I have a simple trig problem that I need help with. And I can't remember
high school math right now. Here is the problem. Hopefully one of you will
have the info/knowledge handy.

I have a simple cabinet that has a 12 degree, low pitched top. The top can
not exceed the back or front. What would the length of the top be for each
horizontal foot? Put another way, for each foot horizontally, how long is
the angled top? I don't have a depth yet, but can calculate the top piece
easily enough once I get the above info.

Thanks,
Lee

My memory of trig says that the top is the hypotenuse of the right
triangle, the horizontal measurement is the adjacent side. cos angle
= adjacent side /hypotenuse. Hypotenuse =adjacent side/cos
12degrees.

My calculator says that for each 12" distance on the horizontal, the
top sloped at 12 degrees will be 12.2681 inches long.

Somebody check me!!!

Old guy.

On Nov 29, 10:11*pm, "Lee Michaels"
wrote:
I have a simple trig problem that I need help with. And I can't remember
high school math right now. *Here is the problem. *Hopefully one of you will
have the info/knowledge handy.

I have a simple cabinet that has a 12 degree, low pitched top. The top can
not exceed the back or front. What would the length of the top be for each
horizontal foot? *Put another way, for each foot horizontally, how long is
the angled top? *I don't have a depth yet, but can calculate the top piece
easily enough once I get the above info.

Thanks,
Lee

"Old Guy" wrote in message
...
My memory of trig says that the top is the hypotenuse of the right
triangle, the horizontal measurement is the adjacent side. cos angle
= adjacent side /hypotenuse. Hypotenuse =adjacent side/cos
12degrees.

My calculator says that for each 12" distance on the horizontal, the
top sloped at 12 degrees will be 12.2681 inches long.

Somebody check me
_________________________________________________


You're right

"CW" wrote in message
m...

"Old Guy" wrote in message
...
My memory of trig says that the top is the hypotenuse of the right
triangle, the horizontal measurement is the adjacent side. cos angle
= adjacent side /hypotenuse. Hypotenuse =adjacent side/cos
12degrees.

My calculator says that for each 12" distance on the horizontal, the
top sloped at 12 degrees will be 12.2681 inches long.

Somebody check me
_________________________________________________


You're right


Thanks, both of you.

That will free up some time for me tomorrow to work on some other things.

The wreck is a resource.

Lee Michaels wrote:

And I can't remember
high school math right now.

Feel your pain ... took every math course HS/university had to offer and
now would welcome a calculator to add up the points on them dominoes in
my hand.

--
www.e-woodshop.net
Last update: 10/22/08
KarlC@ (the obvious)

"Swingman" wrote

Lee Michaels wrote:

And I can't remember high school math right now.

Feel your pain ... took every math course HS/university had to offer and
now would welcome a calculator to add up the points on them dominoes in my
hand.

--
Yep, we ain't spring chickens any more.

The funny thing is that some things, I remember very well and some things
not at all. Even math things.

And there appears to be no rhyme or reason about what is retained and what
is not.

On Mon, 30 Nov 2009 01:07:36 -0500, the infamous "Lee Michaels"
scrawled the following:


"CW" wrote in message
om...

"Old Guy" wrote in message
...
My memory of trig says that the top is the hypotenuse of the right
triangle, the horizontal measurement is the adjacent side. cos angle
= adjacent side /hypotenuse. Hypotenuse =adjacent side/cos
12degrees.

My calculator says that for each 12" distance on the horizontal, the
top sloped at 12 degrees will be 12.2681 inches long.

Somebody check me
_________________________________________________


You're right


Thanks, both of you.

That will free up some time for me tomorrow to work on some other things.

The wreck is a resource.

Young punk kid, bringing his homework here. grumble, grumble

--
Some days, it's not even worth chewing through the restraints.

Lee Michaels wrote:
"Swingman" wrote

Lee Michaels wrote:

And I can't remember high school math right now.
Feel your pain ... took every math course HS/university had to offer and
now would welcome a calculator to add up the points on them dominoes in my
hand.

