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"Bill R" wrote in message ... I cannot get my head around the concept of power factor and, as there seems to be no answer for the large discrepancy in the reading between the two meters the whole thing seems to be a bit of a fudge. Anyway, assuming all this to be true how does my consumer meter know how much electricity is being effectively used. I can't explain the readings on the devices you mentioned. They sound like nonsense to me. You probably read this WIKI page on meters: http://en.wikipedia.org/wiki/Electricity_meter -"The induction type meter has separate coils for voltage and current"- So does that mean the readings are different when the voltage and current are out of phase? The meter is varying the reading according to the users power factor? On the WIKI Power Factor page it says: -"The significance of power factor lies in the fact that utility companies supply customers with volt-amperes, but bill them for watts.-" So now I'm confused! But ok, here's my recollection of college explanation of Power factor: With AC the voltage and current are normally in phase, that is, as the voltage rises the current rises at the same time. If you drew a graph of voltage and current the two sinewaves would be superimposed on each other. However this is only the case for a purely resistive load. For inductive or capacitive loads the voltage and current are pulled out of phase. The degree to which they are pulled out of phase is the power factor and is measured as a number between 0 and 1. Inductive loads such as motors: When the voltage and current of each cycle starts to rise the inductance of the windings opposes the change and generates a back emf that impedes the current flow. The current cannot flow until the voltage has overcome the back emf. The current is said to lag the voltage, or put the other way around, the voltage leads the current. Capacitive loads: As the voltage and current of each cycle begins to rise the current rushes in but the voltage cannot not rise immediately because the current has first to fill or charge the capacitor. The current is said to lead the voltage. Don't suppose that helps much. On the Wiki page you mentioned: http://en.wikipedia.org/wiki/Power_factor Note the section headed: -Importance of power factor in distribution systems- I recall being told that if industrial loads were all electric motors the power company would need to have four power stations instead of the one they would need if the loads were only resistive. For this reason power companies charged more for users with low power factors. Industrial users with lots of motors had capacitor rooms to try to correct for the inductance of the motors and bring the PF closer to 1 and thereby to reduce their bill. Bringing this back to the previous post, if the concept of power factor really does effectively reduce the actual amount of power used why are we being urged to replace tungsten bulbs in favour of the new bulbs. The difference in wattage may be far greater overstated than the actual difference. As the old tungston light bulbs are more or less purely resistive so have a PF of 1 any other type of bulb is going to be worse. I thought I heard the new type light bulbs are slightly capacitive? Really I think you have had the 'bamboozle them with tech speak' treatment. Roger R |
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Norman Wells coughed up some electrons that declared:
Then you have completely misuderstood relativity. I'm still waiting for you to refute the Wikipedia article I cited... |
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"Kennedy McEwen" wrote in message ... However, any small country could, with the right technology, investment and political will (which is the most likely barrier in the UK), punch well above its weight with carbon capture. Indeed, with the appropriate carbon trading agreements in place, it could be as profitable a business as any currently vomiting CO2 across the planet. However it would be far more sensible to do it in a country that had vast amounts of "free" solar energy, like in the Sahara, the CO2 could be stored in the oilfields where the oil has come from. Or maybe it could be used to grow algae and then be dumped in an oceanic trench to make some coal/oil for use in a few million years. |
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"Kennedy McEwen" wrote in message ... In article , Norman Wells writes Atmospheric extraction is totally unfeasible. Have you _any_ idea how big the atmosphere is, and how small in comparison any man-made extractor would be? Yes, at surface density, it is equivalent to a uniform layer a little less than 5 miles thick over the surface of the globe, some 200million square miles, making the atmosphere approximately 1billion cubic miles at surface density. How many would we need do you think? That depends on how fast you think we need to do it. The argument, whether you believe it or not, is that we have managed to cause the problem simply by a few hundred large CO2 producers over a couple of hundred years. So a similar number of capture units should be capable of sweeping it all up in a similar time, probably faster. At a few hundred feet per minute a single atmospheric extraction unit with a scrubber area of only 1 square mile, would take around 20,000 to remove all CO2 from the atmosphere, so a distributed system of 50 such systems around the planet would clear the problem in less time that it took to create it in the first place - and we don't WANT to get rid of all of the CO2 or we'd be in for a very cold future. Wouldn't it be good for the equatorial countries? They could extract lots of CO2 and cool down to a nice climate and leave us to freeze. And wouldn't it be better to use trees as we always have? No, because trees rely on natural air movement to access the atmosphere, not forced air movement. And they tend to decay or be burned, releasing their captured CO2 in the timescale. Not if you dump them in an ocean trench. |
