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![]() wrote in message ... Christopher A. Steele wrote: Sometimes it gets so hot around here it's difficult to sleep at night (to the point I sometimes have to get up two or three times to cool off in the shower just to get comfortable for a few minutes). Sir Turtle might suggest a space heater to raise the room temp to 95 F, which he describes as "too cold," vs 60 F ("too hot" :-) I'm curious: given 'x' ambient temperature in my bedroom at night (and 'y' relative humidity, I suppose) and closed bedroom windows and doors, how do I calculate the amount of heat (heat load??) that has to be 'removed' from my body so that I can sleep comfortably... An ASHRAE-standard 154 pound human dissipates 253 Btu/h when sleeping. Is there a formula? Sure. ASHRAE-standard 55-2004 ("Thermal environmental conditions for human occupancy") defines two "comfort zones," winter (with a clo = 1 clothing thermal resistance) and summer (clo = 0.5.) Its BASIC program estimates the Predicted Mean Vote (PMV: +3 hot, +2 warm, +1 slightly warm, 0 neutral, -1 slightly cool, -2 cool, and -3 cold) and the Predicted Percentage Dissatisfied (PPD) based on clothing, activity, metabolic rate, external work, air temp, mean radiant temp, air velocity, and RH... 50 CLO = 1'clothing insulation (clo) 60 MET=1.1'metabolic rate (met) 70 WME=0'external work (met) 80 TA=19.6'air temp (C) 90 TR=19.6'mean radiant temp (C) 100 VEL=.1'air velocity (m/s) 120 RH=86'relative humidity (%) make one of RH or PA non-zero... 130 PA=0'water vapor pressure 140 DEF FNPS(T)=EXP(16.6536-4030.183/(TA+235))'sat vapor pressure, kPa 150 IF PA=0 THEN PA=RH*10*FNPS(TA)'water vapor pressure, Pa 160 ICL=.155*CLO'clothing resistance (m^2K/W) 170 M=MET*58.15'metabolic rate (W/m^2) 180 W=WME*58.15'external work in (W/m^2) 190 MW=M-W'internal heat production 200 IF ICL.078 THEN FCL=1+1.29*ICL ELSE FCL=1.05+.645*ICL'clothing factor 210 HCF=12.1*SQR(VEL)'forced convection conductance 220 TAA=TA+273'air temp (K) 230 TRA=TR+273'mean radiant temp (K) 250 TCLA=TAA+(35.5-TA)/(3.5*(6.45*ICL+.1))'est clothing temp 260 P1=ICL*FCL:P2=P1*3.96:P3=P1*100:P4=P1*TAA'intermed iate values 300 P5=308.7-.028*MW+P2*(TRA/100)^4 310 XN=TCLA/100 320 XF=XN 330 N=0'number of iterations 340 EPS=.00015'stop iteration when met 350 XF=(XF+XN)/2'natural convection conductance 360 HCN=2.38*ABS(100*XF-TAA)^.25 370 IF HCFHCN THEN HC=HCF ELSE HC=HCN 380 XN=(P5+P4*HC-P2*XF^4)/(100+P3*HC) 390 N=N+1 400 IF N150 GOTO 550 410 IF ABS(XN-XF)EPS GOTO 350 420 TCL=100*XN-273'clothing surface temp (C) 440 HL1=.00305*(5733-6.99*MW-PA)'heat loss diff through skin 450 IF MW58.15 THEN HL2=.42*(MW-58.15) ELSE HL2=0'heat loss by sweating 460 HL3=.000017*M*(5867-PA)'latent respiration heat loss 470 HL4=.0014*M*(34-TA)'dry respiration heat loss 480 HL5=3.96*FCL*(XN^4-(TRA/100)^4)'heat loss by radiation 490 HL6=FCL*HC*(TCL-TA)'heat loss by convection 510 TS=.303*EXP(-.036*M)+.028'thermal sensation transfer coefficient 520 PMV=TS*(MW-HL1-HL2-HL3-HL4-HL5-HL6)'predicted mean vote 530 PPD=100-95*EXP(-.03353*PMV^4-.2179*PMV^2)'predicted % dissatisfied 540 GOTO 580 550 PMV=99999!:PPD=100 580 PRINT TA,RH,CLO,PMV,PPD T (C) RH clo PMV PPD 19.6 86 1 -.4778556 9.769089 23.9 66 1 .4732535 9.676994 25.7 15 1 .5239881 10.74283 21.2 20 1 -.4779105 9.770202 23.6 67 .5 -.4747404 9.706658 26.8 56 .5 .5145492 10.53611 27.9 13 .5 .5003051 10.23146 24.7 16 .5 -.4883473 9.982468 The first 4 lines are the winter comfort zone corners. The second 4 lines are the summer comfort zone corners. An average person is "comfortable" when the PMV = 0. "Travis Jordan" writes: The ASHRAE calculations for heat gain assume 600 BTU/H per person. That's 150 calories / hour. That works for large Btus. mj writes: Being uncomfortable typically has more to due with humidity than temperature... The ASHRAE 55-2004 comfort zone disagrees, based on surveys of 21,000 people. Nick This is Turtle. if you can't explain %RH as to temperature that most people likes , you just explaining what you think and have no ideal of the real world is thinking. You sure quote the ASHRAE a lot but I wished you could understand it in real life terms. Here is one for you. 5%RH or there about and 90ºF = pretty cool. What do you think and don't try to justify your reply with references but explain it in real life terms. Nick you live in a book and if I took your book away from you. You would be speechless. TURTLE |
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