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Electronics Repair (sci.electronics.repair) Discussion of repairing electronic equipment. Topics include requests for assistance, where to obtain servicing information and parts, techniques for diagnosis and repair, and annecdotes about success, failures and problems. |
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Folowing on from thread lower down. I just tried this to see what sort of
results you get simulating such a multi-secondary transformer using a known good one but not using the primary. I used a variac supply near the bottom of its range at 18volts and a 25 ohm, 20W dropper to feed 50Hz (UK)ac into a secondary. Assuming you have a reasonable idea of the voltage of one 'unknown' secondary. The transformer I used was 240V (UK) with marked 2 separate secondaries of 6.3V, 0.6A and a 150-0-150 at 25mA. With 3.43V ac on one '6.3V' secondary there was open circuit 3.40 on the other isolated '6.3' and 161.4V end-to-end on the '150-0-150' and incidently 116.4 on the primary. Then loading with different resistors 100K, 161.4 drops to 159.1 5.8K on 161.4 drops to 55.8, 3.43 input drops to 1.64 swapping to 5.8K on 3.4 , no change 1K on 161.4 to 12.1 and 3.43 to 0.771 swap to 1K on 3.4 , drops to 3.39 270 ohm , 161.4 to 3.34V 270 on 3.40, drops to 3.37 56 ohm on 161.4 to .704 and 3.43 to .54V 56 on 3.4 , drops to 3.28 and 3.43 to 3.42 8.2 ohm on 3.4 , drops to 2.55 and 3.4 drops to 2.99V The size of the transformer gives an idea of the overal sum of Volt x amps as well as repeating the above with load resistors on each secondary should give an idea of voltages and currents per secondary, without powering the primary. Anyone care to make an empirical formula from the above loading data and give an idea of its applicability to the general case ? -- Diverse Devices, Southampton, England electronic hints and repair briefs , schematics/manuals list on http://home.graffiti.net/diverse:graffiti.net/ |
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