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#1
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Mitre question???
I want to make an 8 sided table top. What would he mitre angle be for
the skirting? |
#2
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JAKE wrote:
I want to make an 8 sided table top. What would he mitre angle be for the skirting? Tell me you are kidding. Dave |
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"JAKE" wrote in message ... I want to make an 8 sided table top. What would he mitre angle be for the skirting? 22.5 |
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Here is the way to figure any of these questions
For every side add 180 degrees, after 4 sides. example 6 sides....360(for the four sides then 180 (for fifth side) + 180 (for sixth side) add up...360 + 180 +180 =720 Now divide by number of sides....720/6 =120...divide 120 in half because you are mitering 60 degrees. Now let's try it on the 8 sided table. 360 for the square + 180 + 180 + 180 + 180 + 1080 1080/8= 135 135/2=67.5 degrees If you flipp the board over it equals 22.5 degrees. "Leon" wrote in message . .. "JAKE" wrote in message ... I want to make an 8 sided table top. What would he mitre angle be for the skirting? 22.5 ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#5
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"John "The Toymaker" Gilham" wrote in message ... Here is the way to figure any of these questions For every side add 180 degrees, after 4 sides. example 6 sides....360(for the four sides then 180 (for fifth side) + 180 (for sixth side) add up...360 + 180 +180 =720 Now divide by number of sides....720/6 =120...divide 120 in half because you are mitering 60 degrees. Now let's try it on the 8 sided table. 360 for the square + 180 + 180 + 180 + 180 + 1080 1080/8= 135 135/2=67.5 degrees If you flipp the board over it equals 22.5 degrees. Geez you made that complicated. The simple equation to any sided table is simply take the number of sides multiply by 2 and divide that number in to 360. Period. More simply put, 360 divided by double the sides. 360/(4 sides x 2) = 45 360/(8 sides x 2) = 22.5 360/(60 sides x 2) = 3 |
#6
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"John "The Toymaker" Gilham" wrote in message ... Here is the way to figure any of these questions For every side add 180 degrees, after 4 sides. example 6 sides....360(for the four sides then 180 (for fifth side) + 180 (for sixth side) add up...360 + 180 +180 =720 Now divide by number of sides....720/6 =120...divide 120 in half because you are mitering 60 degrees. Wrong A 6 sides table would require 30 degree cuts. 360/ (6 sides x 2) = 30 |
#7
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Leon wrote:
"John "The Toymaker" Gilham" wrote in message ... Here is the way to figure any of these questions For every side add 180 degrees, after 4 sides. example 6 sides....360(for the four sides then 180 (for fifth side) + 180 (for sixth side) add up...360 + 180 +180 =720 Now divide by number of sides....720/6 =120...divide 120 in half because you are mitering 60 degrees. Wrong A 6 sides table would require 30 degree cuts. 360/ (6 sides x 2) = 30 I'm not sure which is more intriguing: the fact that the question was brought up by a "woodworker", or the confusion it has engendered in this thread... Dave |
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#9
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"Leon" wrote in message . .. "John "The Toymaker" Gilham" wrote in message ... Here is the way to figure any of these questions For every side add 180 degrees, after 4 sides. example 6 sides....360(for the four sides then 180 (for fifth side) + 180 (for sixth side) add up...360 + 180 +180 =720 Now divide by number of sides....720/6 =120...divide 120 in half because you are mitering 60 degrees. Wrong A 6 sides table would require 30 degree cuts. 360/ (6 sides x 2) = 30 180 / (number of sides) has always worked for me. What's with all the complicated equations?? |
#10
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If the table top is accurately cut, then 22.5degrees
John On Tue, 19 Jul 2005 10:22:14 -0400, (JAKE) wrote: I want to make an 8 sided table top. What would he mitre angle be for the skirting? |
#11
