On 9/5/2013 10:29 PM, pyotr filipivich wrote:

Here are a whole bunch of diameters for you...
http://en.wikipedia.org/wiki/.25_ACP
That should be a fair start.

That is, and gives me cartridge dimensions. Which is fair, but
I'm after the dimensions of the actual "bullet" (the lead pellet) the
round launches. I know the pellet is at least (23.11 - 15.62 =) 7.49
mm - but that is just from the tip of the pellet to the edge of the
cartridge rim.

Warning - bad ASCII art ahead B-)

Brass Cartridge length:
0------------v = 15.62 -.51 mm
__________
| |____
| |_____)
|_________ |

OAL Length -------^ is 23.11 mm

My question is How far left of the "v" (15.62) is the bullet seated? 1
mm? 2 mm? (Bullet over all length is 7.49 mm +????mm)


32 grains of bullet at 1100 fps - almost 100 ft.lb.
Hardly metal working.
You could do that - in plastic.

I could. But I still want a "real" cartridge, with a lead bullet.

And I figure, "WTH - let us scale it up to take a 45 ACP." Which
is a "whole more serious" project.

Once this exercise is done, I move onto scaling up a 9mm Mauser
Broomhandle into something "serious".
--
pyotr filipivich
"With Age comes Wisdom. Although more often, Age travels alone."

I do not know for sure, but if you check with the bullet manufactures
like Hornady or Sierra their on line sites might have bullet lengths. If
that doesn't help try to find a catalog from either one of them.