Home |
Search |
Today's Posts |
#1
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
I have a variable transformer, http://www.faqs.org/docs/electric/AC/02149.png
If the current in the load (set in the middle at say 120 volts) is 3 amps, I assume the current from the source (240 volts) will be 1.5 amps. Does this mean that the current in half the windings is 4.5 amps (3 plus 1.5), or 1.5 amps (3 minus 1.5), or will the load current be out of phase with the source? -- http://petersparrots.com http://petersphotos.com A man goes into a library and asks for a book on suicide. The librarian says, "**** off, you won't bring it back!" |
#2
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
Lieutenant Scott wrote:
I have a variable transformer, http://www.faqs.org/docs/electric/AC/02149.png If the current in the load (set in the middle at say 120 volts) is 3 amps, I assume the current from the source (240 volts) will be 1.5 amps. Does this mean that the current in half the windings is 4.5 amps (3 plus 1.5), or 1.5 amps (3 minus 1.5), or will the load current be out of phase with the source? Looong time since I used a variable transformer (and then it was a stepped transformer), but you can look at it better by considering Power, i.e. if your load is using 360 Watts (120v x 3amps), so your primary winding must be delivering at least that much power, so 360W/240V gives 1.5Amps (In reality it will be a bit more (1.6A maybe), due to losses with-in the transformer). So the transformer would have two totally separate windings, one (the Primary) creating a magnetic field which induces the voltage into the secondary winding to supply the loads current. How the phases relate to each other ....... I think they end up in phase, depending on the actual load! HTH Daniel |
#4
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
Lieutenant Scott wrote:
On Sun, 25 Nov 2012 12:57:49 -0000, wrote: Lieutenant Scott wrote: I have a variable transformer, http://www.faqs.org/docs/electric/AC/02149.png If the current in the load (set in the middle at say 120 volts) is 3 amps, I assume the current from the source (240 volts) will be 1.5 amps. Does this mean that the current in half the windings is 4.5 amps (3 plus 1.5), or 1.5 amps (3 minus 1.5), or will the load current be out of phase with the source? Looong time since I used a variable transformer (and then it was a stepped transformer), but you can look at it better by considering Power, i.e. if your load is using 360 Watts (120v x 3amps), so your primary winding must be delivering at least that much power, so 360W/240V gives 1.5Amps (In reality it will be a bit more (1.6A maybe), due to losses with-in the transformer). So the transformer would have two totally separate windings, one (the Primary) creating a magnetic field which induces the voltage into the secondary winding to supply the loads current. How the phases relate to each other ....... I think they end up in phase, depending on the actual load! What confused me about the Variac was it only has one winding. If it was a normal transformer stepping from 240 to 120 volts, the currents are easy to work out. But with the Variac, the current going through the load is in the same coil as the primary current from the supply. I would think it goes the *opposite* way if they're in phase, as source and load share a common neutral at the bottom, so this would mean LESS current in total flows in the bottom half of the coil? (Subtracting one current from the other). Gee, didn't even notice you were talking about a Variac!! O.K., what I explained above was for a normal Transformer which would have two connections for the primary winding and two for the secondary winding. Now if you connect the two "Earth" or "Neutral" connections together, you do end up with an (effective) three connection device, with both the primary winding and the secondary sharing the third connection. I think my mathematics still applies!! Daniel |
#5
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
On Mon, 26 Nov 2012 12:40:18 -0000, wrote:
Lieutenant Scott wrote: On Sun, 25 Nov 2012 12:57:49 -0000, wrote: Lieutenant Scott wrote: I have a variable transformer, http://www.faqs.org/docs/electric/AC/02149.png If the current in the load (set in the middle at say 120 volts) is 3 amps, I assume the current from the source (240 volts) will be 1.5 amps. Does this mean that the current in half the windings is 4.5 amps (3 plus 1.5), or 1.5 amps (3 minus 1.5), or will the load current be out of phase with the source? Looong time since I used a variable transformer (and then it was a stepped transformer), but you can look at it better by considering Power, i.e. if your load is using 360 Watts (120v x 3amps), so your primary winding must be delivering at least that much power, so 360W/240V gives 1.5Amps (In reality it will be a bit more (1.6A maybe), due to losses with-in the transformer). So the transformer would have two totally separate windings, one (the Primary) creating a magnetic field which induces the voltage into the secondary winding to supply the loads current. How the phases relate to each other ....... I think they end up in phase, depending on the actual load! What confused me about the Variac was it only has one winding. If it was a normal transformer stepping from 240 to 120 volts, the currents are easy to work out. But with the Variac, the current going through the load is in the same coil as the primary current from the supply. I would think it goes the *opposite* way if they're in phase, as source and load share a common neutral at the bottom, so this would mean LESS current in total flows in the bottom half of the coil? (Subtracting one current from the other). Gee, didn't even notice you were talking about a Variac!! O.K., what I explained above was for a normal Transformer which would have two connections for the primary winding and two for the secondary winding. Now if you connect the two "Earth" or "Neutral" connections together, you do end up with an (effective) three connection device, with both the primary winding and the secondary sharing the third connection. I think my mathematics still applies!! Daniel The thing is my 3 amps and my 1.5 amps are in the same wire. If they're opposing that's fine, if they're not it adds to 4.5 amps and gets hotter. My thinking is when the current is flowing from top to bottom from the source, that it will flow bottom to top in your secondary (or in mine back through the same wire, subtracting from the current. (The source getting the "negative" on the "earth" side at the same time as the source does the same). -- http://petersparrots.com http://petersphotos.com "I was walking down fifth avenue today and I found a wallet, and I was gonna keep it, rather than return it, but I thought: well, if I lost a hundred and fifty dollars, how would I feel? And I realized I would want to be taught a lesson." -- Emo Philips |
#6
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
Lieutenant Scott wrote:
On Mon, 26 Nov 2012 12:40:18 -0000, wrote: Lieutenant Scott wrote: On Sun, 25 Nov 2012 12:57:49 -0000, wrote: Lieutenant Scott wrote: I have a variable transformer, http://www.faqs.org/docs/electric/AC/02149.png If the current in the load (set in the middle at say 120 volts) is 3 amps, I assume the current from the source (240 volts) will be 1.5 amps. Does this mean that the current in half the windings is 4.5 amps (3 plus 1.5), or 1.5 amps (3 minus 1.5), or will the load current be out of phase with the source? Looong time since I used a variable transformer (and then it was a stepped transformer), but you can look at it better by considering Power, i.e. if your load is using 360 Watts (120v x 3amps), so your primary winding must be delivering at least that much power, so 360W/240V gives 1.5Amps (In reality it will be a bit more (1.6A maybe), due to losses with-in the transformer). So the transformer would have two totally separate windings, one (the Primary) creating a magnetic field which induces the voltage into the secondary winding to supply the loads current. How the phases relate to each other ....... I think they end up in phase, depending on the actual load! What confused me about the Variac was it only has one winding. If it was a normal transformer stepping from 240 to 120 volts, the currents are easy to work out. But with the Variac, the current going through the load is in the