I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other

Harry K

c
"Harry K" wrote in message
om...
I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other

Harry K

The answer is "A". 100 mph, because

E1=E2 when two cars hit head on which means each car would absorb 50 kmh of
kinetic energy BUT when a car hits a wall
E1 is divided in 1/2, 1/2 going to the wall and 1/2 to the car. It's all in
the wording of the question.


"Harry K" wrote in message
om...
I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other

Harry K

On Thu, 25 Nov 2004 11:14:19 -0500, "HotRod"
wrote:

The answer is "A". 100 mph, because

E1=E2 when two cars hit head on which means each car would absorb 50 kmh of
kinetic energy BUT when a car hits a wall
E1 is divided in 1/2, 1/2 going to the wall and 1/2 to the car. It's all in
the wording of the question.


"Harry K" wrote in message
. com...
I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other

Harry K

D. Who gives a flying **** .......LOL

On 25 Nov 2004 08:00:27 -0800, (Harry K)
wrote:

I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other

Harry K

50mph because ...........................................

2 cars of equal mass that crash head on at 50 mph
can also be looked at as one car going 100mph crashing
into a stationary car of the same mass.

When that happens the force of the collision at 100mph is
cut in two and split equally between two cars.

Let's see...

The driver in the car is going 50 miles per hour, hits the "other car",
then suddenly stops going 50 miles per hour.

The driver in the car is going 50 miles per hour, hits the "solid object",
then suddenly stops going 50 miles per hour.

In both cases, the driver is slammed into the seatbelt/airbag/dashboard at
50 miles per hour. Answer b!




"Harry K" wrote in message
I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other

Harry K

By the way, were the drivers OK after this crash? I hope they were wearing
their seatbelts...

wrote in message
...
On 25 Nov 2004 08:00:27 -0800, (Harry K)
wrote:

I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other

Harry K

50mph because ...........................................

2 cars of equal mass that crash head on at 50 mph
can also be looked at as one car going 100mph crashing
into a stationary car of the same mass.

When that happens the force of the collision at 100mph is
cut in two and split equally between two cars.

because of the theory of relativity, the colision will be slightly less than
100 mph.

randy

wrote in message
...
On 25 Nov 2004 08:00:27 -0800, (Harry K)
wrote:

I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other

Harry K

50mph because ...........................................

2 cars of equal mass that crash head on at 50 mph
can also be looked at as one car going 100mph crashing
into a stationary car of the same mass.

When that happens the force of the collision at 100mph is
cut in two and split equally between two cars.

ps, if you hit a wall at 100mph, the wall absorbs some shock. but the
effect is the same.

randy

Harry K wrote:
I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other

Harry K


B. yawn

Bob

another answer, neither driver will feel a thing...

randy

"Harry K" wrote in message
om...
I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other

Harry K

Harry K wrote:
I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other

Harry K

The correct answer is C and B

If both cars, and drivers were mirror images of each other and hit
perfectly head on, it will be B, but since it is highly unlikely they will
be perfectly matched, it will be C as the force will be slight unequal as
some parts will not collide etc. But it will be close to B.


--
Joseph E. Meehan

26 + 6 = 1 It's Irish Math

You *are* bored.

I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other


Hmmm...is this a trick question? It's been a while....

Look at billard balls. When the cue ball strikes a stationary ball
head-on (ignoring spin), the stationary ball beings moving and the cue
ball stops dead.
Let's say the cue ball was travelling at 50mph. Effectively it has
hit a 'brick wall' at 50mph since it stopped dead. So if the second
ball was travelling in the opposite direction at the same speed, the
cue ball would not just stop, but 'bounce' and travel at 50mph in the
oppposite direction. Effectively hitting a wall at 100mph.

Correct so far? Maybe, maybe not. At this point I don't care.

Now, that's all well and good but cars are a different story.
Collisions are not perfectly elastic due to crumple zones and other
losses. Assuming both cars 'stick' together after the collision, the
wreck will remain stationary at the point of impact. In this case,
each driver will feel the effect of hitting a wall at 50mph (i.e. each
goes from 50mph to 0mph).

If the cars 'bounce' off each other, then the impact will be somewhere
between 50 and 100mph.

Of course, dont forget about seat belts and air bags which may save
their lives....if that gas leak didn't engulf the vehicles in flames
first.

Do you actually have an answer to this 'problem'?

