Home |
Search |
Today's Posts |
![]() |
|
Home Repair (alt.home.repair) For all homeowners and DIYers with many experienced tradesmen. Solve your toughest home fix-it problems. |
Reply |
|
LinkBack | Thread Tools | Display Modes |
#1
![]()
Posted to alt.home.repair
|
|||
|
|||
![]()
I understand that double pole circuit breakers feed 240v (two120's) to
water heaters, stoves, ect... But, Im confused about the amperage marking on the middle tab; I see that most say 30A. Does that mean the each pole from that circuit breaker can handle up to 30A each pole? 30 + 30 = 60A total? or is the amps on each hot leg split into two; 15 amps each pole; 15 + 15 = 30A? I never worked with 240V circuits before, obviosly. I just need to install a small baseboard heater in my shop for the upcoming winters; it calls for a 20A 240v breaker. Another quick question, but off topic: Why don't wire manufactures insulate the bare ground wire inside romex cables? |
#2
![]()
Posted to alt.home.repair
|
|||
|
|||
![]()
Each pole of a breaker, single, double or triple, provides the amperage
marked on the breaker. Double pole 20 amp gives you 20 amps on each legs or 20 amps @240 volts I too, would like the ground wires to be insulated for my own safety wrote in message ups.com... I understand that double pole circuit breakers feed 240v (two120's) to water heaters, stoves, ect... But, Im confused about the amperage marking on the middle tab; I see that most say 30A. Does that mean the each pole from that circuit breaker can handle up to 30A each pole? 30 + 30 = 60A total? or is the amps on each hot leg split into two; 15 amps each pole; 15 + 15 = 30A? I never worked with 240V circuits before, obviosly. I just need to install a small baseboard heater in my shop for the upcoming winters; it calls for a 20A 240v breaker. Another quick question, but off topic: Why don't wire manufactures insulate the bare ground wire inside romex cables? |
#4
![]()
Posted to alt.home.repair
|
|||
|
|||
![]() |
#5
![]()
Posted to alt.home.repair
|
|||
|
|||
![]()
In article , "RBM" rbm2(remove wrote:
Each pole of a breaker, single, double or triple, provides the amperage marked on the breaker. Double pole 20 amp gives you 20 amps on each legs or 20 amps @240 volts I too, would like the ground wires to be insulated for my own safety How would insulating the ground wire improve safety? -- Regards, Doug Miller (alphageek at milmac dot com) It's time to throw all their damned tea in the harbor again. |
#6
![]()
Posted to alt.home.repair
|
|||
|
|||
![]() |
#7
![]()
Posted to alt.home.repair
|
|||
|
|||
![]()
On Mon, 12 Jun 2006 07:09:40 -0400, "RBM" rbm2(remove
wrote: Each pole of a breaker, single, double or triple, provides the amperage marked on the breaker. Double pole 20 amp gives you 20 amps on each legs or 20 amps @240 volts I too, would like the ground wires to be insulated for my own safety imho: Ground Wires 'do not' carry current except under ground fault conditions. In that case, the breaker/fuse will break the circuit asap(by design). So it normally carries 0 voltage, 0 current. hth, tom wrote in message oups.com... I understand that double pole circuit breakers feed 240v (two120's) to water heaters, stoves, ect... But, Im confused about the amperage marking on the middle tab; I see that most say 30A. Does that mean the each pole from that circuit breaker can handle up to 30A each pole? 30 + 30 = 60A total? or is the amps on each hot leg split into two; 15 amps each pole; 15 + 15 = 30A? I never worked with 240V circuits before, obviosly. I just need to install a small baseboard heater in my shop for the upcoming winters; it calls for a 20A 240v breaker. Another quick question, but off topic: Why don't wire manufactures insulate the bare ground wire inside romex cables? |
#8
![]()
Posted to alt.home.repair
|
|||
|
|||
![]() "Tom The Great" wrote in message ... On Mon, 12 Jun 2006 07:09:40 -0400, "RBM" rbm2(remove wrote: Each pole of a breaker, single, double or triple, provides the amperage marked on the breaker. Double pole 20 amp gives you 20 amps on each legs or 20 amps @240 volts I too, would like the ground wires to be insulated for my own safety imho: Ground Wires 'do not' carry current except under ground fault conditions. In that case, the breaker/fuse will break the circuit asap(by design). So it normally carries 0 voltage, 0 current. You are correct that it normally carries nothing, but why would a breaker open on a ground fault? (unless it is a gfci...) |
#9
![]()
Posted to alt.home.repair
|
|||
|
|||
![]()
On Mon, 12 Jun 2006 11:46:52 GMT, (Doug Miller)