--
Yep, we ain't spring chickens any more.

The funny thing is that some things, I remember very well and some things
not at all. Even math things.

And there appears to be no rhyme or reason about what is retained and what
is not.

No kidding ... as a young Ist LT FO, and when under heavy fire and
needing an immediate "danger close" fire mission, I used to radio in
what we in the artillery referred to as "black magic" fire missions.

Instead of radioing the guns a "right 200, drop 200, FFE" correction and
let the FDC figure the commands to the gun, I would radio the actual
elevation and deflection settings for all six guns at once, saving time
and possibly lives (mine included, which was probably the biggest
incentive) ... try that with bullets whizzing by.

Now I'm lucky to set the right fraction on the table saw fence half the
time, and nothing brings more trial and error than figuring what angle
to cut!!

--
www.e-woodshop.net
Last update: 10/22/08
KarlC@ (the obvious)

On Nov 30, 9:52*am, "Lee Michaels"
wrote:
"Swingman" *wrote

Lee Michaels wrote:

And I can't remember high school math right now.

Feel your pain ... took every math course HS/university had to offer and
now would welcome a calculator to add up the points on them dominoes in my
hand.

--

Yep, we ain't spring chickens any more.

The funny thing is that some things, I remember very well and some things
not at all. Even math things.

And there appears to be no rhyme or reason about what is retained and what
is not.

That /is/ strange the way the memory selects what to retain and what
not. The thing that gets me, is those moments when I say to myself: "I
KNOW that I KNOW this, but it won't come to me." Then, usually after 3
deep breaths, the fresh oxygen uncorks some of those memories and then
I suddenly remember.
Try that method. It works.

Lee Michaels wrote:
"Swingman" wrote

Lee Michaels wrote:

And I can't remember high school math right now.
Feel your pain ... took every math course HS/university had to offer and
now would welcome a calculator to add up the points on them dominoes in my
hand.

Yep, we ain't spring chickens any more.

The funny thing is that some things, I remember very well and some things
not at all. Even math things.

And there appears to be no rhyme or reason about what is retained and what
is not.

Me too:

http://www.iedu.com/DeSoto/Projects/CNC/trig.html

--
Morris Dovey
DeSoto Solar
DeSoto, Iowa USA
http://www.iedu.com/DeSoto/

"Swingman" wrote in

No kidding ... as a young Ist LT FO, and when under heavy fire and needing
an immediate "danger close" fire mission, I used to radio in what we in
the artillery referred to as "black magic" fire missions.

Instead of radioing the guns a "right 200, drop 200, FFE" correction and
let the FDC figure the commands to the gun, I would radio the actual
elevation and deflection settings for all six guns at once, saving time
and possibly lives (mine included, which was probably the biggest
incentive) ... try that with bullets whizzing by.

Now THAT is a real world application of math! Definitely old school.

These day, with targeting computers, laser guided and GPS bombs/shells. such
traditional math skills are probably not needed any more.

Oops, sorry about that. Am I making you feel old again?

On Sun, 29 Nov 2009 23:11:43 -0500, "Lee Michaels"
wrote:

I have a simple trig problem that I need help with. And I can't remember
high school math right now. Here is the problem. Hopefully one of you will
have the info/knowledge handy.

I have a simple cabinet that has a 12 degree, low pitched top. The top can
not exceed the back or front. What would the length of the top be for each
horizontal foot? Put another way, for each foot horizontally, how long is
the angled top? I don't have a depth yet, but can calculate the top piece
easily enough once I get the above info.

Thanks,
Lee



I couldn't figure out the formulas for triangles until I was taking
College Algebra being taught by a High School teacher.

He said all you have to do is remember is Chief Sohcohtoa (So-Ka-Toa)

If you remember his name you will remember the formulas:

SOH means: Sin = Opposite over Hypotenuse

COH means: Cos = Opposite over Hypotenuse

TOA means: Tan = Opposite over Adjacent

Gordon Shumway wrote:

I couldn't figure out the formulas for triangles until I was taking
College Algebra being taught by a High School teacher.

