I'm no good at math. I'm trying to determine the amount of water in a
1½" (one and one half inch) galvanized steel pipe, per foot. My
reason for this is because I'm trying to calculate the water weight in
a well pipe. Here's the issue. My well has 300 feet of pipe going to
the submersible pump. I found the weight of the actual pipe, per
foot. Also the weight of the pump, as well as the wire.

One foot of 1.5" diameter schedule 40 galvanized pipe weighs 2.72
pounds. The pump is about 25 lbs. The wire weighs about 21 lbs per 100
feet.

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

There are a few other small parts such as the fittings, foot valve (if
there is one), etc. But I know the pump is actually set at 292 feet,
so I can knock off a few pounds for that, but these small parts will
add a little. Also, this pump is 40 years old, so it may weight a
little more than the new ones. Either way, I can assume this whole
thing weighs around 900lbs.

However, there is water in the pipes and that is likely a significant
amount of weight added. My problem occurs here. How the heck does a
person calculate the amount (or weight) of the water in one foot of
1.5" pipe? (Or in 10 feet or 100 feet)?

I found online that the weight of one gallon of water is approximately
8.35 lb. Now I only need to figure out how to determine the amount of
water in the pipe.....

Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

wrote:
I'm no good at math. I'm trying to determine the amount of water in a
1½" (one and one half inch) galvanized steel pipe, per foot. My
reason for this is because I'm trying to calculate the water weight in
a well pipe. Here's the issue. My well has 300 feet of pipe going to
the submersible pump. I found the weight of the actual pipe, per
foot. Also the weight of the pump, as well as the wire.

One foot of 1.5" diameter schedule 40 galvanized pipe weighs 2.72
pounds. The pump is about 25 lbs. The wire weighs about 21 lbs per 100
feet.

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

There are a few other small parts such as the fittings, foot valve (if
there is one), etc. But I know the pump is actually set at 292 feet,
so I can knock off a few pounds for that, but these small parts will
add a little. Also, this pump is 40 years old, so it may weight a
little more than the new ones. Either way, I can assume this whole
thing weighs around 900lbs.

However, there is water in the pipes and that is likely a significant
amount of weight added. My problem occurs here. How the heck does a
person calculate the amount (or weight) of the water in one foot of
1.5" pipe? (Or in 10 feet or 100 feet)?

I found online that the weight of one gallon of water is approximately
8.35 lb. Now I only need to figure out how to determine the amount of
water in the pipe.....

Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

volume is pi*(radius squared)* length.
for 300 feet
I get 6358 cubic inches 27.6 gallons 230 pounds.
Somebody should check my math, 'cause I'm senile.

You could always pump out the water.

On Nov 9, 6:44*am, wrote:
I'm no good at math. *I'm trying to determine the amount of water in a
1½" (one and one half inch) galvanized steel pipe, per foot. *My
reason for this is because I'm trying to calculate the water weight in
a well pipe. *Here's the issue. *My well has 300 feet of pipe going to
the submersible pump. *I found the weight of the actual pipe, per
foot. *Also the weight of the pump, as well as the wire.

One foot of 1.5" diameter schedule 40 galvanized pipe weighs 2.72
pounds. The pump is about 25 lbs. The wire weighs about 21 lbs per 100
feet.

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

There are a few other small parts such as the fittings, foot valve (if
there is one), etc. *But I know the pump is actually set at 292 feet,
so I can knock off a few pounds for that, but these small parts will
add a little. *Also, this pump is 40 years old, so it may weight a
little more than the new ones. *Either way, I can assume this whole
thing weighs around 900lbs.

However, there is water in the pipes and that is likely a significant
amount of weight added. *My problem occurs here. *How the heck does a
person calculate the amount (or weight) of the water in one foot of
1.5" pipe? *(Or in 10 feet or 100 feet)?

I found online that the weight of one gallon of water is approximately
8.35 lb. *Now I only need to figure out how to determine the amount of
water in the pipe.....

Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

take a one foot piece of 1.5 inch pipe of any type, seal one end, fill
with water. pour into old empty milk jug, do repeatedly till your
happy with answer.....

things to ponder once you pull up pipe weight will go down no doubt
pipe will have to be cut apart as you go. sell scrap pipe at metal
recyclers. around here its with about 12 bucks per hundred, so you
have over a 100 bucks of scrap

the pipe is 300 feet long, is that well depth or total length of pipe
from pump including surface run? if surface that makes it far easier

replace schedule 40 with roll of poly pipe, that will cut costs, non
corosive and lightweight.

what are you doing for water during project?

snip

A problem much easier solved with metric measurements.
Reminder. google does calculations for you. Google knows conversions.

1. What is the inside diameter of the pipe? Say it is 1 inch, or 2.54 cm.
2. The length is 300 feet or 300*30 cm, or 9000 cm (a foot is actually a
little over 30 cm, 30.48 cm, so you can redo the math).
3. Volume of pipe is 2.54*(pi)*9000 or 71,816.8081 cm^3 or 72,000 cm^3
4. 1 cm^3 weighs 1 gram
5. water in pipe weighs 72,000 gram, or 72 kg
6. 1 kg= 2.2 lbs
Final: Water in pipe weighs about 158.4 lbs

(Sorry ...)
Major variable is the actual inside diameter.

--
Best regards
Han
email address is invalid

Han wrote in
:

snip

A problem much easier solved with metric measurements.
Reminder. google does calculations for you. Google knows
conversions.

1. What is the inside diameter of the pipe? Say it is 1 inch, or 2.54
cm. 2. The length is 300 feet or 300*30 cm, or 9000 cm (a foot is
actually a little over 30 cm, 30.48 cm, so you can redo the math).
3. Volume of pipe is 2.54*(pi)*9000 or 71,816.8081 cm^3 or 72,000
cm^3 4. 1 cm^3 weighs 1 gram
5. water in pipe weighs 72,000 gram, or 72 kg
6. 1 kg= 2.2 lbs
Final: Water in pipe weighs about 158.4 lbs

(Sorry ...)
Major variable is the actual inside diameter.


Sorry, need to use pi*r squared not 2r*pi
(2.54/2)squared*pi*9000=~45000 grams
45 kg=100.32 lbs

Better?

--
Best regards
Han
email address is invalid

On Nov 9, 6:44*am, wrote:
I'm no good at math. *I'm trying to determine the amount of water in a
1½" (one and one half inch) galvanized steel pipe, per foot. *My
reason for this is because I'm trying to calculate the water weight in
a well pipe. *Here's the issue. *My well has 300 feet of pipe going to
the submersible pump. *I found the weight of the actual pipe, per
foot. *Also the weight of the pump, as well as the wire.

