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#1
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Measuring load on a circuit breaker.
Hi,
Does anyone know of a way to measure the current being used on a single circuit breaker from just one of the wall outlets on that circuit? ie; I want to be able to plug something in anywhere in the house and be able to tell from there how many amps the circuit breaker is using. thanks |
#2
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Measuring load on a circuit breaker.
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#3
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Measuring load on a circuit breaker.
On Tue, 20 Feb 2007 14:42:07 -0600, Chris Friesen
wrote: wrote: Does anyone know of a way to measure the current being used on a single circuit breaker from just one of the wall outlets on that circuit? Nope. You need a clamp-on ammeter around the wire going to the breaker. What are you plugging into the outlet? The easiest method is just estimate it from the power rating of the device you are plugging in. There should be a Wattage (Power) marking somewhere on a nameplate on the device. The current will be approximately = P/120 (assuming your voltage is 120V). Example - If you are running a 1200 W space heater, that would take 10A. If it is a motorized appliance, such as a vacuum cleaner, it will have a power factor of less than one, which means it will draw slightly more current than it actually consumes in measurable output power. If it is a heavy duty appliance like an air-conditioner, the startup currrent may be high (almost double) during the fraction of a second that it is coming up to spead. |
#4
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Measuring load on a circuit breaker.
"Chris Friesen" wrote in message ... wrote: Does anyone know of a way to measure the current being used on a single circuit breaker from just one of the wall outlets on that circuit? Nope. You need a clamp-on ammeter around the wire going to the breaker. Ummm, the circuit breaker is fed by a bus ... that you cannot clamp around. |
#5
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Measuring load on a circuit breaker.
wrote in message oups.com... Hi, Does anyone know of a way to measure the current being used on a single circuit breaker from just one of the wall outlets on that circuit? ie; I want to be able to plug something in anywhere in the house and be able to tell from there how many amps the circuit breaker is using. thanks There is usually a black wire connected to the circuit breaker. If you can clamp around that wire with the appropriate ammeter (Google clamp-on ammeter) you can measure the current in that circuit. What are you trying to accomplish? |
#6
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Measuring load on a circuit breaker.
On Tue, 20 Feb 2007 16:59:14 -0500, "Charles Schuler"
wrote: "Chris Friesen" wrote in message ... wrote: Does anyone know of a way to measure the current being used on a single circuit breaker from just one of the wall outlets on that circuit? Nope. You need a clamp-on ammeter around the wire going to the breaker. Ummm, the circuit breaker is fed by a bus ... that you cannot clamp around. Looks like someone can't tell the difference between "to" and "from". That reminds me of the numerous people who kept confusing "inputs" and "outputs" on audio/video equipment. -- Mark Lloyd http://notstupid.laughingsquid.com "Unlike biological evolution. 'intelligent design' is not a genuine scientific theory and, therefore, has no place in the curriculum of our nation's public school classes." -- Ted Kennedy |
#7
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Measuring load on a circuit breaker.
On Tue, 20 Feb 2007 16:59:14 -0500, "Charles Schuler"
wrote: "Chris Friesen" wrote in message ... wrote: Does anyone know of a way to measure the current being used on a single circuit breaker from just one of the wall outlets on that circuit? Nope. You need a clamp-on ammeter around the wire going to the breaker. Ummm, the circuit breaker is fed by a bus ... that you cannot clamp around. Hummm, but the buss is fed by a main and that main is fed by wire that you can clamp around. |
#8
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Measuring load on a circuit breaker.
Hummm, but the buss is fed by a main and that main is fed by wire that you can clamp around. Not in any power panel that I have seen recently. |
#9
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Measuring load on a circuit breaker.
Charles Schuler wrote:
Hummm, but the buss is fed by a main and that main is fed by wire that you can clamp around. Not in any power panel that I have seen recently. I think he meant that the bus was fed through the main breaker, which IS fed by a wire, usually coming from the meter base. But, to make a meaningful measurement using that wire he'd have to switch off ALL the other breakers on that feed's side of the panel. Not a very practical solution, is it? G Jeff -- Jeffry Wisnia (W1BSV + Brass Rat '57 EE) The speed of light is 1.8*10^12 furlongs per fortnight. |
#10
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Measuring load on a circuit breaker.
But, to make a meaningful measurement using that wire he'd have to switch off ALL the other breakers on that feed's side of the panel. Not a very practical solution, is it? G No Jeff, it surely is not! |
#11
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Measuring load on a circuit breaker.