Borrall Wonnell wrote:
You *are* bored.

I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other


Hmmm...is this a trick question? It's been a while....

Look at billard balls. When the cue ball strikes a stationary ball
head-on (ignoring spin), the stationary ball beings moving and the cue
ball stops dead.
Let's say the cue ball was travelling at 50mph. Effectively it has
hit a 'brick wall' at 50mph since it stopped dead.

Not really. The "brick wall" or more correctly an immovable object does
not absorb any of the energy, it moves not at all. The stationary ball
absorbs all the forward energy (ignoring losses) and uses this energy to
move with. If the cue ball hits an immovable object it must absorb the
energy itself, either bouncing off or flexing or breaking up.

So if the second
ball was travelling in the opposite direction at the same speed, the
cue ball would not just stop, but 'bounce' and travel at 50mph in the
oppposite direction. Effectively hitting a wall at 100mph.

Correct so far? Maybe, maybe not. At this point I don't care.

Now, that's all well and good but cars are a different story.
Collisions are not perfectly elastic due to crumple zones and other
losses. Assuming both cars 'stick' together after the collision, the
wreck will remain stationary at the point of impact. In this case,
each driver will feel the effect of hitting a wall at 50mph (i.e. each
goes from 50mph to 0mph).

If the cars 'bounce' off each other, then the impact will be somewhere
between 50 and 100mph.

Of course, dont forget about seat belts and air bags which may save
their lives....if that gas leak didn't engulf the vehicles in flames
first.

Do you actually have an answer to this 'problem'?

--
Joseph E. Meehan

26 + 6 = 1 It's Irish Math

Damn, and I just packed up my old college physic books for storage until my
office gets renovation completed! I would have loved to look that one up, I
can not remember most of my physics stuff, too long ago.

MC


"Joseph Meehan" wrote in message
...
Borrall Wonnell wrote:
You *are* bored.

I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other


Hmmm...is this a trick question? It's been a while....

Look at billard balls. When the cue ball strikes a stationary ball
head-on (ignoring spin), the stationary ball beings moving and the cue
ball stops dead.
Let's say the cue ball was travelling at 50mph. Effectively it has
hit a 'brick wall' at 50mph since it stopped dead.

Not really. The "brick wall" or more correctly an immovable object
does
not absorb any of the energy, it moves not at all. The stationary ball
absorbs all the forward energy (ignoring losses) and uses this energy to
move with. If the cue ball hits an immovable object it must absorb the
energy itself, either bouncing off or flexing or breaking up.

So if the second
ball was travelling in the opposite direction at the same speed, the
cue ball would not just stop, but 'bounce' and travel at 50mph in the
oppposite direction. Effectively hitting a wall at 100mph.

Correct so far? Maybe, maybe not. At this point I don't care.

Now, that's all well and good but cars are a different story.
Collisions are not perfectly elastic due to crumple zones and other
losses. Assuming both cars 'stick' together after the collision, the
wreck will remain stationary at the point of impact. In this case,
each driver will feel the effect of hitting a wall at 50mph (i.e. each
goes from 50mph to 0mph).

If the cars 'bounce' off each other, then the impact will be somewhere
between 50 and 100mph.

Of course, dont forget about seat belts and air bags which may save
their lives....if that gas leak didn't engulf the vehicles in flames
first.

Do you actually have an answer to this 'problem'?

--
Joseph E. Meehan

26 + 6 = 1 It's Irish Math

C Both cars absorb impact. And at less than 50mph in concrete,
the cars crunch-absorb the energy, concrete will not . each car is like
an acordion, compressing, slowing impact and force as they de-acelerate.

C but there is velocity of the second car.. so plus 50+ ?

Most of this energy is consumed in wadding up metal. That is the current design
criteria.

(Borrall Wonnell) wrote in message . com...
You *are* bored.

I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other


Hmmm...is this a trick question? It's been a while....

Look at billard balls. When the cue ball strikes a stationary ball
head-on (ignoring spin), the stationary ball beings moving and the cue
ball stops dead.
Let's say the cue ball was travelling at 50mph. Effectively it has
hit a 'brick wall' at 50mph since it stopped dead. So if the second
ball was travelling in the opposite direction at the same speed, the
cue ball would not just stop, but 'bounce' and travel at 50mph in the
oppposite direction. Effectively hitting a wall at 100mph.