same coil as the primary current from the supply. I would think it goes the *opposite* way if they're in phase, as source and load share a common neutral at the bottom, so this would mean LESS current in total flows in the bottom half of the coil? (Subtracting one current from the other). Gee, didn't even notice you were talking about a Variac!! O.K., what I explained above was for a normal Transformer which would have two connections for the primary winding and two for the secondary winding. Now if you connect the two "Earth" or "Neutral" connections together, you do end up with an (effective) three connection device, with both the primary winding and the secondary sharing the third connection. I think my mathematics still applies!! Daniel The thing is my 3 amps and my 1.5 amps are in the same wire. If they're opposing that's fine, if they're not it adds to 4.5 amps and gets hotter. My thinking is when the current is flowing from top to bottom from the source, that it will flow bottom to top in your secondary (or in mine back through the same wire, subtracting from the current. (The source getting the "negative" on the "earth" side at the same time as the source does the same). No, think of a see-saw.....The current flows in at the pivot point and each flows towards one of the ends...the 3 amps (being heavier) goes to the bottom end, and flows out to load and back to the pivot point (the "centre tap"). The 1.5'ish amps flows out the top, off to the mains supply and back to the pivot point (the "centre tap"). The only place that both currents are flowing together is at the centre tap, and then they go their own ways! And, at the centre tap (and only at the tap), you may have both the 1.5 amps (main winding current) and the 3 amps (secondary current) flowing, and, depending on the phase angle between them, the amount of current flowing at any particular time, at the centre tap could be anywhere between 1.5 amps and 4.5 amps! But, in the windings the most current would be 3 Amps. Daniel |
#7
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
On Tue, 27 Nov 2012 09:55:33 -0000, wrote:
Lieutenant Scott wrote: On Mon, 26 Nov 2012 12:40:18 -0000, wrote: Lieutenant Scott wrote: On Sun, 25 Nov 2012 12:57:49 -0000, wrote: Lieutenant Scott wrote: Looong time since I used a variable transformer (and then it was a stepped transformer), but you can look at it better by considering Power, i.e. if your load is using 360 Watts (120v x 3amps), so your primary winding must be delivering at least that much power, so 360W/240V gives 1.5Amps (In reality it will be a bit more (1.6A maybe), due to losses with-in the transformer). So the transformer would have two totally separate windings, one (the Primary) creating a magnetic field which induces the voltage into the secondary winding to supply the loads current. How the phases relate to each other ....... I think they end up in phase, depending on the actual load! What confused me about the Variac was it only has one winding. If it was a normal transformer stepping from 240 to 120 volts, the currents are easy to work out. But with the Variac, the current going through the load is in the same coil as the primary current from the supply. I would think it goes the *opposite* way if they're in phase, as source and load share a common neutral at the bottom, so this would mean LESS current in total flows in the bottom half of the coil? (Subtracting one current from the other). Gee, didn't even notice you were talking about a Variac!! O.K., what I explained above was for a normal Transformer which would have two connections for the primary winding and two for the secondary winding. Now if you connect the two "Earth" or "Neutral" connections together, you do end up with an (effective) three connection device, with both the primary winding and the secondary sharing the third connection. I think my mathematics still applies!! Daniel The thing is my 3 amps and my 1.5 amps are in the same wire. If they're opposing that's fine, if they're not it adds to 4.5 amps and gets hotter. My thinking is when the current is flowing from top to bottom from the source, that it will flow bottom to top in your secondary (or in mine back through the same wire, subtracting from the current. (The source getting the "negative" on the "earth" side at the same time as the source does the same). No, think of a see-saw.....The current flows in at the pivot point and each flows towards one of the ends...the 3 amps (being heavier) goes to the bottom end, and flows out to load and back to the pivot point (the "centre tap"). The 1.5'ish amps flows out the top, off to the mains supply and back to the pivot point (the "centre tap"). The only place that both currents are flowing together is at the centre tap, and then they go their own ways! And, at the centre tap (and only at the tap), you may have both the 1.5 amps (main winding current) and the 3 amps (secondary current) flowing, and, depending on the phase angle between them, the amount of current flowing at any particular time, at the centre tap could be anywhere between 1.5 amps and 4.5 amps! But, in the windings the most current would be 3 Amps. Daniel I think that's the same as what I'm saying. So 1.5 amps comes from the source to the bottom common point (common connection to source and load), and goes through the load to the centre tap. The other 1.5 amps the load is getting is circulating through the bottom half of the coil: centre tap to bottom, then through the load, back to the centre tap. I make that 1.5 amps in all the coil though. Another clue might be that the Variac states that 3A LOAD is the maximum, no matter what voltage you've selected by moving the centre tap. There must be a physics book on this somewhere online..... -- http://petersparrots.com http://petersphotos.com Why isn;t the apostrophe next to the L? Who ever uses the semicolon??? |
#8
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
Lieutenant Scott wrote:
On Tue, 27 Nov 2012 09:55:33 -0000, wrote: Lieutenant Scott wrote: On Mon, 26 Nov 2012 12:40:18 -0000, wrote: Lieutenant Scott wrote: On Sun, 25 Nov 2012 12:57:49 -0000, wrote: Lieutenant Scott wrote: Looong time since I used a variable transformer (and then it was a stepped transformer), but you can look at it better by considering Power, i.e. if your load is using 360 Watts (120v x 3amps), so your primary winding must be delivering at least that much power, so 360W/240V gives 1.5Amps (In reality it will be a bit more (1.6A maybe), due to losses with-in the transformer). So the transformer would have two totally separate windings, one (the Primary) creating a magnetic field which induces the voltage into the secondary winding to supply the loads current. How the phases relate to each other ....... I think they end up in phase, depending on the actual load! What confused me about the Variac was it only has one winding. If it was a normal transformer stepping from 240 to 120 volts, the currents are easy to work out. But with the Variac, the current going through the load is in the same coil as the primary current from the supply. I would think it goes the *opposite* way if they're in phase, as source and load share a common neutral at the bottom, so this would mean LESS current in total flows in the bottom half of the coil? (Subtracting one current from the other). Gee, didn't even notice you were talking about a Variac!! O.K., what I explained above was for a normal Transformer which would have two connections for the primary winding and two for the secondary winding. Now if you connect the two "Earth" or "Neutral" connections together, you do end up with an (effective) three connection device, with both the primary winding and the secondary sharing the third connection. I think my mathematics still applies!! Daniel The thing is my 3 amps and my 1.5 amps are in the same wire. If they're opposing that's fine, if they're not it adds to 4.5 amps and gets hotter. My thinking is when the current is flowing from top to bottom from the source, that it will flow bottom to top in your secondary (or in mine back through the same wire, subtracting from the current. (The source getting the "negative" on the "earth" side at the same time as the source does the same). No, think of a see-saw.....The current flows in at the pivot point and each flows towards one of the ends...the 3 amps (being heavier) goes to the bottom