On Tue, 20 Feb 2007 17:35:03 -0500, "Charles Schuler"
wrote: Hummm, but the buss is fed by a main and that main is fed by wire that you can clamp around. Not in any power panel that I have seen recently. OTOH, since he's wondering about the power used on one circut, many people might suggest clamping the ammeter on the wire that feeds that circut. You know, where it comes off the breaker. I know that sounds crazy, but it might work anyway. |
#12
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Measuring load on a circuit breaker.
wrote in message oups.com... Hi, Does anyone know of a way to measure the current being used on a single circuit breaker from just one of the wall outlets on that circuit? ie; I want to be able to plug something in anywhere in the house and be able to tell from there how many amps the circuit breaker is using. thanks I have an adaptor for my ammeter that I can plug into an ordinary wall receptacle. It has a loop on it to clamp around and I can plug an appliance into it to see what the load is for that appliance. I think Amprobe makes it. John Grabowski http://www.mrelectrician.tv |
#13
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Measuring load on a circuit breaker.
Charles Schuler wrote:
"Chris Friesen" wrote Nope. You need a clamp-on ammeter around the wire going to the breaker. Ummm, the circuit breaker is fed by a bus ... that you cannot clamp around. The circuit has one wire attached to the breaker, and the other goes to the neutral bus (assuming a 120V circuit). You can put a meter around the wire that is connected to the breaker. Are you seriously arguing about wether a wire goes "to" or "from" a breaker? In an AC circuit where current flows both ways? Chris |
#14
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Measuring load on a circuit breaker.
On Tue, 20 Feb 2007 17:47:10 -0600, Chris Friesen
wrote: Charles Schuler wrote: "Chris Friesen" wrote Nope. You need a clamp-on ammeter around the wire going to the breaker. Ummm, the circuit breaker is fed by a bus ... that you cannot clamp around. The circuit has one wire attached to the breaker, and the other goes to the neutral bus (assuming a 120V circuit). You can put a meter around the wire that is connected to the breaker. Are you seriously arguing about wether a wire goes "to" or "from" a breaker? In an AC circuit where current flows both ways? Consider that while current does flow both ways (or more correctly, is ALTERNATING direction), POWER goes one way. "Direction" is useful there. Chris -- Mark Lloyd http://notstupid.laughingsquid.com "Unlike biological evolution. 'intelligent design' is not a genuine scientific theory and, therefore, has no place in the curriculum of our nation's public school classes." -- Ted Kennedy |
#15
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Measuring load on a circuit breaker.
On Tue, 20 Feb 2007 18:30:25 -0500, "John Grabowski"
wrote: wrote in message roups.com... Hi, Does anyone know of a way to measure the current being used on a single circuit breaker from just one of the wall outlets on that circuit? ie; I want to be able to plug something in anywhere in the house and be able to tell from there how many amps the circuit breaker is using. thanks I have an adaptor for my ammeter that I can plug into an ordinary wall receptacle. It has a loop on it to clamp around and I can plug an appliance into it to see what the load is for that appliance. I think Amprobe makes it. John Grabowski http://www.mrelectrician.tv I'm using a Kill-A-Watt meter for that now, but previously I had a VOM attachment for that. I made it from a remote control cord (just a switch at one end) with the switch removed and replaced with banana plugs. -- Mark Lloyd http://notstupid.laughingsquid.com "Unlike biological evolution. 'intelligent design' is not a genuine scientific theory and, therefore, has no place in the curriculum of our nation's public school classes." -- Ted Kennedy |
#16
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Measuring load on a circuit breaker.
Why not?
-- Steve Barker "Charles Schuler" wrote in message ... Hummm, but the buss is fed by a main and that main is fed by wire that you can clamp around. Not in any power panel that I have seen recently. |
#17
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Measuring load on a circuit breaker.
Mark Lloyd wrote:
Consider that while current does flow both ways (or more correctly, is ALTERNATING direction), POWER goes one way. "Direction" is useful there. How do you figure that? Power is a scalar quantity given by I^2*R. Power dissipated by a load is always positive no matter which direction the current flows through the load. Chris |
#18
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Measuring load on a circuit breaker.
