Can anyone here provide the ultimate shear strengths of copper (both
hard and annealed), yellow brass, and A36 or 1018 steel? Thanks.

Bert

The rule of thumb is shear strength = ~1/3 of the tensile strength. There
are some exceptions...like carbon thread, glass fiber, etc. iirc, 1018C
runs about 30 ksi, so shear strength is ~10ksi.

StaticsJason

"Bert" wrote in message
...
Can anyone here provide the ultimate shear strengths of copper (both
hard and annealed), yellow brass, and A36 or 1018 steel? Thanks.

Bert

Did you mean to say 2/3? Everything I've read indicates that shear
strength is typically 60 to 90% of tensile strength. But I'm looking
for something a little more precise for the materials in question.
Surely that information must be available somewhere, but I haven't
found it on the web or in my limited home library.

Bert

"Statics" wrote:

The rule of thumb is shear strength = ~1/3 of the tensile strength. There
are some exceptions...like carbon thread, glass fiber, etc. iirc, 1018C
runs about 30 ksi, so shear strength is ~10ksi.

StaticsJason

"Bert" wrote in message
.. .
Can anyone here provide the ultimate shear strengths of copper (both
hard and annealed), yellow brass, and A36 or 1018 steel? Thanks.

Bert

In article , Bert says...

Did you mean to say 2/3? Everything I've read indicates that shear
strength is typically 60 to 90% of tensile strength. But I'm looking
for something a little more precise for the materials in question.
Surely that information must be available somewhere, but I haven't
found it on the web or in my limited home library.

I've made cursory investigations (ie, talking to everyone
I know who knows more about this stuff than me...) and
have yet to come across a theory that explains how one
would calculate one from the other, and how they are
related physically.

Jim

==================================================
please reply to:
JRR(zero) at yktvmv (dot) vnet (dot) ibm (dot) com
==================================================

Get thee to an elementary engineering text.
Mechanics of Materials by EP Popov will do nicely.

Look for "failure theories"
Maximum shear stress theory and
Maximum distortion energy theory.

Erich


"jim rozen" wrote in message
...
In article , Bert says...
I've made cursory investigations (ie, talking to everyone
I know who knows more about this stuff than me...) and
have yet to come across a theory that explains how one
would calculate one from the other, and how they are
related physically.

Jim

==================================================
please reply to:
JRR(zero) at yktvmv (dot) vnet (dot) ibm (dot) com
==================================================

In article , Kathy and Erich Coiner
says...


Get thee to an elementary engineering text.
Mechanics of Materials by EP Popov will do nicely.

Easy name to remember, I will search it out next
week. Thank you!

Jim

==================================================
please reply to:
JRR(zero) at yktvmv (dot) vnet (dot) ibm (dot) com
==================================================

"jim rozen" wrote in message
...
In article , Kathy and Erich
Coiner
says...


Get thee to an elementary engineering text.
Mechanics of Materials by EP Popov will do nicely.

Easy name to remember, I will search it out next
week. Thank you!

Jim

You are welcome.

Erich

"Kathy and Erich Coiner" wrote in message
...

"jim rozen" wrote in message
...
In article , Kathy and Erich
Coiner
says...


Get thee to an elementary engineering text.
Mechanics of Materials by EP Popov will do nicely.

Easy name to remember, I will search it out next
week. Thank you!

Jim

You are welcome.

Erich


Or "Introduction to Mechanics of Solids" by same author (if indeed it is not
the same book). I still have my school copy, purchased for $14.95!

(Tom Robeson) wrote:

Bert wrote in message . ..
Can anyone here provide the ultimate shear strengths of copper (both
hard and annealed), yellow brass, and A36 or 1018 steel? Thanks.

A36----Rb70--ultimate shear 50,000
1018---Rb 45-60-------------42,000
alloy 260 (cartridge brass) 1/2 hard-Rb70----40,000
110 copper-soft-Rf40--------22,000
110 copper-hard-Rb50--------28,000
Tom

Thanks, Tom. For future reference, may I ask where you found this
data?

Bert

I wonder if I recall this right... Ultimate Shear Strength (USS) is
related to Ultimate Tensile Strength (UTS) by Poisson's Ratio.
Poisson's Ratio is simply the ratio of the original cross-sectional area
of the tensile sample divided by the area of the failed surface (normal
to the pull axis) on the tensile sample. So, if we have a one inch
diameter tensile sample of mild steel and pull it to failure, we should
have seen a tensile strength maximum of about 55,000 psi.

Let's see ... The original sample had about 0.784 sq. in of area, the
failed section had an area of about 0.470 sq. in. UTS from the test was
about 55,000 psi, so:

0.470
------ * 50,000 = about 30,000 psi for USS.
0.785

Look up the UTS in a table, multiply it times Poisson's ratio to get
USS, or do the ratio of failed sample area (often given in tables) to
original sample area and multiply times the UTS.

Cliff - Did I remember it right??

Jeff Thompson

Al wrote:

"Kathy and Erich Coiner" wrote in message
...

"jim rozen" wrote in message
...

In article , Kathy and Erich

Coiner

says...


Get thee to an elementary engineering text.
Mechanics of Materials by EP Popov will do nicely.

Easy name to remember, I will search it out next
week. Thank you!

Jim


You are welcome.

Erich



Or "Introduction to Mechanics of Solids" by same author (if indeed it is not
the same book). I still have my school copy, purchased for $14.95!

In my haste, I gave you figures for yield strength rather than ultimate.
Are you designing shearing dies or parts that need to sustain shear loading?

If designing parts to survive shear loading keep in mind that in ductile
materials, deformation and/or necking (in the case of tensile loading) can
increase the stress in the part without significant increase in load when in
the failure region of the stress - strain curve.

Designing a ductile part assuming that it will stay the same shape (and load
bearing cross section) all the way up to the ultimate stress can be
dangerous.

If you are intentionally cutting something, ultimate stress is your figure;
if you are designing a part for safe use, yield stress is what you should
design with.

"Mechanics of Materials" by Gere & Timoshenko is a good reference, though
the other book(s) mentioned in the thread would likely do fine.

hth,
StaticsJason

PS: A36 is so named because its tensile yield strength is 36ksi.

"Statics" wrote in message
...
The rule of thumb is shear strength = ~1/3 of the tensile strength. There
are some exceptions...like carbon thread, glass fiber, etc. iirc, 1018C
runs about 30 ksi, so shear strength is ~10ksi.

StaticsJason

"Bert" wrote in message
...
Can anyone here provide the ultimate shear strengths of copper (both
hard and annealed), yellow brass, and A36 or 1018 steel? Thanks.

Bert