One foot of 1.5" diameter schedule 40 galvanized pipe weighs 2.72
pounds. The pump is about 25 lbs. The wire weighs about 21 lbs per 100
feet.

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

There are a few other small parts such as the fittings, foot valve (if
there is one), etc. *But I know the pump is actually set at 292 feet,
so I can knock off a few pounds for that, but these small parts will
add a little. *Also, this pump is 40 years old, so it may weight a
little more than the new ones. *Either way, I can assume this whole
thing weighs around 900lbs.

However, there is water in the pipes and that is likely a significant
amount of weight added. *My problem occurs here. *How the heck does a
person calculate the amount (or weight) of the water in one foot of
1.5" pipe? *(Or in 10 feet or 100 feet)?

I found online that the weight of one gallon of water is approximately
8.35 lb. *Now I only need to figure out how to determine the amount of
water in the pipe.....

Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

LOL...

Call someone who knows what they are doing to help you and who
has the right equipment to actually grip the pipe while pulling it
up...

You are going to have to cut the pipe every 10-15 feet depending on
how high you can lift the bucket on your tractor/loader and it is
going to break your balls to attempt doing this "project" yourself...

However, it is your well and your tractor/loader, if you want to screw
up both of them that is up to you but when you lose your grip on
the pipe as you try to redneck this job it will be really expensive
to have a well company come in and extract the broken piece
from the bottom of the well after you drop it down there than it
would have been for them to pull the pipe and pump and replace
it all for you...

~~ Evan

On Wed, 9 Nov 2011 04:09:15 -0800 (PST), bob haller
wrote:

On Nov 9, 6:44*am, wrote:
I'm no good at math. *I'm trying to determine the amount of water in a
1½" (one and one half inch) galvanized steel pipe, per foot. *My
reason for this is because I'm trying to calculate the water weight in
a well pipe. *Here's the issue. *My well has 300 feet of pipe going to
the submersible pump. *I found the weight of the actual pipe, per
foot. *Also the weight of the pump, as well as the wire.

One foot of 1.5" diameter schedule 40 galvanized pipe weighs 2.72
pounds. The pump is about 25 lbs. The wire weighs about 21 lbs per 100
feet.

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

There are a few other small parts such as the fittings, foot valve (if
there is one), etc. *But I know the pump is actually set at 292 feet,
so I can knock off a few pounds for that, but these small parts will
add a little. *Also, this pump is 40 years old, so it may weight a
little more than the new ones. *Either way, I can assume this whole
thing weighs around 900lbs.

However, there is water in the pipes and that is likely a significant
amount of weight added. *My problem occurs here. *How the heck does a
person calculate the amount (or weight) of the water in one foot of
1.5" pipe? *(Or in 10 feet or 100 feet)?

I found online that the weight of one gallon of water is approximately
8.35 lb. *Now I only need to figure out how to determine the amount of
water in the pipe.....

Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

take a one foot piece of 1.5 inch pipe of any type, seal one end, fill
with water. pour into old empty milk jug, do repeatedly till your
happy with answer.....

That will work too....

things to ponder once you pull up pipe weight will go down no doubt
pipe will have to be cut apart as you go. sell scrap pipe at metal
recyclers. around here its with about 12 bucks per hundred, so you
have over a 100 bucks of scrap

I know it had to be cut apart or unscrewed. I like the $100 for
scrap. The pump alone is going to cost $600 or more depending on
which one I get. Then the pipe and possibly wire, and whatever
fittings and stuff are needed.

the pipe is 300 feet long, is that well depth or total length of pipe
from pump including surface run? if surface that makes it far easier

Yep, it will get lighter as it comes up and is cut apart....
Just hope my tractor can handle the initial pull. It sounds like I'm
150lbs over the lifting capability, and I know what the tractor can
handle from lifting round bales of hay. But maybe a few hydraulic
jacks can help the initial lift.

replace schedule 40 with roll of poly pipe, that will cut costs, non
corosive and lightweight.

That's the plan.

what are you doing for water during project?

I will be hauling it on 55gal barrels from a neighbor. But I have
livestock too, and they use a lot of water. The plan is to pump the
water for the livestock out of a spring fed creek which is on the
neighbors land, but only a about 50 feet away. (He said I could).
I still have to rent or borrow some sort of pump for that.

My well pump is still pumping, but it cuts out every few minutes now.
It took 4 hours to fill the stock tanks yesterday (about 550 gallons).

Major pain in the ass....

On Wed, 09 Nov 2011 04:03:19 -0800, mike wrote:
Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

volume is pi*(radius squared)* length.
for 300 feet
I get 6358 cubic inches 27.6 gallons 230 pounds.
Somebody should check my math, 'cause I'm senile.

That sounds about right, just from guessing....
I'm senile too

You could always pump out the water.

Not really, there is a foot valve or built in one way valve, and since
the pump is under water, it wont come out as air.

On Nov 9, 7:55*am, wrote:
On Wed, 9 Nov 2011 04:09:15 -0800 (PST), bob haller
wrote:





On Nov 9, 6:44*am, wrote:
I'm no good at math. *I'm trying to determine the amount of water in a
1½" (one and one half inch) galvanized steel pipe, per foot. *My
reason for this is because I'm trying to calculate the water weight in
a well pipe. *Here's the issue. *My well has 300 feet of pipe going to
the submersible pump. *I found the weight of the actual pipe, per
foot. *Also the weight of the pump, as well as the wire.

One foot of 1.5" diameter schedule 40 galvanized pipe weighs 2.72
pounds. The pump is about 25 lbs. The wire weighs about 21 lbs per 100
feet.

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

There are a few other small parts such as the fittings, foot valve (if
there is one), etc. *But I know the pump is actually set at 292 feet,
so I can knock off a few pounds for that, but these small parts will
add a little. *Also, this pump is 40 years old, so it may weight a
little more than the new ones. *Either way, I can assume this whole
thing weighs around 900lbs.

However, there is water in the pipes and that is likely a significant
amount of weight added. *My problem occurs here. *How the heck does a
person calculate the amount (or weight) of the water in one foot of
1.5" pipe? *(Or in 10 feet or 100 feet)?

I found online that the weight of one gallon of water is approximately
8.35 lb. *Now I only need to figure out how to determine the amount of
water in the pipe.....

Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

take a one foot piece of 1.5 inch pipe of any type, seal one end, fill
with water. pour into old empty milk jug, do repeatedly till your
happy with answer.....

That will work too....



things to ponder once you pull up pipe weight will go down no doubt
pipe will have to be cut apart as you go. sell scrap pipe at metal
recyclers. around here its with about 12 bucks per hundred, so you
have over a 100 bucks of scrap

I know it had to be cut apart or unscrewed. *I like the $100 for
scrap. *The pump alone is going to cost $600 or more depending on
which one I get. *Then the pipe and possibly wire, and whatever
fittings and stuff are needed.

the pipe is 300 feet long, is that well depth or total length of pipe
from pump including surface run? if surface that makes it far easier

Yep, it will get lighter as it comes up and is cut apart....
Just hope my tractor can handle the initial pull. *It sounds like I'm
150lbs over the lifting capability, and I know what the tractor can
handle from lifting round bales of hay. *But maybe a few hydraulic
jacks can help the initial lift.

replace schedule 40 with roll of poly pipe, that will cut costs, non
corosive and lightweight.

That's the plan.



what are you doing for water during project?

I will be hauling it on 55gal barrels from a neighbor. *But I have
livestock too, and they use a lot of water. *The plan is to pump the
water for the livestock out of a spring fed creek which is on the
neighbors land, but only a about 50 feet away. (He said I could).
I still have to rent or borrow some sort of pump for that.

My well pump is still pumping, but it cuts out every few minutes now.
It took 4 hours to fill the stock tanks yesterday (about 550 gallons).

Major pain in the ass....- Hide quoted text -

- Show quoted text -

I would prepare for a new well, the water table may have dropped, the
well may be collapsing, etc etc.


once you start pulling what water you have is over....

i would at least talk to pros in advance.

say you begin pulling on a sunday by monday morning you realize its a
lost cause..... and your well is now totally out of serviceL(

so you call some local drillers who are all tied up on other jobs for
over a week

thats called a bad day

On Wed, 9 Nov 2011 04:46:31 -0800 (PST), Evan
wrote:

On Nov 9, 6:44*am, wrote:
I'm no good at math. *I'm trying to determine the amount of water in a
1½" (one and one half inch) galvanized steel pipe, per foot. *My
reason for this is because I'm trying to calculate the water weight in
a well pipe. *Here's the issue. *My well has 300 feet of pipe going to
the submersible pump. *I found the weight of the actual pipe, per
foot. *Also the weight of the pump, as well as the wire.

One foot of 1.5" diameter schedule 40 galvanized pipe weighs 2.72
pounds. The pump is about 25 lbs. The wire weighs about 21 lbs per 100
feet.

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

There are a few other small parts such as the fittings, foot valve (if
there is one), etc. *But I know the pump is actually set at 292 feet,
so I can knock off a few pounds for that, but these small parts will
add a little. *Also, this pump is 40 years old, so it may weight a
little more than the new ones. *Either way, I can assume this whole
thing weighs around 900lbs.

However, there is water in the pipes and that is likely a significant
amount of weight added. *My problem occurs here. *How the heck does a
person calculate the amount (or weight) of the water in one foot of
1.5" pipe? *(Or in 10 feet or 100 feet)?

I found online that the weight of one gallon of water is approximately
8.35 lb. *Now I only need to figure out how to determine the amount of
water in the pipe.....

Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

LOL...

Call someone who knows what they are doing to help you and who
has the right equipment to actually grip the pipe while pulling it
up...

You are going to have to cut the pipe every 10-15 feet depending on
how high you can lift the bucket on your tractor/loader and it is
going to break your balls to attempt doing this "project" yourself...

However, it is your well and your tractor/loader, if you want to screw
up both of them that is up to you but when you lose your grip on
the pipe as you try to redneck this job it will be really expensive
to have a well company come in and extract the broken piece
from the bottom of the well after you drop it down there than it
would have been for them to pull the pipe and pump and replace
it all for you...

~~ Evan

I already called a well company. When I heard their estimate of $4000
(which will likely be $5000 or more), I'll do it myself. I'm not
worried about the tractor loader. It wont break, it just wont lift if
the weight it too much. I know I have to cut the pipe, that's what my
sawsall is for. I intend to rent a clamping device that prevents the
pipe from dropping in the well. That's the tool I have not yet found.

That well company's estimate is charging $1200 for a pump I can get
for around $600, and $900 for the wire, which I can get for $470 (if I
need it), and they said they will NOT reuse wire. On top of that, they
said that to get their truck in there, I will have to cut down several
trees. I dont have to cut any trees to get my tractor in there, other
then taking off a few small low branches. But that's because they
refuse to come in from the rear but driving thru some pasture and crop
field. They insist they have to come in from the driveway. My tractor
can come in from anywhere.

I'd be happy to pay someone to just come and pull the pipes. But not
when they're trying to rob me at gunpoint. Even a friend of mine who
is an electrician and has worked with that company, told me to avoid
them. The problem is that they are a monoply around here. There was
a really old man who used to do it, and was fair. In fact he's the
guy who installed the current pump 40 years ago. His son still has
all the equipment but dont want to do the work. I already asked him
about renting the machinery, but he said no. And why the hell would I
be stupid enough to spend $900 to replace the wire, when it's likely
still good. But that's just a sign of the times, waste waste waste...
(because companies like that dont want to get their hands dirty using
something that;s not brand new and wrapped in plastic).

The way I see it, these days you either DIY, or you get robbed. I
just put rear brakes on my pickup. Cost $94. That was new shoes,
drums turned, new spring kit, and both rear emergency brake cables
(which were stuck, and probably caused the excessive wear). I know a
guy who just had his rear shoes replaced by a dealer. Cost $672, and
they only changed the shoes, no springs or e-brake cables. Drums
might have been turned or maybe not. The only parts listed was the
shoes on his bill, and they were almost $100, the rest was labor.

On 11/9/2011 7:58 AM, wrote:
On Wed, 09 Nov 2011 04:03:19 -0800, wrote:
Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

volume is pi*(radius squared)* length.
for 300 feet
I get 6358 cubic inches 27.6 gallons 230 pounds.
Somebody should check my math, 'cause I'm senile.

That sounds about right, just from guessing....
I'm senile too

You could always pump out the water.

Not really, there is a foot valve or built in one way valve, and since
the pump is under water, it wont come out as air.


Assuming 1.5 is id, then calculation is right.