On Tue, 20 Feb 2007 23:34:41 -0600, Chris Friesen
wrote: Mark Lloyd wrote: Consider that while current does flow both ways (or more correctly, is ALTERNATING direction), POWER goes one way. "Direction" is useful there. How do you figure that? Power is a scalar quantity given by I^2*R. Power dissipated by a load is always positive no matter which direction the current flows through the load. Chris Basically what I said. Considering that there's a "source" of the power and a "load" where it's dissipated. it would be hard not to see a direction in there. -- Mark Lloyd http://notstupid.laughingsquid.com "Unlike biological evolution. 'intelligent design' is not a genuine scientific theory and, therefore, has no place in the curriculum of our nation's public school classes." -- Ted Kennedy |
#19
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Measuring load on a circuit breaker.
Mark Lloyd wrote:
Considering that there's a "source" of the power and a "load" where it's dissipated. it would be hard not to see a direction in there. Technically you don't have a "power source" in an electrical circuit. You either have a voltage source or a current source or a combination of the two. Power doesn't flow in a circuit--only current does. Power is dissipated by the various components in a circuit. The instantaneous power dissipated by any particular component can be given by I^2*R, where I is the instantaneous current flowing through the component and R is the resistance of the component. (This is all assuming a purely resistive load.) The electrical utility applies an alternating voltage to the conductors attached to the house. This causes an alternating current to flow in those conductors, with the amount of current depending on the resistance of the various circuits in the house. Thus, whether you say the hot wire "goes to", or is "connected to", or "comes from" the breaker, it is all equivalent. Chris |
#20
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Measuring load on a circuit breaker.
On Wed, 21 Feb 2007 15:55:14 -0600, Chris Friesen
wrote: Mark Lloyd wrote: Considering that there's a "source" of the power and a "load" where it's dissipated. it would be hard not to see a direction in there. Technically you don't have a "power source" in an electrical circuit. You either have a voltage source or a current source or a combination of the two. Right. Still a source. Power doesn't flow in a circuit--only current does. Power is dissipated by the various components in a circuit. The instantaneous power dissipated by any particular component can be given by I^2*R, where I is the instantaneous current flowing through the component and R is the resistance of the component. (This is all assuming a purely resistive load.) The electrical utility applies an alternating voltage to the conductors attached to the house. This causes an alternating current to flow in those conductors, with the amount of current depending on the resistance of the various circuits in the house. Thus, whether you say the hot wire "goes to", or is "connected to", or "comes from" the breaker, it is all equivalent. No matter what, there is still a logical direction. Note that this direction does seem to correspond to what direction the bill comes in. Chris -- Mark Lloyd http://notstupid.laughingsquid.com "Unlike biological evolution. 'intelligent design' is not a genuine scientific theory and, therefore, has no place in the curriculum of our nation's public school classes." -- Ted Kennedy |
#21
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Measuring load on a circuit breaker.
On Wed, 21 Feb 2007 15:55:14 -0600, Chris Friesen
wrote: Mark Lloyd wrote: Considering that there's a "source" of the power and a "load" where it's dissipated. it would be hard not to see a direction in there. Technically you don't have a "power source" in an electrical circuit. You either have a voltage source or a current source or a combination of the two. Power doesn't flow in a circuit--only current does. Power is dissipated by the various components in a circuit. The instantaneous power dissipated by any particular component can be given by I^2*R, where I is the instantaneous current flowing through the component and R is the resistance of the component. (This is all assuming a purely resistive load.) The electrical utility applies an alternating voltage to the conductors attached to the house. This causes an alternating current to flow in those conductors, with the amount of current depending on the resistance of the various circuits in the house. Thus, whether you say the hot wire "goes to", or is "connected to", or "comes from" the breaker, it is all equivalent. Chris I am slow. There is no power source in an electrical circuit? Why do they call it the power company? Ours is called Georgia Power. Isn't a combination of voltage and current "power" by definition? http://www.google.com/search?hl=en&q=georgia+power |
#22
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Measuring load on a circuit breaker.
Mark Lloyd wrote:
On Tue, 20 Feb 2007 23:34:41 -0600, Chris Friesen wrote: Mark Lloyd wrote: Consider that while current does flow both ways (or more correctly, is ALTERNATING direction), POWER goes one way. "Direction" is useful there. How do you figure that? Power is a scalar quantity given by I^2*R. Power dissipated by a load is always positive no matter which direction the current flows through the load. Chris Basically what I said. Considering that there's a "source" of the power and a "load" where it's dissipated. it would be hard not to see a direction in there. Hi, This is quite improper statement. From basic Ohm's law, current/voltage produces power measured in Watts usually which can be converted into Joule, Calorie, Horse Power, etc. Current flows, power does not. There is phantom power(false power, wasted power) in inductive cicuit. Many loads are not pure resistive. There is always inductive/capacitive component. |
#23
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Measuring load on a circuit breaker.
