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Default OT? Weigh your car by checking tire pressure?


"Dave Baker" wrote in message
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"Rich Grise" wrote in message
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Saturday morning TV is mostly cartoons, yes, but there's one show that's
not a cartoon, but it's still fun:
http://www.beakmansworldtv.com/

It's like Stealth Educational TV - like Mr. Wizard for the 21st century
kid. And they do Real Science.

But today, they said that you can weigh your car by using your tire
pressure. What you do is measure the footprint of each tire, take its
pressure, and then the footprint of the tire times the PSI equals
the number of pounds that the tire is supporting, and their sum is the
weight of the car. (except for the tires themselves, I presume).

But they did the experiment - they measured the footprints of the four
tires on Some very well-preserved Nash Rambler, and their PSI, and did
the arithmetic, and came up with a number that was within 10% of the
car's
"official" weight.

Well, I'm a little uncomfortable with that. What about the pressure
that's
in a tire when it's not on the car? Where does that pressure go? Is that
that 10% fudge factor that they admitted to in the show?

How much does the pressure change when you take a standalone tire, mount
it on the car, and let the car down on it?

Or do they get around that by saying, "Well, you can ignore that, because
the tire's not supporting any weight". Or is it entirely ( or mostly) due
to the flattening of the bottom of the tire? Does the "bias pressure" (a
term I just made up now, for the pressure that's there when it's not on
the car) get lost below the noise floor?


There are two sources of error in that method. The first, which is the one
I think you are referring to is the increase in pressure as you put weight
on the tyre. This will be the inverse of the reduction in volume of the
tyre as the bottom of the tread flattens and will be very small.

The second, which is the significant one, is the amount of the load which
is being supported by the stiffness of the tyre tread and sidewalls. If
the tyre were a balloon, i.e. perfectly elastic, the measurement as above
would be exactly correct.

So the result they should have obtained is a calculated weight somewhat
less than the actual weight of the car.
--
Dave Baker - Puma Race Engines

There's at least one more error, Dave! When you bring the rubber close
enough to the tarmac Van der Waals forces kick in and give you some extra
attraction, so some extra "contact area".


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