end, and flows out to load and back to the pivot point (the "centre tap"). The 1.5'ish amps flows out the top, off to the mains supply and back to the pivot point (the "centre tap"). The only place that both currents are flowing together is at the centre tap, and then they go their own ways! And, at the centre tap (and only at the tap), you may have both the 1.5 amps (main winding current) and the 3 amps (secondary current) flowing, and, depending on the phase angle between them, the amount of current flowing at any particular time, at the centre tap could be anywhere between 1.5 amps and 4.5 amps! But, in the windings the most current would be 3 Amps. Daniel I think that's the same as what I'm saying. So 1.5 amps comes from the source to the bottom common point (common connection to source and load), and goes through the load to the centre tap. No, the load current goes to the centre point, not the bottom point The other 1.5 amps the load is getting is circulating through the bottom half of the coil: centre tap to bottom, then through the load, back to the centre tap. I make that 1.5 amps in all the coil though. Another clue might be that the Variac states that 3A LOAD is the maximum, no matter what voltage you've selected by moving the centre tap. There must be a physics book on this somewhere online..... Back to the beginning, forget that you have a Variac, just think of a transformer with four connection points. The Primary winding is connected to the mains and the secondary winding is connected to the load. Current flows from the wall socket, into one terminal of the Primary winding, flows through the Primary, and current then flows back to the wall socket. No if's, no maybe's. The alternating current flowing in the Primary produces a fluctuating magnetic field around the Primary winding. This fluctuating magnetic field also cuts the windings of the Secondary winding. This induces a voltage into the Secondary winding. If there is no load connected, there is no load current flowing, just voltage at the Secondary winding terminals. Because the is no load, load current will be zero! Now when you connect a load to the Secondary winding, the voltage induced into the Secondary winding causes a current to flow from one end of the Secondary winding, out through the load and back in the other end of the secondary winding. Totally separate from the Primary. The Primary current has not gone anywhere near the secondary winding, but the Primary current has caused the magnetic field which then caused the Secondary current. Daniel |
#9
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
On Tue, 27 Nov 2012 14:49:56 -0000, wrote:
Lieutenant Scott wrote: On Tue, 27 Nov 2012 09:55:33 -0000, wrote: Lieutenant Scott wrote: On Mon, 26 Nov 2012 12:40:18 -0000, wrote: Lieutenant Scott wrote: Gee, didn't even notice you were talking about a Variac!! O.K., what I explained above was for a normal Transformer which would have two connections for the primary winding and two for the secondary winding. Now if you connect the two "Earth" or "Neutral" connections together, you do end up with an (effective) three connection device, with both the primary winding and the secondary sharing the third connection. I think my mathematics still applies!! Daniel The thing is my 3 amps and my 1.5 amps are in the same wire. If they're opposing that's fine, if they're not it adds to 4.5 amps and gets hotter. My thinking is when the current is flowing from top to bottom from the source, that it will flow bottom to top in your secondary (or in mine back through the same wire, subtracting from the current. (The source getting the "negative" on the "earth" side at the same time as the source does the same). No, think of a see-saw.....The current flows in at the pivot point and each flows towards one of the ends...the 3 amps (being heavier) goes to the bottom end, and flows out to load and back to the pivot point (the "centre tap"). The 1.5'ish amps flows out the top, off to the mains supply and back to the pivot point (the "centre tap"). The only place that both currents are flowing together is at the centre tap, and then they go their own ways! And, at the centre tap (and only at the tap), you may have both the 1.5 amps (main winding current) and the 3 amps (secondary current) flowing, and, depending on the phase angle between them, the amount of current flowing at any particular time, at the centre tap could be anywhere between 1.5 amps and 4.5 amps! But, in the windings the most current would be 3 Amps. Daniel I think that's the same as what I'm saying. So 1.5 amps comes from the source to the bottom common point (common connection to source and load), and goes through the load to the centre tap. No, the load current goes to the centre point, not the bottom point The other 1.5 amps the load is getting is circulating through the bottom half of the coil: centre tap to bottom, then through the load, back to the centre tap. I make that 1.5 amps in all the coil though. Another clue might be that the Variac states that 3A LOAD is the maximum, no matter what voltage you've selected by moving the centre tap. There must be a physics book on this somewhere online..... Back to the beginning, forget that you have a Variac, just think of a transformer with four connection points. The Primary winding is connected to the mains and the secondary winding is connected to the load. Current flows from the wall socket, into one terminal of the Primary winding, flows through the Primary, and current then flows back to the wall socket. No if's, no maybe's. The alternating current flowing in the Primary produces a fluctuating magnetic field around the Primary winding. This fluctuating magnetic field also cuts the windings of the Secondary winding. This induces a voltage into the Secondary winding. If there is no load connected, there is no load current flowing, just voltage at the Secondary winding terminals. Because the is no load, load current will be zero! Now when you connect a load to the Secondary winding, the voltage induced into the Secondary winding causes a current to flow from one end of the Secondary winding, out through the load and back in the other end of the secondary winding. Totally separate from the Primary. The Primary current has not gone anywhere near the secondary winding, but the Primary current has caused the magnetic field which then caused the Secondary current. Daniel Yes I understand a normal transformer. But... in your example above, is the current flowing in the same direction in the primary and secondary? I know it's AC, but think of the first half of the sine wave. Now think of the Variac. The "secondary" is actually half of the primary. One half of the coil is just a bit of primary. The other half of the coil is BOTH half the primary and all the secondary. So this part of the winding carries TWO currents. It matters if the currents are in the same direction, as they might either add or subtract from each other. -- http://petersparrots.com http://petersphotos.com The easiest way to find something lost around the house is to buy a replacement. |
#10
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
Lieutenant Scott wrote:
On Tue, 27 Nov 2012 14:49:56 -0000, wrote: Lieutenant Scott wrote: Snip Back to the beginning, forget that you have a Variac, just think of a transformer with four connection points. The Primary winding is connected to the mains and the secondary winding is connected to the load. Current flows from the wall socket, into one terminal of the Primary winding, flows through the Primary, and current then flows back to the wall socket. No if's, no maybe's. The alternating current flowing in the Primary produces a fluctuating magnetic field around the Primary winding. This fluctuating magnetic field also cuts the windings of the Secondary winding. This induces a voltage into the Secondary winding. If there is no load connected, there is no load current flowing, just voltage at the Secondary winding terminals. Because the is no load, load current will be zero! Now when you connect a load to the Secondary winding, the voltage induced into the Secondary winding causes a current to flow from one end of the Secondary winding, out through the load and back in the other end of the secondary winding. Totally separate from the Primary. The Primary current has not gone anywhere near the secondary winding, but the Primary current has caused the magnetic field which then caused the Secondary current. Daniel Yes I understand a normal transformer. But... in your example above, is the current flowing in the same direction in the primary and secondary? I know it's AC, but think of the first half of the sine wave. Now think of the Variac. The "secondary" is actually half of the primary. One half of the coil is just a bit of primary. The other half of the coil is BOTH half the primary and all the secondary. So this part of the winding carries TWO currents. It matters if the currents are in the same direction, as they might either add or subtract from each other. Not possible, Scotty, you cannot have both Primary and Secondary currents flowing in one part of the (primary & Secondary) winding and just Primary current flowing in the remainder of the (primary) winding. Cannot happen!! As for the phase relationships between totally separated Primary and Secondary windings, this can depend on the load connected to the Secondary (i.e. is the load purely resistive or capacitively reactive or inductively reactive. And the phase relationship would also depend if the "top" or the "bottom" of the Secondary is connected to the bottom of the Primary winding!! Forget a transformer.....think of two series resistors with a centre take-off point, say a nine ohm resistor and a one ohm resistor with ten volts applied across the combination. One amp of current would be flowing through the two resistors, with nine volts developed across the nine ohm resister and one volt across the one ohm resistor. Now, if you connect another resistor across the one ohm resistor, you don't get an increase of current flowing through the one ohm resistor to provide the current that would flow through the additional resistor. Daniel |
#11
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
On Mon, 10 Dec 2012 14:18:53 -0000, wrote:
Lieutenant Scott wrote: On Tue, 27 Nov 2012 14:49:56 -0000, wrote: Lieutenant Scott wrote: Snip Back to the beginning, forget that you have a Variac, just think of a transformer with four connection points. The Primary winding is connected to the mains and the secondary winding is connected to the load. Current flows from the wall socket, into one terminal of the Primary winding, flows through the Primary, and current then flows back to the wall socket. No if's, no maybe's. The alternating current flowing in the Primary produces a fluctuating magnetic field around the Primary winding. This fluctuating magnetic field also cuts the windings of the Secondary winding. This induces a voltage into the Secondary winding. If there is no load connected, there is no load current flowing, just voltage at the Secondary winding terminals. Because the is no load, load current will be zero! Now when you connect a load to the Secondary winding, the voltage induced into the Secondary winding causes a current to flow from one end of the Secondary winding, out through the load and back in the other end of the secondary winding. Totally separate from the Primary. The Primary current has not gone anywhere near the secondary winding, but the Primary current has caused the magnetic field which then caused the Secondary current. Daniel Yes I understand a normal transformer. But... in your example above, is the current flowing in the same direction in the primary and secondary? I know it's AC, but think of the first half of the sine wave. Now think of the Variac. The "secondary" is actually half of the primary. One half of the coil is just a bit of primary. The other half of the coil is BOTH half the primary and all the secondary. So this part of the winding carries TWO currents. It matters if the currents are in the same direction, as they might either add or subtract from each other. Not possible, Scotty, you cannot have both Primary and Secondary currents flowing in one part of the (primary & Secondary) winding and just Primary current flowing in the remainder of the (primary) winding. Cannot happen!! As for the phase relationships between totally separated Primary and Secondary windings, this can depend on the load connected to the Secondary (i.e. is the load purely resistive or capacitively reactive or inductively reactive. And the phase relationship would also depend if the "top" or the "bottom" of the Secondary is connected to the bottom of the Primary winding!! I know, because one cancels the other out, it's more like the magnetic force pushing against the existing current and reducing it. But you can think of it as adding and subtracting currents. Forget a transformer.....think of two series resistors with a centre take-off point, say a nine ohm resistor and a one ohm resistor with ten volts applied across the combination. One amp of current would be flowing through the two resistors, with nine volts developed across the nine ohm resister and one volt across the one ohm resistor. Now, if you connect another resistor across the one ohm resistor, you don't get an increase of current flowing through the one ohm resistor to provide the current that would flow through the additional resistor. I find that more confusing - as a transformer is actually creating the voltage on the output. -- http://petersparrots.com http://petersphotos.com You've heard of "Virgin Wool from New Zealand?" It's a myth. |
#12
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
Lieutenant Scott wrote:
On Mon, 10 Dec 2012 14:18:53 -0000, wrote: Lieutenant Scott wrote: On Tue, 27 Nov 2012 14:49:56 -0000, wrote: Lieutenant Scott wrote: Snip Back to the beginning, forget that you have a Variac, just think of a transformer with four connection points. The Primary winding is connected to the mains and the secondary winding is connected to the load. Current flows from the wall socket, into one terminal of the Primary winding, flows through the Primary, and current then flows back to the wall socket. No if's, no maybe's. The alternating current flowing in the Primary produces a fluctuating magnetic field around the Primary winding. This fluctuating magnetic field also cuts the windings of the Secondary winding. This induces a voltage into the Secondary winding. If there is no load connected, there is no load current flowing, just voltage at the Secondary winding terminals. Because the is no load, load current will be zero! Now when you connect a load to the Secondary winding, the voltage induced into the Secondary winding causes a current to flow from one end of the Secondary winding, out through the load and back in the other end of the secondary winding. Totally separate from the Primary. The Primary current has not gone anywhere near the secondary winding, but the Primary current has caused the magnetic field which then caused the Secondary current. Daniel Yes I understand a normal transformer. But... in your example above, is the current flowing in the same direction in the primary and secondary? I know it's AC, but think of the first half of the sine wave. Now think of the Variac. The "secondary" is actually half of the primary. One half of the coil is just a bit of primary. The other half of the coil is BOTH half the primary and all the secondary. So this part of the winding carries TWO currents. It matters if the currents are in the same direction, as they might either add or subtract from each other. Not possible, Scotty, you cannot have both Primary and Secondary currents flowing in one part of the (primary & Secondary) winding and just Primary current flowing in the remainder of the (primary) winding. Cannot happen!! As for the phase relationships between totally separated Primary and Secondary windings, this can depend on the load connected to the Secondary (i.e. is the load purely resistive or capacitively reactive or inductively reactive. And the phase relationship would also depend if the "top" or the "bottom" of the Secondary is connected to the bottom of the Primary winding!! I know, because one cancels the other out, it's more like the magnetic force pushing against the existing current and reducing it. But you can think of it as adding and subtracting currents. Forget a transformer.....think of two series resistors with a centre take-off point, say a nine ohm resistor and a one ohm resistor with ten volts applied across the combination. One amp of current would be flowing through the two resistors, with nine volts developed across the nine ohm resister and one volt across the one ohm resistor. Now, if you connect another resistor across the one ohm resistor, you don't get an increase of current flowing through the one ohm resistor to provide the current that would flow through the additional resistor. I find that more confusing - as a transformer is actually creating the voltage on the output. "a transformer is actually creating the voltage on the output" in exactly the same way as, in your impractical transformer, the primary current flowing through the "secondary" winding creates the secondary current .......... *ain't going to happen!!* Daniel |