He said all you have to do is remember is Chief Sohcohtoa (So-Ka-Toa)

If you remember his name you will remember the formulas:

SOH means: Sin = Opposite over Hypotenuse

COH means: Cos = Opposite over Hypotenuse

TOA means: Tan = Opposite over Adjacent

And don't forget that the squaw on the hippopotamus is
equal to the sum of the squaws on the other two hides.

Gordon Shumway wrote:
On Sun, 29 Nov 2009 23:11:43 -0500, "Lee Michaels"
wrote:

I have a simple trig problem that I need help with. And I can't remember
high school math right now. Here is the problem. Hopefully one of you will
have the info/knowledge handy.

I have a simple cabinet that has a 12 degree, low pitched top. The top can
not exceed the back or front. What would the length of the top be for each
horizontal foot? Put another way, for each foot horizontally, how long is
the angled top? I don't have a depth yet, but can calculate the top piece
easily enough once I get the above info.

Thanks,
Lee



I couldn't figure out the formulas for triangles until I was taking
College Algebra being taught by a High School teacher.

He said all you have to do is remember is Chief Sohcohtoa (So-Ka-Toa)

If you remember his name you will remember the formulas:

SOH means: Sin = Opposite over Hypotenuse

COH means: Cos = Opposite over Hypotenuse

TOA means: Tan = Opposite over Adjacent

Correction:
CAH - Cos = Adjacent over Hypotenuse

--
Froz...


The system will be down for 10 days for preventive maintenance.

On Sun, 29 Nov 2009 21:08:33 -0800, "CW"
wrote:


"Old Guy" wrote in message
...
My memory of trig says that the top is the hypotenuse of the right
triangle, the horizontal measurement is the adjacent side. cos angle
= adjacent side /hypotenuse. Hypotenuse =adjacent side/cos
12degrees.

My calculator says that for each 12" distance on the horizontal, the
top sloped at 12 degrees will be 12.2681 inches long.

Somebody check me
_______________________________________________ __


You're right

....heh...I'd just lay out a 12 degree line from the corner of a square
piece of whatever, measure out 12" on the square side, square up to
the angled line and then measure *that*...

cg

"Charlie Groh" wrote in message
...
On Sun, 29 Nov 2009 21:08:33 -0800, "CW"
wrote:


"Old Guy" wrote in message
...
My memory of trig says that the top is the hypotenuse of the right
triangle, the horizontal measurement is the adjacent side. cos angle
= adjacent side /hypotenuse. Hypotenuse =adjacent side/cos
12degrees.

My calculator says that for each 12" distance on the horizontal, the
top sloped at 12 degrees will be 12.2681 inches long.

Somebody check me
________________________________________________ _


You're right

...heh...I'd just lay out a 12 degree line from the corner of a square
piece of whatever, measure out 12" on the square side, square up to
the angled line and then measure *that*...

Normally I would do that. But I don't have access to the actual cabinet and
I am not sure of the dimensions just yet. That will change within the next
week. I needed to know the dimensions of the top piece to determine
materials size/costs.

When working for others, sometimes you have to jump through hoops tht you
never would otherwise.

"Charlie Groh" wrote in message
...


...heh...I'd just lay out a 12 degree line from the corner of a square
piece of whatever, measure out 12" on the square side, square up to
the angled line and then measure *that*...


Won't work - too simple, does not involve anything from Leigh Valley, does
not require any additional "how do I..." posts, does not leave room for an
ethics statement highlighting the superiority of the poster's own personal
sense of ethics (which apparently must apply to everyone else), and most
importantly - it's something one could do on one's own, without posting a
"how do I..." to the newsgroup.

Get with the program Charlie...

--

-Mike-

"Lee Michaels" wrote in message
...