wrote: In article . com, wrote: I understand that double pole circuit breakers feed 240v (two120's) to water heaters, stoves, ect... But, Im confused about the amperage marking on the middle tab; I see that most say 30A. Does that mean the each pole from that circuit breaker can handle up to 30A each pole? 30 + 30 = 60A total? or is the amps on each hot leg split into two; 15 amps each pole; 15 + 15 = 30A? Depends on how it's wired, actually. A double-pole breaker can provide one 240V circuit, or two 120V circuits. In your example, a 30A double-pole breaker will provide one 30A circuit at 240V, or two 30A circuits at 120V. Another quick question, but off topic: Why don't wire manufactures insulate the bare ground wire inside romex cables? Because it would be pointless to do so. The grounding wire is intended to insure that the metal frames of equipment (e.g. a washing machine) and exposed metal components of the premises wiring (e.g. conduits or receptacle boxes) are grounded and cannot become live. In other words -- it's connected to things that are not insulated anyway, and thus no purpose would be served by insulating it. That's one thing people often do not understand. If you have a 100A service and only use 120V items in the house, you can actually draw 200A. But if you have all 240V appliances, you can only use 100A. Of course most homes have both, so that's where the mathematics comes into play. Mark |
#10
![]()
Posted to alt.home.repair
|
|||
|
|||
![]()
According to Toller :
You are correct that it normally carries nothing, but why would a breaker open on a ground fault? (unless it is a gfci...) A ground fault is simply a leak to the grounding conductor - it could be a few milliamps, or many amps. Breakers trip on big ones. GFCIs trip on small ones. -- Chris Lewis, Una confibula non set est It's not just anyone who gets a Starship Cruiser class named after them. |
#11
![]()
Posted to alt.home.repair
|
|||
|
|||
![]()
Chris Lewis wrote:
According to Toller : You are correct that it normally carries nothing, but why would a breaker open on a ground fault? (unless it is a gfci...) A ground fault is simply a leak to the grounding conductor - it could be a few milliamps, or many amps. A ground fault is a leak to ground. It may or may not pass through the grounding conductor. Breakers trip on big ones. GFCIs trip on small ones. Breakers trip on excessive current regardless of the path that it takes. GFCIs trip on an unbalance between the two wires that compose the active circuit. -- --John to email, dial "usenet" and validate (was jclarke at eye bee em dot net) |
#12
![]()
Posted to alt.home.repair
|
|||
|
|||
![]() "Pete C." wrote in message ... wrote: That's one thing people often do not understand. If you have a 100A service and only use 120V items in the house, you can actually draw 200A. But if you have all 240V appliances, you can only use 100A. Of course most homes have both, so that's where the mathematics comes into play. Mark The total power is the same either way or in combination. 100A x 240V = 24,000W or 200A x 120V = 24,000W or 50A x 240V = 12,000W + 100A x 120V = 12,000W = 24,000W total etc... If you happen to have a perfectly balanced system, which is most unlikely... |
#13
![]()
Posted to alt.home.repair
|
|||
|
|||
![]()
Toller wrote:
"Pete C." wrote in message ... wrote: That's one thing people often do not understand. If you have a 100A service and only use 120V items in the house, you can actually draw 200A. But if you have all 240V appliances, you can only use 100A. Of course most homes have both, so that's where the mathematics comes into play. Mark The total power is the same either way or in combination. 100A x 240V = 24,000W or 200A x 120V = 24,000W or 50A x 240V = 12,000W + 100A x 120V = 12,000W = 24,000W total etc... If you happen to have a perfectly balanced system, which is most unlikely... It makes no difference how balanced or unbalanced you have the system, you will not be pulling more than 24,000W at least not for more than a few min before the main breaker trips. It could well be less than that number if you max out one leg first. You need to have the system balanced to reach the 24,000W load, but the total amount of power available from the service is 24,000W no matter what. Pete C. |
#14
![]()
Posted to alt.home.repair
|
|||
|
|||
![]()
If they were insulated, I wouldn't have to be so careful while flailing them
around inside panel boxes "Doug Miller" wrote in message y.net... In article , "RBM" rbm2(remove wrote: Each pole of a breaker, single, double or triple, provides the amperage marked on the breaker. Double pole 20 amp gives you 20 amps on each legs or 20 amps @240 volts I too, would like the ground wires to be insulated for my own safety How would insulating the ground wire improve safety? -- Regards, Doug Miller (alphageek at milmac dot com) It's time to throw all their damned tea in the harbor again. |
#15
![]()
Posted to alt.home.repair
|
|||
|
|||
![]()
On Mon, 12 Jun 2006 20:56:43 GMT, "Pete C."
