase output when the convertor is running in a steady state. (ii) It might be an advantage when trying to plug reverse the load motor. As far as I can see (on the most simplistic level), the motor with the most kinetic energy will win. I can't seem to find any used flywheels to fit my motor, but I can get a brand new flywheel for £40. I'm not sure if it is worth it in order to satisfy my scientific curiousity. If I get a different motor, I can get a flywheel for next to nothing, but that will involve lots of effort, bartering and deals in order to get a motor which isn't quite so cool. Any opinions and arguments? Thoughts would be appreciated... Best wishes, Chris |
#20
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![]() "Don Foreman" wrote in message ... On Tue, 3 Jan 2006 17:20:12 -0600, "Robert Swinney" wrote: IMO, you need to lose the thinking of a RPC as being a form of generator. It isn't. Think more of the RPC as a network in which parts of it rotate in order to supply current throughout. Part of the RPC is the load motor. The idler generates nothing without the load as part of a network. Sure it does. With the idler spinning, a voltage is generated in the third leg that is in quadrature to line voltage, even if there are no capacitors anywhere. Transformer action can not produce a quadrature voltage so it must be (and is) generated by the rotating rotor field -- which always is in quadrature with the stator field. No load, no generation, Don. An idler running with no load motor does not constitute a RPC. The network and supported current flow through that network makes a RPC. Remember the idler is running as a single-phase machine and the 3rd leg is open, that is, until it is connected into a RPC. IMO, a flywheel on the idler cannot act as anything more than additional dynamic load on the network. It would be aprox. the same to put the flywheel on the load motor instead. Forget flywheels and spend the money on enhancing the idler-load network with proper capacitance. Complex current flows in all parts of the RPC. In simplistic terms, the idler-load current paths can be viewed as series resonant circuits. If there are capacitors. But idlers without any run caps still work. In fact, they work quite well if they're large enough. OK. So they aren't series resonant circuits when there are no run caps - granted. But the interconnection of idler and load and their associated current paths are the same, even without run caps. |
#21
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Don Young sez:
"Since the running idler and load motors are directly connected in parallel .. . ." You are right about there being "many ways to understand and describe how things work" but the concept of an idler and load motor's respective windings being in parallel is not one of them. Bob Swinney "Don Young" wrote in message ... wouldn't plug reversing with identical motors and no mechanical load have an equal chance of reversing either motor? When running free, it seems to me that either motor could be considered to be the source or load for the third phase leg. I tend to believe that the idler requires more mechanical inertia than the load to maintain the best functioning. If an induction motor does not "generate", is induced counter EMF imaginary and the use of common induction motors as generators impossible? There are many ways to understand and describe how things work and I like to think of the RPC as simply a running induction motor with the magnetized rotor inducing EMF not only into the line energized windings (counter EMF) but also into the unenergized and phase displaced windings. Note that, when disconnected and still turning, an induction motor still has voltage across its windings and loading this voltage with "braking" resistors will mechanically load the rotor. I do not claim that this is the only way to describe it or that any description can change the operating principles involved. Don Young "Christopher Tidy" wrote in message ... Hi all, I'm trying to figure out if there is any benefit in adding a flywheel to a rotary phase convertor. I've heard varying opinions on the subject. Having thought about it myself, I've reached the following conclusions: (i) The sag in voltage on the third line is caused by the fact that it is not connected directly to the supply. The flywheel doesn't change this. Nor will it change the steady speed at which the rotor turns, so unless it has some averaging effect on a cycle-by-cycle basis which I haven't considered, it won't affect the quality of the three phase output when the convertor is running in a steady state. (ii) It might be an advantage when trying to plug reverse the load motor. As far as I can see (on the most simplistic level), the motor with the most kinetic energy will win. I can't seem to find any used flywheels to fit my motor, but I can get a brand new flywheel for £40. I'm not sure if it is worth it in order to satisfy my scientific curiousity. If I get a different motor, I can get a flywheel for next to nothing, but that will involve lots of effort, bartering and deals in order to get a motor which isn't quite so cool. Any opinions and arguments? Thoughts would be appreciated... Best wishes, Chris |
#22
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In article ,
Rex B wrote: [...] Then maybe one needs a "dual-mass" flywheel like they are putting on the diesel pickups now. That sounds like an interesting thingy. Got any details on it? -- B.B. --I am not a goat! thegoat4 at airmail dot net |
#23
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On 3 Jan 2006 13:58:38 -0800, jim rozen
wrote: Those who suggest a flywheel is bad say that rotary converters deliver transient power to the generated phase by allowing the rotor to slip, and a flywheel prevents this. Those who suggest a flywheel is good say that that flywheels store rotational energy and will this is made available to transient loads. Those two preceeding statements are pure paraphrase on my part, and I of course apologize if I have mis-represented anyones comments. But there's no empirical data out there as far as I can tell. It wouldn't be that hard to instrument and measure. Jim Dont forget a nice heavy rotor IS a flywheel. Gunner The aim of untold millions is to be free to do exactly as they choose and for someone else to pay when things go wrong. In the past few decades, a peculiar and distinctive psychology has emerged in England. Gone are the civility, sturdy independence, and admirable stoicism that carried the English through the war years .. It has been replaced by a constant whine of excuses, complaints, and special pleading. The collapse of the British character has been as swift and complete as the collapse of British power. Theodore Dalrymple, |
#24
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In article , Robert Swinney says...