On Nov 9, 8:40*am, wrote:
On Wed, 9 Nov 2011 04:46:31 -0800 (PST), Evan





wrote:
On Nov 9, 6:44*am, wrote:
I'm no good at math. *I'm trying to determine the amount of water in a
1½" (one and one half inch) galvanized steel pipe, per foot. *My
reason for this is because I'm trying to calculate the water weight in
a well pipe. *Here's the issue. *My well has 300 feet of pipe going to
the submersible pump. *I found the weight of the actual pipe, per
foot. *Also the weight of the pump, as well as the wire.

One foot of 1.5" diameter schedule 40 galvanized pipe weighs 2.72
pounds. The pump is about 25 lbs. The wire weighs about 21 lbs per 100
feet.

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

There are a few other small parts such as the fittings, foot valve (if
there is one), etc. *But I know the pump is actually set at 292 feet,
so I can knock off a few pounds for that, but these small parts will
add a little. *Also, this pump is 40 years old, so it may weight a
little more than the new ones. *Either way, I can assume this whole
thing weighs around 900lbs.

However, there is water in the pipes and that is likely a significant
amount of weight added. *My problem occurs here. *How the heck does a
person calculate the amount (or weight) of the water in one foot of
1.5" pipe? *(Or in 10 feet or 100 feet)?

I found online that the weight of one gallon of water is approximately
8.35 lb. *Now I only need to figure out how to determine the amount of
water in the pipe.....

Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

LOL...

Call someone who knows what they are doing to help you and who
has the right equipment to actually grip the pipe while pulling it
up...

You are going to have to cut the pipe every 10-15 feet depending on
how high you can lift the bucket on your tractor/loader and it is
going to break your balls to attempt doing this "project" yourself...

However, it is your well and your tractor/loader, if you want to screw
up both of them that is up to you but when you lose your grip on
the pipe as you try to redneck this job it will be really expensive
to have a well company come in and extract the broken piece
from the bottom of the well after you drop it down there than it
would have been for them to pull the pipe and pump and replace
it all for you...

~~ Evan

I already called a well company. *When I heard their estimate of $4000
(which will likely be $5000 or more), I'll do it myself. *I'm not
worried about the tractor loader. *It wont break, it just wont lift if
the weight it too much. *I know I have to cut the pipe, that's what my
sawsall is for. *I intend to rent a clamping device that prevents the
pipe from dropping in the well. *That's the tool I have not yet found.

That well company's estimate is charging $1200 for a pump I can get
for around $600, and $900 for the wire, which I can get for $470 (if I
need it), and they said they will NOT reuse wire. On top of that, they
said that to get their truck in there, I will have to cut down several
trees. *I dont have to cut any trees to get my tractor in there, other
then taking off a few small low branches. *But that's because they
refuse to come in from the rear but driving thru some pasture and crop
field. *They insist they have to come in from the driveway. My tractor
can come in from anywhere.

I'd be happy to pay someone to just come and pull the pipes. *But not
when they're trying to rob me at gunpoint. *Even a friend of mine who
is an electrician and has worked with that company, told me to avoid
them. *The problem is that they are a monoply around here. *There was
a really old man who used to do it, and was fair. *In fact he's the
guy who installed the current pump 40 years ago. *His son still has
all the equipment but dont want to do the work. *I already asked him
about renting the machinery, but he said no. *And why the hell would I
be stupid enough to spend $900 to replace the wire, when it's likely
still good. *But that's just a sign of the times, waste waste waste...
(because companies like that dont want to get their hands dirty using
something that;s not brand new and wrapped in plastic).

The way I see it, these days you either DIY, or you get robbed.


I agree this isn't rocket science and given that you have a
tractor to do the pulling, well within the capability of the DIY
job. And as you've figured out, you'll save a lot of money.
As long as you use some common sense, it should go fine.
Key thing as you;ve already figured out is to make sure you
don't lose the pipe down the well. I can think of several ways
to do that.

Some folks in this group are alarmists and for some reason
just think that many jobs like this require a professional,
probably because they don't have much experience in
fixing things themselves.



*I
just put rear brakes on my pickup. *Cost $94. *That was new shoes,
drums turned, new spring kit, and both rear emergency brake cables
(which were stuck, and probably caused the excessive wear). *I know a
guy who just had his rear shoes replaced by a dealer. *Cost $672, and
they only changed the shoes, no springs or e-brake cables. *Drums
might have been turned or maybe not. *The only parts listed was the
shoes on his bill, and they were almost $100, the rest was labor.- Hide quoted text -


Again, I agree. You can save a huge amount doing routine
brake work yourself. But some would tell you you're gonna
die if you dare touch them.

One of the major brake/auto repair chains is running a radio
ad here in the NYC area. The ad says to come to them for
your brake work, tell them how much you want to spend, and
they will work within your budget to do the work. That one
strikes me as particularly odd. Like if a guy comes in and
says he only has $125 to spend on a job that should cost
$400, what are they gonna do on a job where safety is at
risk? I guess they won't compromise safety, but there are
other half-assed ways to save money too that will come back
to cost you more in the end.

231 cubic inches per gallon
8.35 pounds per gallon

The internal diameter is a bit less than 1.5 inches, but
lets use that.
The other fellow's pi x r squared x length is correct.

3.14 x 0.75 x 0.75 x 12 = 1.75 cubic inches per foot.

Since there are 231 cubic inches per gallon, that's

1/75 / 231 = 0.007582 gallons

Gallon weighs 8.35 pounds

0.007582 gallons x 8.35 = 0.0633155 pounds

0.0633155 pounds x 300 feet = 18.99465 pounds

--
Christopher A. Young
Learn more about mathematics
www.lds.org
..


"mike"
wrote in message ...

volume is pi*(radius squared)* length.
for 300 feet
I get 6358 cubic inches 27.6 gallons 230 pounds.
Somebody should check my math, 'cause I'm senile.

You could always pump out the water.

On Wed, 09 Nov 2011 04:03:19 -0800, mike wrote:

wrote:
I'm no good at math. I'm trying to determine the amount of water in a
1½" (one and one half inch) galvanized steel pipe, per foot. My
reason for this is because I'm trying to calculate the water weight in
a well pipe. Here's the issue. My well has 300 feet of pipe going to
the submersible pump. I found the weight of the actual pipe, per
foot. Also the weight of the pump, as well as the wire.

