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#1
Posted to sci.electronics.basics,alt.electronics,alt.electronics.analog
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Is this what they called it a Hybrid Capacitor?
6 capacitors 60 farad @ 2.7V EACH in serie, then they parallel with a 0.5
farad 16V. I don't see how you can get 60 farad out of this circuit. The maximum you can get from this circuit is 10.5 Farad. How can they call this a 60 Farad? No wonder why I am not getting the power it's supposed to hold. I bought this funky Lanzar600 hybrid capacitor, and my voltage meter shows its voltage drops fast!! Because it looks like one of the 6 capacitors felt off the PCB, and the 0.5farad hardware doesn't hold it tight niether, so I think I'm getting 10 farad if I'm not wrong or less. I thought the formula is supposed to be = 1/((1/C1)+(1/C2)+(1/C3)+(1/C4)+(1/C5)+(1/C6)) = ResultA in parallel with C7(0.5farad) but C7 is not connected, I should end up with 10 farad? or 0.5 farad? Sounds like a fraud product to me unless if I'm mistaken. I need you experts to tell me if my thinking is wrong. Thanks. |
#2
Posted to sci.electronics.basics,alt.electronics,alt.electronics.analog
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Is this what they called it a Hybrid Capacitor?
On Wed, 17 Jun 2009 11:39:52 -0700, "Richard"
wrote: 6 capacitors 60 farad @ 2.7V EACH in serie, then they parallel with a 0.5 farad 16V. I don't see how you can get 60 farad out of this circuit. The maximum you can get from this circuit is 10.5 Farad. How can they call this a 60 Farad? No wonder why I am not getting the power it's supposed to hold. I bought this funky Lanzar600 hybrid capacitor, and my voltage meter shows its voltage drops fast!! Because it looks like one of the 6 capacitors felt off the PCB, and the 0.5farad hardware doesn't hold it tight niether, so I think I'm getting 10 farad if I'm not wrong or less. I thought the formula is supposed to be = 1/((1/C1)+(1/C2)+(1/C3)+(1/C4)+(1/C5)+(1/C6)) = ResultA in parallel with C7(0.5farad) but C7 is not connected, I should end up with 10 farad? or 0.5 farad? Sounds like a fraud product to me unless if I'm mistaken. I need you experts to tell me if my thinking is wrong. --- If this is what you're talking about: (View in Courier) +-[C1]-[C2]-[C3]-[C4]-[C5]-[C6]-+ | | +-------------[C7]--------------+ | | A B then there's 10.5F from A to B. Also, if the capacitances of C1 - C6 aren't equal (which they won't be) then the voltage across AB wont divide equally and you could easily get 2.7V across one or more of them. Sounds to me like you've been had. JF |
#3
Posted to sci.electronics.basics,alt.electronics,alt.electronics.analog
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Is this what they called it a Hybrid Capacitor?
"John Fields" wrote in message ... On Wed, 17 Jun 2009 11:39:52 -0700, "Richard" wrote: 6 capacitors 60 farad @ 2.7V EACH in serie, then they parallel with a 0.5 farad 16V. I don't see how you can get 60 farad out of this circuit. The maximum you can get from this circuit is 10.5 Farad. How can they call this a 60 Farad? No wonder why I am not getting the power it's supposed to hold. I bought this funky Lanzar600 hybrid capacitor, and my voltage meter shows its voltage drops fast!! Because it looks like one of the 6 capacitors felt off the PCB, and the 0.5farad hardware doesn't hold it tight niether, so I think I'm getting 10 farad if I'm not wrong or less. I thought the formula is supposed to be = 1/((1/C1)+(1/C2)+(1/C3)+(1/C4)+(1/C5)+(1/C6)) = ResultA in parallel with C7(0.5farad) but C7 is not connected, I should end up with 10 farad? or 0.5 farad? Sounds like a fraud product to me unless if I'm mistaken. I need you experts to tell me if my thinking is wrong. --- If this is what you're talking about: (View in Courier) +-[C1]-[C2]-[C3]-[C4]-[C5]-[C6]-+ | | +-------------[C7]--------------+ | | A B then there's 10.5F from A to B. Also, if the capacitances of C1 - C6 aren't equal (which they won't be) then the voltage across AB wont divide equally and you could easily get 2.7V across one or more of them. Sounds to me like you've been had. JF Thanks, yes so true, From AMAZON - GOOLGOLSHOP -LANZAR600 Fake 60 farad capacitor. None of them wanted to give me refund or warranty, just had it in less than 3 days, what a fraud of America! You don't have to go to Nigeria to see this ****. |
#4
Posted to sci.electronics.basics,alt.electronics,alt.electronics.analog
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Is this what they called it a Hybrid Capacitor?