No load, no generation, Don. An idler running with no load motor does not constitute a RPC. The network and supported current flow through that network makes a RPC. Remember the idler is running as a single-phase machine and the 3rd leg is open, that is, until it is connected into a RPC. No current flow, yes. But the third leg does come up in voltage, even when open circuited. While it won't do any work, folks would be tempted to say that the third leg is indeed "generated" even when it's open circuited. Another one of those semantic mine fields.... Jim -- ================================================== please reply to: JRR(zero) at pkmfgvm4 (dot) vnet (dot) ibm (dot) com ================================================== |
#25
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Don, I think you have a great insight here. The two motors are clearly
in parallel; swap a lead on either motor and the "bigger" one wins. I still am not sure if a flywheel has any significant effect on which one is bigger (though it seems like it would). Steve Don Young wrote: Since the running idler and load motors are directly connected in parallel, wouldn't plug reversing with identical motors and no mechanical load have an equal chance of reversing either motor? When running free, it seems to me that either motor could be considered to be the source or load for the third phase leg. I tend to believe that the idler requires more mechanical inertia than the load to maintain the best functioning. If an induction motor does not "generate", is induced counter EMF imaginary and the use of common induction motors as generators impossible? There are many ways to understand and describe how things work and I like to think of the RPC as simply a running induction motor with the magnetized rotor inducing EMF not only into the line energized windings (counter EMF) but also into the unenergized and phase displaced windings. Note that, when disconnected and still turning, an induction motor still has voltage across its windings and loading this voltage with "braking" resistors will mechanically load the rotor. I do not claim that this is the only way to describe it or that any description can change the operating principles involved. Don Young "Christopher Tidy" wrote in message ... Hi all, I'm trying to figure out if there is any benefit in adding a flywheel to a rotary phase convertor. I've heard varying opinions on the subject. Having thought about it myself, I've reached the following conclusions: (i) The sag in voltage on the third line is caused by the fact that it is not connected directly to the supply. The flywheel doesn't change this. Nor will it change the steady speed at which the rotor turns, so unless it has some averaging effect on a cycle-by-cycle basis which I haven't considered, it won't affect the quality of the three phase output when the convertor is running in a steady state. (ii) It might be an advantage when trying to plug reverse the load motor. As far as I can see (on the most simplistic level), the motor with the most kinetic energy will win. I can't seem to find any used flywheels to fit my motor, but I can get a brand new flywheel for £40. I'm not sure if it is worth it in order to satisfy my scientific curiousity. If I get a different motor, I can get a flywheel for next to nothing, but that will involve lots of effort, bartering and deals in order to get a motor which isn't quite so cool. Any opinions and arguments? Thoughts would be appreciated... Best wishes, Chris |
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![]() Robert Swinney wrote: IMO, you need to lose the thinking of a RPC as being a form of generator. Bob Swinney In my opinion you need to realize that a RPC is an induction generator. As far as flywheels are concerned, a flywheel will keep the slip angle from changing as quickly. So a RPC without a flywheel will draw power from the mains more quickly when the load is increased. Score points for that side. On the other hand, a RPC with a flywheel will draw power from the flywheel when the load is increased as well as from the mains. So score points for the other side. In the real world, it does not make much difference as the change in speed of the RPC should be slight, and therefore only a small amount of power can be drawn from the flywheel. Having a flywheel would help with an undersized RPC when the load motor is plugged. Dan |
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Don sez:
" Sure it does. With the idler spinning, a voltage is generated in the third leg that is in quadrature to line voltage, even if there are no capacitors anywhere. Transformer action can not produce a quadrature voltage so it must be (and is) generated by the rotating rotor field -- which always is in quadrature with the stator field." I'm not sure what you mean, Don. You said "Transformer action can not produce a quadrature voltage so it must be (and is) generated by the rotating rotor field -- which always is in quadrature with the stator field". Firstly, I don't understand why the issue must be complicated by bringing the rotor field into the picture. It is well known the stator field and rotor field are more or less locked into rotation at the same speed, but it is incongruous to speculate the rotor field is solely responsible for the stator field's third leg voltage. Remember we are essentially talking about a single phase motor here with an open coil connected to the center point of the line-fed main winding. I respectfully submit the third leg voltage is not in quatrature with line voltage. The only way for that to be a true statement would be in the special case of a precise amount of capacitance connected from one line side to the end of the 3rd leg coil; an amount of capacitance (start cap if you will) necessary to achieve an exact 90 degree phase shift between line voltage and the 3rd. leg. Bob Swinney |
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On Wed, 4 Jan 2006 00:12:38 -0600, "Robert Swinney"
wrote: Don Young sez: "Since the running idler and load motors are directly connected in parallel . . ." You are right about there being "many ways to understand and describe how things work" but the concept of an idler and load motor's respective windings being in parallel is not one of them. Bob Swinney Hey, Bob, what about delta-wound motors? Sure looks parallel to me! |
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On Tue, 3 Jan 2006 23:14:07 -0600, "Don Young"
wrote: Since the running idler and load motors are directly connected in parallel, wouldn't plug reversing with identical motors and no mechanical load have an equal chance of reversing either motor? When running free, it seems to me that either motor could be considered to be the source or load for the third phase leg. I tend to believe that the idler requires more mechanical inertia than the load to maintain the best functioning. Interesting! The relative impedances are also important here. The larger motor with lower impedance (and probably higher inertia) will govern. Look at the terminal voltage where the two third legs are connected. If the motors were perfectly matched, their effects would cancel and this terminal voltage would be zero. If they are not matched, the voltage (phase) of that terminal will be determined by the motor with the lower impedance, and the phase of this voltage determines (or indicates) the direction in which both motors turn. If an induction motor does not "generate", is induced counter EMF imaginary and the use of common induction motors as generators impossible? There are many ways to understand and describe how things work and I like to think of the RPC as simply a running induction motor with the magnetized rotor inducing EMF not only into the line energized windings (counter EMF) but also into the unenergized and phase displaced windings. Right, up to here. Note that, when disconnected and still turning, an induction motor still has voltage across its windings and loading this voltage with "braking" resistors will mechanically load the rotor. Only if the rotor has some significant permanent magnetism -- not usually the case. |
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Hey, Don, it sounds like you are beginning to go off half cocked, sort of
"Iggy style". Do this: Visualize 2 deltas connected in "parallel" if you will.. Obviously the current paths through the branches, where the lines are connected, are in parallel. Now look at the common point where the other 2 legs of both deltas connect together. Those points are no more in parallel than they would be if they were between two wyes. It may be helpful to look at the configuration in its wye equivalent. Same thing. All this speaks to the very complex current flow in an idler and load connected as a RPC. Two 3-phase induction motors running on the same 3-phase line do not constitute a RPC. A RPC is two 3-phase induction motors running on single-phase current. Capacitor augmentation assists in tuning the network such that it appears to be operating from a 3-phase line. Bob Swinney "Don Foreman" wrote in message ... On Wed, 4 Jan 2006 00:12:38 -0600, "Robert Swinney" wrote: Don Young sez: "Since the running idler and load motors are directly connected in parallel . . ." You are right about there being "many ways to understand and describe how things work" but the concept of an idler and load motor's respective windings being in parallel is not one of them. Bob Swinney Hey, Bob, what about delta-wound motors? Sure looks parallel to me! |
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Don,