One foot of 1.5" diameter schedule 40 galvanized pipe weighs 2.72
pounds. The pump is about 25 lbs. The wire weighs about 21 lbs per 100
feet.

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

There are a few other small parts such as the fittings, foot valve (if
there is one), etc. But I know the pump is actually set at 292 feet,
so I can knock off a few pounds for that, but these small parts will
add a little. Also, this pump is 40 years old, so it may weight a
little more than the new ones. Either way, I can assume this whole
thing weighs around 900lbs.

However, there is water in the pipes and that is likely a significant
amount of weight added. My problem occurs here. How the heck does a
person calculate the amount (or weight) of the water in one foot of
1.5" pipe? (Or in 10 feet or 100 feet)?

I found online that the weight of one gallon of water is approximately
8.35 lb. Now I only need to figure out how to determine the amount of
water in the pipe.....

Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

volume is pi*(radius squared)* length.
for 300 feet
I get 6358 cubic inches 27.6 gallons 230 pounds.
Somebody should check my math, 'cause I'm senile.

You're correct but note that the water in the pipe below the well level
doesn't count.

You could always pump out the water.

Isn't that what the pump is for? ;-)

On 09 Nov 2011 12:40:33 GMT, Han wrote:

Han wrote in
:

snip

A problem much easier solved with metric measurements.
Reminder. google does calculations for you. Google knows
conversions.

1. What is the inside diameter of the pipe? Say it is 1 inch, or 2.54
cm. 2. The length is 300 feet or 300*30 cm, or 9000 cm (a foot is
actually a little over 30 cm, 30.48 cm, so you can redo the math).
3. Volume of pipe is 2.54*(pi)*9000 or 71,816.8081 cm^3 or 72,000
cm^3 4. 1 cm^3 weighs 1 gram
5. water in pipe weighs 72,000 gram, or 72 kg
6. 1 kg= 2.2 lbs
Final: Water in pipe weighs about 158.4 lbs

(Sorry ...)
Major variable is the actual inside diameter.


Sorry, need to use pi*r squared not 2r*pi
(2.54/2)squared*pi*9000=~45000 grams
45 kg=100.32 lbs

I guess it wasn't that much easier. Even "Senile" Mike got it right the first
time using imperial units. ;-)


Better?

On 11/9/2011 5:44 AM, wrote:
I'm no good at math. I'm trying to determine the amount of water in a
1½" (one and one half inch) galvanized steel pipe, per foot. My
reason for this is because I'm trying to calculate the water weight in
a well pipe. Here's the issue. My well has 300 feet of pipe going to
the submersible pump. I found the weight of the actual pipe, per
foot. Also the weight of the pump, as well as the wire.

....

http://www.engineeringtoolbox.com/ansi-steel-pipes-d_305.html

--

On Nov 9, 8:26*am, "
wrote:
On Wed, 09 Nov 2011 04:03:19 -0800, mike wrote:
wrote:
I'm no good at math. *I'm trying to determine the amount of water in a
1½" (one and one half inch) galvanized steel pipe, per foot. *My
reason for this is because I'm trying to calculate the water weight in
a well pipe. *Here's the issue. *My well has 300 feet of pipe going to
the submersible pump. *I found the weight of the actual pipe, per
foot. *Also the weight of the pump, as well as the wire.

One foot of 1.5" diameter schedule 40 galvanized pipe weighs 2.72
pounds. The pump is about 25 lbs. The wire weighs about 21 lbs per 100
feet.

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

There are a few other small parts such as the fittings, foot valve (if
there is one), etc. *But I know the pump is actually set at 292 feet,
so I can knock off a few pounds for that, but these small parts will
add a little. *Also, this pump is 40 years old, so it may weight a
little more than the new ones. *Either way, I can assume this whole
thing weighs around 900lbs.

However, there is water in the pipes and that is likely a significant
amount of weight added. *My problem occurs here. *How the heck does a
person calculate the amount (or weight) of the water in one foot of
1.5" pipe? *(Or in 10 feet or 100 feet)?

I found online that the weight of one gallon of water is approximately
8.35 lb. *Now I only need to figure out how to determine the amount of
water in the pipe.....

Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

volume is pi*(radius squared)* length.
for 300 feet
I get 6358 cubic inches 27.6 gallons 230 pounds.
Somebody should check my math, 'cause I'm senile.

You're correct but note that the water in the pipe below the well level
doesn't count.

You could always pump out the water.

Isn't that what the pump is for? *;-)- Hide quoted text -

- Show quoted text -

According to my ACE Pocket Reference guidebook, "Weight of Water in a
Pipe" is formulated as:
Pounds Water = Pipe Length feet x (Pipe diameter inches(squared)) x
0.34

So based on that formula,
Pipe Length feet = 300
(Pipe diameter inches (squared)) = 1.5 squared = 2.25

so the formula = 300 x 2.25 x 0.34 = 229.5 pounds

Robin

On Nov 9, 6:23*am, "Stormin Mormon"
wrote:
231 cubic inches per gallon
8.35 pounds per gallon

The internal diameter is a bit less than 1.5 inches, but
lets use that.
The other fellow's pi x r squared x length is correct.

3.14 x 0.75 x 0.75 x 12 = 1.75 cubic inches per foot.

Since there are 231 cubic inches per gallon, that's

1/75 / 231 = 0.007582 gallons

Gallon weighs 8.35 pounds

0.007582 gallons x 8.35 = 0.0633155 pounds

0.0633155 pounds x 300 feet = 18.99465 pounds

--
Christopher A. Young
Learn more about mathematics
*www.lds.org
.

"mike"
wrote in ...

volume is pi*(radius squared)* length.
for 300 feet
I get 6358 cubic inches 27.6 gallons 230 pounds.
Somebody should check my math, 'cause I'm senile.

You could always pump out the water.

CY-

Recheck your calc...... looks like you're off by 12x.

~230lbs is the right answer

On Wed, 9 Nov 2011 07:47:40 -0800 (PST), rlz wrote:

On Nov 9, 8:26*am, "
wrote:
On Wed, 09 Nov 2011 04:03:19 -0800, mike wrote:
wrote:
I'm no good at math. *I'm trying to determine the amount of water in a
1½" (one and one half inch) galvanized steel pipe, per foot. *My
reason for this is because I'm trying to calculate the water weight in
a well pipe. *Here's the issue. *My well has 300 feet of pipe going to
the submersible pump. *I found the weight of the actual pipe, per
foot. *Also the weight of the pump, as well as the wire.