On Thu, 18 Jun 2009 17:46:06 -0700, "Richard"
wrote: "John Fields" wrote in message .. . On Wed, 17 Jun 2009 11:39:52 -0700, "Richard" wrote: 6 capacitors 60 farad @ 2.7V EACH in serie, then they parallel with a 0.5 farad 16V. I don't see how you can get 60 farad out of this circuit. The maximum you can get from this circuit is 10.5 Farad. How can they call this a 60 Farad? No wonder why I am not getting the power it's supposed to hold. I bought this funky Lanzar600 hybrid capacitor, and my voltage meter shows its voltage drops fast!! Because it looks like one of the 6 capacitors felt off the PCB, and the 0.5farad hardware doesn't hold it tight niether, so I think I'm getting 10 farad if I'm not wrong or less. I thought the formula is supposed to be = 1/((1/C1)+(1/C2)+(1/C3)+(1/C4)+(1/C5)+(1/C6)) = ResultA in parallel with C7(0.5farad) but C7 is not connected, I should end up with 10 farad? or 0.5 farad? Sounds like a fraud product to me unless if I'm mistaken. I need you experts to tell me if my thinking is wrong. --- If this is what you're talking about: (View in Courier) +-[C1]-[C2]-[C3]-[C4]-[C5]-[C6]-+ | | +-------------[C7]--------------+ | | A B then there's 10.5F from A to B. Also, if the capacitances of C1 - C6 aren't equal (which they won't be) then the voltage across AB wont divide equally and you could easily get 2.7V across one or more of them. Sounds to me like you've been had. JF Thanks, yes so true, From AMAZON - GOOLGOLSHOP -LANZAR600 Fake 60 farad capacitor. None of them wanted to give me refund or warranty, just had it in less than 3 days, what a fraud of America! --- Sorry about that... Maybe if you contacted Lanzar directly you could get some satisfaction? By Mail: 1600 63rd Street Brooklyn N.Y. 11204 By Phone: 1-800-444-5671 718-535-1800 By Fax: 718-236-2400 By Email For sales Questions Email For support questions email For Website questions email --- You don't have to go to Nigeria to see this ****. --- Yup. JF |
#5
Posted to sci.electronics.basics,alt.electronics,alt.electronics.analog
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Is this what they called it a Hybrid Capacitor?
Dont listen to words.
Get a cap meter and measure it yourself. Then you will know for sure. But please tell me this ... If you put two capacitors in series, Then do you get 180deg of phase shift across them both or do you simply get 90 degrees like in a single capacitor ??? I would like to build a filter but can not find an exact value 1/2 of what I got so I want to put two in series but since this filter relies on phase shift will putting two in series to get the right value mess up the needed phase shift of 90 degrees. Regards, ELI the ICE Man (p.s.)Voltage leads current by 90 deg in an inductor. Current leads Voltage in a capacitor by 100 grads. "Richard" wrote in message net... 6 capacitors 60 farad @ 2.7V EACH in serie, then they parallel with a 0.5 farad 16V. I don't see how you can get 60 farad out of this circuit. The maximum you can get from this circuit is 10.5 Farad. How can they call this a 60 Farad? No wonder why I am not getting the power it's supposed to hold. I bought this funky Lanzar600 hybrid capacitor, and my voltage meter shows its voltage drops fast!! Because it looks like one of the 6 capacitors felt off the PCB, and the 0.5farad hardware doesn't hold it tight niether, so I think I'm getting 10 farad if I'm not wrong or less. I thought the formula is supposed to be = 1/((1/C1)+(1/C2)+(1/C3)+(1/C4)+(1/C5)+(1/C6)) = ResultA in parallel with C7(0.5farad) but C7 is not connected, I should end up with 10 farad? or 0.5 farad? Sounds like a fraud product to me unless if I'm mistaken. I need you experts to tell me if my thinking is wrong. Thanks. |
#6
Posted to sci.electronics.basics,alt.electronics,alt.electronics.analog
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Is this what they called it a Hybrid Capacitor?
Geoffrey wrote:
Dont listen to words. Get a cap meter and measure it yourself. Then you will know for sure. But please tell me this ... If you put two capacitors in series, Then do you get 180deg of phase shift across them both or do you simply get 90 degrees like in a single capacitor ??? I would like to build a filter but can not find an exact value 1/2 of what I got so I want to put two in series but since this filter relies on phase shift will putting two in series to get the right value mess up the needed phase shift of 90 degrees. Regards, ELI the ICE Man (p.s.)Voltage leads current by 90 deg in an inductor. Current leads Voltage in a capacitor by 100 grads. When you put two capacitors in series, the total circuit capacitance can be calculated by:- 1/CT = 1/C1 + 1/C2 i.e. invert the value of each capacitor, add these values then invert again. Effectively, by putting the two capacitors in series, you are increasing the distance between the capacitors plates. Phase shifting will still be the same, as phase shift is not due to the capacitor alone, but in the capacitor and the circuit resistance. Daniel |
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