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Dropping 1V from a Regulated 6V Wall Wart
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Active8
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Dropping 1V from a Regulated 6V Wall Wart
On Tue, 30 Dec 2003 08:57:09 -0600,
said...
On Tue, 30 Dec 2003 12:36:45 GMT, Active8
,invalid wrote:
Rough guess...
---+------------------+
| |
| 10 |
| ___ |/
+---|___|---+----|
| |
| |
- |
5.6 500mW ^ +---------
|
-------------+----------------
---
Closer guess:
Ib ~ Ie/ß = 200mA/100 = 2mA
IZt = 20mA
R = (Vin-VZ)/(IZt+Ib) = 0.4V/0.022A = 18.18...R ~ 20R
Ok, I incorrectly guessed Beta (Chaos Master told me how to get
special characters and it doesn't work here) of 200 and set Iz at
40mA (a waste) to get the 500mW zener to operate at about half it's
rating. I know, I only needed 10mA if Ib really were 10mA.
--
Best Regards,
Mike
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