wrote: Toller wrote: "Pete C." wrote in message ... wrote: That's one thing people often do not understand. If you have a 100A service and only use 120V items in the house, you can actually draw 200A. But if you have all 240V appliances, you can only use 100A. Of course most homes have both, so that's where the mathematics comes into play. Mark The total power is the same either way or in combination. 100A x 240V = 24,000W or 200A x 120V = 24,000W or 50A x 240V = 12,000W + 100A x 120V = 12,000W = 24,000W total etc... If you happen to have a perfectly balanced system, which is most unlikely... It makes no difference how balanced or unbalanced you have the system, you will not be pulling more than 24,000W at least not for more than a few min before the main breaker trips. It could well be less than that number if you max out one leg first. You need to have the system balanced to reach the 24,000W load, but the total amount of power available from the service is 24,000W no matter what. Limited to 12,000W per side. Pete C. |
#16
![]()
Posted to alt.home.repair
|
|||
|
|||
![]()
On Mon, 12 Jun 2006 13:34:31 GMT, "Toller" wrote:
"Tom The Great" wrote in message .. . On Mon, 12 Jun 2006 07:09:40 -0400, "RBM" rbm2(remove wrote: Each pole of a breaker, single, double or triple, provides the amperage marked on the breaker. Double pole 20 amp gives you 20 amps on each legs or 20 amps @240 volts I too, would like the ground wires to be insulated for my own safety imho: Ground Wires 'do not' carry current except under ground fault conditions. In that case, the breaker/fuse will break the circuit asap(by design). So it normally carries 0 voltage, 0 current. You are correct that it normally carries nothing, but why would a breaker open on a ground fault? (unless it is a gfci...) If a hot comes in contact with a metal casing, that is grounded, it is called a ground fault. Following the NEC all grounded equipment conductors (the ground wire) have to have as lose impedance to electricy back to the source. So using ohms law E=IR E is electrical potencial, or Voltage I is current R is resistance. Solve for I (current) results in I = E/R substitute numbers for lowest norm voltage. I = 120 / ~0 *Note: Used 0 since a small house has almost 0 ohms back to the panel on the ground wires. So calc Current, and you have an almost infinite amount of current, a short, and the breaker will open on this ground. A normal breaker should open on any ground fault over thier set points. Meaning a 15 amp breaker should open on any ground faults over 15 amps, on over current protection. Ofcourse an almost infinite current, should trip the breaker on short circuit protection. hth, (please ignore spelling errors) tom |
#17
![]()
Posted to alt.home.repair
|
|||
|
|||
![]() |
#18
![]()
Posted to alt.home.repair
|
|||
|
|||
![]()
In article , ~^Johnny^~ wrote:
On Mon, 12 Jun 2006 08:34:35 -0500, wrote: That's one thing people often do not understand. If you have a 100A service and only use 120V items in the house, you can actually draw 200A. No way. Your total load calc may be 200 A at 120 V, but you are still pulling 100 amps. You've got two 120 volt loads in series, that's all. You are STILl pulling 100 amps at 240 volts. Which is exactly the same electrical power as 200A at 120V. Since the individual loads are in series/parallel, they share half teh voltage, so the total load calc comes out to 200 amps, but only 100 amps are flowing through the service. Really. 100A at 240V -- and, as noted above, if only 120V loads are in use, the total current draw is (up to) 200A at 120V. -- Regards, Doug Miller (alphageek at milmac dot com) It's time to throw all their damned tea in the harbor again. |