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On Tue, 19 Jul 2005 13:03:40 -0400, "gw" wrote:
180 / (number of sides) has always worked for me. What's with all the complicated equations?? That will work. The math is how to get there. |
#12
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"Guess who" wrote in message ... On Tue, 19 Jul 2005 10:22:14 -0400, (JAKE) wrote: I want to make an 8 sided table top. What would he mitre angle be for the skirting? Asked and answered just recently, so my first impression was that this is a troll. A Google would bring the result. However, since it has been answered several ways, I'll suggest yet another method, still based on the same principles. 8 sides = 8 triangles to the center. The center angle is then divided 8 ways = 360/8 = 45 Each triangle has two angles at the outside that are equal, and the angles in a triangle add to 180, so they add to 180 - 45 = 135. Being equal, they are each 67.5 degrees. Do the same sort of calculation for any number of sides [oteh thsan 8.] As you can see by using math you've come up with a completly wrong answer. By using common sense the angle for the skirt cuts would be 22.5. This is not rocket science. |
#13
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"Leon" wrote in
: "John "The Toymaker" Gilham" wrote in message ... Here is the way to figure any of these questions For every side add 180 degrees, after 4 sides. example 6 sides....360(for the four sides then 180 (for fifth side) + 180 (for sixth side) add up...360 + 180 +180 =720 Now divide by number of sides....720/6 =120...divide 120 in half because you are mitering 60 degrees. Wrong A 6 sides table would require 30 degree cuts. 360/ (6 sides x 2) = 30 Which of course is the same thing. 30 and 60 degree angles are complimentary. |
#15
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Secret Squirrel wrote:
.... Which of course is the same thing. 30 and 60 degree angles are complimentary. And on top of liking each other, they're "complementary" in forming a right angle... |
#16
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Secret Squirrel wrote:
.... 22.5 and 67.5 are complimentary angles. ... You've the wrong "compliment" here (BTW, I didn't post until after I read the second time, just to be sure...). Angles are "complementary", we give each other "compliments" for good work, etc., ... |
#17
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#18
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"gw" wrote in message =
... |=20 | "Leon" wrote in message | . .. | | "John "The Toymaker" Gilham" wrote in message | ... | Here is the way to figure any of these questions | | For every side add 180 degrees, after 4 sides. example 6 | sides....360(for the four sides then 180 (for fifth side) + 180 = (for | sixth | side) add up...360 + 180 +180 =3D720 Now divide by number of | sides....720/6 =3D120...divide 120 in half because you are = mitering 60 | degrees. | | Wrong | | A 6 sides table would require 30 degree cuts. 360/ (6 sides x 2) = =3D 30 | | |=20 | 180 / (number of sides) has always worked for me. What's with all the | complicated equations?? |=20 |=20 Rube Goldberg ring a bell??? --=20 PDQ |
#19
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"Secret Squirrel" wrote in message . 97.131... "Leon" wrote in : "John "The Toymaker" Gilham" wrote in message ... Which of course is the same thing. 30 and 60 degree angles are complimentary. Actually you probably are not going to find a 60 degree setting on any saw. So uh you would set to 30 degrees. |
#20
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"Secret Squirrel" wrote in message Which as I mentioned to another poster is the same thing. 22.5 and 67.5 are complimentary angles. It's just a matter of which side of the line you're cutting. And I will mention again that you will not find 67.6 degrees on your saw. |
#21
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"gw" wrote in message ... 180 / (number of sides) has always worked for me. What's with all the complicated equations?? That will work also but for me it is easier to remember 360 as that forms a complete circle vs. a straight line. Actually 360 divided by the total number of cuts works also. |
#22
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Gotta hand it to you, you sure know how to make things complicated.