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"Norman Wells" wrote in message ... How much energy do you think that will involve? How will these 'scrubbers' work exactly, and how will they be powered? To extract anything that constitutes just 0.04% of the atmosphere by passing it _all_ through scrubbers, at speeds sufficient to suck in all the atmosphere of the planet rather than wait for it to come to you, seems enormously wasteful. It is, but unlike other green technologies it might extract significantly more carbon than it uses. It is nowhere near as wasteful as wind turbines, solar PV, etc. |
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Yes, we should all pay full attention to a fictional work whose main
premise is that a nuclear meltdown in the USA would burrow its way through the earth all the way to China, shouldn't we? You daft pillock! That wasn't the main theme at all! The "China Syndrome" was a casual term used in the US nuclear industry at that time to refer to a meltdown, and the film makers just used it in the title because it sounds catchy. Have you seen the film? It raised some VERY important issues about how the drive for private profit can compromise safety. That's all. SteveT |
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"Zero Tolerance" wrote in message
... "It's not worth taking any action, ever, because China cancels it all out, always" is, if you will forgive me saying so, not the freshest of arguments. Indeed not, but it is an important and valid argument. The UK acting alone, without China, America, India and Russia, will make no difference to global warming, but will damage itself economically. Only if ALL the big players join in can we make a difference. That is where we must put our efforts. That is a simple, incontrovertible fact, and to ignore it leads to bad policy decisions. SteveT |
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"Norman Wells" wrote in message
... sigh Education today. Norman, you are making yourself look a prat. You need to do a little reading about mass-energy equivalence. Then you will understand. Do you accept that an object increases in mass as it approaches light speed? If so, everything else follows. SteveT |
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"Norman Wells" wrote in message ... : Steve Terry wrote: : "J G Miller" wrote in message : ... : : The important thing is the French have run their Nuclear power : industry on military lines, if something needs fixing it's done. : : The EU now want it privatised, which is worrying as Three mile island : was run that way. : : Remember the theme of the movie the China Syndrome was it costs : money to do things properly, so under a privatised regime it's : tempting to cut corners. : : Yes, we should all pay full attention to a fictional work whose main premise : is that a nuclear meltdown in the USA would burrow its way through the earth : all the way to China, shouldn't we? Particularly since any knowledge at all : of gravity renders that impossible, and any knowledge of geography means it : should have been called The Indian Ocean Syndrome. : OTOH we SHOULD all take notice of the core (no pun intended) issues that caused the two worst nuclear accidents thus far, cutting costs... -- Regards, Jerry. |
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Jerry wrote:
"Norman Wells" wrote in message ... Steve Terry wrote: "J G Miller" wrote in message ... The important thing is the French have run their Nuclear power industry on military lines, if something needs fixing it's done. The EU now want it privatised, which is worrying as Three mile island was run that way. Remember the theme of the movie the China Syndrome was it costs money to do things properly, so under a privatised regime it's tempting to cut corners. Yes, we should all pay full attention to a fictional work whose main premise is that a nuclear meltdown in the USA would burrow its way through the earth all the way to China, shouldn't we? Particularly since any knowledge at all of gravity renders that impossible, and any knowledge of geography means it should have been called The Indian Ocean Syndrome. OTOH we SHOULD all take notice of the core (no pun intended) issues that caused the two worst nuclear accidents thus far, cutting costs... Everything we do is subject to cost constraints. What matters is cost-effectiveness and cost-benefit. There has never been an industry yet without accidents. |
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"Ron Lowe" wrote in message ... isn't it 2.7 absolute or summat? Better pack a fleece, then. And a head-torch, it might be dark. No point, there won't be any usable energy left to make heat for the fleece to keep in or operate the torch. |
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Sofa - Spud wrote:
alexander.keys1 wrote: There have been a lot of comments recently about the waste of energy due to appliances being left on standby, and various gizmo's that are on offer to turn them off automatically, or otherwise purporting to save energy. What everybody seems to be forgetting is that an energy- saving device comes with most UK socket outlets, it's called a 'switch', and when put into the 'off' position, power cosumption is zero! None of my appliances, including computers, digital TV receivers, etc. have come to harm through this practice, I always switch off at the wall, back in the day when there were fewer appliances this was standard procedure to avoid fire risk. From years of having old TV that buzz and smell we always switch off at the plug when we go to bed, same for the PC, various chargers etc as well. It's a habit from years ago and the old fire safety films. Shutting the doors to the lounge , hall etc as well. Milton Jones: "At the end of the day, my dad goes round switching everything off and pulling out all the plugs. Very safety conscious. Quite why he got the sack from air traffic control...". |
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Steve Thackery wrote:
Yes, we should all pay full attention to a fictional work whose main premise is that a nuclear meltdown in the USA would burrow its way through the earth all the way to China, shouldn't we? You daft pillock! That wasn't the main theme at all! The "China Syndrome" was a casual term used in the US nuclear industry at that time to refer to a meltdown Got any proof of that? , and the film makers just used it in the title because it sounds catchy. Alarmist more like. Have you seen the film? It raised some VERY important issues about how the drive for private profit can compromise safety. That's all. It certainly illustrates how the producers' drive for profit can make the title of a film blatantly compromise the truth. As regards the plot, though, it's fiction. |
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On Fri, 18 Sep 2009 09:57:17 +0100, "Roger R"
wrote: "Bill R" wrote in message ... I cannot get my head around the concept of power factor and, as there seems to be no answer for the large discrepancy in the reading between the two meters the whole thing seems to be a bit of a fudge. Anyway, assuming all this to be true how does my consumer meter know how much electricity is being effectively used. I can't explain the readings on the devices you mentioned. They sound like nonsense to me. You probably read this WIKI page on meters: http://en.wikipedia.org/wiki/Electricity_meter -"The induction type meter has separate coils for voltage and current"- So does that mean the readings are different when the voltage and current are out of phase? The meter is varying the reading according to the users power factor? On the WIKI Power Factor page it says: -"The significance of power factor lies in the fact that utility companies supply customers with volt-amperes, but bill them for watts.-" So now I'm confused! But ok, here's my recollection of college explanation of Power factor: With AC the voltage and current are normally in phase, that is, as the voltage rises the current rises at the same time. If you drew a graph of voltage and current the two sinewaves would be superimposed on each other. However this is only the case for a purely resistive load. For inductive or capacitive loads the voltage and current are pulled out of phase. The degree to which they are pulled out of phase is the power factor and is measured as a number between 0 and 1. Inductive loads such as motors: When the voltage and current of each cycle starts to rise the inductance of the windings opposes the change and generates a back emf that impedes the current flow. The current cannot flow until the voltage has overcome the back emf. The current is said to lag the voltage, or put the other way around, the voltage leads the current. Capacitive loads: As the voltage and current of each cycle begins to rise the current rushes in but the voltage cannot not rise immediately because the current has first to fill or charge the capacitor. The current is said to lead the voltage. Don't suppose that helps much. On the Wiki page you mentioned: http://en.wikipedia.org/wiki/Power_factor Note the section headed: -Importance of power factor in distribution systems- I often wondered if a domestic user could reduce the power factor of the supply and hence reduce the bill. I recall being told that if industrial loads were all electric motors the power company would need to have four power stations instead of the one they would need if the loads were only resistive. For this reason power companies charged more for users with low power factors. Industrial users with lots of motors had capacitor rooms to try to correct for the inductance of the motors and bring the PF closer to 1 and thereby to reduce their bill. AFAIK industries are charged for VA not W, so PF does not affect their bill. IOW they can't save money by reducing their PF. Bringing this back to the previous post, if the concept of power factor really does effectively reduce the actual amount of power used why are we being urged to replace tungsten bulbs in favour of the new bulbs. The difference in wattage may be far greater overstated than the actual difference. As the old tungston light bulbs are more or less purely resistive so have a PF of 1 any other type of bulb is going to be worse. I thought I heard the new type light bulbs are slightly capacitive? Really I think you have had the 'bamboozle them with tech speak' treatment. -- (\__/) M. (='.'=) Due to the amount of spam posted via googlegroups and (")_(") their inaction to the problem. I am blocking most articles posted from there. If you wish your postings to be seen by everyone you will need use a different method of posting. [Reply-to address valid until it is spammed.] |
