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#1
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Electricital question
We just bought a cabin. It has a 100 amp service breaker, and a service
panel with 5 20 amp breakers. I know on appliances, all I have to do to find out the amperage is RTFM, but for lights and such, how do I calculate just how much wattage I can put on any breaker circuit? The lighting is inadequate. I will need more. I have a licensed electrician friend who will come and wire everything, so it will be done right and safe. I just need to get an idea how many lights we are talking about so I can do some shopping. I don't want to max everything out and put up a ton of lights. I just want to balance them, and not put so many that I am approaching critical mass. TIA Steve |
#2
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SteveB wrote:
We just bought a cabin. It has a 100 amp service breaker, and a service panel with 5 20 amp breakers. I know on appliances, all I have to do to find out the amperage is RTFM, but for lights and such, how do I calculate just how much wattage I can put on any breaker circuit? The lighting is inadequate. I will need more. I have a licensed electrician friend who will come and wire everything, so it will be done right and safe. I just need to get an idea how many lights we are talking about so I can do some shopping. I don't want to max everything out and put up a ton of lights. I just want to balance them, and not put so many that I am approaching critical mass. TIA Steve Wattage devided by the voltage (120) is amps. Or just add up the wattage. 20 amps x 120v = 2400 watts. Lights are easy since the wattage is written on each bulb. |
#3
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You don't want to exceed 80% of the capacity of the circuit. If you are
using a 15 amp circuit don't exceed 1200 watts on the circuit "SteveB" wrote in message news:j1aKe.84965$4o.53276@fed1read06... We just bought a cabin. It has a 100 amp service breaker, and a service panel with 5 20 amp breakers. I know on appliances, all I have to do to find out the amperage is RTFM, but for lights and such, how do I calculate just how much wattage I can put on any breaker circuit? The lighting is inadequate. I will need more. I have a licensed electrician friend who will come and wire everything, so it will be done right and safe. I just need to get an idea how many lights we are talking about so I can do some shopping. I don't want to max everything out and put up a ton of lights. I just want to balance them, and not put so many that I am approaching critical mass. TIA Steve |
#4
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"SteveB" wrote in message news:j1aKe.84965$4o.53276@fed1read06... We just bought a cabin. It has a 100 amp service breaker, and a service panel with 5 20 amp breakers. I know on appliances, all I have to do to find out the amperage is RTFM, but for lights and such, how do I calculate just how much wattage I can put on any breaker circuit? The lighting is inadequate. I will need more. I have a licensed electrician friend who will come and wire everything, so it will be done right and safe. I just need to get an idea how many lights we are talking about so I can do some shopping. I don't want to max everything out and put up a ton of lights. I just want to balance them, and not put so many that I am approaching critical mass. TIA Steve this is Turtle. In normal lighting circuits it is hard to over load normal lighting wattages to just light up a cabin. Just take 1 -- 20 amp breaker and circuit for lights only and that gives you 20 -- 100 watt light bulbs to light up the cabin. One Circuit is what I thinik you need for all lighting to the cabin. Now really 19.6 -- 100 watt light bulbs to be exact. TURTLE |
#5
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"TURTLE" wrote in message ... "SteveB" wrote in message news:j1aKe.84965$4o.53276@fed1read06... We just bought a cabin. It has a 100 amp service breaker, and a service panel with 5 20 amp breakers. I know on appliances, all I have to do to find out the amperage is RTFM, but for lights and such, how do I calculate just how much wattage I can put on any breaker circuit? The lighting is inadequate. I will need more. I have a licensed electrician friend who will come and wire everything, so it will be done right and safe. I just need to get an idea how many lights we are talking about so I can do some shopping. I don't want to max everything out and put up a ton of lights. I just want to balance them, and not put so many that I am approaching critical mass. TIA Steve this is Turtle. In normal lighting circuits it is hard to over load normal lighting wattages to just light up a cabin. Just take 1 -- 20 amp breaker and circuit for lights only and that gives you 20 -- 100 watt light bulbs to light up the cabin. One Circuit is what I thinik you need for all lighting to the cabin. Now really 19.6 -- 100 watt light bulbs to be exact. TURTLE Not the best idea: Pop the breaker an dthe whole place goes dark. They should be mixed on at least two breakers, and instead of 20 bulbs, that would be 16 bulbs. Over 80% usage will allow normal variations in the grid, cabin, over time, breakers, etc. to begin to heat the breaker, thus degrading it over time and leaving no safety overhead. So with a min two lines you've got 32 bulbs now, lots more than you'll need. Not sure where the 80% figure comes from, nec, ul, mfg, whatever, but it's reality. HTH, Pop |
#6