#13
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
On Tue, 11 Dec 2012 13:18:22 -0000, wrote:
Lieutenant Scott wrote: On Mon, 10 Dec 2012 14:18:53 -0000, wrote: Lieutenant Scott wrote: On Tue, 27 Nov 2012 14:49:56 -0000, wrote: Lieutenant Scott wrote: Snip Back to the beginning, forget that you have a Variac, just think of a transformer with four connection points. The Primary winding is connected to the mains and the secondary winding is connected to the load. Current flows from the wall socket, into one terminal of the Primary winding, flows through the Primary, and current then flows back to the wall socket. No if's, no maybe's. The alternating current flowing in the Primary produces a fluctuating magnetic field around the Primary winding. This fluctuating magnetic field also cuts the windings of the Secondary winding. This induces a voltage into the Secondary winding. If there is no load connected, there is no load current flowing, just voltage at the Secondary winding terminals. Because the is no load, load current will be zero! Now when you connect a load to the Secondary winding, the voltage induced into the Secondary winding causes a current to flow from one end of the Secondary winding, out through the load and back in the other end of the secondary winding. Totally separate from the Primary. The Primary current has not gone anywhere near the secondary winding, but the Primary current has caused the magnetic field which then caused the Secondary current. Daniel Yes I understand a normal transformer. But... in your example above, is the current flowing in the same direction in the primary and secondary? I know it's AC, but think of the first half of the sine wave. Now think of the Variac. The "secondary" is actually half of the primary. One half of the coil is just a bit of primary. The other half of the coil is BOTH half the primary and all the secondary. So this part of the winding carries TWO currents. It matters if the currents are in the same direction, as they might either add or subtract from each other. Not possible, Scotty, you cannot have both Primary and Secondary currents flowing in one part of the (primary & Secondary) winding and just Primary current flowing in the remainder of the (primary) winding. Cannot happen!! As for the phase relationships between totally separated Primary and Secondary windings, this can depend on the load connected to the Secondary (i.e. is the load purely resistive or capacitively reactive or inductively reactive. And the phase relationship would also depend if the "top" or the "bottom" of the Secondary is connected to the bottom of the Primary winding!! I know, because one cancels the other out, it's more like the magnetic force pushing against the existing current and reducing it. But you can think of it as adding and subtracting currents. Forget a transformer.....think of two series resistors with a centre take-off point, say a nine ohm resistor and a one ohm resistor with ten volts applied across the combination. One amp of current would be flowing through the two resistors, with nine volts developed across the nine ohm resister and one volt across the one ohm resistor. Now, if you connect another resistor across the one ohm resistor, you don't get an increase of current flowing through the one ohm resistor to provide the current that would flow through the additional resistor. I find that more confusing - as a transformer is actually creating the voltage on the output. "a transformer is actually creating the voltage on the output" in exactly the same way as, in your impractical transformer, the primary current flowing through the "secondary" winding creates the secondary current .......... *ain't going to happen!!* Daniel http://petersphotos.com/temp/transformer.jpg Correct so far? Where I've written "?A", it has to add up to 1.5A upwards, otherwise you'd be getting current from nowhere - 3 amps has to come out of the centre tap. I see this as the 1.5A flowing down (round the source circuit), plus the 3A flowing up round the load circuit. 1.5 down plus 3 up = 1.5 up. -- http://petersparrots.com http://petersphotos.com Why are they called buildings, when they're already finished? Shouldn't they be called builts? |
#14
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
Lieutenant Scott wrote:
On Tue, 11 Dec 2012 13:18:22 -0000, wrote: Lieutenant Scott wrote: On Mon, 10 Dec 2012 14:18:53 -0000, wrote: Lieutenant Scott wrote: On Tue, 27 Nov 2012 14:49:56 -0000, wrote: Lieutenant Scott wrote: Snip Back to the beginning, forget that you have a Variac, just think of a transformer with four connection points. The Primary winding is connected to the mains and the secondary winding is connected to the load. Current flows from the wall socket, into one terminal of the Primary winding, flows through the Primary, and current then flows back to the wall socket. No if's, no maybe's. The alternating current flowing in the Primary produces a fluctuating magnetic field around the Primary winding. This fluctuating magnetic field also cuts the windings of the Secondary winding. This induces a voltage into the Secondary winding. If there is no load connected, there is no load current flowing, just voltage at the Secondary winding terminals. Because the is no load, load current will be zero! Now when you connect a load to the Secondary winding, the voltage induced into the Secondary winding causes a current to flow from one end of the Secondary winding, out through the load and back in the other end of the secondary winding. Totally separate from the Primary. The Primary current has not gone anywhere near the secondary winding, but the Primary current has caused the magnetic field which then caused the Secondary current. Daniel Yes I understand a normal transformer. But... in your example above, is the current flowing in the same direction in the primary and secondary? I know it's AC, but think of the first half of the sine wave. Now think of the Variac. The "secondary" is actually half of the primary. One half of the coil is just a bit of primary. The other half of the coil is BOTH half the primary and all the secondary. So this part of the winding carries TWO currents. It matters if the currents are in the same direction, as they might either add or subtract from each other. Not possible, Scotty, you cannot have both Primary and Secondary currents flowing in one part of the (primary & Secondary) winding and just Primary current flowing in the remainder of the (primary) winding. Cannot happen!! As for the phase relationships between totally separated Primary and Secondary windings, this can depend on the load connected to the Secondary (i.e. is the load purely resistive or capacitively reactive or inductively reactive. And the phase relationship would also depend if the "top" or the "bottom" of the Secondary is connected to the bottom of the Primary winding!! I know, because one cancels the other out, it's more like the magnetic force pushing against the existing current and reducing it. But you can think of it as adding and subtracting currents. Forget a transformer.....think of two series resistors with a centre take-off point, say a nine ohm resistor and a one ohm resistor with ten volts applied across the combination. One amp of current would be flowing through the two resistors, with nine volts developed across the nine ohm resister and one volt across the one ohm resistor. Now, if you connect another resistor across the one ohm resistor, you don't get an increase of current flowing through the one ohm resistor to provide the current that would flow through the additional resistor. I find that more confusing - as a transformer is actually creating the voltage on the output. "a transformer is actually creating the voltage on the output" in exactly the same way as, in your impractical transformer, the primary current flowing through the "secondary" winding creates the secondary current .......... *ain't going to happen!!* Daniel http://petersphotos.com/temp/transformer.jpg Correct so far? Where I've written "?A", it has to add up to 1.5A upwards, otherwise you'd be getting current from nowhere - 3 amps has to come out of the centre tap. I see this as the 1.5A flowing down (round the source circuit), plus the 3A flowing up round the load circuit. 1.5 down plus 3 up = 1.5 up. Sorry I've been away so long!! Your diagram is not going to happen.....ever!! Primary power = 240 Vp times 1.5 Ip equals 360 Watts Secondary power = 120 Vs times 3.0 Is equals 360 watts Secondary power equals Primary power, so no (i.e. zero, zilch) power can be dissipated in the top half of the transformer, so zero voltage developed across the top half of the transformer, so Vs must equal Vp, i.e. 240 V not the 120 V your diagram shows. Not going to happen....ever!! Sorry!! Daniel |