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"Tim S" wrote in message ... Do you have a degree in physics then? I have one from imperial college. Have a look at this: http://en.wikipedia.org/wiki/Mass%E2...gy_equivalence Specifically: "In relativity, removing energy is removing mass, and the formula m = E/c2 tells you how much mass is lost when energy is removed. In a chemical or nuclear reaction, the mass of the atoms that come out is less than the mass of the atoms that go in, and the difference in mass shows up as heat and light with the same relativistic mass. It may well be true of a nuclear reaction, however you haven't posted anything convincing about chemical reactions or explained where the energy is converted to mass when you lift a weight up and increase its potential energy, or even wind a clock spring up. It does not require an increase in mass to store energy. In this case, the E in the formula is the energy released and removed, and the mass m is how much the mass goes down. In the same way, when any kind of energy is added, the increase in the mass is equal to the added energy divided by c2. For example, when water is heated in a microwave oven, the oven adds about 1.11×10?17 kg of mass for every joule of heat added to the water." However a nuclear reaction creates energy from mass it doesn't just store energy like a rechargeable battery or the dinorwig hydro plant. If you feel that's wrong, you should probably go and correct it... It would take a life time to correct Wiki and then someone comes along and cocks it up again. |
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Steve Thackery wrote:
"Norman Wells" wrote in message ... sigh Education today. Norman, you are making yourself look a prat. You need to do a little reading about mass-energy equivalence. Then you will understand. Energy and mass are _not_ freely interconvertible. You require absolutely extreme conditions for it to happen. On earth, you will only find it happening in nuclear reactions. Do you accept that an object increases in mass as it approaches light speed? Yes. If so, everything else follows. No it doesn't. |
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"The Natural Philosopher" wrote in message ... dennis@home wrote: "Max Demian" wrote in message ... "Owain" wrote in message ... On 16 Sep, 23:42, "Max Demian" wrote: Energy is neither created nor destroyed Only according to classical physics. Except in nuclear power stations and in stars. ;) And springs and batteries and everything else that stores energy. (Not that you can measure the differences in mass.) Surely if you're storing energy you're not creating or destroying it? Maybe, but it violates the conservation of mass. You can store energy without converting it to mass. Chemical (batteries), and mechanical (springs) methods store energy without converting it to mass. Oh, but they DO. Its a very very very small change though. We calculated the difference in weight between a discharged and charged lithium batery. Much less than a microgram IIRC. Just because you can calculate a mass change using e=mc2 doesn't mean there is a mass change. You should be able to measure a change that big BTW. |
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"The Natural Philosopher" wrote in message ... A chemical compound does not weigh QUITE the same as its elements taken separately. A physicist doesn't confuse mass with weight BTW. You can see the effect described and IIRC tested in terms of light pressure on a sail ..photons - things with no rest mass at all, are emitted by even chemical reactions, and can exert momentum changes on things. Light pressure has nowt to do with the mass of photons. The little paddles driven around when you shine a light on them are not driven by the momentum of photons at all as anyone with an O'level in physics should be able to tell you. |
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dennis@home coughed up some electrons that declared:
"Tim S" wrote in message ... Do you have a degree in physics then? I have one from imperial college. That's better than me (York) but I did work at Imperial for some years in the Dept of Computing, so next door to your old bit. When were you there? Have a look at this: http://en.wikipedia.org/wiki/Mass%E2...gy_equivalence Specifically: "In relativity, removing energy is removing mass, and the formula m = E/c2 tells you how much mass is lost when energy is removed. In a chemical or nuclear reaction, the mass of the atoms that come out is less than the mass of the atoms that go in, and the difference in mass shows up as heat and light with the same relativistic mass. It may well be true of a nuclear reaction, however you haven't posted anything convincing about chemical reactions or explained where the energy is converted to mass when you lift a weight up and increase its potential energy, or even wind a clock spring up. It does not require an increase in mass to store energy. My teaching was that the energy/mass equivalence theory was fundamental - it required no explicit mechanism. It's an effect more than a "requirement". But it is consistent with the theory that observed mass increases with relative speed. In this case, the E in the formula is the energy released and removed, and the mass m is how much the mass goes down. In the same way, when any kind of energy is added, the increase in the mass is equal to the added