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Metalworking (rec.crafts.metalworking) Discuss various aspects of working with metal, such as machining, welding, metal joining, screwing, casting, hardening/tempering, blacksmithing/forging, spinning and hammer work, sheet metal work. |
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I found this in a 1908 Audel's Millwright's Manual.
If you square the diameter of a circle and multiply by .7854, you get the area of the circle. Also,4 X 0.7854 = Pi. With a little thought, you can get along without pi, if you want to. Okay, "So What?" you say. Well, note that .7854 means that a circle that just fits into its enscribed square contains 78.54% of the area of that square. And that's about 80%. So, an easy way to ESTIMATE the area of a circle in your head is to simply think "8 tenths of the area of the enscribed square = the area". Example: A guy offers you a piece of steel just for coming and getting it off the place RIGHT NOW! You need to know the approximate weight of a 5" diameter bar of steel that is 5 feet long, so you can decide whether you will be able to lift it into your car trunk by yourself. So, 5 X 5 = 25. 80% of 25 (in your head) is 20. That's area of the circle. 20 X 60 (5 feet in inches) is 1200. There's the volume of the bar! That's all there is to it! Now for the weight: A cubic inch of steel weighs 0.283 pounds think 2 Ate 3 (cannibalism of numbers???). 0.283 is about .3 So the bar weighs 1200 X .3 = (in your head) about 360 pounds. Sorry, Maybe you can lift it, but I'd have to pass on this one!!! Well, maybe I could------ Pete Stanaitis |