"John "The Toymaker" Gilham" wrote in message ... Here is the way to figure any of these questions For every side add 180 degrees, after 4 sides. example 6 sides....360(for the four sides then 180 (for fifth side) + 180 (for sixth side) add up...360 + 180 +180 =720 Now divide by number of sides....720/6 =120...divide 120 in half because you are mitering 60 degrees. Now let's try it on the 8 sided table. 360 for the square + 180 + 180 + 180 + 180 + 1080 1080/8= 135 135/2=67.5 degrees If you flipp the board over it equals 22.5 degrees. via Encryption =---- |
#23
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"Leon" wrote in
m: "Secret Squirrel" wrote in message . 97.131... "Leon" wrote in : "John "The Toymaker" Gilham" wrote in message ... Which of course is the same thing. 30 and 60 degree angles are complimentary. Actually you probably are not going to find a 60 degree setting on any saw. So uh you would set to 30 degrees. of course not. The point was that someone, I'm not sure who, said that the math was wrong. The math was absolutely correct. Understanding that 30 and 60 degree angles are complementary is necesarry for practical application, but doesn't make his original statement incorrect. |
#24
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"Secret Squirrel" wrote in message . 97.131... of course not. The point was that someone, I'm not sure who, said that the math was wrong. The math was absolutely correct. Understanding that 30 and 60 degree angles are complementary is necesarry for practical application, but doesn't make his original statement incorrect. Well in one of his examples his math was wrong. He went on to give another examples of Now let's try it on the 8 sided table. 360 for the square + 180 + 180 + 180 + 180 + 1080 1080/8= 135 135/2=67.5 degrees If you flipp the board over it equals 22.5 degrees. That does not add up. He adds 360+180+180+180+180+1080 which would normally = 2160 not 1080. A reasonable person would gibe an answer to the saw setting to come up with the end result. He simply made this way too complicated for some one that could not determine the answer in the first place. Typically and or at least I was always taught to make the equasion as simple as possible. Why not use a formula that gives the angle setting found on the saw? |
#25
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Why not just divide 360 by the number of sides. This gives you the angle of
each joint. Mitre each side joint at half this angle and assemble. 8 sides = 360/8=45 45/2=22.5 There, just mitre at 22.5 degrees. Oldun |
#26
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"Oldun" wrote in message ... Why not just divide 360 by the number of sides. This gives you the angle of each joint. Mitre each side joint at half this angle and assemble. 8 sides = 360/8=45 45/2=22.5 There, just mitre at 22.5 degrees. Oldun If you read higher up in the thread I made that same BASIC suggestion a few days back. Actually I divide the sides by the number of end cuts needed. More simply put, 360 divided by double the sides. 360/(4 sides x 2 end cuts) = 45 360/(8 sides x 2 end cuts) = 22.5 360/(60 sides x 2 end cuts) = 3 |
#27
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On 7/24/2005 9:58 AM Leon mumbled something about the following:
"Oldun" wrote in message ... Why not just divide 360 by the number of sides. This gives you the angle of each joint. Mitre each side joint at half this angle and assemble. 8 sides = 360/8=45 45/2=22.5 There, just mitre at 22.5 degrees. Oldun If you read higher up in the thread I made that same BASIC suggestion a few days back. Actually I divide the sides by the number of end cuts needed. More simply put, 360 divided by double the sides. 360/(4 sides x 2 end cuts) = 45 360/(8 sides x 2 end cuts) = 22.5 360/(60 sides x 2 end cuts) = 3 This only works with shapes of 4 or more sides, it doesn't work for a triangle. -- Odinn RCOS #7 SENS(less) "The more I study religions the more I am convinced that man never worshipped anything but himself." -- Sir Richard Francis Burton Reeky's unofficial homepage ... http://www.reeky.org '03 FLHTI ........... http://www.sloanclan.org/gallery/ElectraGlide '97 VN1500D ......... http://www.sloanclan.org/gallery/VulcanClassic Atlanta Biker Net ... http://www.atlantabiker.net Vulcan Riders Assoc . http://www.vulcanriders.org rot13 to reply |
#28
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Odinn wrote:
If you read higher up in the thread I made that same BASIC suggestion a few days back. Actually I divide the sides by the number of end cuts needed. More simply put, 360 divided by double the sides. 360/(4 sides x 2 end cuts) = 45 360/(8 sides x 2 end cuts) = 22.5 360/(60 sides x 2 end cuts) = 3 This only works with shapes of 4 or more sides, it doesn't work for a triangle. Actually it ONLY works for equilateral triangles and REGULAR polygons. Try your method or his (same thing really) on a parallelogram, trapezoid or rhombus and get back to us. |