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"Pop" wrote in message ... "TURTLE" wrote in message ... "SteveB" wrote in message news:j1aKe.84965$4o.53276@fed1read06... We just bought a cabin. It has a 100 amp service breaker, and a service panel with 5 20 amp breakers. I know on appliances, all I have to do to find out the amperage is RTFM, but for lights and such, how do I calculate just how much wattage I can put on any breaker circuit? The lighting is inadequate. I will need more. I have a licensed electrician friend who will come and wire everything, so it will be done right and safe. I just need to get an idea how many lights we are talking about so I can do some shopping. I don't want to max everything out and put up a ton of lights. I just want to balance them, and not put so many that I am approaching critical mass. TIA Steve this is Turtle. In normal lighting circuits it is hard to over load normal lighting wattages to just light up a cabin. Just take 1 -- 20 amp breaker and circuit for lights only and that gives you 20 -- 100 watt light bulbs to light up the cabin. One Circuit is what I thinik you need for all lighting to the cabin. Now really 19.6 -- 100 watt light bulbs to be exact. TURTLE Not the best idea: Pop the breaker an dthe whole place goes dark. They should be mixed on at least two breakers, and instead of 20 bulbs, that would be 16 bulbs. Over 80% usage will allow normal variations in the grid, cabin, over time, breakers, etc. to begin to heat the breaker, thus degrading it over time and leaving no safety overhead. So with a min two lines you've got 32 bulbs now, lots more than you'll need. Not sure where the 80% figure comes from, nec, ul, mfg, whatever, but it's reality. HTH, Pop This is Turtle. He was asking what number of breakers would be need for lighting for the cabin. I said 19.6 for a 20 amp breaker will support the 19.6 light bulbs and will be the 80% of the amperate of the 20 amp breaker. He can split up the bulb in all area , but all lighting would not need more than 1 --- 20 amp circuit, no matter how he run it. With two circiuts of 20 amps he could put not 32 -- 100 watt light bulbs but 39.2 --- 100 light bulbs. This would still be compliant of the 80% rule of the two 20 amp breaker circuits. Now the degrading of the breaker to trip at lower amperages is just a effect you have to deal with 20 to 30 years from now and just wait 20 years or so and think about them. TURTLE |
#7
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Dear Steve, the formula is
volts times amps = watts So, you can say that the 110 volt circuit, times 20 amps = 2200 watts. Hint: Try using flourescent, or compact fluorescent bulbs. They use a lot less power. -- Christopher A. Young Learn more about Jesus www.lds.org www.mormons.com "SteveB" wrote in message news:j1aKe.84965$4o.53276@fed1read06... We just bought a cabin. It has a 100 amp service breaker, and a service panel with 5 20 amp breakers. I know on appliances, all I have to do to find out the amperage is RTFM, but for lights and such, how do I calculate just how much wattage I can put on any breaker circuit? The lighting is inadequate. I will need more. I have a licensed electrician friend who will come and wire everything, so it will be done right and safe. I just need to get an idea how many lights we are talking about so I can do some shopping. I don't want to max everything out and put up a ton of lights. I just want to balance them, and not put so many that I am approaching critical mass. TIA Steve |
#8
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Stormin Mormon wrote:
volts times amps = watts So, you can say that the 110 volt circuit, times 20 amps = 2200 watts. Hint: Try using flourescent, or compact fluorescent bulbs. They use a lot less power. At a lower power factor... watts = 0.4 x volts x amps, for some undercounter fluorescents. Nick |
#9
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#10
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George E. Cawthon wrote:
...watts = 0.4 x volts x amps, for some undercounter fluorescents. Do fluorescent lights have a power factor? Sure... 0.4 in the case above. But, that said, if the undercounter light fixture say 15W, then that is how much is used regardless of power factor Yes. and w=va still applies. or am I wrong... You am wrong. W = PFxVxA. Nick |
#11
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#12
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In article ,
wrote: George E. Cawthon wrote: ...watts = 0.4 x volts x amps, for some undercounter fluorescents. Do fluorescent lights have a power factor? Sure... 0.4 in the case above. But, that said, if the undercounter light fixture say 15W, then that is how much is used regardless of power factor Yes. and w=va still applies. or am I wrong... You am wrong. W = PFxVxA. Nick QUESTION about this "power factor": (it has been *so long* since I understood any of that stuff, that I've forgotten all but a few words describing it.) With DC, the pf is 1.0? With AC, I'm not sure what it is. Of course there's the "rms" stuff, trying to get an average value of a sine-wave. The pf, I recall from *ages* (decades) ago, had something to do with the voltage and current "waves" getting out of sync with each other, due to a coil or a capacitor (one shifting in one direction, one in the other). I recall something about having to use trig to get the pf, maybe it was the sine or cosine of the degrees of lead or lag? If so, then since those functions range between plus and minus one, then maybe the pf I dimly recall is the reciprocal of yours? Anyway -- here's my question: How do you get a substantial pf for a fluorscent (sp?) light? (Huge electric motor, I understand how.) And a pf for an incandescent light, that would involve no phase shift at all? Obvously, I could use some mental fill-in! Thanks! David |
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