I used to have a wooden sail boat that was made in the 30s. There
were several forged iron rings on various spars and I was told that
the way to get them on was to make the ring with a slightly smaller
inside dimension than the OD of the spar at th desird ring position,
grease the spar, heat the ring, position the ring on the spar and then
toss a bucket of water on it. The ring shrinks and is forever at the
correct place.

Well, lately I have been making myself a new cane. The shaft is
hickory, head mahogany. The shaft is reduced into a shouldered
spindle where it goes into the head. I wanted a transitional
pretty-pretty between the two different woods and decided to use
brass. A piece of 3/4" brass pipe is just the right outside diameter
but the inside diameter was a bit too small to get over the spindle so
I decided to try the heat & quench method ala spar rings.

I cut off a 5/8" wide piece of the pipe to use as my ferrule and
heated it up to see if it would expand enough to get over my spindle.
The dang thing didn't get any bigger; in fact, the ID *decreased*.
Huh? I thought about that for a moment and decided that the wall of
the brass ring must be expanding both outward and inward and therefore
the ID was decreasing, OD increasing.

But then I started thinking about what would happen if I cut the brass
ring and flattened it out into a strip. That strip would be 5/8"
wide, about 1/8" thick and 3+" long. Heat that and each dimension
should increase but the length would increase most, right? Bend that
now elongated piece of brass back into a ring and the ID should be
bigger, right? So why did my piece of pipe decrease in ID when I
heated it?

--

dadiOH
____________________________

dadiOH's dandies v3.06...
....a help file of info about MP3s, recording from
LP/cassette and tips & tricks on this and that.
Get it at http://mysite.verizon.net/xico

On Mar 4, 7:14 am, "dadiOH" wrote:
I used to have a wooden sail boat that was made in the 30s. There
were several forged iron rings on various spars and I was told that
the way to get them on was to make the ring with a slightly smaller
inside dimension than the OD of the spar at th desird ring position,
grease the spar, heat the ring, position the ring on the spar and then
toss a bucket of water on it. The ring shrinks and is forever at the
correct place.

Well, lately I have been making myself a new cane. The shaft is
hickory, head mahogany. The shaft is reduced into a shouldered
spindle where it goes into the head. I wanted a transitional
pretty-pretty between the two different woods and decided to use
brass. A piece of 3/4" brass pipe is just the right outside diameter
but the inside diameter was a bit too small to get over the spindle so
I decided to try the heat & quench method ala spar rings.

I cut off a 5/8" wide piece of the pipe to use as my ferrule and
heated it up to see if it would expand enough to get over my spindle.
The dang thing didn't get any bigger; in fact, the ID *decreased*.
Huh? I thought about that for a moment and decided that the wall of
the brass ring must be expanding both outward and inward and therefore
the ID was decreasing, OD increasing.

But then I started thinking about what would happen if I cut the brass
ring and flattened it out into a strip. That strip would be 5/8"
wide, about 1/8" thick and 3+" long. Heat that and each dimension
should increase but the length would increase most, right? Bend that
now elongated piece of brass back into a ring and the ID should be
bigger, right? So why did my piece of pipe decrease in ID when I
heated it?

Are you sure it wasn't distorting? Maybe the overall interior 'area'
was increasing in size while a particular diameter was decreasing?

R

On Mar 4, 7:14*am, "dadiOH" wrote:
I used to have a wooden sail boat that was made in the 30s. *There
were several forged iron rings on various spars and I was told that
the way to get them on was to make the ring with a slightly smaller
inside dimension than the OD of the spar at th desird ring position,
grease the spar, heat the ring, position the ring on the spar and then
toss a bucket of water on it. *The ring shrinks and is forever at the
correct place.

Well, lately I have been making myself a new cane. *The shaft is
hickory, head mahogany. *The shaft is reduced into a shouldered
spindle where it goes into the head. *I wanted a transitional
pretty-pretty between the two different woods and decided to use
brass. *A piece of 3/4" brass pipe is just the right outside diameter
but the inside diameter was a bit too small to get over the spindle so
I decided to try the heat & quench method ala spar rings.

I cut off a 5/8" wide piece of the pipe to use as my ferrule and
heated it up to see if it would expand enough to get over my spindle.
The dang thing didn't get any bigger; in fact, the ID *decreased*.
Huh? *I thought about that for a moment and decided that the wall of
the brass ring must be expanding both outward and inward and therefore
the ID was decreasing, OD increasing.

But then I started thinking about what would happen if I cut the brass
ring and flattened it out into a strip. *That strip would be 5/8"
wide, about 1/8" thick and 3+" long. *Heat that and each dimension
should increase but the length would increase most, right? *Bend that
now elongated piece of brass back into a ring and the ID should be
bigger, right? *So why did my piece of pipe decrease in ID when I
heated it?

--

dadiOH
____________________________

dadiOH's dandies v3.06...
...a help file of info about MP3s, recording from
LP/cassette and tips & tricks on this and that.
Get it athttp://mysite.verizon.net/xico

It didn't.

As the ring expands with heat, so will the hole. Not by much, though.

The coefficient of expansion of brass is .00001 per degree
Fahrenheit. That's almost twice that of steel or wrought iron.
Still, heating your ring by 400 degrees would expand it only .003" in
diameter. Not much, is it? Not much by woodworking standards anyway.

You'd be better off heating the wood to shrink it by drying.

I'd just press it on, though.

John Martin