Terry wrote:
On Wed, 21 Feb 2007 15:55:14 -0600, Chris Friesen wrote: Mark Lloyd wrote: Considering that there's a "source" of the power and a "load" where it's dissipated. it would be hard not to see a direction in there. Technically you don't have a "power source" in an electrical circuit. You either have a voltage source or a current source or a combination of the two. Power doesn't flow in a circuit--only current does. Power is dissipated by the various components in a circuit. The instantaneous power dissipated by any particular component can be given by I^2*R, where I is the instantaneous current flowing through the component and R is the resistance of the component. (This is all assuming a purely resistive load.) The electrical utility applies an alternating voltage to the conductors attached to the house. This causes an alternating current to flow in those conductors, with the amount of current depending on the resistance of the various circuits in the house. Thus, whether you say the hot wire "goes to", or is "connected to", or "comes from" the breaker, it is all equivalent. Chris I am slow. There is no power source in an electrical circuit? Why do they call it the power company? Ours is called Georgia Power. Isn't a combination of voltage and current "power" by definition? http://www.google.com/search?hl=en&q=georgia+power Hmmm, They don't send power to you. They send electrons to you which will produce power, LOL! |
#24
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Measuring load on a circuit breaker.
In article iUMDh.1122344$5R2.839435@pd7urf3no, Tony Hwang wrote:
Many loads are not pure resistive. There is always inductive/capacitive component. Really? Always? What's the inductive or capacitative component in a light bulb? -- Regards, Doug Miller (alphageek at milmac dot com) It's time to throw all their damned tea in the harbor again. |
#25
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Measuring load on a circuit breaker.
Ours is called Kansas City Power and Light. Which am I receiving?
-- Steve Barker "Terry" wrote in message ... I am slow. There is no power source in an electrical circuit? Why do they call it the power company? Ours is called Georgia Power. Isn't a combination of voltage and current "power" by definition? http://www.google.com/search?hl=en&q=georgia+power |
#26
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Measuring load on a circuit breaker.
On Feb 23, 8:55 pm, Tony Hwang wrote:
Terry wrote: On Wed, 21 Feb 2007 15:55:14 -0600, Chris Friesen wrote: Mark Lloyd wrote: Considering that there's a "source" of the power and a "load" where it's dissipated. it would be hard not to see a direction in there. Technically you don't have a "power source" in an electrical circuit. You either have a voltage source or a current source or a combination of the two. Power doesn't flow in a circuit--only current does. Power is dissipated by the various components in a circuit. The instantaneous power dissipated by any particular component can be given by I^2*R, where I is the instantaneous current flowing through the component and R is the resistance of the component. (This is all assuming a purely resistive load.) The electrical utility applies an alternating voltage to the conductors attached to the house. This causes an alternating current to flow in those conductors, with the amount of current depending on the resistance of the various circuits in the house. Thus, whether you say the hot wire "goes to", or is "connected to", or "comes from" the breaker, it is all equivalent. Chris I am slow. There is no power source in an electrical circuit? Why do they call it the power company? Ours is called Georgia Power. Isn't a combination of voltage and current "power" by definition? http://www.google.com/search?hl=en&q=georgia+power Hmmm, They don't send power to you. They send electrons to you which will produce power, LOL! I know they only send electrons, and they get them back. Why am I being charged for them? |
#27
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Measuring load on a circuit breaker.
Doug Miller wrote:
In article iUMDh.1122344$5R2.839435@pd7urf3no, Tony Hwang wrote: Many loads are not pure resistive. There is always inductive/capacitive component. Really? Always? What's the inductive or capacitative component in a light bulb? Hi, Filament has an amount of inductance/capacitance. it is very fine coil. Even piece of wire has finite capacitance and inductnace. Why do you think there is a surge current when light bulb is turn on? Ever heard of phase compensating capacitor or lump inductor. Or go inside a power room in any big commercial building, what do you see there? Do you know why electric cable is some times criss crossed or twisted? Simply to answer your question, Yes, really, always. It becomes very critical on high frequency. Todays florescent bulbs are driven by 44KHz current. Pure resistive circuit in real world is problably near none. Z^2 is combination of R and j(Xl-Xc). Remember HS physics class? Xl and Xc cancels each other, equal value, whatever left is either Xl, or Xc. In real world most load is inductive. In inductive circuit voltage is leading and current is lagging. This phase difference produces wasted power which does not do any work. Ideally the phase difference should be zero. That is why KVA is not equal to Watt rating of a device.(efficiency) I spent my working life on RF telecommunication(mobile and fixed base), UPS, MG, Antenna farm, stuff like that. |
#28
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Measuring load on a circuit breaker.