Correct so far? Maybe, maybe not. At this point I don't care.

Now, that's all well and good but cars are a different story.
Collisions are not perfectly elastic due to crumple zones and other
losses. Assuming both cars 'stick' together after the collision, the
wreck will remain stationary at the point of impact. In this case,
each driver will feel the effect of hitting a wall at 50mph (i.e. each
goes from 50mph to 0mph).

If the cars 'bounce' off each other, then the impact will be somewhere
between 50 and 100mph.

Of course, dont forget about seat belts and air bags which may save
their lives....if that gas leak didn't engulf the vehicles in flames
first.

Do you actually have an answer to this 'problem'?

Yes, it is 50mph give or take allowing for crumple zones etc. I first
saw this on in sophmore physics class in HS back in 1951. Quite a
discussion and got into involved math etc but it all comes down to a
simple mind excercise.

From what speed did each driver stop?? 50mph.

Harry K

"Harry K" wrote in message
om...
(Borrall Wonnell) wrote in message
. com...
You *are* bored.

I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other


Hmmm...is this a trick question? It's been a while....

Look at billard balls. When the cue ball strikes a stationary ball
head-on (ignoring spin), the stationary ball beings moving and the cue
ball stops dead.
Let's say the cue ball was travelling at 50mph. Effectively it has
hit a 'brick wall' at 50mph since it stopped dead. So if the second
ball was travelling in the opposite direction at the same speed, the
cue ball would not just stop, but 'bounce' and travel at 50mph in the
oppposite direction. Effectively hitting a wall at 100mph.

Correct so far? Maybe, maybe not. At this point I don't care.

Now, that's all well and good but cars are a different story.
Collisions are not perfectly elastic due to crumple zones and other
losses. Assuming both cars 'stick' together after the collision, the
wreck will remain stationary at the point of impact. In this case,
each driver will feel the effect of hitting a wall at 50mph (i.e. each
goes from 50mph to 0mph).

If the cars 'bounce' off each other, then the impact will be somewhere
between 50 and 100mph.

Of course, dont forget about seat belts and air bags which may save
their lives....if that gas leak didn't engulf the vehicles in flames
first.

Do you actually have an answer to this 'problem'?

Yes, it is 50mph give or take allowing for crumple zones etc. I first
saw this on in sophmore physics class in HS back in 1951. Quite a
discussion and got into involved math etc but it all comes down to a
simple mind excercise.

From what speed did each driver stop?? 50mph.

so the impact is the same whether you hit a wall, a 50mph car, or a
100000mph car.

i dont buy it.

randy

"xrongor" wrote in message
...

"Harry K" wrote in message
om...
(Borrall Wonnell) wrote in message
. com...
You *are* bored.

I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other


Hmmm...is this a trick question? It's been a while....

Look at billard balls. When the cue ball strikes a stationary ball
head-on (ignoring spin), the stationary ball beings moving and the cue
ball stops dead.
Let's say the cue ball was travelling at 50mph. Effectively it has
hit a 'brick wall' at 50mph since it stopped dead. So if the second
ball was travelling in the opposite direction at the same speed, the
cue ball would not just stop, but 'bounce' and travel at 50mph in the
oppposite direction. Effectively hitting a wall at 100mph.

Correct so far? Maybe, maybe not. At this point I don't care.

Now, that's all well and good but cars are a different story.
Collisions are not perfectly elastic due to crumple zones and other
losses. Assuming both cars 'stick' together after the collision, the
wreck will remain stationary at the point of impact. In this case,
each driver will feel the effect of hitting a wall at 50mph (i.e. each
goes from 50mph to 0mph).

If the cars 'bounce' off each other, then the impact will be somewhere
between 50 and 100mph.

Of course, dont forget about seat belts and air bags which may save
their lives....if that gas leak didn't engulf the vehicles in flames
first.

Do you actually have an answer to this 'problem'?

Yes, it is 50mph give or take allowing for crumple zones etc. I first
saw this on in sophmore physics class in HS back in 1951. Quite a
discussion and got into involved math etc but it all comes down to a
simple mind excercise.

From what speed did each driver stop?? 50mph.

so the impact is the same whether you hit a wall, a 50mph car, or a
100000mph car.

i dont buy it.

randy

although i may be overthinking it. seems inertia comes into play
somewhere..