See my previous post, where I tried to show 2 induction motors operating from single phase current in a RPC configuration cannot be in parallel. Bob Swinney "Don Foreman" wrote in message ... On Tue, 3 Jan 2006 23:14:07 -0600, "Don Young" wrote: Since the running idler and load motors are directly connected in parallel, wouldn't plug reversing with identical motors and no mechanical load have an equal chance of reversing either motor? When running free, it seems to me that either motor could be considered to be the source or load for the third phase leg. I tend to believe that the idler requires more mechanical inertia than the load to maintain the best functioning. Interesting! The relative impedances are also important here. The larger motor with lower impedance (and probably higher inertia) will govern. Look at the terminal voltage where the two third legs are connected. If the motors were perfectly matched, their effects would cancel and this terminal voltage would be zero. If they are not matched, the voltage (phase) of that terminal will be determined by the motor with the lower impedance, and the phase of this voltage determines (or indicates) the direction in which both motors turn. If an induction motor does not "generate", is induced counter EMF imaginary and the use of common induction motors as generators impossible? There are many ways to understand and describe how things work and I like to think of the RPC as simply a running induction motor with the magnetized rotor inducing EMF not only into the line energized windings (counter EMF) but also into the unenergized and phase displaced windings. Right, up to here. Note that, when disconnected and still turning, an induction motor still has voltage across its windings and loading this voltage with "braking" resistors will mechanically load the rotor. Only if the rotor has some significant permanent magnetism -- not usually the case. |
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On Wed, 4 Jan 2006 10:14:13 -0600, "Robert Swinney"
wrote: Don sez: " Sure it does. With the idler spinning, a voltage is generated in the third leg that is in quadrature to line voltage, even if there are no capacitors anywhere. Transformer action can not produce a quadrature voltage so it must be (and is) generated by the rotating rotor field -- which always is in quadrature with the stator field." I'm not sure what you mean, Don. You said "Transformer action can not produce a quadrature voltage so it must be (and is) generated by the rotating rotor field -- which always is in quadrature with the stator field". Firstly, I don't understand why the issue must be complicated by bringing the rotor field into the picture. Because it's there, producing phase shifts and emf's that cannot be produced by a network of similar topology having only R's and L's. It is well known the stator field and rotor field are more or less locked into rotation at the same speed, but it is incongruous to speculate the rotor field is solely responsible for the stator field's third leg voltage. Remember we are essentially talking about a single phase motor here with an open coil connected to the center point of the line-fed main winding. I respectfully submit the third leg voltage is not in quatrature with line voltage. The only way for that to be a true statement would be in the special case of a precise amount of capacitance connected from one line side to the end of the 3rd leg coil; an amount of capacitance (start cap if you will) necessary to achieve an exact 90 degree phase shift between line voltage and the 3rd. leg. The rotor field is always in space quadrature from the stator field. This is well-established in about any textbook on the subject. That being the case, the emf it induces in the third leg is necessarily in quadrature with the emf impressed by the line (and countered by the stator field) in the other two windings. Now consider a Y-connected motor. Rotate the Y 30 degrees clockwise so the right hand leg is horizontal, with line connected across the lefthand legs. Note that the vertical components of the excited coil windings add while the horizontal components cancel. Therefore, there is no emf induced in the horizontal third winding by direct transformer action. Emf induced in the third winding is therefore solely due to the rotor field -- and since that field is in quadrature with the stator field, the emf in the third winding must be in quadrature with the excitation voltage. QED. The terminal voltage on a loaded third winding will vary from exact quadrature due to I Z drops, which have opposite sense in the excited windings from those in a loaded third leg -- look at the directions of current flow. . But if you connect a scope from third terminal to neutral (center of the Y) in an unloaded idler, it would show an emf in quadrature with line voltage. Credit to Jerry Martes for showing me this aspect of induction idlers. |
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In article , Don Foreman says...
