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Metalworking (rec.crafts.metalworking) Discuss various aspects of working with metal, such as machining, welding, metal joining, screwing, casting, hardening/tempering, blacksmithing/forging, spinning and hammer work, sheet metal work. |
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#1
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Chinese CFM ? -- Compressor
Anyone here know of a table or spreadsheet anywhere online that will
allow you to estimate the actual approximate CFM rating of a compressor? Seems to me you ought to be able to measure the length of time it takes for the tank to reach several different pressures and then plug that along with the tank size into an equation to get a reasonable estimate of the true (approximate) CFM. Anyone have Avogadro's number memorized? If so maybe I could give him a call... |
#2
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Chinese CFM ? -- Compressor
Dave wrote:
Anyone here know of a table or spreadsheet anywhere online that will allow you to estimate the actual approximate CFM rating of a compressor? Volume (of tank) * pressure (in tank; value in bar) = aspirated volume. If the tank is pressure-less, start your stopwatch, stop it when it is full. Divide aspirated volume by that time (in minutes). That's only a guesstimate, because efficency will decrease with rising pressure and the formula also doesn't consider rise of temperature. But you have a good ballpark. Nick -- Motor Modelle // Engine Models http://www.motor-manufaktur.de DIY-DRO - YADRO - Eigenbau-Digitalanzeige |
#3
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Chinese CFM ? -- Compressor
A variation on that theme is to measure the time required to increase
the pressure of the tank by 15 psi (14.7psi is atmospheric pressure at sea level.) Let me try a sample calculation. 25 gallon tank x 0.1337 cuft/gal = 3.34 cubic feet If it takes 30 seconds to increase the tank pressure 15 psi, it would take one minute to increase the tank pressure 30 psi (disregarding efficiencies). 30 seconds is half a minute. 3.34 cubic feet / 0.5 minute = 6.68 CFM Richard Nick Müller wrote: Dave wrote: Anyone here know of a table or spreadsheet anywhere online that will allow you to estimate the actual approximate CFM rating of a compressor? Volume (of tank) * pressure (in tank; value in bar) = aspirated volume. If the tank is pressure-less, start your stopwatch, stop it when it is full. Divide aspirated volume by that time (in minutes). That's only a guesstimate, because efficency will decrease with rising pressure and the formula also doesn't consider rise of temperature. But you have a good ballpark. Nick -- http://www.fergusonsculpture.com Sculptures in copper and other metals |
#4
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Chinese CFM ? -- Compressor
Richard Ferguson wrote:
A variation on that theme is to measure the time required to increase the pressure of the tank by 15 psi (14.7psi is atmospheric pressure at sea level.) Let me try a sample calculation. 25 gallon tank x 0.1337 cuft/gal = 3.34 cubic feet If it takes 30 seconds to increase the tank pressure 15 psi, it would take one minute to increase the tank pressure 30 psi (disregarding efficiencies). 30 seconds is half a minute. 3.34 cubic feet / 0.5 minute = 6.68 CFM Richard Thanks, that is very straightforward. So if I measure the time from 60psi to 75psi and plug that in I should get a conservative value of true CFM for 60psi ? |
#5
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Chinese CFM ? -- Compressor
You bet! I may not remember much from college, but 6.023 times 10 to the
twenty third has worked every time when I needed Avogadro's number. Thanks for waking the old memory cells Bert "Dave" wrote in message oups.com... Anyone here know of a table or spreadsheet anywhere online that will allow you to estimate the actual approximate CFM rating of a compressor? Seems to me you ought to be able to measure the length of time it takes for the tank to reach several different pressures and then plug that along with the tank size into an equation to get a reasonable estimate of the true (approximate) CFM. Anyone have Avogadro's number memorized? If so maybe I could give him a call... |
#6
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Chinese CFM ? -- Compressor
I don't know about a conservative value, but you would have a ballpark