One foot of 1.5" diameter schedule 40 galvanized pipe weighs 2.72
pounds. The pump is about 25 lbs. The wire weighs about 21 lbs per 100
feet.

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

There are a few other small parts such as the fittings, foot valve (if
there is one), etc. *But I know the pump is actually set at 292 feet,
so I can knock off a few pounds for that, but these small parts will
add a little. *Also, this pump is 40 years old, so it may weight a
little more than the new ones. *Either way, I can assume this whole
thing weighs around 900lbs.

However, there is water in the pipes and that is likely a significant
amount of weight added. *My problem occurs here. *How the heck does a
person calculate the amount (or weight) of the water in one foot of
1.5" pipe? *(Or in 10 feet or 100 feet)?

I found online that the weight of one gallon of water is approximately
8.35 lb. *Now I only need to figure out how to determine the amount of
water in the pipe.....

Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

volume is pi*(radius squared)* length.
for 300 feet
I get 6358 cubic inches 27.6 gallons 230 pounds.
Somebody should check my math, 'cause I'm senile.

You're correct but note that the water in the pipe below the well level
doesn't count.

You could always pump out the water.

Isn't that what the pump is for? *;-)- Hide quoted text -

- Show quoted text -

According to my ACE Pocket Reference guidebook, "Weight of Water in a
Pipe" is formulated as:
Pounds Water = Pipe Length feet x (Pipe diameter inches(squared)) x
0.34

Simple formula for a cylinder X constant (weight per unit water).

So based on that formula,
Pipe Length feet = 300
(Pipe diameter inches (squared)) = 1.5 squared = 2.25

so the formula = 300 x 2.25 x 0.34 = 229.5 pounds

....and this disagrees with what I said, how? You still have to subtract the
weight of the water in the submerged pipe.

Stormin Mormon wrote:
231 cubic inches per gallon
8.35 pounds per gallon

The internal diameter is a bit less than 1.5 inches, but
lets use that.
The other fellow's pi x r squared x length is correct.

3.14 x 0.75 x 0.75 x 12 = 1.75 cubic inches per foot.

Since there are 231 cubic inches per gallon, that's

1/75 / 231 = 0.007582 gallons

Gallon weighs 8.35 pounds

0.007582 gallons x 8.35 = 0.0633155 pounds

0.0633155 pounds x 300 feet = 18.99465 pounds

Wrong again. As well considered as your political opinions.

wrote:
I know I have to cut the pipe, that's what my
sawsall is for.

You might consider a metal abrasive cutoff blade or 3 in your skillsaw instead
of the sawsall. It'll probably be a lot faster.

Thanks, it did sound a bit low.
I found the mistake.

--
Christopher A. Young
Learn more about Jesus
www.lds.org
..


"DD_BobK" wrote in message
...
On Nov 9, 6:23 am, "Stormin Mormon"
wrote:
231 cubic inches per gallon
8.35 pounds per gallon

The internal diameter is a bit less than 1.5 inches, but
lets use that.
The other fellow's pi x r squared x length is correct.

3.14 x 0.75 x 0.75 x 12 = 1.75 cubic inches per foot.
(should read per
linear inch)


Since there are 231 cubic inches per gallon, that's

1/75 / 231 = 0.007582 gallons

Gallon weighs 8.35 pounds

0.007582 gallons x 8.35 = 0.0633155 pounds

0.0633155 pounds x 300 feet = 18.99465 pounds

--
Christopher A. Young
Learn more about mathematics
www.lds.org
.

"mike"
wrote in ...

volume is pi*(radius squared)* length.
for 300 feet
I get 6358 cubic inches 27.6 gallons 230 pounds.
Somebody should check my math, 'cause I'm senile.

You could always pump out the water.

CY-

Recheck your calc...... looks like you're off by 12x.

~230lbs is the right answer

On 11/9/2011 8:40 AM, wrote:

I already called a well company. When I heard their estimate of $4000
(which will likely be $5000 or more), I'll do it myself. I'm not
worried about the tractor loader. It wont break, it just wont lift if
the weight it too much. I know I have to cut the pipe, that's what my
sawsall is for. I intend to rent a clamping device that prevents the
pipe from dropping in the well. That's the tool I have not yet found.

Wow! I had mine replaced not long ago (about 600' down, new 1.5hp
goulds pump, old wire and pipe) for a grand total of $1324.66 including tax.

I missed the beginning of the thread, what size is your pump?

On Nov 9, 7:55*am, wrote:
On Wed, 9 Nov 2011 04:09:15 -0800 (PST), bob haller
wrote:





On Nov 9, 6:44*am, wrote:
I'm no good at math. *I'm trying to determine the amount of water in a
1½" (one and one half inch) galvanized steel pipe, per foot. *My
reason for this is because I'm trying to calculate the water weight in
a well pipe. *Here's the issue. *My well has 300 feet of pipe going to
the submersible pump. *I found the weight of the actual pipe, per
foot. *Also the weight of the pump, as well as the wire.

One foot of 1.5" diameter schedule 40 galvanized pipe weighs 2.72
pounds. The pump is about 25 lbs. The wire weighs about 21 lbs per 100
feet.

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

There are a few other small parts such as the fittings, foot valve (if
there is one), etc. *But I know the pump is actually set at 292 feet,
so I can knock off a few pounds for that, but these small parts will
add a little. *Also, this pump is 40 years old, so it may weight a
little more than the new ones. *Either way, I can assume this whole
thing weighs around 900lbs.

However, there is water in the pipes and that is likely a significant
amount of weight added. *My problem occurs here. *How the heck does a
person calculate the amount (or weight) of the water in one foot of
1.5" pipe? *(Or in 10 feet or 100 feet)?

I found online that the weight of one gallon of water is approximately
8.35 lb. *Now I only need to figure out how to determine the amount of
water in the pipe.....

Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

take a one foot piece of 1.5 inch pipe of any type, seal one end, fill
with water. pour into old empty milk jug, do repeatedly till your
happy with answer.....

That will work too....



things to ponder once you pull up pipe weight will go down no doubt
pipe will have to be cut apart as you go. sell scrap pipe at metal
recyclers. around here its with about 12 bucks per hundred, so you
have over a 100 bucks of scrap

I know it had to be cut apart or unscrewed. *I like the $100 for
scrap. *The pump alone is going to cost $600 or more depending on
which one I get. *Then the pipe and possibly wire, and whatever
fittings and stuff are needed.

the pipe is 300 feet long, is that well depth or total length of pipe
from pump including surface run? if surface that makes it far easier

Yep, it will get lighter as it comes up and is cut apart....
Just hope my tractor can handle the initial pull. *It sounds like I'm
150lbs over the lifting capability, and I know what the tractor can
handle from lifting round bales of hay. *But maybe a few hydraulic
jacks can help the initial lift.

replace schedule 40 with roll of poly pipe, that will cut costs, non
corosive and lightweight.