#29
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On 7/24/2005 10:45 AM Unquestionably Confused mumbled something about
the following: Odinn wrote: If you read higher up in the thread I made that same BASIC suggestion a few days back. Actually I divide the sides by the number of end cuts needed. More simply put, 360 divided by double the sides. 360/(4 sides x 2 end cuts) = 45 360/(8 sides x 2 end cuts) = 22.5 360/(60 sides x 2 end cuts) = 3 This only works with shapes of 4 or more sides, it doesn't work for a triangle. Actually it ONLY works for equilateral triangles and REGULAR polygons. Try your method or his (same thing really) on a parallelogram, trapezoid or rhombus and get back to us. Okay 360 / (3 x 2) = 60 An equilateral triangle has 60 degree angles. I must not be getting it, because I can't seem to match 2 60 degree angles and end up with a 60 degree angle. -- Odinn RCOS #7 SENS(less) "The more I study religions the more I am convinced that man never worshipped anything but himself." -- Sir Richard Francis Burton Reeky's unofficial homepage ... http://www.reeky.org '03 FLHTI ........... http://www.sloanclan.org/gallery/ElectraGlide '97 VN1500D ......... http://www.sloanclan.org/gallery/VulcanClassic Atlanta Biker Net ... http://www.atlantabiker.net Vulcan Riders Assoc . http://www.vulcanriders.org rot13 to reply |
#30
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"Odinn" wrote in message ... On 7/24/2005 9:58 AM Leon mumbled something about the following: This only works with shapes of 4 or more sides, it doesn't work for a triangle. It certainly does work with a triangle. However you will be hard pressed to find a saw that will cut at 60 degrees. The solution if using a TS would be to set the saw at 30 degrees and put the board on end and run through the saw. |
#31
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"Unquestionably Confused" wrote in message . .. Actually it ONLY works for equilateral triangles and REGULAR polygons. How do you define REGULAR polygons? |
#32
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"Odinn" wrote in message ... 360 / (3 x 2) = 60 An equilateral triangle has 60 degree angles. I must not be getting it, because I can't seem to match 2 60 degree angles and end up with a 60 degree angle. An equilateral triangle has 60 degree angles at the end of each peice. That is because you end up with a 120 degree angle when matching up 2 60 degree angles. Add 3 120 degree angles up and you get 360 degrees. An equilateral triangle. |
#33
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On 7/24/2005 10:58 AM Leon mumbled something about the following:
"Odinn" wrote in message ... 360 / (3 x 2) = 60 An equilateral triangle has 60 degree angles. I must not be getting it, because I can't seem to match 2 60 degree angles and end up with a 60 degree angle. An equilateral triangle has 60 degree angles at the end of each peice. That is because you end up with a 120 degree angle when matching up 2 60 degree angles. Add 3 120 degree angles up and you get 360 degrees. An equilateral triangle. and how do I come up with 120 degrees? 360 ( 3 sides X 2) is the equation we were using doesn't come up with 120. -- Odinn RCOS #7 SENS(less) "The more I study religions the more I am convinced that man never worshipped anything but himself." -- Sir Richard Francis Burton Reeky's unofficial homepage ... http://www.reeky.org '03 FLHTI ........... http://www.sloanclan.org/gallery/ElectraGlide '97 VN1500D ......... http://www.sloanclan.org/gallery/VulcanClassic Atlanta Biker Net ... http://www.atlantabiker.net Vulcan Riders Assoc . http://www.vulcanriders.org rot13 to reply |
#34
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"Leon" wrote in message
How do you define REGULAR polygons? There is only one definition: all angles in a REGULAR polygon are equal. The sum of the _exterior_ angles of ANY polygon is 360 degrees. The sum of the _interior_ angles of ANY polygon = 180° (n-2) where n=number of sides There shouldn't be much more any one needs. LOL -- www.e-woodshop.net Last update: 7/23/05 |
#35
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Leon wrote:
"Unquestionably Confused" wrote in message . .. Actually it ONLY works for equilateral triangles and REGULAR polygons. How do you define REGULAR polygons? sides all equal length and angles all the same. Rectangle would also fit here even though the sides differ so _I_ would define a rectangle with its 90 degree corners as a regular polygon but that might be stretching it. Also, an "Oops, my bad" is owed to Odinn. I got hung up on the angle feature and what I was thinking was equilateral triangle, three equal angles, divide them by 2 and that's your cut. Won't work on any other triangle AFAIK. None of the methods discussed here will work on parallelograms, trapezoids, or rhombi (sp?) |
