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Metalworking (rec.crafts.metalworking) Discuss various aspects of working with metal, such as machining, welding, metal joining, screwing, casting, hardening/tempering, blacksmithing/forging, spinning and hammer work, sheet metal work. |
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#1
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Spring Constant
Hello,
Cannot understand Carr Mc Master 'spring constants' in their spring section. They state 'the spring constant is the number of pounds force required to compress the spring one inch' The spring constants being given seem to be far too large. A long 36 inch spring being made out of 0.013 inch wire has a spring constant of 4.8. ie it takes 4.8 pounds to compress the spring one inch. Where am I going wrong. TIA. Jack |
#2
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Spring Constant
Where am I going wrong.
Skipping, or sleeping through, high school physics? Try googling "Hooke's Law" or "F = -kx". |
#3
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Spring Constant
wrote: (clip)it takes 4.8 pounds to compress the spring one inch. Where am I going wrong. ^^^^^^^^^^^^^^^^ I don't see anything wrong with a spring constant of about 5 lb/in on a spring like that. We're talking about a coil spring in compression or tension, right? You don't state the diameter of the coil, or the turn spacing, but it seems reasonable to me that if you compress a spring about 3% of its length, you might expect to exert about 5 lb. TIA. Jack |
#4
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Spring Constant
You neglected to say that the spring is question has an
OD of .094" And this section of the catalog is for continous length which states: Springs have open ends and can be cut to the length you need. Great for manufacturing, utility, and maintenance jobs. To determine the length (in inches) to which to cut your spring, take the spring constant and divide it by the number of coils per inch. Then take this value and divide it by your desired spring rate in lbs./inch. From what I can tell, this means that the spring constant is NOT the K value from your textbook but the spring value for ONE turn. DIVIDE by the number of turns to get the spring constant from the textbook. Don't complain to me, I just read the fine print!!! wrote: Hello, Cannot understand Carr Mc Master 'spring constants' in their spring section. They state 'the spring constant is the number of pounds force required to compress the spring one inch' The spring constants being given seem to be far too large. A long 36 inch spring being made out of 0.013 inch wire has a spring constant of 4.8. ie it takes 4.8 pounds to compress the spring one inch. Where am I going wrong. TIA. Jack |
#6
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Spring Constant
Hooke's Law is also only valid within the elastic limit of the spring.
If you take a small spring and stretch it an inch, it will probably never recover. Bugs |
#7
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Spring Constant
RoyJ wrote: You neglected to say that the spring is question has an OD of .094" And this section of the catalog is for continous length which states: Springs have open ends and can be cut to the length you need. Great for manufacturing, utility, and maintenance jobs. To determine the length (in inches) to which to cut your spring, take the spring constant and divide it by the number of coils per inch. Then take this value and divide it by your desired spring rate in lbs./inch. From what I can tell, this means that the spring constant is NOT the K value from your textbook but the spring value for ONE turn. DIVIDE by the number of turns to get the spring constant from the textbook. Don't complain to me, I just read the fine print!!! Thanks for that, I am inclined to say that they are using the term "Spring Constant" in a not so very scientifically correct manner :-| The spring is no good for me as it has too many turns per inch. Cheers wrote: Hello, Cannot understand Carr Mc Master 'spring constants' in their spring section. They state 'the spring constant is the number of pounds force required to compress the spring one inch' The spring constants being given seem to be far too large. A long 36 inch spring being made out of 0.013 inch wire has a spring constant of 4.8. ie it takes 4.8 pounds to compress the spring one inch. Where am I going wrong. TIA. Jack |
#8
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Spring Constant
ff wrote:
A coil spring is really a torsion spring formed in a spiral. When compressed or extended beyond it's rest length the wire is being twisted, not bending. Hey, thanks Fred! I never stopped to think about coil springs working that way, I just stopped at "Pull it and it stretches, pull it twice as hard and it stretches twice as far." That hit me about the same way as the first time someone pointed out to me that the "working fluid" in my car's engine isn't gasoline, it's air. The gasoline just heats it and makes it expand. Jeff -- Jeffry Wisnia (W1BSV + Brass Rat '57 EE) "Truth exists; only falsehood has to be invented." |