On 25 Nov 2004 08:00:27 -0800, (Harry K)
wrote:

I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other

Harry K

I suggest you consult this site: http://britneyspears.ac/lasers.htm

"xrongor" wrote in message ...
"xrongor" wrote in message
...

"Harry K" wrote in message
om...
(Borrall Wonnell) wrote in message
. com...
You *are* bored.

I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other


Hmmm...is this a trick question? It's been a while....

Look at billard balls. When the cue ball strikes a stationary ball
head-on (ignoring spin), the stationary ball beings moving and the cue
ball stops dead.
Let's say the cue ball was travelling at 50mph. Effectively it has
hit a 'brick wall' at 50mph since it stopped dead. So if the second
ball was travelling in the opposite direction at the same speed, the
cue ball would not just stop, but 'bounce' and travel at 50mph in the
oppposite direction. Effectively hitting a wall at 100mph.

Correct so far? Maybe, maybe not. At this point I don't care.

Now, that's all well and good but cars are a different story.
Collisions are not perfectly elastic due to crumple zones and other
losses. Assuming both cars 'stick' together after the collision, the
wreck will remain stationary at the point of impact. In this case,
each driver will feel the effect of hitting a wall at 50mph (i.e. each
goes from 50mph to 0mph).

If the cars 'bounce' off each other, then the impact will be somewhere
between 50 and 100mph.

Of course, dont forget about seat belts and air bags which may save
their lives....if that gas leak didn't engulf the vehicles in flames
first.

Do you actually have an answer to this 'problem'?

Yes, it is 50mph give or take allowing for crumple zones etc. I first
saw this on in sophmore physics class in HS back in 1951. Quite a
discussion and got into involved math etc but it all comes down to a
simple mind excercise.

From what speed did each driver stop?? 50mph.

so the impact is the same whether you hit a wall, a 50mph car, or a
100000mph car.

i dont buy it.

randy

although i may be overthinking it. seems inertia comes into play
somewhere..

Yes it does but each vehicle has an inertia of mass times speed (1 car
x 50mph for simplicity). The inertia is expended during the crash and
each one expends its own inertia, i.e., 1 car x 50 mph, resulting in 0
mph and 0 inertia.

Harry K

"xrongor" wrote in message ...
"Harry K" wrote in message
om...
(Borrall Wonnell) wrote in message
. com...
You *are* bored.

I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other


Hmmm...is this a trick question? It's been a while....

Look at billard balls. When the cue ball strikes a stationary ball
head-on (ignoring spin), the stationary ball beings moving and the cue
ball stops dead.
Let's say the cue ball was travelling at 50mph. Effectively it has
hit a 'brick wall' at 50mph since it stopped dead. So if the second
ball was travelling in the opposite direction at the same speed, the
cue ball would not just stop, but 'bounce' and travel at 50mph in the
oppposite direction. Effectively hitting a wall at 100mph.

Correct so far? Maybe, maybe not. At this point I don't care.

Now, that's all well and good but cars are a different story.
Collisions are not perfectly elastic due to crumple zones and other
losses. Assuming both cars 'stick' together after the collision, the
wreck will remain stationary at the point of impact. In this case,
each driver will feel the effect of hitting a wall at 50mph (i.e. each
goes from 50mph to 0mph).

If the cars 'bounce' off each other, then the impact will be somewhere
between 50 and 100mph.

Of course, dont forget about seat belts and air bags which may save
their lives....if that gas leak didn't engulf the vehicles in flames
first.

Do you actually have an answer to this 'problem'?

Yes, it is 50mph give or take allowing for crumple zones etc. I first
saw this on in sophmore physics class in HS back in 1951. Quite a
discussion and got into involved math etc but it all comes down to a
simple mind excercise.

From what speed did each driver stop?? 50mph.

so the impact is the same whether you hit a wall, a 50mph car, or a
100000mph car.

i dont buy it.

randy

Almost right but not if you are doing 50mph and the other car is doing
100000 mph. in that case you would experience an impact of almost
infinity. The problem is stated cars of equal mass at equal speed.
It is a common belief that the speeds add, i.e, the impact would be
100 mph, they don't.

Harry K

"Harry K" wrote in message
om...
"xrongor" wrote in message
...
"xrongor" wrote in message
...

"Harry K" wrote in message
om...
(Borrall Wonnell) wrote in message
. com...
You *are* bored.