#36
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Leon wrote:
"Odinn" wrote in message ... 360 / (3 x 2) = 60 An equilateral triangle has 60 degree angles. I must not be getting it, because I can't seem to match 2 60 degree angles and end up with a 60 degree angle. An equilateral triangle has 60 degree angles at the end of each peice. That is because you end up with a 120 degree angle when matching up 2 60 degree angles. Add 3 120 degree angles up and you get 360 degrees. An equilateral triangle. No, Odinn's right. ANY triangle is a three-sided polygon. The sum of the angles of a triangle is 180 degrees. The END of each side of an equilateral triangle is a 30 degree angle which meets another 30 degree angle to come up with 60 degrees. I'm not Unquestionably Confused for nuttin' g |
#37
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"Unquestionably Confused" wrote in message news:MjOEe.378 How do you define REGULAR polygons? sides all equal length and angles all the same. Rectangle would also fit here even though the sides differ so _I_ would define a rectangle with its 90 degree corners as a regular polygon but that might be stretching it. Ok that is not correct in reference to the equasion only working on Regular polygons. All sides do have to be equal angles but all pieces DO NOT have to be the same length. With the formula that I use all pieces do not have to be the same length. All parallel pieces have to be equal length. Also, an "Oops, my bad" is owed to Odinn. I got hung up on the angle feature and what I was thinking was equilateral triangle, three equal angles, divide them by 2 and that's your cut. Won't work on any other triangle AFAIK. I agree. |
#38
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"Odinn" wrote in message ... On 7/24/2005 10:58 AM Leon mumbled something about the following: "Odinn" wrote in message ... and how do I come up with 120 degrees? 360 ( 3 sides X 2) is the equation we were using doesn't come up with 120. Well. I will admit that it does become a bit tricky at this point. Because most saws will not tilt the blades much past 45 degrees, a 60 degree bevel has to be accomplished by rotating the board 90 degrees and has it to be cut at the 30 degree setting. This leaves you with a complimentary result angle of 60 degrees. I'll post a PDF file to alt.binaries. picture.woodworking with a CAD drawing of the set up and how the angles are "conjured up". |
#39
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"Unquestionably Confused" wrote in message news:uoOEe.381 No, Odinn's right. ANY triangle is a three-sided polygon. The sum of the angles of a triangle is 180 degrees. Yes I agree to a point. My formula of dividing the total number of cut, "2 on each end of 3 pieces" into 360 still works on a triangle but the set up on the saw has to be bit different since a TS will not tilt its blade 60 degrees in relation to the fence. You have to rotate the piece of wood to be parallel to the fence and the 30 degree setting on the bevel will give you a complementary 60 degree angle result. If the blade would tilt to 60 degrees in relation to the fence you could cut it in the traditional mannor. The END of each side of an equilateral triangle is a 30 degree angle which meets another 30 degree angle to come up with 60 degrees. Correct but again my formula works for the saw bevel setting or perceived saw bevel setting. Since the saw will not tilt past 45 degrees you have to rotate the board parallel with the fence to end up with what the same angle that the saw would cut if it could tilt to 60 degrees during a normal setting with the work laying flat on the TS top. I posted a CAD drawing in PDF format to a.b.p.w. You will have to open the file to see the drawing. |
#40
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Leon wrote:
sides all equal length and angles all the same. Rectangle would also fit here even though the sides differ so _I_ would define a rectangle with its 90 degree corners as a regular polygon but that might be stretching it. Ok that is not correct in reference to the equasion only working on Regular polygons. All sides do have to be equal angles but all pieces DO NOT have to be the same length. But if you have a polygon (more than four sides), how can you have equal angles AND differing sides. I submit that you can't. Imagine a pentagon with four sides being 2' long and 1 side 3' long. Show me the equal anglesg With the formula that I use all pieces do not have to be the same length. All parallel pieces have to be equal length. Okay. With this one, assume it's a parallelogram. Four sides are parallel (by definition) with the opposing side. Angles differ on two corners. |
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