#19
![]()
Posted to alt.home.repair
|
|||
|
|||
![]() |
#20
![]()
Posted to alt.home.repair
|
|||
|
|||
![]()
On Fri, 23 Jun 2006 08:11:40 -0700, ~^Johnny^~
wrote: On Fri, 23 Jun 2006 13:22:41 GMT, (Doug Miller) wrote: 100A at 240V -- and, as noted above, if only 120V loads are in use, the total current draw is (up to) 200A at 120V. The power consumption is equivalent to 200A at 120V, but only 100A are flowing. Kirchoff's Law will not be violated! Currents in series do not add; =voltages= add. It's still 100A at 240V. Better yet, Look at it this way: If I hang ten 12V lamps in series across a 120V line, and each lamp is 120 watts, am I pulling a total of 100 amps? I am not! I am drawing ten amps! Each lamp gets 12V at 10A. 100A doesn't ever flow, anywhere in the circuit. But I'm still consuming 1200W: 120V at 10A, _NOT_ 12V at 100A. If the lamps were in parallel, they would require 100A at 12V. But they're not. That's a load calculation only. An Edison circuit is just a 240 volt circuit with a grounded center-tap. In theory, if loads are balanced, the neutral drops out of the circuit, as the individial loads become a series-parallel voltage divider network. Each load receives 120V at its rated =power=. -- -john wide-open at throttle dot info |
#21
![]()
Posted to alt.home.repair
|
|||
|
|||
![]() "~^Johnny^~" wrote in message ... On Fri, 23 Jun 2006 08:11:40 -0700, ~^Johnny^~ wrote: On Fri, 23 Jun 2006 13:22:41 GMT, (Doug Miller) wrote: 100A at 240V -- and, as noted above, if only 120V loads are in use, the total current draw is (up to) 200A at 120V. The power consumption is equivalent to 200A at 120V, but only 100A are flowing. Kirchoff's Law will not be violated! Currents in series do not add; =voltages= add. It's still 100A at 240V. Better yet, Look at it this way: If I hang ten 12V lamps in series across a 120V line, and each lamp is 120 watts, am I pulling a total of 100 amps? I am not! I am drawing ten amps! Each lamp gets 12V at 10A. 100A doesn't ever flow, anywhere in the circuit. But I'm still consuming 1200W: 120V at 10A, _NOT_ 12V at 100A. If the lamps were in parallel, they would require 100A at 12V. But they're not. That's a load calculation only. An Edison circuit is just a 240 volt circuit with a grounded center-tap. In theory, if loads are balanced, the neutral drops out of the circuit, as the individial loads become a series-parallel voltage divider network. Each load receives 120V at its rated =power=. -- -john wide-open at throttle dot info Assume you have a 200 amp 240 vac breaker with max load, you measure the current on each leg and it is 200amps.This DOES NOT add up to 400 amps. The current you measure on one leg is the SAME current you are measuring on the other leg. Dont confuse same as meaning equal. Same means same as in you read the curent on a conductor and slide the clamp on amp meter down the wire a couple of inches and read the SAME current again. If the currents in each side are not equal then the current in the low side combined with the current in the neutral will be the SAME as the current in the high side.. Kirchoff's law explains this a lot more easily using math than English. |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
High price of 600 amp circuit breakers? | Metalworking | |||
High price of 600 amp circuit breakers? | Metalworking | |||
load testing circuit breakers | Home Ownership | |||
Lamp killing circuit breakers? | Home Repair | |||
Is it a radial or ring circuit? | UK diy |