The rotor field is always in space quadrature from the stator field. This is well-established in about any textbook on the subject. That being the case, the emf it induces in the third leg is necessarily in quadrature with the emf impressed by the line (and countered by the stator field) in the other two windings. I thought it was the rotor *current* that was in quadrature. Basically the rotor currents cause a rotating B field to exist inside the stator. How it does this doesn't matter much, but suffice it to say that the phase of the rotating B field agrees with the incoming excitation (which of course supplies all the power to the gizmo) which means it will cause the correct phase voltage to exist on the third lead. Jim -- ================================================== please reply to: JRR(zero) at pkmfgvm4 (dot) vnet (dot) ibm (dot) com ================================================== |
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On Wed, 4 Jan 2006 11:42:34 -0600, "Robert Swinney"
wrote: Hey, Don, it sounds like you are beginning to go off half cocked, sort of "Iggy style". Look at http://users.goldengate.net/~dforeman/delta_3D/ Colored lines are windings, white lines are connections. 'Splain to me how the windings of same colors are not in parallel... Don "Half-cocked" Foreman |
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On Wed, 4 Jan 2006 11:45:55 -0600, "Robert Swinney"
wrote: Don, See my previous post, where I tried to show 2 induction motors operating from single phase current in a RPC configuration cannot be in parallel. I saw it. I just don't agree with it. See recent post showing things in 3D. Transform to Y using the usual Y-delta transforms if you like. See any textbook on the subject. In the Y case they don't look in parallel if there is no neutral connection. However, since a delta depiction clearly shows that they *ARE* in parallel, they are in freakin' parallel, BOB! Must I glue up some popsicle sticks for you? Can you explain the discrepancy? :) Hint: if there is no potential between unconnected points (the neutrals in a Y configuration) then they are effectively connected. Don "half-cocked" Foreman half cocked my arse....grumble mutter ....chuckle |
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Sorry, Don. We were discussing RPC's and I assumed (we know what that does)
you were thinking of RPC's as well. Two 3-phase induction motors connected as a RPC are not, repeat are not in parallel. I'm afraid you have jumped to the conclusion that two 3-phase induction motors connected in RPC fashion are merely connected in parallel. That is not the case. See a later post in which I tried to explain the defference. Bob (if it sounds like Iggy, it might be Iggy, No! it can't be) Swinney "Don Foreman" wrote in message news ![]() On Wed, 4 Jan 2006 11:42:34 -0600, "Robert Swinney" wrote: Hey, Don, it sounds like you are beginning to go off half cocked, sort of "Iggy style". Look at http://users.goldengate.net/~dforeman/delta_3D/ Colored lines are windings, white lines are connections. 'Splain to me how the windings of same colors are not in parallel... Don "Half-cocked" Foreman |
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Well, Don - you've missed the point again! What part of "2 induction
motors operating from single phase current in a RPC configuration cannot be in parallel" did you fail to understand. Your well intentioned, and colorful, drawings were not of a RPC configuration. Draw out a RPC and I think you may understand. Oh! be sure to include some capacitors. They (in electronic terms) might be considered as steering capacitors, for it is their job to force the convoluted currents to flow in such a way as to *emulate* true 3-phase. Note, I said *emulate* because current flow in a RPC is not the same as current flow in parallel connected 3-phase motors, no matter which transform is used. Bob Swinney "Don Foreman" wrote in message ... On Wed, 4 Jan 2006 11:45:55 -0600, "Robert Swinney" wrote: Don, See my previous post, where I tried to show 2 induction motors operating from single phase current in a RPC configuration cannot be in parallel. I saw it. I just don't agree with it. See recent post showing things in 3D. Transform to Y using the usual Y-delta transforms if you like. See any textbook on the subject. In the Y case they don't look in parallel if there is no neutral connection. However, since a delta depiction clearly shows that they *ARE* in parallel, they are in freakin' parallel, BOB! Must I glue up some popsicle sticks for you? Can you explain the discrepancy? :) Hint: if there is no potential between unconnected points (the neutrals in a Y configuration) then they are effectively connected. Don "half-cocked" Foreman half cocked my arse....grumble mutter ....chuckle |
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In article , Robert Swinney says...
Well, Don - you've missed the point again! What part of "2 induction motors operating from single phase current in a RPC configuration cannot be in parallel" did you fail to understand. Probably the same one I can't see. They look like they're in parallel to me. Unless I'm missing something. Granted the term "parallel" is a bit of a misnomer here but each winding of my load motor is in fact in parallel with a winding in the idler motor. Jim (half cocked also?) -- ================================================== please reply to: JRR(zero) at pkmfgvm4 (dot) vnet (dot) ibm (dot) com ================================================== |
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On Wed, 4 Jan 2006 13:00:58 -0600, "Robert Swinney"
wrote: Sorry, Don. We were discussing RPC's and I assumed (we know what that does) you were thinking of RPC's as well. Two 3-phase induction motors connected as a RPC are not, repeat are not in parallel. I'm afraid you have jumped to the conclusion that two 3-phase induction motors connected in RPC fashion are merely connected in parallel. That is not the case. Mine is! Works fine. |
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On Wed, 4 Jan 2006 13:00:58 -0600, "Robert Swinney"
wrote: Sorry, Don. We were discussing RPC's and I assumed (we know what that does) you were thinking of RPC's as well. Two 3-phase induction motors connected as a RPC are not, repeat are not in parallel. I'm afraid you have jumped to the conclusion that two 3-phase induction motors connected in RPC fashion are merely connected in parallel. That is not the case. Hanrahan seems to think it is the case. The presence of the capacitors notwithstanding, his motors are connected in parallel. http://www.metalwebnews.com/howto/ph-conv/fig1.html |
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