Normally I would do that. But I don't have access to the actual cabinet
and I am not sure of the dimensions just yet. That will change within the
next week. I needed to know the dimensions of the top piece to determine
materials size/costs.

Yeahbut you can lay it out on paper, and then you'll have your answer.


When working for others, sometimes you have to jump through hoops tht you
never would otherwise.


No... say it ain't so Joe...

--

-Mike-

"Lee Michaels" wrote in message
...
I have a simple trig problem that I need help with. And I can't remember
high school math right now. Here is the problem. Hopefully one of you
will have the info/knowledge handy.

I have a simple cabinet that has a 12 degree, low pitched top. The top can
not exceed the back or front. What would the length of the top be for each
horizontal foot? Put another way, for each foot horizontally, how long is
the angled top? I don't have a depth yet, but can calculate the top piece
easily enough once I get the above info.

It's hard that way, but working men without much education normally just
draw out the triangle for a problem like that. Mathematicians call it the
Graphical Method.

Tim W

On Mon, 30 Nov 2009 12:31:30 -0500, FrozenNorth
wrote:

Gordon Shumway wrote:
On Sun, 29 Nov 2009 23:11:43 -0500, "Lee Michaels"
wrote:

I have a simple trig problem that I need help with. And I can't remember
high school math right now. Here is the problem. Hopefully one of you will
have the info/knowledge handy.

I have a simple cabinet that has a 12 degree, low pitched top. The top can
not exceed the back or front. What would the length of the top be for each
horizontal foot? Put another way, for each foot horizontally, how long is
the angled top? I don't have a depth yet, but can calculate the top piece
easily enough once I get the above info.

Thanks,
Lee



I couldn't figure out the formulas for triangles until I was taking
College Algebra being taught by a High School teacher.

He said all you have to do is remember is Chief Sohcohtoa (So-Ka-Toa)

If you remember his name you will remember the formulas:

SOH means: Sin = Opposite over Hypotenuse

COH means: Cos = Opposite over Hypotenuse

TOA means: Tan = Opposite over Adjacent

Correction:
CAH - Cos = Adjacent over Hypotenuse

Oops. That's exactly what I meant to say!

I can't understand why Spell check didn't catch that! :-(

Gordon Shumway

What color do Smurfs become when they hold their breath?

"Swingman" wrote

Now I'm lucky to set the right fraction on the table saw fence half
the time, and nothing brings more trial and error than figuring what
angle to cut!!

Which is why I use trig to layout angle on a piece of hardboard.

Do it right and you get the complimentary angle as a freebie.

Lew

On Nov 30, 9:59*am, "Lee Michaels"
wrote:
"Charlie Groh" wrote in message

...



On Sun, 29 Nov 2009 21:08:33 -0800, "CW"
wrote:

"Old Guy" wrote in message
...
My memory of trig says that the top is the hypotenuse of the right
triangle, the horizontal measurement is the adjacent side. *cos angle
= adjacent side */hypotenuse. * * Hypotenuse =adjacent side/cos
12degrees.

My calculator says that for each 12" distance on the horizontal, the
top sloped at 12 degrees will be 12.2681 inches long.

... *I needed to know the dimensions of the top piece to determine
materials size/costs.

The material has to be oversize, though; you're gonna have to start
with
a s4s board, assuming 3/4 thickness, that is as wide as the distance
from TOP/UPPER edge to BOTTOM/LOWER's perpendicular projection onto
the upper surface, if the board is to be beveled

Instead of 12" == 12 / cos(12 degrees) = 12.26809"
it's 12" == 12/cos(12 degrees) + 3/4 * sin(12 degrees)
= 12.42402"

On Mon, 30 Nov 2009 09:52:11 -0500, the infamous "Lee Michaels"
scrawled the following:


"Swingman" wrote

Lee Michaels wrote:

And I can't remember high school math right now.

Feel your pain ... took every math course HS/university had to offer and
now would welcome a calculator to add up the points on them dominoes in my
hand.

--
Yep, we ain't spring chickens any more.