On Sat, 24 Feb 2007 01:55:49 GMT, Tony Hwang wrote:
Terry wrote: On Wed, 21 Feb 2007 15:55:14 -0600, Chris Friesen wrote: Mark Lloyd wrote: Considering that there's a "source" of the power and a "load" where it's dissipated. it would be hard not to see a direction in there. Technically you don't have a "power source" in an electrical circuit. You either have a voltage source or a current source or a combination of the two. Power doesn't flow in a circuit--only current does. Power is dissipated by the various components in a circuit. The instantaneous power dissipated by any particular component can be given by I^2*R, where I is the instantaneous current flowing through the component and R is the resistance of the component. (This is all assuming a purely resistive load.) The electrical utility applies an alternating voltage to the conductors attached to the house. This causes an alternating current to flow in those conductors, with the amount of current depending on the resistance of the various circuits in the house. Thus, whether you say the hot wire "goes to", or is "connected to", or "comes from" the breaker, it is all equivalent. Chris I am slow. There is no power source in an electrical circuit? Why do they call it the power company? Ours is called Georgia Power. Isn't a combination of voltage and current "power" by definition? http://www.google.com/search?hl=en&q=georgia+power Hmmm, They don't send power to you. They send electrons to you which will produce power, LOL! It's an ENERGY source. That has no effect on the validity of the concept of "source", and the direction (as mentioned with a circuit breaker). -- Mark Lloyd http://notstupid.laughingsquid.com "Unlike biological evolution. 'intelligent design' is not a genuine scientific theory and, therefore, has no place in the curriculum of our nation's public school classes." -- Ted Kennedy |
#29
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Measuring load on a circuit breaker.
On 23 Feb 2007 19:18:26 -0800, "Terry" wrote:
On Feb 23, 8:55 pm, Tony Hwang wrote: Terry wrote: On Wed, 21 Feb 2007 15:55:14 -0600, Chris Friesen wrote: Mark Lloyd wrote: Considering that there's a "source" of the power and a "load" where it's dissipated. it would be hard not to see a direction in there. Technically you don't have a "power source" in an electrical circuit. You either have a voltage source or a current source or a combination of the two. Power doesn't flow in a circuit--only current does. Power is dissipated by the various components in a circuit. The instantaneous power dissipated by any particular component can be given by I^2*R, where I is the instantaneous current flowing through the component and R is the resistance of the component. (This is all assuming a purely resistive load.) The electrical utility applies an alternating voltage to the conductors attached to the house. This causes an alternating current to flow in those conductors, with the amount of current depending on the resistance of the various circuits in the house. Thus, whether you say the hot wire "goes to", or is "connected to", or "comes from" the breaker, it is all equivalent. Chris I am slow. There is no power source in an electrical circuit? Why do they call it the power company? Ours is called Georgia Power. Isn't a combination of voltage and current "power" by definition? http://www.google.com/search?hl=en&q=georgia+power Hmmm, They don't send power to you. They send electrons to you which will produce power, LOL! I know they only send electrons, and they get them back. Why am I being charged for them? Why are you being charged for water, when they get most of that back (city sewer)? |
#30
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Measuring load on a circuit breaker.
On Fri, 23 Feb 2007 20:16:26 -0600, "Steve Barker"
wrote: Ours is called Kansas City Power and Light. Which am I receiving? The bill. All that paper and ink cost something :-) |
#31
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Measuring load on a circuit breaker.
