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Metalworking (rec.crafts.metalworking) Discuss various aspects of working with metal, such as machining, welding, metal joining, screwing, casting, hardening/tempering, blacksmithing/forging, spinning and hammer work, sheet metal work. |
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#41
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Math question
On Wed, 07 Oct 2009 14:31:56 -0600, SteveB wrote:
"Rich Grise" wrote in message news On Wed, 07 Oct 2009 13:10:58 -0600, SteveB wrote: How do I figure the area of a pool from the perimeter? You don't. You need more information. It is a kidney shaped (exaggerated) pool. Divide it into segments - two semicircles for the ends, and groups of triangles or trapezoids for the middle, get their area, and add. What is it you're trying to accomplish? Good Luck! Rich To figure the surface area having only the perimeter as a known variable. Measure the perimeter, square the measurement, and multiply it by the perimeter-to-area constant for the shape in question. For a square pool the constant is 1/16, for a circular pool the constant is 1/(4*pi), for an infinitely skinny pool the constant is 0. For your pool you'll have to consult an appropriate handbook, or calculate it. To find the correct constant for the shape of your pool, first calculate it's surface area, then divide that area by the perimeter squared. Then you'll have the correct constant, and you can calculate your pool surface area -- or the surface area of any other pool with an exactly similar shape -- just by knowing the perimeter. -- www.wescottdesign.com |
#42
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Math question
On Oct 7, 7:15*pm, Gunner Asch wrote:
On Wed, 07 Oct 2009 21:39:48 +0100, Mark Rand wrote: On Wed, 7 Oct 2009 13:10:58 -0600, "SteveB" wrote: How do I figure the area of a pool from the perimeter? *It is a kidney shaped (exaggerated) pool. Steve Fix a rule to the side of the pool. Bail out one (or more) 55 gallon drums full from the pool Area per inch change per drum is approx 88.23 sq ft. Walk around the perimeter feeling happy :-) Mark Rand RTFM Not with a curved bottom..... If you only drain a few drums from the pool, the bottom stays full and thus has no bearing on the calculation (assuming that the sides are parallel). |
#43
Posted to rec.crafts.metalworking
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Math question
In article , Mark Rand wrote:
On Wed, 7 Oct 2009 13:10:58 -0600, "SteveB" wrote: How do I figure the area of a pool from the perimeter? It is a kidney shaped (exaggerated) pool. Fix a rule to the side of the pool. Bail out one (or more) 55 gallon drums full from the pool Area per inch change per drum is approx 88.23 sq ft. 88.17 Walk around the perimeter feeling happy :-) Clever. It would be easier still to *add* 55 gallons. |
#44
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Math question
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#45
Posted to rec.crafts.metalworking
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Math question
On 2009-10-08, Doug Miller wrote:
In article , (Edward A. Falk) wrote: We have a winna! It would be nice if you'd quote the post you're responding to so that other people would know what the heck you're talking about... he was responding to my post. It is actually simple. Have a helper on the other end of the pool. Draw a straight line along the pool. Start with the edge of the pool. Go in 1 foot steps along that straight line. Measure width across the pool perpendicularly to that line, for every such foot step. Add those widths. This is the area of the pool in square feet. It will be relatively accurate. i |
#46
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Math question
On Wed, 07 Oct 2009 16:15:57 -0700, Gunner Asch
wrote: On Wed, 07 Oct 2009 21:39:48 +0100, Mark Rand wrote: On Wed, 7 Oct 2009 13:10:58 -0600, "SteveB" wrote: How do I figure the area of a pool from the perimeter? It is a kidney shaped (exaggerated) pool. Steve Fix a rule to the side of the pool. Bail out one (or more) 55 gallon drums full from the pool Area per inch change per drum is approx 88.23 sq ft. Walk around the perimeter feeling happy :-) Mark Rand RTFM Not with a curved bottom..... You don't bail the water out of the bottom of the pool, you bail it out of the top :-) Mark Rand RTFM |
#47
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Math question
