On Mon, 01 Sep 2008 04:37:06 GMT, Ross Herbert
wrote:

On Sun, 31 Aug 2008 21:20:34 -0700, John Larkin
wrote:

:On Mon, 1 Sep 2008 13:57:04 +1000, "Phil Allison"
wrote:
:
:
:Can you come up with a better way to reduce or eliminate cable inductance?
:
:I've used an easier one:
:
:Start with a hunk of the MIL-spec stranded wire, #8 or #10 maybe, the
:kind with the fine silver-plated strands and very thin-skin black
:teflon insulation.
:
:Stuff that inside a tubular woven copper braid. Pull the braid to
:tighten it around the inner conductor, then finish with shrink tubing.
:The result is homemade coax with a very thin dielectric, which
:translates to very low inductance per unit length.
:
:I've done this for driving longish (like 10 m) runs to NMR gradient
:coils, where the cable L really matters. The improvement over other
:constructions, like twisted pairs, is dramatic.
:
:
:John
:
:

Sounds good to me.

Somewhat along these lines John?
http://www.sumikoaudio.net/ocos/idx_products.htm

No. They show a thin inner conductor with thick insulation. Impedance
goes as the log of D/d, where D is the diameter of the shield and d is
the diameter of the inner conductor. So to make D/d approach 1 (and
impedance approach zero) the insulation must be as thin as possible
(which adds capacitance, of course.)

The impedance graphs and text on the cited web page are made-up lies.
But I suppose the wilder the lies, the more audiophools will pay.

Audio doesn't really matter anyhow.

John