On Sat, 24 Feb 2007 01:53:18 GMT, Tony Hwang wrote:
Mark Lloyd wrote: On Tue, 20 Feb 2007 23:34:41 -0600, Chris Friesen wrote: Mark Lloyd wrote: Consider that while current does flow both ways (or more correctly, is ALTERNATING direction), POWER goes one way. "Direction" is useful there. How do you figure that? Power is a scalar quantity given by I^2*R. Power dissipated by a load is always positive no matter which direction the current flows through the load. Chris Basically what I said. Considering that there's a "source" of the power and a "load" where it's dissipated. it would be hard not to see a direction in there. Hi, This is quite improper statement. From basic Ohm's law, current/voltage produces power measured in Watts usually which can be converted into Joule, Calorie, Horse Power, etc. Current flows, power does not. There is phantom power(false power, wasted power) in inductive cicuit. Many loads are not pure resistive. There is always inductive/capacitive component. Yes. BTW, it was in dealing with that, that I learned about complex numbers. None of this changes the logical direction here. -- Mark Lloyd http://notstupid.laughingsquid.com "Unlike biological evolution. 'intelligent design' is not a genuine scientific theory and, therefore, has no place in the curriculum of our nation's public school classes." -- Ted Kennedy |
#32
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Measuring load on a circuit breaker.
I hear ya. and we don't even use that anymore. Pay online and no bill is
sent. LOL -- Steve Barker "Harry" wrote in message ... On Fri, 23 Feb 2007 20:16:26 -0600, "Steve Barker" wrote: Ours is called Kansas City Power and Light. Which am I receiving? The bill. All that paper and ink cost something :-) |
#33
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Measuring load on a circuit breaker.
Cause they are pushy (double meaning).
E = IR; Electrons = In, Returned. -- Christopher A. Young You can't shout down a troll. You have to starve them. .. "Terry" wrote in message ups.com... : Hmmm, : They don't send power to you. They send electrons to you which will : produce power, LOL! : : I know they only send electrons, and they get them back. Why am I : being charged for them? : : |
#34
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Measuring load on a circuit breaker.
So many things to respond to. I'll have to reply inline.
-- Christopher A. Young You can't shout down a troll. You have to starve them. .. "Tony Hwang" wrote in message news:8HODh.1128989$R63.787394@pd7urf1no... : Hi, : Filament has an amount of inductance/capacitance. it is very fine coil. : Even piece of wire has finite capacitance and inductnace. Why do you : think there is a surge current when light bulb is turn on? CY: Cause the resistance of the filament is much less when the filament is cold. Ever heard of : phase compensating capacitor or lump inductor. Or go inside a power room : in any big commercial building, what do you see there? Do you know why : electric cable is some times criss crossed or twisted? CY: Cables are twisted or crissed to reduce the ammount of power going from wire to wire by inductance. Twisted pair phone wire has less hum in the phone. : Simply to answer your question, Yes, really, always. It becomes very : critical on high frequency. Todays florescent bulbs are driven by 44KHz : current. Pure resistive circuit in real world is problably near none. : Z^2 is combination of R and j(Xl-Xc). Remember HS physics class? : Xl and Xc cancels each other, equal value, whatever left is either Xl, : or Xc. In real world most load is inductive. In inductive circuit : voltage is leading and current is lagging. This phase difference : produces wasted power which does not do any work. Ideally the phase : difference should be zero. CY: Didn't know that about fluorescent RF. I knew it was higher voltage. : That is why KVA is not equal to Watt rating of a device.(efficiency) : I spent my working life on RF telecommunication(mobile and fixed base), : UPS, MG, Antenna farm, stuff like that. CY: Sounds like good experience to have. |
#35
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Measuring load on a circuit breaker.
On 23 Feb 2007 19:18:26 -0800, "Terry" wrote:
On Feb 23, 8:55 pm, Tony Hwang wrote: Terry wrote: On Wed, 21 Feb 2007 15:55:14 -0600, Chris Friesen wrote: [snip] I know they only send electrons, and they get them back. Why am I being charged for them? The electrons are going back and forth (AC) and never get anywhere. What's being sent is the kinetic energy carried by electrons. Interestingly, power companies claim that electricity moves at the speed of light. This is impossible for electrons (nonzero mass). -- Mark Lloyd http://notstupid.laughingsquid.com "Unlike biological evolution. 'intelligent design' is not a genuine scientific theory and, therefore, has no place in the curriculum of our nation's public school classes." -- Ted Kennedy |
#36
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Measuring load on a circuit breaker.
