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Electronics Repair (sci.electronics.repair) Discussion of repairing electronic equipment. Topics include requests for assistance, where to obtain servicing information and parts, techniques for diagnosis and repair, and annecdotes about success, failures and problems. |
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My son has a pellet stove, and it is great except for when they lose power. This sometimes is for days, and when it happens during the Winter we can usually count on seeing them over here for the duration of the outage. It's always nice to have them visit but I would like to help them to be more self sufficient if possible.
He tells me that during startup the ignitor requires 500watts, but once the thing is cranking, the blower and auger take about 250watts. If this were to run off an inverter though I don't know what the 12volt side would require. I have a 2000VA UPS that is not being used right now. It uses 5 12volt 7AH batteries. If I used 5 sealed group 24 or larger automotive type batteries and except for the initial 500watt startup demand I am drawing approximately one quarter maximum continuous load, the inverter shouldn't overheat and therefore should be able to run continuously. Given this scenario, can anyone venture a guess as to how long he'll be able to run the stove before the batteries drop to the point that the inverter shuts down? Thanks, Lenny |
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#3
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#4
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wrote:
My son has a pellet stove, and it is great except for when they lose power. This sometimes is for days, and when it happens during the Winter we can usually count on seeing them over here for the duration of the outage. It's always nice to have them visit but I would like to help them to be more self sufficient if possible. He tells me that during startup the ignitor requires 500watts, but once the thing is cranking, the blower and auger take about 250watts. If this were to run off an inverter though I don't know what the 12volt side would require. I have a 2000VA UPS that is not being used right now. It uses 5 12volt 7AH batteries. If I used 5 sealed group 24 or larger automotive type batteries and except for the initial 500watt startup demand I am drawing approximately one quarter maximum continuous load, the inverter shouldn't overheat and therefore should be able to run continuously. Given this scenario, can anyone venture a guess as to how long he'll be able to run the stove before the batteries drop to the point that the inverter shuts down? Thanks, Lenny The blower on my gas furnace is about 300 watts. Starter is minimal. With a 120 AHR battery, I could get about 4 hours running time, but that's a bit too long for good battery life. Powered off solar, which is not going to recoup in one sunny day. Greg |
#5
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On Sunday, September 22, 2013 1:18:13 PM UTC-4, wrote:
My son has a pellet stove, and it is great except for when they lose power. This sometimes is for days, and when it happens during the Winter we can usually count on seeing them over here for the duration of the outage. It's always nice to have them visit but I would like to help them to be more self sufficient if possible. He tells me that during startup the ignitor requires 500watts, but once the thing is cranking, the blower and auger take about 250watts. If this were to run off an inverter though I don't know what the 12volt side would require. I have a 2000VA UPS that is not being used right now. It uses 5 12volt 7AH batteries. If I used 5 sealed group 24 or larger automotive type batteries and except for the initial 500watt startup demand I am drawing approximately one quarter maximum continuous load, the inverter shouldn't overheat and therefore should be able to run continuously. Given this scenario, can anyone venture a guess as to how long he'll be able to run the stove before the batteries drop to the point that the inverter shuts down? Thanks, Lenny Not sure about the bigger batteries. But 5 x 12V @ 7AH is 5*12 = 60 V * 7 A *3600 seconds ~ 1.5 x10^6 joules. Divided by 250 watts is about 6000 seconds, a little less than two hours, (assuming 100% efficiency) As Mike said, get a generator. George H. |
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#8
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A propane or natural gas powered generator makes more sense if there really are that many failures. Or, maybe run an invertor from your car battery and generator, easy enough to do if you keep your car gassed up when weather is threatening and you have a place to park the car outside close enough to the house for a reasonable number of extension cords from the generator so you don't have too large a voltage drop.
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