#15
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
On Fri, 04 Jan 2013 13:14:54 -0000, wrote:
Lieutenant Scott wrote: On Tue, 11 Dec 2012 13:18:22 -0000, wrote: Lieutenant Scott wrote: On Mon, 10 Dec 2012 14:18:53 -0000, wrote: Lieutenant Scott wrote: Snip Not possible, Scotty, you cannot have both Primary and Secondary currents flowing in one part of the (primary & Secondary) winding and just Primary current flowing in the remainder of the (primary) winding. Cannot happen!! As for the phase relationships between totally separated Primary and Secondary windings, this can depend on the load connected to the Secondary (i.e. is the load purely resistive or capacitively reactive or inductively reactive. And the phase relationship would also depend if the "top" or the "bottom" of the Secondary is connected to the bottom of the Primary winding!! I know, because one cancels the other out, it's more like the magnetic force pushing against the existing current and reducing it. But you can think of it as adding and subtracting currents. Forget a transformer.....think of two series resistors with a centre take-off point, say a nine ohm resistor and a one ohm resistor with ten volts applied across the combination. One amp of current would be flowing through the two resistors, with nine volts developed across the nine ohm resister and one volt across the one ohm resistor. Now, if you connect another resistor across the one ohm resistor, you don't get an increase of current flowing through the one ohm resistor to provide the current that would flow through the additional resistor. I find that more confusing - as a transformer is actually creating the voltage on the output. "a transformer is actually creating the voltage on the output" in exactly the same way as, in your impractical transformer, the primary current flowing through the "secondary" winding creates the secondary current .......... *ain't going to happen!!* Daniel http://petersphotos.com/temp/transformer.jpg Correct so far? Where I've written "?A", it has to add up to 1.5A upwards, otherwise you'd be getting current from nowhere - 3 amps has to come out of the centre tap. I see this as the 1.5A flowing down (round the source circuit), plus the 3A flowing up round the load circuit. 1.5 down plus 3 up = 1.5 up. Sorry I've been away so long!! Your diagram is not going to happen.....ever!! Primary power = 240 Vp times 1.5 Ip equals 360 Watts Secondary power = 120 Vs times 3.0 Is equals 360 watts Secondary power equals Primary power, so no (i.e. zero, zilch) power can be dissipated in the top half of the transformer, so zero voltage developed across the top half of the transformer, so Vs must equal Vp, i.e. 240 V not the 120 V your diagram shows. Not going to happen....ever!! Sorry!! Daniel It was simply a rough diagram to work out the approximate current flow, I was assuming no losses! -- http://petersparrots.com http://petersphotos.com A conclusion is simply the place where someone got tired of thinking. |
#16
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
Lieutenant Scott wrote:
On Fri, 04 Jan 2013 13:14:54 -0000, wrote: Lieutenant Scott wrote: On Tue, 11 Dec 2012 13:18:22 -0000, wrote: Lieutenant Scott wrote: On Mon, 10 Dec 2012 14:18:53 -0000, wrote: Lieutenant Scott wrote: Snip Not possible, Scotty, you cannot have both Primary and Secondary currents flowing in one part of the (primary & Secondary) winding and just Primary current flowing in the remainder of the (primary) winding. Cannot happen!! As for the phase relationships between totally separated Primary and Secondary windings, this can depend on the load connected to the Secondary (i.e. is the load purely resistive or capacitively reactive or inductively reactive. And the phase relationship would also depend if the "top" or the "bottom" of the Secondary is connected to the bottom of the Primary winding!! I know, because one cancels the other out, it's more like the magnetic force pushing against the existing current and reducing it. But you can think of it as adding and subtracting currents. Forget a transformer.....think of two series resistors with a centre take-off point, say a nine ohm resistor and a one ohm resistor with ten volts applied across the combination. One amp of current would be flowing through the two resistors, with nine volts developed across the nine ohm resister and one volt across the one ohm resistor. Now, if you connect another resistor across the one ohm resistor, you don't get an increase of current flowing through the one ohm resistor to provide the current that would flow through the additional resistor. I find that more confusing - as a transformer is actually creating the voltage on the output. "a transformer is actually creating the voltage on the output" in exactly the same way as, in your impractical transformer, the primary current flowing through the "secondary" winding creates the secondary current .......... *ain't going to happen!!* Daniel http://petersphotos.com/temp/transformer.jpg Correct so far? Where I've written "?A", it has to add up to 1.5A upwards, otherwise you'd be getting current from nowhere - 3 amps has to come out of the centre tap. I see this as the 1.5A flowing down (round the source circuit), plus the 3A flowing up round the load circuit. 1.5 down plus 3 up = 1.5 up. Sorry I've been away so long!! Your diagram is not going to happen.....ever!! Primary power = 240 Vp times 1.5 Ip equals 360 Watts Secondary power = 120 Vs times 3.0 Is equals 360 watts Secondary power equals Primary power, so no (i.e. zero, zilch) power can be dissipated in the top half of the transformer, so zero voltage developed across the top half of the transformer, so Vs must equal Vp, i.e. 240 V not the 120 V your diagram shows. Not going to happen....ever!! Sorry!! Daniel It was simply a rough diagram to work out the approximate current flow, I was assuming no losses! In my calculations I was assuming no losses, too, so it doesn't work, in any case. Daniel |
#17
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
On Sat, 05 Jan 2013 11:30:14 -0000, wrote:
Lieutenant Scott wrote: On Fri, 04 Jan 2013 13:14:54 -0000, wrote: Lieutenant Scott wrote: On Tue, 11 Dec 2012 13:18:22 -0000, wrote: Lieutenant Scott wrote: "a transformer is actually creating the voltage on the output" in exactly the same way as, in your impractical transformer, the primary current flowing through the "secondary" winding creates the secondary current .......... *ain't going to happen!!* Daniel http://petersphotos.com/temp/transformer.jpg Correct so far? Where I've written "?A", it has to add up to 1.5A upwards, otherwise you'd be getting current from nowhere - 3 amps has to come out of the centre tap. I see this as the 1.5A flowing down (round the source circuit), plus the 3A flowing up round the load circuit. 1.5 down plus 3 up = 1.5 up. Sorry I've been away so long!! Your diagram is not going to happen.....ever!! Primary power = 240 Vp times 1.5 Ip equals 360 Watts Secondary power = 120 Vs times 3.0 Is equals 360 watts Secondary power equals Primary power, so no (i.e. zero, zilch) power can be dissipated in the top half of the transformer, so zero voltage developed across the top half of the transformer, so Vs must equal Vp, i.e. 240 V not the 120 V your diagram shows. Not going to happen....ever!! Sorry!! Daniel It was simply a rough diagram to work out the approximate current flow, I was assuming no losses! In my calculations I was assuming no losses, too, so it doesn't work, in any case. Daniel The diagram I drew at http://petersphotos.com/temp/transformer.jpg makes perfect sense to me. If you create a secondary coil in the lower half and seperate the two circuits, it's just like a normal transformer. -- http://petersparrots.com http://petersphotos.com System error 4C: kernel panic |