On Wed, 07 Oct 2009 20:23:18 -0600, SteveB wrote:
"Lloyd E. Sponenburgh" lloydspinsidemindspring.com wrote in message . 3.70... fired this volley in news:656dee88-c74d-4919-a95a- : You can't do it just by measuring the perimeter unless it's a regular figure, circle, semicircle, triangle, hexagon, or whatever. WRONG! Check out what planimeters do! (geeesh!) I Googled planimeter, and came up with http://en.wikipedia.org/wiki/Planimeter So did I - and for a swimming pool, wouldn't that need one BIG HONKING planimeter? Thanks, Rich |
#48
Posted to rec.crafts.metalworking
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Math question
Ignoramus19678 wrote:
On 2009-10-08, Doug Miller wrote: In article , (Edward A. Falk) wrote: We have a winna! It would be nice if you'd quote the post you're responding to so that other people would know what the heck you're talking about... he was responding to my post. It is actually simple. Have a helper on the other end of the pool. Draw a straight line along the pool. Start with the edge of the pool. Go in 1 foot steps along that straight line. Measure width across the pool perpendicularly to that line, for every such foot step. Add those widths. This is the area of the pool in square feet. It will be relatively accurate. i Which was a simplified version of mine. Hrump... |
#49
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Math question
Rich Grise fired this volley in
news So did I - and for a swimming pool, wouldn't that need one BIG HONKING planimeter? No..... one can do it from an aerial photo. And FWIW, even a BIG HONKING planimeter is easy to make, easy to salvage afterwards. LLoyd |
#51
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Math question
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#52
Posted to rec.crafts.metalworking
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Math question
Lloyd E. Sponenburgh wrote:
Rich Grise fired this volley in news Then you're pretty much out of luck. Rich! Bull! That's _exactly_ what a planimeter does for a living! No, it integrates surface area while measuring BOTH perimeter and angle traveled from a single point, simultaneously. That makes a big difference, although I still don't know exactly how they work. But, they require you to stick a pin in the paper at one point and not move it until you've traced the entire perimeter. Jon |
#53
Posted to rec.crafts.metalworking
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Math question
Let the Record show that Gunner Asch on
or about Wed, 07 Oct 2009 16:15:26 -0700 did write/type or cause to appear in rec.crafts.metalworking the following: On Wed, 7 Oct 2009 14:39:16 -0700 (PDT), Jim Wilkins wrote: On Oct 7, 4:31*pm, "SteveB" wrote: To figure the surface area having only the perimeter as a known variable. Steve In general, you can't. If you kick in the side of a 5 gallon bucket, how much does it hold? The rim length hasn't changed. In this particular case, call the manufacturer or installer. jsw Or bail it out and count the gallons and then convert to square feet of water Fill a 55 gallon drum with water and seal it. Roll it into the pool. Repeat until you can measure an increase in water level. Estimate the volume of the barrels. pyotr - pyotr filipivich We will drink no whiskey before its nine. It's eight fifty eight. Close enough! |
#54
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Math question
On 2009-10-08, Rich Grise wrote:
On Wed, 07 Oct 2009 20:23:18 -0600, SteveB wrote: "Lloyd E. Sponenburgh" lloydspinsidemindspring.com wrote in message . 3.70... fired this volley in news:656dee88-c74d-4919-a95a- : You can't do it just by measuring the perimeter unless it's a regular figure, circle, semicircle, triangle, hexagon, or whatever. WRONG! Check out what planimeters do! (geeesh!) I Googled planimeter, and came up with http://en.wikipedia.org/wiki/Planimeter So did I - and for a swimming pool, wouldn't that need one BIG HONKING planimeter? Or a nice aerial or satellite view from directly overhead and a measurement between two known locations to calculate a scale factor. Find the view, print it out, measure the distance between the two known locations on the printout and the real world, then run the planimeter around it and calculate the full scale area from the indicated area and the scale factor. I've got a nice old planimeter which I bought at a hamfest about ten or fifteen years ago. How much accuracy is needed for this project? Enjoy, DoN. -- Email: | Voice (all times): (703) 938-4564 (too) near Washington D.C. | http://www.d-and-d.com/dnichols/DoN.html --- Black Holes are where God is dividing by zero --- |
