On Tue, 17 Feb 2004 04:24:27 GMT, BottleBob
wrote:



Lewis Hartswick wrote:

Nick Hull wrote:

In article ,
Santa Cruz Mike wrote:

Cliff.. have you figured out how a bowl can have a 10 inch diameter
and a 30 inch circumference yet?

Is it impossible?

Not if you measure ID diameter and OD circumference


Woops Nick. Check that again. :-)
...lew...


Lewis:

Nick had the right idea but inverted the OD/ID. If you had a bowl with
a wall thickness of something like .2255 "cubits" you could check the
diameter across the OD and get 10 "cubits". 10 "cubits" minus .451
"cubits" (2 walls) = 9.549 "cubits". 9.549 "cubits" X pi = 29.999
"cubits" on the ID of the bowl.

--
BottleBob
http://home.earthlink.net/~bottlbob


Bob, lets keep it simple.. 10 units OD and 30 units OD Circumference..
no tricks.. and PI does not equal 3.0

Later,
Mike