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Watson A.Name - Watt Sun, Dark Remover
 
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Default Dropping 1V from a Regulated 6V Wall Wart

In article ,
mentioned...
On Tue, 30 Dec 2003 12:36:45 GMT, Active8
,invalid wrote:


Rough guess...



---+------------------+
| |
| 10 |
| ___ |/
+---|___|---+----|
| |
| |
- |
5.6 500mW ^ +---------
|
-------------+----------------


---
Closer guess:

Ib ~ Ie/ß = 200mA/100 = 2mA

IZt = 20mA

R = (Vin-VZ)/(IZt+Ib) = 0.4V/0.022A = 18.18...R ~ 20R


Yeah, I was thinking something really low like that.

But these approaches have been to establish a new regulated voltage,
dependent on the value of the zener. There's nothing wrong with this,
but it would be simpler to just use a LDO 5V regulator as someone
suggested.

I figured that since the 6V input was already well regulated, that it
would be easy to just drop a single volt. My subject: line kind of
said that. And if I use a 1N4002 inline with the input, it gives me
5.4 to 5.2V or so, over most of the current range, which is not all
that bad. And I did say I wanted to keep it simple. It's not that
I'm unappreciative of all the input others have given, it's been a
good learning experience seeing these neat little circuits. I've
saved many of them to disk, to experiment with later. So I thank all
who contributed.

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