On 12/8/2016 6:54 PM, John Harmon wrote:
amdx actually said:

But what is 1/60th of a degree in inches?
That depends on the length.

Following that statement to the logical next step, here is a
representiative track for my sedan from this thread:
http://www.bimmerforums.com/forum/sh...nsion-Overhaul

That photo says that the track is:
- Front Track Width = 1512 mm
- Rear Track Width = 1526 mm

So now what's 1/60th of a degree, in millimeters?



You have a misunderstanding, to figure millimeter or inches,
you need to have two lines that are connected like a below,

l****/
l /
l /
l /
l/
The angle between l and /, we will call 1/60 of a degree,
the **** is the millimeters or inches, BUT, the quantity of millimeters
or inches depends on the length of l, as you can see the longer l the
larger **** will be. But the angle stays the same.


Use the link below
may help you see it.



http://www.carbidedepot.com/formulas-trigright.asp
I put in a 1 degree angle for (angle a) and 16" for
(side B) Then hit calculate to find (side a).
This says you need 0.279" of tilt top to bottom
on a 16" wheel.
Note: this triangle is rotated 90* to your wheel.
So take that into account when thinking about the calculation.
Bottom line, for a 1 degree angle you need a tilt of 0.279" over 16".
That's measurable, but you need a post 90* off the floor to measure from.
Second note: Side (a) the tilt at the top (mm or inches), Side (b) is
perpendicular to the floor, Side (c) would be the tilt of the wheel.
Angle (a) is the degrees of the angle you set.

Mikek