That's the plan.



what are you doing for water during project?

I will be hauling it on 55gal barrels from a neighbor. *But I have
livestock too, and they use a lot of water. *The plan is to pump the
water for the livestock out of a spring fed creek which is on the
neighbors land, but only a about 50 feet away. (He said I could).
I still have to rent or borrow some sort of pump for that.

My well pump is still pumping, but it cuts out every few minutes now.
It took 4 hours to fill the stock tanks yesterday (about 550 gallons).

Major pain in the ass....- Hide quoted text -

- Show quoted text -

I don't know squat about well pumps, so don't slap me too hard for
this question:

Instead of renting/borrowing a pump for the creek, why can't you use
the pump that you are going to use in the well to pump the livestock
water from the creek?

Once you have the old still-sort-of working pump out of the well, swap
it for the new one at the creek while you install the new one in the
well.

What don't I know?

On 11/9/2011 5:44 AM, wrote:
....

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

....

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

As others said, it'll add another 200 lb+/-

But, you're forgetting about what the breakout force will be; the
snubbers and that it's been sitting in place for however long means the
initial friction forces will likely be close to that of half the weight
or perhaps even more. I don't think you have any chance w/ your front
loader in a direct lift; not to mention the hassle of trying to deal
with such a rube goldberg setup.

--

" wrote in
:

I guess it wasn't that much easier. Even "Senile" Mike got it right
the first time using imperial units. ;-)


Hey, I'm retired. May I have a senior moment?
I still think that metric is easier for this kind of thing. Formulae for
circumference, surface and volume should be imprt=inted on my brain, but
this time ...

--
Best regards
Han
email address is invalid

On 11/9/2011 6:36 AM, Han wrote:
....
A problem much easier solved with metric measurements.
....

How so much? What's pi in metric units?

--

Is the OP CERTAIN, its a bad pump? or has the water table fallen? or a
myriad of other possibilties, like a cracked or rusted out main
pipe......

best wishes on your project but plan in advance for gotchas.....

like the well collapsed on the pump

have the financing inorder for a entire new well

On Nov 9, 4:51*pm, dpb wrote:
On 11/9/2011 6:36 AM, Han wrote:
... A problem much easier solved with metric measurements.

...
....

How so much? *What's pi in metric units? *
....
I believe this would be a metric pi:

http://www.venere.com/blog/images/british-pie.jpg

On Wed, 09 Nov 2011 15:24:10 -0500, Tony Miklos
wrote:

On 11/9/2011 8:40 AM, wrote:

I already called a well company. When I heard their estimate of $4000
(which will likely be $5000 or more), I'll do it myself. I'm not
worried about the tractor loader. It wont break, it just wont lift if
the weight it too much. I know I have to cut the pipe, that's what my
sawsall is for. I intend to rent a clamping device that prevents the
pipe from dropping in the well. That's the tool I have not yet found.

Wow! I had mine replaced not long ago (about 600' down, new 1.5hp
goulds pump, old wire and pipe) for a grand total of $1324.66 including tax.

I missed the beginning of the thread, what size is your pump?

That sounds much more reasonable. I just got a second estimate for
$2800. Better than the first one, but still seems quite high. The
pump is a 1 HP, down approx 300ft. This new estimate is everything
new, pump, pipe, fittings, control box. They said they would try to
save some of the old pipe if possible, and can put plastic pipe below
the good steel pipe, but it's hard to know what is needed. They
insist the wire be replaced because the new code requires 4 wires now
(a ground wire is added).

On Wed, 09 Nov 2011 14:54:40 -0600, dpb wrote:

On 11/9/2011 5:44 AM, wrote:
...

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

...

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

As others said, it'll add another 200 lb+/-

But, you're forgetting about what the breakout force will be; the
snubbers and that it's been sitting in place for however long means the
initial friction forces will likely be close to that of half the weight
or perhaps even more. I don't think you have any chance w/ your front
loader in a direct lift; not to mention the hassle of trying to deal
with such a rube goldberg setup.

I was just informed that the drop pipe is actually inch and a quarter,
not inch and a half. That takes off a few pounbut I know the initial
breaking loose the pitless and all that is gonna be tough.

Thomas J. Glover's Pocket Ref. Sequoia Press. More than you want to know
about "stuff". And very handy.

Steve

On 11/9/2011 6:55 PM, wrote:
On Wed, 09 Nov 2011 15:24:10 -0500, Tony Miklos
wrote:

On 11/9/2011 8:40 AM, wrote:

I already called a well company. When I heard their estimate of $4000
(which will likely be $5000 or more), I'll do it myself. I'm not
worried about the tractor loader. It wont break, it just wont lift if
the weight it too much. I know I have to cut the pipe, that's what my
sawsall is for. I intend to rent a clamping device that prevents the
pipe from dropping in the well. That's the tool I have not yet found.

Wow! I had mine replaced not long ago (about 600' down, new 1.5hp
goulds pump, old wire and pipe) for a grand total of $1324.66 including tax.

I missed the beginning of the thread, what size is your pump?

That sounds much more reasonable. I just got a second estimate for
$2800. Better than the first one, but still seems quite high. The
pump is a 1 HP, down approx 300ft. This new estimate is everything
new, pump, pipe, fittings, control box. They said they would try to
save some of the old pipe if possible, and can put plastic pipe below
the good steel pipe, but it's hard to know what is needed. They
insist the wire be replaced because the new code requires 4 wires now
(a ground wire is added).

I must admit my well guys work amazingly cheap so I'd add about $400 to
my price for a more realistic comparison. Most likely anyone who drills
wells will be higher priced, repairs are stuff they don't like to be
bothered with.

dpb wrote in :

On 11/9/2011 6:36 AM, Han wrote:
...
A problem much easier solved with metric measurements.
...

How so much? What's pi in metric units?

lol


--
Best regards
Han
email address is invalid

On 09 Nov 2011 21:00:54 GMT, Han wrote:

" wrote in
:

I guess it wasn't that much easier. Even "Senile" Mike got it right
the first time using imperial units. ;-)


Hey, I'm retired. May I have a senior moment?
I still think that metric is easier for this kind of thing. Formulae for
circumference, surface and volume should be imprt=inted on my brain, but
this time ...

