Dropping 1V from a Regulated 6V Wall Wart
On Tue, 30 Dec 2003 12:36:45 GMT, Active8
,invalid wrote:
Rough guess...
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5.6 500mW ^ +---------
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Closer guess:
Ib ~ Ie/ß = 200mA/100 = 2mA
IZt = 20mA
R = (Vin-VZ)/(IZt+Ib) = 0.4V/0.022A = 18.18...R ~ 20R
--
John Fields
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