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Power Factor & kWH?
Hi all,
As I recall there are a few people here with the expertise to answer these questions easily. Simple 4 u, not 4 me! g Yes, I've done a bunch of googling and recalling the "old school days", but it's not getting me where I need to be g. Neglecting small interferences/insertion losses, etc.: -------------------------------- Short description: Here's an actual example of measurements/calcs: 120Vac measured 0.29A rms measured 24W measured 35 VA measured PF = W / VA, or 24 / 35 = 0.686..., or about 68%. Right? -- What numbers do I use to get kWH? Is it VA / W? -- How many kWH do you calculate from those figures, assuming it can be done? If it can't be done, what's missing? -- How did you get to your result? -- At 10 cents/kWH, how much would it cost me per hour? ---------- end short descrip ----------- You wouldn't believe the amount of work and research I've done to get my head around this! And how confused I am at the moment! All I started out to do was to calculate what some of the major device costs around the house are in order to make a point to some people about the cost of, say, leaving the lights on in an unoccupied room over night, or never turning off say a coffee maker, computers, radio, stereo, TV, holiday lights; things like that. And I ended up with a brain-ache so I next decided to go where there might be some brighter brain cells than my own! And here I am! Thanks for your hopefully understandable responses; it's been over 4 decades since I was in college, so be kind please g! Wellll, one more question while I have your attention: I've always heard and read that residential homes never required power factor adjustments of any kind because the power factors would never get very low. If I'm interpreting my numbers right however, I'm seeing PF numbers that are surprisingly low. Most every home is full of motors and other inductive appliances. How low IS a "low" power factor number? Or do power companies account for power factors at the facility? Just curious. Regards, Pop |
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