#56
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Math question
Jon Elson wrote:
Lloyd E. Sponenburgh wrote: Rich Grise fired this volley in news Then you're pretty much out of luck. Rich! Bull! That's _exactly_ what a planimeter does for a living! No, it integrates surface area while measuring BOTH perimeter and angle traveled from a single point, simultaneously. That makes a big difference, although I still don't know exactly how they work. But, they require you to stick a pin in the paper at one point and not move it until you've traced the entire perimeter. Of course. Analog or digital, you still have to set one of the bounds as a fixed point. The other can be varied to suit, but not both. -- John R. Carroll |
#57
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Math question
DoN. Nichols wrote:
On 2009-10-08, Rich Grise wrote: On Wed, 07 Oct 2009 20:23:18 -0600, SteveB wrote: "Lloyd E. Sponenburgh" lloydspinsidemindspring.com wrote in message . 3.70... fired this volley in news:656dee88-c74d-4919-a95a- : You can't do it just by measuring the perimeter unless it's a regular figure, circle, semicircle, triangle, hexagon, or whatever. WRONG! Check out what planimeters do! (geeesh!) I Googled planimeter, and came up with http://en.wikipedia.org/wiki/Planimeter So did I - and for a swimming pool, wouldn't that need one BIG HONKING planimeter? Or a nice aerial or satellite view from directly overhead and a measurement between two known locations to calculate a scale factor. Find the view, print it out, measure the distance between the two known locations on the printout and the real world, then run the planimeter around it and calculate the full scale area from the indicated area and the scale factor. I've got a nice old planimeter which I bought at a hamfest about ten or fifteen years ago. How much accuracy is needed for this project? Enjoy, DoN. Not that much, apparently. SteveB's (OP) solution was to measure across the pool in several places, average the widths and multiply by the length. Close enough for non-financial government work. |
#58
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Math question
cavelamb wrote:
Wes wrote: My greatest regret in high school is that I didn't wise up and start on the right track to take Calculus. Never too late to get smart, Wes! Periodically, I pick up a text book, periodically I set it back down. Seriously, if I wasn't a wage slave and was part of the idle rich, I'd be in some college learning it. Fwiw, I was pretty good solving trigonometric identities 15 years ago when I attended a local college for a while. Only got a 3.5 in Trig but I was prouder of the 3.5 than the 4.0 in college algebra. The gentlemen that taught the trig class, was a definite nerd, horn rimmed glasses, trousers belted high but he was a good teacher, also head of the mathemetics department. He mentioned he did his calculus problems as a student in ink Wes |
#59
Posted to rec.crafts.metalworking
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Math question
Wes wrote:
cavelamb wrote: Wes wrote: My greatest regret in high school is that I didn't wise up and start on the right track to take Calculus. Never too late to get smart, Wes! Periodically, I pick up a text book, periodically I set it back down. Seriously, if I wasn't a wage slave and was part of the idle rich, I'd be in some college learning it. Fwiw, I was pretty good solving trigonometric identities 15 years ago when I attended a local college for a while. Only got a 3.5 in Trig but I was prouder of the 3.5 than the 4.0 in college algebra. The gentlemen that taught the trig class, was a definite nerd, horn rimmed glasses, trousers belted high but he was a good teacher, also head of the mathemetics department. He mentioned he did his calculus problems as a student in ink Wes There are many ways to study things. http://www.understandingcalculus.com/ http://www.wannalearn.com/Academic_S...tics/Calculus/ |
#60
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Math question
On Fri, 09 Oct 2009 18:54:56 -0400, Wes wrote:
.. He mentioned he did his calculus problems as a student in ink Wes Ummm. How else does one do calculus problems then? Expiring minds need to know :-) Mark Rand(suddenly feeling old) RTFM |