#18
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
Lieutenant Scott wrote:
On Sat, 05 Jan 2013 11:30:14 -0000, wrote: Lieutenant Scott wrote: On Fri, 04 Jan 2013 13:14:54 -0000, wrote: Snip Sorry I've been away so long!! Your diagram is not going to happen.....ever!! Primary power = 240 Vp times 1.5 Ip equals 360 Watts Secondary power = 120 Vs times 3.0 Is equals 360 watts Secondary power equals Primary power, so no (i.e. zero, zilch) power can be dissipated in the top half of the transformer, so zero voltage developed across the top half of the transformer, so Vs must equal Vp, i.e. 240 V not the 120 V your diagram shows. Not going to happen....ever!! Sorry!! Daniel It was simply a rough diagram to work out the approximate current flow, I was assuming no losses! In my calculations I was assuming no losses, too, so it doesn't work, in any case. Daniel The diagram I drew at http://petersphotos.com/temp/transformer.jpg makes perfect sense to me. If you create a secondary coil in the lower half and seperate the two circuits, it's just like a normal transformer. If.....If.....If What you drew *Will not* work! No if's, no but's, no maybe's!! Daniel |
#19
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
On Mon, 07 Jan 2013 15:25:06 -0000, wrote:
Lieutenant Scott wrote: On Sat, 05 Jan 2013 11:30:14 -0000, wrote: Lieutenant Scott wrote: On Fri, 04 Jan 2013 13:14:54 -0000, wrote: Snip Sorry I've been away so long!! Your diagram is not going to happen.....ever!! Primary power = 240 Vp times 1.5 Ip equals 360 Watts Secondary power = 120 Vs times 3.0 Is equals 360 watts Secondary power equals Primary power, so no (i.e. zero, zilch) power can be dissipated in the top half of the transformer, so zero voltage developed across the top half of the transformer, so Vs must equal Vp, i.e. 240 V not the 120 V your diagram shows. Not going to happen....ever!! Sorry!! Daniel It was simply a rough diagram to work out the approximate current flow, I was assuming no losses! In my calculations I was assuming no losses, too, so it doesn't work, in any case. Daniel The diagram I drew at http://petersphotos.com/temp/transformer.jpg makes perfect sense to me. If you create a secondary coil in the lower half and seperate the two circuits, it's just like a normal transformer. If.....If.....If What you drew *Will not* work! No if's, no but's, no maybe's!! Ok, please redraw my diagram showing me where you think the currents travel. -- http://petersparrots.com http://petersphotos.com President Bush was in South Dakota recently. There was an awkward moment at Mount Rushmore when President Bush said, "Hey, look, it's those guys on the money!" - Conan Obrien |
#20
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
Lieutenant Scott wrote:
On Mon, 07 Jan 2013 15:25:06 -0000, wrote: Lieutenant Scott wrote: On Sat, 05 Jan 2013 11:30:14 -0000, wrote: Lieutenant Scott wrote: On Fri, 04 Jan 2013 13:14:54 -0000, wrote: Snip Sorry I've been away so long!! Your diagram is not going to happen.....ever!! Primary power = 240 Vp times 1.5 Ip equals 360 Watts Secondary power = 120 Vs times 3.0 Is equals 360 watts Secondary power equals Primary power, so no (i.e. zero, zilch) power can be dissipated in the top half of the transformer, so zero voltage developed across the top half of the transformer, so Vs must equal Vp, i.e. 240 V not the 120 V your diagram shows. Not going to happen....ever!! Sorry!! Daniel It was simply a rough diagram to work out the approximate current flow, I was assuming no losses! In my calculations I was assuming no losses, too, so it doesn't work, in any case. Daniel The diagram I drew at http://petersphotos.com/temp/transformer.jpg makes perfect sense to me. If you create a secondary coil in the lower half and seperate the two circuits, it's just like a normal transformer. If.....If.....If What you drew *Will not* work! No if's, no but's, no maybe's!! Ok, please redraw my diagram showing me where you think the currents travel. Scott, I don't have great graphics skills, but:- http://www.albury.net.au/~dxmm/transformer_mod.jpeg If you joined the primary and secondary 0V wires, you are left with a three contact transformer!! Daniel |
#21
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
On Tue, 08 Jan 2013 12:39:50 -0000, wrote:
Lieutenant Scott wrote: On Mon, 07 Jan 2013 15:25:06 -0000, wrote: Lieutenant Scott wrote: On Sat, 05 Jan 2013 11:30:14 -0000, wrote: Lieutenant Scott wrote: Snip In my calculations I was assuming no losses, too, so it doesn't work, in any case. Daniel The diagram I drew at http://petersphotos.com/temp/transformer.jpg makes perfect sense to me. If you create a secondary coil in the lower half and seperate the two circuits, it's just like a normal transformer. If.....If.....If What you drew *Will not* work! No if's, no but's, no maybe's!! Ok, please redraw my diagram showing me where you think the currents travel. Scott, I don't have great graphics skills, but:- http://www.albury.net.au/~dxmm/transformer_mod.jpeg If you joined the primary and secondary 0V wires, you are left with a three contact transformer!! In your diagram the current for the load should go the other way. -- http://petersparrots.com http://petersphotos.com If the Internet is a superhighway, then AOL must be a fleet of farm equipment that straddles five lanes and pays no heed to "Keep Right Except to Pass" signs. |
#22
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
Lieutenant Scott wrote:
On Tue, 08 Jan 2013 12:39:50 -0000, wrote: Lieutenant Scott wrote: On Mon, 07 Jan 2013 15:25:06 -0000, wrote: Lieutenant Scott wrote: On Sat, 05 Jan 2013 11:30:14 -0000, wrote: Lieutenant Scott wrote: Snip In my calculations I was assuming no losses, too, so it doesn't work, in any case. Daniel The diagram I drew at http://petersphotos.com/temp/transformer.jpg makes perfect sense to me. If you create a secondary coil in the lower half and seperate the two circuits, it's just like a normal transformer. If.....If.....If What you drew *Will not* work! No if's, no but's, no maybe's!! Ok, please redraw my diagram showing me where you think the currents travel. Scott, I don't have great graphics skills, but:- http://www.albury.net.au/~dxmm/transformer_mod.jpeg If you joined the primary and secondary 0V wires, you are left with a three contact transformer!! In your diagram the current for the load should go the other way. Yeap, so it should!! My mistake!! Daniel |
#23
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
On Thu, 10 Jan 2013 11:11:19 -0000, wrote:
Lieutenant Scott wrote: On Tue, 08 Jan 2013 12:39:50 -0000, wrote: Lieutenant Scott wrote: On Mon, 07 Jan 2013 15:25:06 -0000, wrote: Lieutenant Scott wrote: Snip If.....If.....If What you drew *Will not* work! No if's, no but's, no maybe's!! Ok, please redraw my diagram showing me where you think the currents travel. Scott, I don't have great graphics skills, but:- http://www.albury.net.au/~dxmm/transformer_mod.jpeg If you joined the primary and secondary 0V wires, you are left with a three contact transformer!! In your diagram the current for the load should go the other way. Yeap, so it should!! My mistake!! Daniel I still don't know what you're saying is wrong with my diagram http://petersphotos.com/temp/transformer.jpg -- http://petersparrots.com http://petersphotos.com The tired doctor was awakened by a phone call in the middle of the night. "Please, you have to come right over," pleaded the distraught young mother. "My child has swallowed a contraceptive." The physician dressed quickly, but before he could get out the door, the phone rang again. "You don't have to come over after all," the woman said with a sigh of relief. "My husband just found another one." |
#24
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
Lieutenant Scott wrote:
On Thu, 10 Jan 2013 11:11:19 -0000, wrote: Lieutenant Scott wrote: On Tue, 08 Jan 2013 12:39:50 -0000, wrote: Lieutenant Scott wrote: On Mon, 07 Jan 2013 15:25:06 -0000, wrote: Lieutenant Scott wrote: Snip If.....If.....If What you drew *Will not* work! No if's, no but's, no maybe's!! Ok, please redraw my diagram showing me where you think the currents travel. Scott, I don't have great graphics skills, but:- http://www.albury.net.au/~dxmm/transformer_mod.jpeg If you joined the primary and secondary 0V wires, you are left with a three contact transformer!! In your diagram the current for the load should go the other way. Yeap, so it should!! My mistake!! Daniel I still don't know what you're saying is wrong with my diagram http://petersphotos.com/temp/transformer.jpg What!! Apart from me saying *it will not work!!* In my diagram, the 1.5A primary current flows &only* in the primary winding of the transformer and the 3.0A secondary current flows *only* in the secondary. Whereas in your diagram, *you* had both flowing in one part of *your* coil, which would not work!! No if's, no but's, no maybe's!! Daniel |
#25
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
On Sat, 12 Jan 2013 12:01:02 -0000, wrote:
Lieutenant Scott wrote: On Thu, 10 Jan 2013 11:11:19 -0000, wrote: Lieutenant Scott wrote: On Tue, 08 Jan 2013 12:39:50 -0000, wrote: Lieutenant Scott wrote: Scott, I don't have great graphics skills, but:- http://www.albury.net.au/~dxmm/transformer_mod.jpeg If you joined the primary and secondary 0V wires, you are left with a three contact transformer!! In your diagram the current for the load should go the other way. Yeap, so it should!! My mistake!! Daniel I still don't know what you're saying is wrong with my diagram http://petersphotos.com/temp/transformer.jpg What!! Apart from me saying *it will not work!!* In my diagram, the 1.5A primary current flows &only* in the primary winding of the transformer and the 3.0A secondary current flows *only* in the secondary. Whereas in your diagram, *you* had both flowing in one part of *your* coil, which would not work!! No if's, no but's, no maybe's!! Daniel The current flowing in my load circuit has to come from somewhere. Redraw my circuit, with the same transformer, showing where you think current flows. |
#26
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
Lieutenant Scott wrote:
On Sat, 12 Jan 2013 12:01:02 -0000, wrote: Lieutenant Scott wrote: On Thu, 10 Jan 2013 11:11:19 -0000, wrote: Lieutenant Scott wrote: On Tue, 08 Jan 2013 12:39:50 -0000, wrote: Lieutenant Scott wrote: Scott, I don't have great graphics skills, but:- http://www.albury.net.au/~dxmm/transformer_mod.jpeg If you joined the primary and secondary 0V wires, you are left with a three contact transformer!! In your diagram the current for the load should go the other way. Yeap, so it should!! My mistake!! Daniel I still don't know what you're saying is wrong with my diagram http://petersphotos.com/temp/transformer.jpg What!! Apart from me saying *it will not work!!* In my diagram, the 1.5A primary current flows &only* in the primary winding of the transformer and the 3.0A secondary current flows *only* in the secondary. Whereas in your diagram, *you* had both flowing in one part of *your* coil, which would not work!! No if's, no but's, no maybe's!! Daniel The current flowing in my load circuit has to come from somewhere. Redraw my circuit, with the same transformer, showing where you think current flows. In my diagram of a couple of days ago, I have tried to use your transformer, with 240V applied across the primary and 120V developed across the secondary in a manner that *DOES* work, but *you* will not see it. You cannot see the difference!! Daniel |
#27
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
On 12/01/2013 9:40 PM, wrote:
Lieutenant Scott wrote: On Sat, 12 Jan 2013 12:01:02 -0000, wrote: Lieutenant Scott wrote: On Thu, 10 Jan 2013 11:11:19 -0000, wrote: Lieutenant Scott wrote: On Tue, 08 Jan 2013 12:39:50 -0000, wrote: Lieutenant Scott wrote: Scott, I don't have great graphics skills, but:- http://www.albury.net.au/~dxmm/transformer_mod.jpeg If you joined the primary and secondary 0V wires, you are left with a three contact transformer!! In your diagram the current for the load should go the other way. Yeap, so it should!! My mistake!! Daniel I still don't know what you're saying is wrong with my diagram http://petersphotos.com/temp/transformer.jpg What!! Apart from me saying *it will not work!!* In my diagram, the 1.5A primary current flows &only* in the primary winding of the transformer and the 3.0A secondary current flows *only* in the secondary. Whereas in your diagram, *you* had both flowing in one part of *your* coil, which would not work!! No if's, no but's, no maybe's!! Daniel The current flowing in my load circuit has to come from somewhere. Redraw my circuit, with the same transformer, showing where you think current flows. In my diagram of a couple of days ago, I have tried to use your transformer, with 240V applied across the primary and 120V developed across the secondary in a manner that *DOES* work, but *you* will not see it. You cannot see the difference!! Daniel Hey guys, why not check out the wiki for variacs ? From what I see of your posts you are straying from reality! |
#28
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
On Sat, 12 Jan 2013 13:40:39 -0000, wrote:
Lieutenant Scott wrote: On Sat, 12 Jan 2013 12:01:02 -0000, wrote: Lieutenant Scott wrote: On Thu, 10 Jan 2013 11:11:19 -0000, wrote: Lieutenant Scott wrote: Yeap, so it should!! My mistake!! Daniel I still don't know what you're saying is wrong with my diagram http://petersphotos.com/temp/transformer.jpg What!! Apart from me saying *it will not work!!* In my diagram, the 1.5A primary current flows &only* in the primary winding of the transformer and the 3.0A secondary current flows *only* in the secondary. Whereas in your diagram, *you* had both flowing in one part of *your* coil, which would not work!! No if's, no but's, no maybe's!! Daniel The current flowing in my load circuit has to come from somewhere. Redraw my circuit, with the same transformer, showing where you think current flows. In my diagram of a couple of days ago, I have tried to use your transformer, with 240V applied across the primary and 120V developed across the secondary in a manner that *DOES* work, but *you* will not see it. You cannot see the difference!! You're not showing a Variac in your diagram. The Variac has the source voltage across the ENTIRE coil. The load is connected across HALF the coil. -- http://petersparrots.com http://petersphotos.com British Rail Customer: "How much does it cost to Bath on the train?" Operator: "If you can get your feet in the sink, then it's free". |
#29
![]()
Posted to alt.electronics
|
|||
|
|||
![]()
On Sat, 12 Jan 2013 13:51:33 -0000, Rheilly Phoull wrote:
On 12/01/2013 9:40 PM, wrote: Lieutenant Scott wrote: On Sat, 12 Jan 2013 12:01:02 -0000, wrote: Lieutenant Scott wrote: On Thu, 10 Jan 2013 11:11:19 -0000, wrote: I still don't know what you're saying is wrong with my diagram http://petersphotos.com/temp/transformer.jpg What!! Apart from me saying *it will not work!!* In my diagram, the 1.5A primary current flows &only* in the primary winding of the transformer and the 3.0A secondary current flows *only* in the secondary. Whereas in your diagram, *you* had both flowing in one part of *your* coil, which would not work!! No if's, no but's, no maybe's!! Daniel The current flowing in my load circuit has to come from somewhere. Redraw my circuit, with the same transformer, showing where you think current flows. In my diagram of a couple of days ago, I have tried to use your transformer, with 240V applied across the primary and 120V developed across the secondary in a manner that *DOES* work, but *you* will not see it. You cannot see the difference!! Daniel Hey guys, why not check out the wiki for variacs ? From what I see of your posts you are straying from reality! Where is it located? -- http://petersparrots.com http://petersphotos.com The little boat gently drifted across the pond exactly the way a bowling ball wouldn't. |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Current flow in main neutral vs. current through water meter | Home Repair | |||
Variac and isolation xfmr - variac and xfmr.jpg | Electronic Schematics | |||
variac question? | Metalworking | |||
Have a question about Variac diode in a HW24T/C528 Hand held. | Electronics Repair | |||
Simple Variac Question | Electronics Repair |