value. You can use the reverse process to figure CFM for tools, turn off the compressor and measure the time it takes the tool to drop the tank presssure from 105psi to 90 psi. As others have noted, the measured CFM for a compressor will probably be less than the published CFM, while the measured CFM for a tool will probably be more than the published CFM. :-( In other words, get a bigger compressor than the CFM numbers suggest would be adequate. You would need to convert gallons to cubic feet, but the sample calculation showed the conversion factor. Richard Dave wrote: Thanks, that is very straightforward. So if I measure the time from 60psi to 75psi and plug that in I should get a conservative value of true CFM for 60psi ? -- http://www.fergusonsculpture.com Sculptures in copper and other metals |
#7
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Chinese CFM ? -- Compressor
The Tagge's wrote:
You bet! I may not remember much from college, but 6.023 times 10 to the twenty third has worked every time when I needed Avogadro's number. Thanks for waking the old memory cells Bert "Dave" wrote in message oups.com... Anyone here know of a table or spreadsheet anywhere online that will allow you to estimate the actual approximate CFM rating of a compressor? Seems to me you ought to be able to measure the length of time it takes for the tank to reach several different pressures and then plug that along with the tank size into an equation to get a reasonable estimate of the true (approximate) CFM. Anyone have Avogadro's number memorized? If so maybe I could give him a call... It's also 781-721-1130, our second home phone line. I listed that line under "J. Avogadro" when we got it years ago, further proof that I'll never grow up. Before they outlawed residential telemarketing it was fun to respond to callers asking for "Mr. Avogadro" with, "Sorry, he passed away." They usually offered condolences and I'd say, "We'll we're pretty much over it, he died in 1856." I looked recently and found there's three other phone numbers for Avogadros in the US, all in California. One of them is in the name of "No Avogadros", obviously another jokester, and the other two are listed in the name of "Amadeo Avogadro", but my references to the number guy all show his first name as "Amedio." Jeff -- Jeffry Wisnia (W1BSV + Brass Rat '57 EE) "Truth exists; only falsehood has to be invented." |
#8
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Chinese CFM ? -- Compressor
Oh, I meant it would be a conservative value because it is being
measured above rather than at the specified pressure. Richard Ferguson wrote: I don't know about a conservative value, but you would have a ballpark value. You can use the reverse process to figure CFM for tools, turn off the compressor and measure the time it takes the tool to drop the tank presssure from 105psi to 90 psi. As others have noted, the measured CFM for a compressor will probably be less than the published CFM, while the measured CFM for a tool will probably be more than the published CFM. :-( In other words, get a bigger compressor than the CFM numbers suggest would be adequate. You would need to convert gallons to cubic feet, but the sample calculation showed the conversion factor. Richard Dave wrote: Thanks, that is very straightforward. So if I measure the time from 60psi to 75psi and plug that in I should get a conservative value of true CFM for 60psi ? |
#9
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Chinese CFM ? -- Compressor
Dave writes:
Anyone here know of a table or spreadsheet anywhere online that will allow you to estimate the actual approximate CFM rating of a compressor? http://www.truetex.com/aircompressors.htm |
#10
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Chinese CFM ? -- Compressor
Thanks for posting the link to that detailed explanation. It confirmed
my understanding and calculations. ;-) Richard Richard J Kinch wrote: Dave writes: Anyone here know of a table or spreadsheet anywhere online that will allow you to estimate the actual approximate CFM rating of a compressor? http://www.truetex.com/aircompressors.htm -- http://www.fergusonsculpture.com Sculptures in copper and other metals |
#11
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Chinese CFM ? -- Compressor
I'm getting the feeling that an actual Chinese CFM is about 50% of what
the rating claims. The Truetex link suggests a big fudge factor. Is this all due to the unknown temperature change? What if you start with a cool compressor, run it, and then let it cool down again? Richard Ferguson wrote: Thanks for posting the link to that detailed explanation. It confirmed my understanding and calculations. ;-) Richard Richard J Kinch wrote: http://www.truetex.com/aircompressors.htm |
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