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Electronics Repair (sci.electronics.repair) Discussion of repairing electronic equipment. Topics include requests for assistance, where to obtain servicing information and parts, techniques for diagnosis and repair, and annecdotes about success, failures and problems. |
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#1
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how much current to run anode?
I am getting a platinum coated anode that will have a surface area of 26
cm2 (100 mm long x 8 mm diameter). For my application, the maximum recommended current density is 200 mA/cm. Based on that, how much current should be flowing through the anode? I calculate square root of 26 (5.1) times 0.2 which is 1.02 A, is this correct? Thanks. |
#2
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how much current to run anode?
On 6/26/2018 9:37 AM, JBI wrote:
I am getting a platinum coated anode that will have a surface area of 26 cm2 (100 mm long x 8 mm diameter).Â* For my application, the maximum recommended current density is 200 mA/cm.Â* Based on that, how much current should be flowing through the anode?Â* I calculate square root of 26 (5.1) times 0.2 which is 1.02 A, is this correct?Â* Thanks. I'm probably confused but, if it's 8mm in diameter, isn't it 25mm* in circumference? And, if it's 25mm, then 25mm x 100mm = 2500mm^2, convert to cm^2 and get 25cm^2. then multiply 200ma x 25cm = 5 amps. I'll let an adult correct me. I have never seen a platinum coated electrode. * have not included areas on end. |
#3
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how much current to run anode?
On 06/26/2018 11:16 AM, amdx wrote:
On 6/26/2018 9:37 AM, JBI wrote: I am getting a platinum coated anode that will have a surface area of 26 cm2 (100 mm long x 8 mm diameter).Â* For my application, the maximum recommended current density is 200 mA/cm.Â* Based on that, how much current should be flowing through the anode?Â* I calculate square root of 26 (5.1) times 0.2 which is 1.02 A, is this correct?Â* Thanks. Â* I'm probably confused but, if it's 8mm in diameter, isn't it 25mm* in circumference?Â* And, if it's 25mm, then 25mm x 100mm = 2500mm^2, convert to cm^2 and get 25cm^2. then multiply 200ma x 25cm = 5 amps. Â* I'll let an adult correct me. I have never seen a platinum coated electrode. * have not included areas on end. You're at the same place I was originally when I did the calculation, which made me question whether or not I should take the square root of the area and then multiply that by current density. When I took the square, I got the 1.02A above, but much closer to your value when I didn't. Platinum coated electrodes have many applications: https://tinyurl.com/yaufchs3 |
#4
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how much current to run anode?
On Tuesday, June 26, 2018 at 11:16:09 AM UTC-4, amdx wrote:
On 6/26/2018 9:37 AM, JBI wrote: I am getting a platinum coated anode that will have a surface area of 26 cm2 (100 mm long x 8 mm diameter).Â* For my application, the maximum recommended current density is 200 mA/cm.Â* Based on that, how much current should be flowing through the anode?Â* I calculate square root of 26 (5.1) times 0.2 which is 1.02 A, is this correct?Â* Thanks. I'm probably confused but, if it's 8mm in diameter, isn't it 25mm* in circumference? And, if it's 25mm, then 25mm x 100mm = 2500mm^2, convert to cm^2 and get 25cm^2. then multiply 200ma x 25cm = 5 amps. I'll let an adult correct me. I have never seen a platinum coated electrode. * have not included areas on end. Lemme see- surface area of a cylinder = pi x D x H. 3.14159 x 8 = 25.133 25.133 x 100 = 2513.3 0.0200 x 2513.3 = 502.7 Divide by 100 (mm - cm) = 5.02 A. add the end-cap, if relevant = pi x r^2 = 3.14159 x 16 = 50.27 = 0.01A Or, close enough. Peter Wieck Melrose Park, PA |
#5
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how much current to run anode?
On 6/26/2018 10:54 AM, JBI wrote:
On 06/26/2018 11:16 AM, amdx wrote: On 6/26/2018 9:37 AM, JBI wrote: I am getting a platinum coated anode that will have a surface area of 26 cm2 (100 mm long x 8 mm diameter).Â* For my application, the maximum recommended current density is 200 mA/cm.Â* Based on that, how much current should be flowing through the anode?Â* I calculate square root of 26 (5.1) times 0.2 which is 1.02 A, is this correct?Â* Thanks. Â*Â* I'm probably confused but, if it's 8mm in diameter, isn't it 25mm* in circumference?Â* And, if it's 25mm, then 25mm x 100mm = 2500mm^2, convert to cm^2 and get 25cm^2. then multiply 200ma x 25cm = 5 amps. Â*Â* I'll let an adult correct me. I have never seen a platinum coated electrode. * have not included areas on end. You're at the same place I was originally when I did the calculation, which made me question whether or not I should take the square root of the area I think the mistake your making is the 26 is already in cm^2, no need to take the square root. Just 26 x 0.2 = 5.2 amps. OR, another way, your anode is 100mm x 8mm dia or 100mm x 25mm, convert to cm for 10cm x 2.5cm this equals 25cm^2. 25cm^2 x 0.2 amps = 5 amps. and then multiply that by current density.Â* When I took the square, I got the 1.02A above, but much closer to your value when I didn't. Platinum coated electrodes have many applications: https://tinyurl.com/yaufchs3 |
#6
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how much current to run anode?
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#7
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how much current to run anode?
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