Thread: jewelry
View Single Post
  #17   Report Post  
Posted to alt.binaries.schematics.electronic
Anthony Fremont Anthony Fremont is offline
external usenet poster
 
Posts: 203
Default jewelry

MassiveProng wrote:
On Thu, 12 Apr 2007 07:38:51 -0500, "Anthony Fremont"
Gave us:

MassiveProng wrote:
On Thu, 12 Apr 2007 04:27:46 -0500, "Anthony Fremont"
Gave us:

MassiveProng wrote:
On Wed, 11 Apr 2007 20:55:04 -0700, John Larkin
Gave us:

This is what is being used in smart munitions now. Survives well
over 15,000 Gs.

http://www.eetimes.com/news/semi/sho...leID=198800293

I saw this in the
"For comparison, dropping a laptop produces a shock of about 2 to 4
g's. "

Where did they come up with that nonsense?

U B Idiot. A drop from 3 feet up generates about 3 to 4 G's.


Just tipping a drive over on a hard table (like one in an external
case that has 0 shock protection, like most of them have) can kill
the drive by subjecting it to hundreds of G's of impact.


Total bull****. You must have had "hundreds of Gs of impact"
applied to your head as a child.

If it's running, it's almost a
guaranteed a head crash.


You don't know much about rugged operational parameters (if
anything).

Square wave, sudden stop. A typical Hard Drive at rest can handle
40Gs.


40G's of NON-IMPACT Vibration and actually it's much more than that,
more like 500G - 1000G @ 1 or 2mS You have to be more definitive
than "sudden stop", if you reduce decel time to 0, then the number
of G's is incalculable.


More total bull****. The number is "theoretically infinite". The
reality is most certainly calculable. You sure don't know much about
numbers that APPROACH zero or infinity. A car coil has a DC standing
flux on it. When the points open, that flux collapses and a
THEORETICALLY infinite voltage is induced. In reality, however, the
number is much much lower.


More of this poor analogy? That voltage is still a tad higher than Vcc
isn't it? What happens when resistance is reduced to 0 as in a
superconductor? I'm not saying decel time is truly 0 when you drop a hard
drive on concrete, but it's not going to be a whole 2mS either, unless you
add up all the impacts as it bounces around.

That is why we don't see Tesla coil events
at our spark plug gaps.


I'm not sure what you're trying to say here. What is a "Tesla coil event"?
What is different about tessla coils and what takes place in an ignition
coil, outside of the Tesla coil having a built in oscillator and it being a
fully tuned circuit?

Maybe by dropping it into a box
of styrofoam peanuts.

You ain't real bright.



Just dropping it a few inches on a hard surface is
many more G's than that.

You aren't very bright at all. Here's some figures for you to
utilize.

http://www.sciencebuddies.org/mentor...html?from=Home



Kids experiments? Where is the science?


You ain't real bright.. at all.

More advanced:

http://www.earsc.com/HOME-Electronic...ex.asp?SID=250


Too bad you didn't seem to read/understand any of it.


Too bad you didn't, dingledorf.

It's mostly about how
tiny little things like rubber grommets can do wonders to lower the
force of non-impact vibration.


No ****.

I double dog dare you to drop your laptop 36" onto a
concrete surface. Be sure to take pics and post them.


That is precisely what the makers of such products do to them. They
ALSO know how many Gs are generated in such events. You do not.


You obviously don't. Manufacturers will also tell me that the MTBF of hard
drives is something like 50 years, do you think that is even remotely
realistic? If you carefully read the artcle you will see that they make
certain ass-u-mptions that don't apply to the real world scenario being
discussed here.

If you think that it
will take a whole 2mS to decelerate and that your laptop will
penetrate the concrete by 1/4" or so while doing so, then who is the
one that "ain't real bright"?


You ain't real bright. Nobody said a goddamned thing like what you
describe.


It's called "doing the math", try it some time. Let's say we drop a hard
drive from 48" (a convenient and practical number). It will take exactly .5
seconds to reach the floor. At that time, it's velocity will be 16 feet/sec
(192 inches/sec). If it takes 2mS to come to a stop, the drive will travel
..384 inches during that 2mS. WHAT WILL BE THE OUTCOME? Do you still wish
to insist that it will hit the floor with 3 or 4Gs of force? I got news for
you, we ain't talking about a half-sin pulse or a 1.5 R(ebound) value. We
are talking thousands of Gs.

For only 14,000 G's, they must have crashed their
high-speed ordinance into something fairly soft.

14k was the limit of their test gear. The munitions get more, but
the MEMs still work! They saw 100kGs likely.

It's like the collapse of a flux wave on a transformer with DC on
it. Theoretically infinite voltage is induced, but we know it is
less, and less still with loading.

A drop to a sudden stop is theoretically infinite G force, but we
know that it gets dampened and is far less, depending on the
conditions involved.


A 36" drop of a hard drive onto concrete will more than prove my
point.

The effect it had on your skull cavity, and brain function sure
leans that way, but you're still wrong.


Very convincing, no wonder the kooks are so taken with you.