The funny thing is that some things, I remember very well and some things
not at all. Even math things.

And there appears to be no rhyme or reason about what is retained and what
is not.

You poor dear, Lee. You're coming down with Somesheimers Disease!

--
Some days, it's not even worth chewing through the restraints.

On Mon, 30 Nov 2009 12:29:46 -0500, the infamous "Greg Neill"
scrawled the following:

Gordon Shumway wrote:

I couldn't figure out the formulas for triangles until I was taking
College Algebra being taught by a High School teacher.

He said all you have to do is remember is Chief Sohcohtoa (So-Ka-Toa)

If you remember his name you will remember the formulas:

SOH means: Sin = Opposite over Hypotenuse

COH means: Cos = Opposite over Hypotenuse

TOA means: Tan = Opposite over Adjacent

And don't forget that the squaw on the hippopotamus is
equal to the sum of the squaws on the other two hides.

That's as bad (and non-PC) as the resistor color code:
-Bad Boys Rape Our Young Girls But Violet Gives Willingly.
Black, brown, red, orange, yellow, gray, blue, violet, green, white.

And the planets, which is now invalidated since they don't consider
Pluto a planet any longer. (Wah!)
-Mr. Victor Eats Many Jam Sandwiches Until Nicely Plump.
Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune, Pluto.

--
Some days, it's not even worth chewing through the restraints.

On Mon, 30 Nov 2009 17:42:17 -0800, Larry Jaques
wrote:

On Mon, 30 Nov 2009 12:29:46 -0500, the infamous "Greg Neill"
scrawled the following:

Gordon Shumway wrote:

I couldn't figure out the formulas for triangles until I was taking
College Algebra being taught by a High School teacher.

He said all you have to do is remember is Chief Sohcohtoa (So-Ka-Toa)

If you remember his name you will remember the formulas:

SOH means: Sin = Opposite over Hypotenuse

COH means: Cos = Opposite over Hypotenuse

TOA means: Tan = Opposite over Adjacent

And don't forget that the squaw on the hippopotamus is
equal to the sum of the squaws on the other two hides.

That's as bad (and non-PC) as the resistor color code:
-Bad Boys Rape Our Young Girls But Violet Gives Willingly.
Black, brown, red, orange, yellow, gray, blue, violet, green, white.

Get Some Now
Gold(5%), Silver(10%), None (20%)

And the planets, which is now invalidated since they don't consider
Pluto a planet any longer. (Wah!)
-Mr. Victor Eats Many Jam Sandwiches Until Nicely Plump.
Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune, Pluto.

On Mon, 30 Nov 2009 13:29:35 -0500, "Mike Marlow"
wrote:


"Charlie Groh" wrote in message
.. .


...heh...I'd just lay out a 12 degree line from the corner of a square
piece of whatever, measure out 12" on the square side, square up to
the angled line and then measure *that*...


Won't work - too simple, does not involve anything from Leigh Valley, does
not require any additional "how do I..." posts, does not leave room for an
ethics statement highlighting the superiority of the poster's own personal
sense of ethics (which apparently must apply to everyone else), and most
importantly - it's something one could do on one's own, without posting a
"how do I..." to the newsgroup.

Get with the program Charlie...

....yes SIR! ;0)

cg

On Mon, 30 Nov 2009 13:29:35 -0500, "Mike Marlow"
wrote:


"Charlie Groh" wrote in message
.. .


...heh...I'd just lay out a 12 degree line from the corner of a square
piece of whatever, measure out 12" on the square side, square up to
the angled line and then measure *that*...


Won't work - too simple, does not involve anything from Leigh Valley, does
not require any additional "how do I..." posts, does not leave room for an
ethics statement highlighting the superiority of the poster's own personal
sense of ethics (which apparently must apply to everyone else), and most
importantly - it's something one could do on one's own, without posting a
"how do I..." to the newsgroup.

Get with the program Charlie...

....yes SIR! ;0)

cg