#61
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Math question
Mark Rand fired this volley in
: Expiring minds need to know :-) hey! That's of MY sigs... and an original one, by me, for me! ('cept, it's "Expiring minds WANT to know!") LLoyd ----------------- Cole's Axiom -- the total intelligence of the planet is constant. The population is increasing exponentially. |
#62
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Math question
Mark Rand wrote:
On Fri, 09 Oct 2009 18:54:56 -0400, Wes wrote: . He mentioned he did his calculus problems as a student in ink Wes Ummm. How else does one do calculus problems then? Expiring minds need to know :-) Mark Rand(suddenly feeling old) RTFM In one's head, of course! |
#63
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Math question
Lloyd E. Sponenburgh writes:
Use a planimeter to do it, or print a picture of it to some sort of scale on graph paper, then break it up into the smallest polygons (of the same shape and size) you can. Use a bitmap editor to trap and count pixels with a histogram. All you need is a plan view digital image. |
#64
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Math question
On Oct 8, 7:27*pm, cavelamb wrote:
DoN. Nichols wrote: On 2009-10-08, Rich Grise wrote: On Wed, 07 Oct 2009 20:23:18 -0600, SteveB wrote: "Lloyd E. Sponenburgh" lloydspinsidemindspring.com wrote in message 68.3.70... fired this volley in news:656dee88-c74d-4919-a95a- : You can't do it just by measuring the perimeter unless it's a regular figure, circle, semicircle, triangle, hexagon, or whatever. WRONG! *Check out what planimeters do! *(geeesh!) I Googled planimeter, and came up with http://en.wikipedia.org/wiki/Planimeter So did I - and for a swimming pool, wouldn't that need one BIG HONKING planimeter? * *Or a nice aerial or satellite view from directly overhead and a measurement between two known locations to calculate a scale factor. Find the view, print it out, measure the distance between the two known locations on the printout and the real world, then run the planimeter around it and calculate the full scale area from the indicated area and the scale factor. * *I've got a nice old planimeter which I bought at a hamfest about ten or fifteen years ago. * *How much accuracy is needed for this project? * *Enjoy, * * * * * *DoN. Not that much, apparently. SteveB's (OP) solution was to measure across the pool in several places, average the widths and multiply by the length. Close enough for non-financial government work.- A potentially accurate method is to divide the central area into triangles and use Heron's formula in a spreadsheet: http://mste.illinois.edu/dildine/heron/triarea.html Assume the ends are semicircles and start the triangles one radius in from the ends. The chord errors on the convex and concave sides may partly compensate for each other if the curvatures are similar. jsw |
#65
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Math question
"John R. Carroll" wrote in message ... Doug Miller wrote: In article , (Edward A. Falk) wrote: In article , Doug Miller wrote: It would be nice if you'd quote the post you're responding to so that other people would know what the heck you're talking about... Ahh, mea culpa. I've gotten too spoiled by a newsreader that threads the posts and lets you know what post follows which, and lets you easily see the previous post. Hadn't realized that not all newsreaders do this. Mine does that. The problem is that I'd apparently already read the post you replied to, and so it had disappeared before I got to yours. Be aware, also, that *nothing* in the NNTP protocol guarantees that posts will arrive at any particular news server in anything even faintly resembling the sequence in which they were generated -- or, indeed, that they will arrive at all. In short, you cannot assume that the post you're replying to will be available for reading by *anyone*, no matter what client software they're using. That's why it's best practice to quote the relevant portion(s) of anything you reply to. Regardless, Iggi's solution is the common place implementation of Simpson's Rule. Marine Architects and Naval Engineer's know it, and French Curves, well. -- John R. Carroll We just did seven real estate studies in the last two days. My formula is actually the best, even over Simpson's Rule. Take four widths, average, then multiply by length. This method is absolutely the best since mathematically, as on the pools, I am expected to be plus or minus 25% accuracy. Steve :-) |