energy divided by c2. For example, when water is heated in a microwave oven, the oven adds about 1.11×10?17 kg of mass for every joule of heat added to the water." However a nuclear reaction creates energy from mass it doesn't just store energy like a rechargeable battery or the dinorwig hydro plant. Hypothetically, you *could* use a nuclear reaction to store energy if you could use energy to reverse a "traditional" exothermic reaction. Small matter of engineering though... But it would be little different conceptually from electrolysing water to H2 + O2, then running that back through a fuel cell. If you feel that's wrong, you should probably go and correct it... It would take a life time to correct Wiki and then someone comes along and cocks it up again. Seems to work well enough for most Wikis - vandalism is trivially undone. Don't be shy - have a go. |
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"The Natural Philosopher" wrote in message ... E=mC^2. its there., If its wrong, you are right, if its right, you are wrong. I would love to see you apply that to quantum mechanics. ;-) |
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Norman Wells coughed up some electrons that declared:
Steve Thackery wrote: "Norman Wells" wrote in message ... sigh Education today. Norman, you are making yourself look a prat. You need to do a little reading about mass-energy equivalence. Then you will understand. Energy and mass are _not_ freely interconvertible. You require absolutely extreme conditions for it to happen. On earth, you will only find it happening in nuclear reactions. Do you accept that an object increases in mass as it approaches light speed? Yes. Looks like a perfect demonstration of mass/energy equivalence to me. Kinetic energy, which is itself a relative phenonemum appears to manifest as increased mass. Where's the problem? If so, everything else follows. No it doesn't. |
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"Enzo Matrix" wrote in message
... Bill Wright wrote: "The Natural Philosopher" wrote in message ... Adrian wrote: English is the de facto international language. One thinmg taht did come over That sounds more like Esperanto! Mi esporas ke kiam vi venos la vetero estos milda. "We [at Google Translate] are not yet able to translate from Esperanto into English." They recognised the language, though. -- Max Demian |
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dennis@home coughed up some electrons that declared:
"The Natural Philosopher" wrote in message ... A chemical compound does not weigh QUITE the same as its elements taken separately. A physicist doesn't confuse mass with weight BTW. You can see the effect described and IIRC tested in terms of light pressure on a sail ..photons - things with no rest mass at all, are emitted by even chemical reactions, and can exert momentum changes on things. Light pressure has nowt to do with the mass of photons. The little paddles driven around when you shine a light on them are not driven by the momentum of photons at all as anyone with an O'level in physics should be able to tell you. Yes, we know that. But that doesn't negate the fact that photons possess momentum, and thus mass. |
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"The Natural Philosopher" wrote in message ... I suppose what Einstein is really saying is that a things apparent mass changes depending on the speed of it *relative to the observer*. There is no such thing as absolute mass, there is only rest mass.. and of course since a photon ALWAYS travels at the speed of light, it aint a photon if it stops and gives up its energy to something else.. However the speed of photons does change so they don't always travel at the "speed of light" as used in e=mc2. |
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"Tim S" wrote in message ... Einstein's own book is surpisingly readable. Feynman wrote some pretty good stuff too and a really fun book is "Mr Tompkins in Wonderland" which is a fictional (but scientifically valid) look at how the world would be if the speed of light were 30mph. Dark, very dark. Of course the real question would be, "what is 30 mph?". |
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"dennis@home" wrote in message
... "The Natural Philosopher" wrote in message ... dennis@home wrote: You can store energy without converting it to mass. Chemical (batteries), and mechanical (springs) methods store energy without converting it to mass. Oh, but they DO. Its a very very very small change though. We calculated the difference in weight between a discharged and charged lithium batery. Much less than a microgram IIRC. Just because you can calculate a mass change using e=mc2 doesn't mean there is a mass change. You should be able to measure a change that big BTW. How big is "much less than a microgram?" (I seem to have started something here.) -- Max Demian |
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dennis@home coughed up some electrons that declared:
"Tim S" wrote in message ... Einstein's own book is surpisingly readable. Feynman wrote some pretty good stuff too and a really fun book is "Mr Tompkins in Wonderland" which is a fictional (but scientifically valid) look at how the world would be if the speed of light were 30mph. Dark, very dark. Of course the real question would be, "what is 30 mph?". What? |
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Max Demian coughed up some electrons that declared:
"dennis@home" wrote in message ... "The Natural Philosopher" wrote in message ... dennis@home wrote: You can store energy without converting it to mass. Chemical (batteries), and mechanical (springs) methods store energy without converting it to mass. Oh, but they DO. Its a very very very small change though. We calculated the difference in weight between a discharged and charged lithium batery. Much less than a microgram IIRC. Just because you can calculate a mass change using e=mc2 doesn't mean there is a mass change. You should be able to measure a change that big BTW. How big is "much less than a microgram?" (I seem to have started something here.) I stated 2.88nanograms for a 60Ah lead acid car battery. Be hard to measure mass to 1 part per billion. |
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Interesting discussion. Here's some food for thought:
If a sealed container does *not* allow particles to pass its walls but *does* allow loss of energy via exchange of thermal radiation with its outer environment, then a chemical reaction within that container could increase the temperature within that container, and as it returns to its original temperature it would lose energy and hence mass due to the relativistic effect of slowing down the vibration (speed) of particles within that container. What about a battery? It's a matter of definitions as to what you consider an ideal battery to be. You *could* argue that an *ideal* battery is sealed to prevent whole atoms from passing through its walls but is allowed to exchange energy with its environment via more than one method. |
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"Steve Terry" wrote in message ... Whereas the Russian way is, what corners? Chernobyl had an excellent post meltdown safety system, that worked. The core melted through the reactor and felt into the offices and storerooms below where it was spread out so much fission stopped. I doubt is the PWRs would do that. ;-) |
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Norman Wells wrote:
The Natural Philosopher wrote: Norman Wells wrote: Because relativity says its so. ANY release of energy is accompanied by a loss of mass. Its vanishingly small for typical mechanical and chemical energy, but its there just the same. If it isn't, relativity is falsified, and there is a huge hue and cry out for an alternative. Then you have completely misuderstood relativity. Energy and mass are interconvertible but only under specific circumstances you will not find on earth outside nuclear reactions. If release of energy is accompanied by a reduction in mass then what you've got is nuclear fission. If you haven't got nuclear fission then you don't get reduction of mass. Oh dear me no. You do. Its just almost unmeasurable, due to the fact that C squared is a frigging big number. Outside of nuclear reactions, all you have is energy conservation and mass conservation, and they are entirely separate. One form of energy can be converted into another, but not into mass, and mass can never be converted into energy. Oh yes it can, it is and it does, BUT the changes are virtually undetectable. sigh Education today. ...seems to have passed you by.. |
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Norman Wells wrote:
Steve Thackery wrote: "Norman Wells" wrote in message ... sigh Education today. Norman, you are making yourself look a prat. You need to do a little reading about mass-energy equivalence. Then you will understand. Energy and mass are _not_ freely interconvertible. You require absolutely extreme conditions for it to happen. On earth, you will only find it happening in nuclear reactions. Do you accept that an object increases in mass as it approaches light speed? Yes. If so, everything else follows. No it doesn't. faulty firmware Norman. Get your brain upgraded. |
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Dave Farrance wrote:
Interesting discussion. Here's some food for thought: If a sealed container does *not* allow particles to pass its walls but *does* allow loss of energy via exchange of thermal radiation with its outer environment, radioatin is 'particles' they are called 'photons' then a chemical reaction within that container could increase the temperature within that container, and as it returns to its original temperature it would lose energy and hence mass due to the relativistic effect of slowing down the vibration (speed) of particles within that container. What about a battery? It's a matter of definitions as to what you consider an ideal battery to be. You *could* argue that an *ideal* battery is sealed to prevent whole atoms from passing through its walls but is allowed to exchange energy with its environment via more than one method. |
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dennis@home wrote:
"Tim S" wrote in message ... Do you have a degree in physics then? I have one from imperial college. Have a look at this: http://en.wikipedia.org/wiki/Mass%E2...gy_equivalence Specifically: "In relativity, removing energy is removing mass, and the formula m = E/c2 tells you how much mass is lost when energy is removed. In a chemical or nuclear reaction, the mass of the atoms that come out is less than the mass of the atoms that go in, and the difference in mass shows up as heat and light with the same relativistic mass. It may well be true of a nuclear reaction, however you haven't posted anything convincing about chemical reactions or explained where the energy is converted to mass when you lift a weight up and increase its potential energy, or even wind a clock spring up. It does not require an increase in mass to store energy. It does. Its very very small though. For all but nuclear reactions. In this case, the E in the formula is the energy released and removed, and the mass m is how much the mass goes down. In the same way, when any kind of energy is added, the increase in the mass is equal to the added energy divided by c2. For example, when water is heated in a microwave oven, the oven adds about 1.11×10?17 kg of mass for every joule of heat added to the water." However a nuclear reaction creates energy from mass it doesn't just store energy like a rechargeable battery or the dinorwig hydro plant. The basic principles are identical. Chemical reactions affect the eolectrn patterns in the atoms. So do nuclear. The only difference is that nuclear reactions also affect the nucleus, which being a lot bigger and heavier so to speak, is a lot more noticeable. If you feel that's wrong, you should probably go and correct it... It would take a life time to correct Wiki and then someone comes along and cocks it up again. |
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dennis@home wrote:
"The Natural Philosopher" wrote in message ... dennis@home wrote: "Max Demian" wrote in message ... "Owain" wrote in message ... On 16 Sep, 23:42, "Max Demian" wrote: Energy is neither created nor destroyed Only according to classical physics. Except in nuclear power stations and in stars. ;) And springs and batteries and everything else that stores energy. (Not that you can measure the differences in mass.) Surely if you're storing energy you're not creating or destroying it? Maybe, but it violates the conservation of mass. You can store energy without converting it to mass. Chemical (batteries), and mechanical (springs) methods store energy without converting it to mass. Oh, but they DO. Its a very very very small change though. We calculated the difference in weight between a discharged and charged lithium batery. Much less than a microgram IIRC. Just because you can calculate a mass change using e=mc2 doesn't mean there is a mass change. You should be able to measure a change that big BTW. what.. less than a few parts per billion? |
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dennis@home wrote:
"The Natural Philosopher" wrote in message ... A chemical compound does not weigh QUITE the same as its elements taken separately. A physicist doesn't confuse mass with weight BTW. You can see the effect described and IIRC tested in terms of light pressure on a sail ..photons - things with no rest mass at all, are emitted by even chemical reactions, and can exert momentum changes on things. Light pressure has nowt to do with the mass of photons. The little paddles driven around when you shine a light on them are not driven by the momentum of photons at all as anyone with an O'level in physics should be able to tell you. I wasn't talking about those devices. |
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The Natural Philosopher wrote:
dennis@home wrote: "The Natural Philosopher" wrote in message ... A chemical compound does not weigh QUITE the same as its elements taken separately. A physicist doesn't confuse mass with weight BTW. You can see the effect described and IIRC tested in terms of light pressure on a sail ..photons - things with no rest mass at all, are emitted by even chemical reactions, and can exert momentum changes on things. Light pressure has nowt to do with the mass of photons. The little paddles driven around when you shine a light on them are not driven by the momentum of photons at all as anyone with an O'level in physics should be able to tell you. I wasn't talking about those devices. No, the question is whether you know what you're talking about at all. |
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On Sep 18, 8:38*am, "Jerry"
wrote: "Kennedy McEwen" wrote in message ... : In article , Bill Wright : writes : : Of course my grandparents' generation used the word for the room (or shed) : with the lavatory in it. : : Derr, isn't that the origin of "coming out of the closet", as in : "cottaging"? Err, no, I think you are thinking of "Skeletons (secrets) in the closet". AIUI the Homosexuals "came out (into the open)", after the many years of having to hide their sexual orientation from the law and society (even post '67 to one degree or other, many still have to 'hide'). Few homosexuals would not want to admit to "cottaging", even today, as it's still an illegal act... Martyrs to their cause. MBQ |
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On Fri, 18 Sep 2009 10:53:01 +0100, Norman Wells wrote:
You require absolutely extreme conditions for it to happen. No you do not. On earth, you will only find it happening in nuclear reactions. Not true. Just you repeating it ad nauseam does not make it so. You have been given examples of how it happens outside of nuclear reactions, and even a link to a government sponsored science site where it states categorically that a car with increasing velocity, and thus increasing kinetic energy, increases in mass. As you continue to make unsubstantiated claims without entering into reasoned debate, you are appearing more and more like the Alf Garnett of physics. |
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On Fri, 18 Sep 2009 10:49:45 +0100, brightside S9 wrote:
Where do you get all this crap from? It sounds to me your physics teacher (if you ever had one) was a chemist or a biologiost. That is a unwarranted slur against chemists and biologists. |
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