I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will
feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other


Hmmm...is this a trick question? It's been a while....

Look at billard balls. When the cue ball strikes a stationary ball
head-on (ignoring spin), the stationary ball beings moving and the
cue
ball stops dead.
Let's say the cue ball was travelling at 50mph. Effectively it has
hit a 'brick wall' at 50mph since it stopped dead. So if the second
ball was travelling in the opposite direction at the same speed, the
cue ball would not just stop, but 'bounce' and travel at 50mph in the
oppposite direction. Effectively hitting a wall at 100mph.

Correct so far? Maybe, maybe not. At this point I don't care.

Now, that's all well and good but cars are a different story.
Collisions are not perfectly elastic due to crumple zones and other
losses. Assuming both cars 'stick' together after the collision, the
wreck will remain stationary at the point of impact. In this case,
each driver will feel the effect of hitting a wall at 50mph (i.e.
each
goes from 50mph to 0mph).

If the cars 'bounce' off each other, then the impact will be
somewhere
between 50 and 100mph.

Of course, dont forget about seat belts and air bags which may save
their lives....if that gas leak didn't engulf the vehicles in flames
first.

Do you actually have an answer to this 'problem'?

Yes, it is 50mph give or take allowing for crumple zones etc. I first
saw this on in sophmore physics class in HS back in 1951. Quite a
discussion and got into involved math etc but it all comes down to a
simple mind excercise.

From what speed did each driver stop?? 50mph.

so the impact is the same whether you hit a wall, a 50mph car, or a
100000mph car.

i dont buy it.

randy

although i may be overthinking it. seems inertia comes into play
somewhere..

Yes it does but each vehicle has an inertia of mass times speed (1 car
x 50mph for simplicity). The inertia is expended during the crash and
each one expends its own inertia, i.e., 1 car x 50 mph, resulting in 0
mph and 0 inertia.

Harry K

i pondered this for a while and the only way it makes sense to me is to
assume at the point of impact you no longer have two objects, but one object
with twice the mass. which is probably correct...

randy

What if they hit at an angle of 90 degrees?

On 25 Nov 2004 08:00:27 -0800, (Harry K)
wrote:

I'm bored so will put forward this one to see what happens:

2 cars of equal mass crash head on at 50 mph. Both drivers will feel
an impact equal to crashing into a solid object at:
a. 100 mph
b. 50 mph
c. Other


hence the term "head on" would not apply.




Remove "YOURPANTIES" to reply

MUADIB®

http://www.angelfire.com/retro/sster...IN%20PAGE.html

one small step for man,.....
One giant leap for attorneys.

The answer is "A". 100 mph, because

E1=E2 when two cars hit head on which means each car would absorb 50 kmh of
kinetic energy BUT when a car hits a wall
E1 is divided in 1/2, 1/2 going to the wall and 1/2 to the car. It's all in
the wording of the question

WHO CARES!!


"HotRod" wrote in message
...
The answer is "A". 100 mph, because

E1=E2 when two cars hit head on which means each car would absorb 50 kmh
of
kinetic energy BUT when a car hits a wall
E1 is divided in 1/2, 1/2 going to the wall and 1/2 to the car. It's all
in
the wording of the question

"HotRod" wrote in message
...
The answer is "A". 100 mph, because

E1=E2 when two cars hit head on which means each car would absorb 50 kmh
of
kinetic energy BUT when a car hits a wall
E1 is divided in 1/2, 1/2 going to the wall and 1/2 to the car. It's all
in
the wording of the question

i'm too lazy to search for the OP.
but i have to add, are the 2 vehicles identical with 0 wind on level ground?
or are you talking about 2 objects in a vacuum colliding at equal mass and
velocity?

did you know that a vehicle without a built in cup holder has a higher
occupant survival rate than vehicles with multiple built-in cup holders?

-a|ex

"Bob" wrote in message news:ZsHqd.584312$mD.467526@attbi_s02...
WHO CARES!!


"HotRod" wrote in message
...
The answer is "A". 100 mph, because

E1=E2 when two cars hit head on which means each car would absorb 50 kmh
of
kinetic energy BUT when a car hits a wall
E1 is divided in 1/2, 1/2 going to the wall and 1/2 to the car. It's all
in
the wording of the question



After all this, I certainly don't

Harry K