how much current to run anode?
I am getting a platinum coated anode that will have a surface area of 26
cm2 (100 mm long x 8 mm diameter). For my application, the maximum recommended current density is 200 mA/cm. Based on that, how much current should be flowing through the anode? I calculate square root of 26 (5.1) times 0.2 which is 1.02 A, is this correct? Thanks. |
how much current to run anode?
On 6/26/2018 9:37 AM, JBI wrote:
I am getting a platinum coated anode that will have a surface area of 26 cm2 (100 mm long x 8 mm diameter).Â* For my application, the maximum recommended current density is 200 mA/cm.Â* Based on that, how much current should be flowing through the anode?Â* I calculate square root of 26 (5.1) times 0.2 which is 1.02 A, is this correct?Â* Thanks. I'm probably confused but, if it's 8mm in diameter, isn't it 25mm* in circumference? And, if it's 25mm, then 25mm x 100mm = 2500mm^2, convert to cm^2 and get 25cm^2. then multiply 200ma x 25cm = 5 amps. I'll let an adult correct me. I have never seen a platinum coated electrode. * have not included areas on end. |
how much current to run anode?
On 06/26/2018 11:16 AM, amdx wrote:
On 6/26/2018 9:37 AM, JBI wrote: I am getting a platinum coated anode that will have a surface area of 26 cm2 (100 mm long x 8 mm diameter).Â* For my application, the maximum recommended current density is 200 mA/cm.Â* Based on that, how much current should be flowing through the anode?Â* I calculate square root of 26 (5.1) times 0.2 which is 1.02 A, is this correct?Â* Thanks. Â* I'm probably confused but, if it's 8mm in diameter, isn't it 25mm* in circumference?Â* And, if it's 25mm, then 25mm x 100mm = 2500mm^2, convert to cm^2 and get 25cm^2. then multiply 200ma x 25cm = 5 amps. Â* I'll let an adult correct me. I have never seen a platinum coated electrode. * have not included areas on end. You're at the same place I was originally when I did the calculation, which made me question whether or not I should take the square root of the area and then multiply that by current density. When I took the square, I got the 1.02A above, but much closer to your value when I didn't. Platinum coated electrodes have many applications: https://tinyurl.com/yaufchs3 |
how much current to run anode?
On Tuesday, June 26, 2018 at 11:16:09 AM UTC-4, amdx wrote:
On 6/26/2018 9:37 AM, JBI wrote: I am getting a platinum coated anode that will have a surface area of 26 cm2 (100 mm long x 8 mm diameter).Â* For my application, the maximum recommended current density is 200 mA/cm.Â* Based on that, how much current should be flowing through the anode?Â* I calculate square root of 26 (5.1) times 0.2 which is 1.02 A, is this correct?Â* Thanks. I'm probably confused but, if it's 8mm in diameter, isn't it 25mm* in circumference? And, if it's 25mm, then 25mm x 100mm = 2500mm^2, convert to cm^2 and get 25cm^2. then multiply 200ma x 25cm = 5 amps. I'll let an adult correct me. I have never seen a platinum coated electrode. * have not included areas on end. Lemme see- surface area of a cylinder = pi x D x H. 3.14159 x 8 = 25.133 25.133 x 100 = 2513.3 0.0200 x 2513.3 = 502.7 Divide by 100 (mm - cm) = 5.02 A. add the end-cap, if relevant = pi x r^2 = 3.14159 x 16 = 50.27 = 0.01A Or, close enough. Peter Wieck Melrose Park, PA |
how much current to run anode?
On 6/26/2018 10:54 AM, JBI wrote:
On 06/26/2018 11:16 AM, amdx wrote: On 6/26/2018 9:37 AM, JBI wrote: I am getting a platinum coated anode that will have a surface area of 26 cm2 (100 mm long x 8 mm diameter).Â* For my application, the maximum recommended current density is 200 mA/cm.Â* Based on that, how much current should be flowing through the anode?Â* I calculate square root of 26 (5.1) times 0.2 which is 1.02 A, is this correct?Â* Thanks. Â*Â* I'm probably confused but, if it's 8mm in diameter, isn't it 25mm* in circumference?Â* And, if it's 25mm, then 25mm x 100mm = 2500mm^2, convert to cm^2 and get 25cm^2. then multiply 200ma x 25cm = 5 amps. Â*Â* I'll let an adult correct me. I have never seen a platinum coated electrode. * have not included areas on end. You're at the same place I was originally when I did the calculation, which made me question whether or not I should take the square root of the area I think the mistake your making is the 26 is already in cm^2, no need to take the square root. Just 26 x 0.2 = 5.2 amps. OR, another way, your anode is 100mm x 8mm dia or 100mm x 25mm, convert to cm for 10cm x 2.5cm this equals 25cm^2. 25cm^2 x 0.2 amps = 5 amps. and then multiply that by current density.Â* When I took the square, I got the 1.02A above, but much closer to your value when I didn't. Platinum coated electrodes have many applications: https://tinyurl.com/yaufchs3 |
how much current to run anode?
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how much current to run anode?
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