#9
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Spring Constant
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#10
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Spring Constant
"Ned Simmons" wrote: And to carry this a bit further, the wire in a typical torsion spring is primarily subject to bending, i.e., it's a coiled up beam. ^^^^^^^^^^^^^ Let's unscramble this a little. A "torsion spring" is an elastic bar subject to twisting--not bending. A "coil spring" is a torsion spring that has been wound into a helix for compactness. A "leaf spring" is a beam in bending. |
#12
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Spring Constant
Leo Lichtman wrote:
"Ned Simmons" wrote: And to carry this a bit further, the wire in a typical torsion spring is primarily subject to bending, i.e., it's a coiled up beam. ^^^^^^^^^^^^^ Let's unscramble this a little. A "torsion spring" is an elastic bar subject to twisting--not bending. A "coil spring" is a torsion spring that has been wound into a helix for compactness. A "leaf spring" is a beam in bending. Which means I suppose that a "clock spring" is just an extra long "leaf spring"? Jeff -- Jeffry Wisnia (W1BSV + Brass Rat '57 EE) "Truth exists; only falsehood has to be invented." |
#13
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Spring Constant
"Jeff Wisnia" wrote: Which means I suppose that a "clock spring" is just an extra long "leaf spring"? ^^^^^^^^^^^^^^^^^^^^^ A "clock spring" is a spring that drives a clock. It so happens that all clock springs ARE "leaf springs." (As far as I know.) ;-) |
#14
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Spring Constant
Ned Simmons wrote:
A torsion *bar* is an elastic bar subject to twisting, a torsion *spring* is a helical beam - like this... http://www.sterlingspring.com/torsion_springs.html Ned Simmons [Middle English torcion, wringing pain in the bowels, from Old French torsion, from Late Latin torsiĆ?, torsiĆ?n-, a wringing pain, variant of Latin tortiĆ?, from tortus, past particple of torquÄre, to twist. See torsade http://www.answers.com/main/ntquery?method=4&dsid=1555&dekey=T0281500&curtab=1 555_1.] http://www.answers.com/main/ntquery;...bar&sbid=lc03b A matter of semantics [The meaning or the interpretation of a word, sentence, or other language form: We're basically agreed; let's not quibble over semantics.] A* torsion bar* is a *spring* Fred |
#15
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Spring Constant
In article ,
says... Ned Simmons wrote: A torsion *bar* is an elastic bar subject to twisting, a torsion *spring* is a helical beam - like this... http://www.sterlingspring.com/torsion_springs.html A matter of semantics [The meaning or the interpretation of a word, sentence, or other language form: We're basically agreed; let's not quibble over semantics.] I wasn't quibbling over semantics I was nitpicking about technical jargon g. A* torsion bar* is a *spring* Agreed, but a torsion bar is not what's typically meant by the term "torsion spring". Ned Simmons |
#16
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Spring Constant
Ned Simmons wrote:
Agreed, but a torsion bar is not what's typically meant by the term "torsion spring". Ned Simmons That's why we *drive* on a *parkway* and *park* on a *driveway*. |
#17
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Spring Constant
"ff" wrote: That's why we *drive* on a *parkway* and *park* on a *driveway*. ^^^^^^^^^^^^^^^^^^ And send shipments by car, and cargo by ship. |
#18
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Spring Constant
Leo Lichtman wrote:
"ff" wrote: That's why we *drive* on a *parkway* and *park* on a *driveway*. ^^^^^^^^^^^^^^^^^^ And send shipments by car, and cargo by ship. Those are examples of a criss-crossed sentence structure called "chiasmus", where the order of words (or parts of words) are reversed with good effect. I've always liked this one by Churchill, which IIRC he used when an early allied battle victory made it appear that the Nazi army wasn't invincible after all. "Now this is not the end. It is not even the beginning of the end. But it is, perhaps, the end of the beginning." But my all time favorite is attributed to Dorothy Parker (1893 - 1967) who said, "I've been too ****ing busy and vise versa." More at: http://www.chiasmus.com/ Jeff -- Jeffry Wisnia (W1BSV + Brass Rat '57 EE) "Truth exists; only falsehood has to be invented." |
#19
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Spring Constant
On Tue, 21 Mar 2006 12:14:13 -0500, with neither quill nor qualm, Jeff
Wisnia quickly quoth: But my all time favorite is attributed to Dorothy Parker (1893 - 1967) who said, "I've been too ****ing busy and vise versa." I love it! I have a button which helps make me popular with the ladies. It says "I snatch kisses, and vise versa." -- Impeach 'em ALL! ---------------------------------------------------- http://diversify.com Website Application Programming |
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