I retired five years ago, but didn't like it so went back to work. I was
retired earlier this year but I'm still too young to do it permanently, so...

Metric is easier if the inputs and output are in metric. Imperial is easier
if the units are imperial, as in this case. Converting is just asking for
trouble. Ask NASA. ;-)

On Wed, 9 Nov 2011 14:18:53 -0800 (PST), DerbyDad03
wrote:

On Nov 9, 4:51*pm, dpb wrote:
On 11/9/2011 6:36 AM, Han wrote:
... A problem much easier solved with metric measurements.

...
...

How so much? *What's pi in metric units? *
...
I believe this would be a metric pi:

http://www.venere.com/blog/images/british-pie.jpg

Certainly not! That would be an imperial pie.

wrote:
On Wed, 09 Nov 2011 14:54:40 -0600, dpb wrote:

On 11/9/2011 5:44 AM, wrote:
...

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

...

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).
As others said, it'll add another 200 lb+/-

But, you're forgetting about what the breakout force will be; the
snubbers and that it's been sitting in place for however long means the
initial friction forces will likely be close to that of half the weight
or perhaps even more. I don't think you have any chance w/ your front
loader in a direct lift; not to mention the hassle of trying to deal
with such a rube goldberg setup.

I was just informed that the drop pipe is actually inch and a quarter,
not inch and a half. That takes off a few pounbut I know the initial
breaking loose the pitless and all that is gonna be tough.

I'd worry more about what you're gonna do when the pipe breaks.

zzzzzzzzzz wrote:
On Wed, 09 Nov 2011 04:03:19 -0800, mike wrote:

wrote:
I'm no good at math. I'm trying to determine the amount of water in a
1½" (one and one half inch) galvanized steel pipe, per foot. My
reason for this is because I'm trying to calculate the water weight in
a well pipe. Here's the issue. My well has 300 feet of pipe going to
the submersible pump. I found the weight of the actual pipe, per
foot. Also the weight of the pump, as well as the wire.

One foot of 1.5" diameter schedule 40 galvanized pipe weighs 2.72
pounds. The pump is about 25 lbs. The wire weighs about 21 lbs per 100
feet.

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

There are a few other small parts such as the fittings, foot valve (if
there is one), etc. But I know the pump is actually set at 292 feet,
so I can knock off a few pounds for that, but these small parts will
add a little. Also, this pump is 40 years old, so it may weight a
little more than the new ones. Either way, I can assume this whole
thing weighs around 900lbs.

However, there is water in the pipes and that is likely a significant
amount of weight added. My problem occurs here. How the heck does a
person calculate the amount (or weight) of the water in one foot of
1.5" pipe? (Or in 10 feet or 100 feet)?

I found online that the weight of one gallon of water is approximately
8.35 lb. Now I only need to figure out how to determine the amount of
water in the pipe.....

Any math experts out there?

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

thanks

volume is pi*(radius squared)* length.
for 300 feet
I get 6358 cubic inches 27.6 gallons 230 pounds.
Somebody should check my math, 'cause I'm senile.

You're correct but note that the water in the pipe below the well level
doesn't count.

Please explain.
Thought experiment:
Assume no friction.
Drain the water outa the pipe.
Pull up on the pipe to raise it off the supports.
Weigh the pipe.
Pour a pound of water into the pipe.
Weigh it again.
Does the weight not increase by a pound?

What counts is the water displaced by the pipe below the water level.
Contents of the pipe does not affect that.


You could always pump out the water.

Isn't that what the pump is for? ;-)

Good point.
Because of the depth,
You'd need a pump that could be lowered down into the 1.5" pipe.
Or maybe a lot of trips with a sponge, or a hollow cup. or a 1: plastic
pipe with a check valve on the end.
;-)

" wrote in
news
I retired five years ago, but didn't like it so went back to work. I
was retired earlier this year but I'm still too young to do it
permanently, so...

I can see that, but I'm 67 now, and I had my fill of certain aspects of my
position, so I will not likely unretire grin.

Metric is easier if the inputs and output are in metric. Imperial is
easier if the units are imperial, as in this case. Converting is just
asking for trouble. Ask NASA. ;-)

Grew up in Hlland, so metric is more natural, really, although imperial has
grown on me the last 42 years ...

What I like about metric is the powers of 10 rather than funny factors
(12"/ft, whatever cubic inches/gal, 11 sq feet/m^2, whatever). also, in my
educatgion it was really important to get the powers of 10 (orders of
magnitude) straight. Sometimes I am good at that, too grin.

--
Best regards
Han
email address is invalid

On 11/9/2011 6:58 PM, wrote:
On Wed, 09 Nov 2011 14:54:40 -0600, wrote:

On 11/9/2011 5:44 AM, wrote:
...

So far I have
300 x 2.72 = 816 lbs for the pipe
300 feet of wire is 63 lbs
plus 25 lbs for the pump

That totals 904 lbs.

...

(I hope it's not over 100 lbs, because my tractor loader cant handle
over 1000 lbs of lifting weight).

As others said, it'll add another 200 lb+/-

But, you're forgetting about what the breakout force will be; the
snubbers and that it's been sitting in place for however long means the
initial friction forces will likely be close to that of half the weight
or perhaps even more. I don't think you have any chance w/ your front
loader in a direct lift; not to mention the hassle of trying to deal
with such a rube goldberg setup.

I was just informed that the drop pipe is actually inch and a quarter,
not inch and a half. That takes off a few pounbut I know the initial
breaking loose the pitless and all that is gonna be tough.

If your bucket lifts 1000lbs you have two (or three) other things to
consider. The pivot action of the bucket tilting up is probably well
over 1000lbs. of force. That should be enough to break it loose. Also,
you could remove the heavy bucket and put something else across the arms
to use to lift with. Now seriously, if I were going to attempt
something like this I would be buying the proper tool to both hold the
pipe in between lifts, and the proper tool to attach to lift it with.
Don't know if it was mentioned, but if the well isn't dry you also have
the buoyancy of the water so the whole thing won't weigh as much.

Another very important thing to keep in mind. While working, if that
thing slips and lets loose, the wire is going to be moving fast down the
well. If your foot or hand were to get tangled in it, you could loose
it. If it happened to jump around and get around your chest, we could
loose you!