1. Wires are twisted to cancel out differential mode noise. Not all
multiconductor phone cables are twisted pair. Always buy the ones that are labelled for multi-line, they are twisted. It really sucks to run a bunch of cable all around carrying 2 lines in it and find out you can hear the person on the other phone. Happened to me years ago. 2. Ground fault breakers have neutral connected to them and then neutral for circuit connects to the breaker along with the black wire on the hot terminal. Reason is that the ground fault breaker needs to monitor the hot to neutral voltage of the circuit and the most accurate way to do that is by monitoring the individual neutral wire for the circuit. 3. Power = Volts x amps (already stated). Other forms of the equation for inductive or capacitive loads and 3 phase. 4. Yes, all electrical wires have some amount, however small, of inductive and capacitive component. For electrical power, the inductance is only an issue with frequencies greater then 60 hz. I remember the days of wiring 400hz motor generators for computer systems. The wires had to be derated for the 400 hz and you had to run them in aluminum conduit because the inductive reactance of the 400 hz in a steel conduit would cause the conductors to heat up. Steel is a good shielding material and it keeps the fields within the conduit much better then aluminum, therefore the fields heating up the wire. So, a great thread in some ways. Wow, all this theory and we still haven't figured out what the author's issue is. |
#37
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Measuring load on a circuit breaker.
"dreamchaser" writes:
2. Ground fault breakers have neutral connected to them and then neutral for circuit connects to the breaker along with the black wire on the hot terminal. Reason is that the ground fault breaker needs to monitor the hot to neutral voltage of the circuit and the most accurate way to do that is by monitoring the individual neutral wire for the circuit. No, it's because the GFI breaker wants to monitor the *current* in the white and black wires. It passes both of them through a small current transformer. If the output of the current transformer is nearly zero, then all the current flowing in the black wire is balanced by the current flowing (in the other direction) in the white wire, none of it is leaking somewhere else, and all is well. But if there's output from the current transformer, the black and white wire currents aren't equal, some of the current is thus finding another path to neutral or ground (or another hot wire, for that matter) and the GFI trips. It can't work at all without monitoring white wire current, so the white wire has to pass through the breaker. Dave |
#38
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Measuring load on a circuit breaker.
On 24 Feb 2007 17:27:51 -0800, "dreamchaser"
wrote: 1. Wires are twisted to cancel out differential mode noise. Not all multiconductor phone cables are twisted pair. Always buy the ones that are labelled for multi-line, they are twisted. It really sucks to run a bunch of cable all around carrying 2 lines in it and find out you can hear the person on the other phone. Happened to me years ago. 2. Ground fault breakers have neutral connected to them and then neutral for circuit connects to the breaker along with the black wire on the hot terminal. Reason is that the ground fault breaker needs to monitor the hot to neutral voltage of the circuit and the most accurate way to do that is by monitoring the individual neutral wire for the circuit. 3. Power = Volts x amps (already stated). Other forms of the equation for inductive or capacitive loads and 3 phase. 4. Yes, all electrical wires have some amount, however small, of inductive and capacitive component. For electrical power, the inductance is only an issue with frequencies greater then 60 hz. I remember the days of wiring 400hz motor generators for computer systems. The wires had to be derated for the 400 hz and you had to run them in aluminum conduit because the inductive reactance of the 400 hz in a steel conduit would cause the conductors to heat up. Steel is a good shielding material and it keeps the fields within the conduit much better then aluminum, therefore the fields heating up the wire. So, a great thread in some ways. Wow, all this theory and we still haven't figured out what the author's issue is. The original question was answered. The answer was no. They don't make such an instrument. |
#39
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Measuring load on a circuit breaker.
I know they only send electrons, and they get them back. Why am I being charged for them? Why are you being charged for water, when they get most of that back (city sewer)? Now I understand things better. The power company sends clean electrons thru the hot wire, they are used and get dirty in the house, and they go back to the power company thru the neutral to be cleaned up and sent back out again on the hot wire. I always wondered what that neutral wire was good for! 8) Don Young |
#40
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Measuring load on a circuit breaker.
On Sat, 24 Feb 2007 21:10:17 -0600, "Don Young"
wrote: I know they only send electrons, and they get them back. Why am I being charged for them? Why are you being charged for water, when they get most of that back (city sewer)? Now I understand things better. The power company sends clean electrons thru the hot wire, they are used and get dirty in the house, and they go back to the power company thru the neutral to be cleaned up and sent back out again on the hot wire. I always wondered what that neutral wire was good for! 8) Don Young And why have 2 hot wires, when those electrons could fit in one? I checked that out. The other hot is just a signal wire for the [censored] evil mind reading and writing interfaces. The ones that make sure you vote for the "right" candidate. You didn't actually read that, for it has never been written. |
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