Hi


It occurred to me one could use a laser level to project arch shapes.
Sit the level lower than the wanted arch, set to horizontal line, and
tilt it upwards. You now get a perfect arch shape on the wall.

Anyone done this? And would it be any use? The destructions dont
mention anything about it.


NT

On 26 Dec 2005 23:00:15 -0800, wrote:

Anyone done this?

Yes, in response to your question.

And would it be any use?

No.

The destructions dont mention anything about it.

Probably because you don't get a curve. the line is always a line. I
thought it would be before I did the test.

--
Cheers
Dave. pam is missing e-mail

In an earlier contribution to this discussion,
Dave Liquorice wrote:

On 26 Dec 2005 23:00:15 -0800, wrote:

Anyone done this?

Yes, in response to your question.

And would it be any use?

No.

The destructions dont mention anything about it.

Probably because you don't get a curve. the line is always a line. I
thought it would be before I did the test.

My first thoughts were that you *would* get an arch, but it would be
inverted.

But Dave is right - the mark on the wall will be the intersection between
the (hopefully) vertical plane of the wall and the inclined plane of the
laser beam - which will be a straight line.
--
Cheers,
Set Square
______
Please reply to newsgroup. Reply address is invalid.

Set Square wrote:
In an earlier contribution to this discussion,
Dave Liquorice wrote:

On 26 Dec 2005 23:00:15 -0800, wrote:

Anyone done this?

Yes, in response to your question.

And would it be any use?

No.

The destructions dont mention anything about it.

Probably because you don't get a curve. the line is always a line. I
thought it would be before I did the test.

My first thoughts were that you *would* get an arch, but it would be
inverted.

But Dave is right - the mark on the wall will be the intersection
between the (hopefully) vertical plane of the wall and the inclined
plane of the laser beam - which will be a straight line.

The following technique might be useful however:

1) Make a scale model your arch.
2) Site your laser level.
3) Mount your arch*.
4) Shine your laser level so the on the wall is half obscured by the
model, and have someone mark it.
5) Repeat 4 for the perimeter of the wall.

* The model needs to be parallel to the wall; have its top on the line
between the desired top of the arch and the point of rotation of the LL;
have the ratios of the distance from the wall to it, and from it to the LL
in the ratio of the sizes of the arch and it.

Set Square wrote:
In an earlier contribution to this discussion,
Dave Liquorice wrote:

On 26 Dec 2005 23:00:15 -0800, wrote:

Anyone done this?

Yes, in response to your question.

And would it be any use?

No.

The destructions dont mention anything about it.

Probably because you don't get a curve. the line is always a line. I
thought it would be before I did the test.

My first thoughts were that you *would* get an arch, but it would be
inverted.

But Dave is right - the mark on the wall will be the intersection between
the (hopefully) vertical plane of the wall and the inclined plane of the
laser beam - which will be a straight line.

Youre quite right of course. I must have hit something curved when
playing with it I spose, without realising.


NT

In message .com,
writes
Set Square wrote:
In an earlier contribution to this discussion,
Dave Liquorice wrote:

On 26 Dec 2005 23:00:15 -0800, wrote:

Anyone done this?

Yes, in response to your question.

And would it be any use?

No.

The destructions dont mention anything about it.

Probably because you don't get a curve. the line is always a line. I
thought it would be before I did the test.

My first thoughts were that you *would* get an arch, but it would be
inverted.

But Dave is right - the mark on the wall will be the intersection between
the (hopefully) vertical plane of the wall and the inclined plane of the
laser beam - which will be a straight line.

Youre quite right of course. I must have hit something curved when
playing with it I spose, without realising.

If I were you, I'd check that there aren't any black holes lying around

--
geoff

Owain wrote:
wrote:
My first thoughts were that you *would* get an arch, but it would be
inverted.
But Dave is right - the mark on the wall will be the intersection
between the (hopefully) vertical plane of the wall and the inclined
plane of the laser beam - which will be a straight line.
Youre quite right of course. I must have hit something curved when
playing with it I spose, without realising.

Gt a computer projector and project the CAD on the wall


Or move to a lighthouse?