#66
Posted to rec.crafts.metalworking
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Math question
"Lloyd E. Sponenburgh" lloydspinsidemindspring.com wrote in message . 3.70... Rich Grise fired this volley in news So did I - and for a swimming pool, wouldn't that need one BIG HONKING planimeter? No..... one can do it from an aerial photo. And FWIW, even a BIG HONKING planimeter is easy to make, easy to salvage afterwards. LLoyd The site I use has measurement capabilities that are very accurate. At times, I will click a 100' line on the screen, set a pair of dividers to that length, then use the dividers to either estimate from the screen, or from a printout. Steve |
#67
Posted to rec.crafts.metalworking
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Math question
"cavelamb" wrote in message m... DoN. Nichols wrote: On 2009-10-08, Rich Grise wrote: On Wed, 07 Oct 2009 20:23:18 -0600, SteveB wrote: "Lloyd E. Sponenburgh" lloydspinsidemindspring.com wrote in message . 3.70... fired this volley in news:656dee88-c74d-4919-a95a- : You can't do it just by measuring the perimeter unless it's a regular figure, circle, semicircle, triangle, hexagon, or whatever. WRONG! Check out what planimeters do! (geeesh!) I Googled planimeter, and came up with http://en.wikipedia.org/wiki/Planimeter So did I - and for a swimming pool, wouldn't that need one BIG HONKING planimeter? Or a nice aerial or satellite view from directly overhead and a measurement between two known locations to calculate a scale factor. Find the view, print it out, measure the distance between the two known locations on the printout and the real world, then run the planimeter around it and calculate the full scale area from the indicated area and the scale factor. I've got a nice old planimeter which I bought at a hamfest about ten or fifteen years ago. How much accuracy is needed for this project? Enjoy, DoN. Not that much, apparently. SteveB's (OP) solution was to measure across the pool in several places, average the widths and multiply by the length. Close enough for non-financial government work. And falls within the + or - 25% parameters set by the employer. Steve |
#68
Posted to rec.crafts.metalworking
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Math question
On Oct 10, 9:22*pm, "John R. Carroll" wrote:
SteveB wrote: ... This method is absolutely the best since mathematically, as on the pools, I am expected to be plus or minus 25% accuracy. Steve *:-) LOL John R. Carroll How do they know if you're wrong? jsw |
#69
Posted to rec.crafts.metalworking
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Math question
SteveB wrote:
"John R. Carroll" wrote in message ... Doug Miller wrote: In article , (Edward A. Falk) wrote: In article , Doug Miller wrote: It would be nice if you'd quote the post you're responding to so that other people would know what the heck you're talking about... Ahh, mea culpa. I've gotten too spoiled by a newsreader that threads the posts and lets you know what post follows which, and lets you easily see the previous post. Hadn't realized that not all newsreaders do this. Mine does that. The problem is that I'd apparently already read the post you replied to, and so it had disappeared before I got to yours. Be aware, also, that *nothing* in the NNTP protocol guarantees that posts will arrive at any particular news server in anything even faintly resembling the sequence in which they were generated -- or, indeed, that they will arrive at all. In short, you cannot assume that the post you're replying to will be available for reading by *anyone*, no matter what client software they're using. That's why it's best practice to quote the relevant portion(s) of anything you reply to. Regardless, Iggi's solution is the common place implementation of Simpson's Rule. Marine Architects and Naval Engineer's know it, and French Curves, well. -- John R. Carroll We just did seven real estate studies in the last two days. My formula is actually the best, even over Simpson's Rule. Take four widths, average, then multiply by length. This method is absolutely the best since mathematically, as on the pools, I am expected to be plus or minus 25% accuracy. Steve :-) LOL -- John R. Carroll |
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