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Electronics Repair (sci.electronics.repair) Discussion of repairing electronic equipment. Topics include requests for assistance, where to obtain servicing information and parts, techniques for diagnosis and repair, and annecdotes about success, failures and problems. |
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Posted to sci.electronics.basics,sci.electronics.repair
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On 2006-08-01, Adam Funk wrote:
On 2006-08-01, Joop van der Velden wrote: Adam Funk wrote: I recently tested a 9V alkaline battery by measuring its open-circuit voltage (9.0 V) and then measuring it with a car headlight lamp (R = 1 Ohm) across the terminals (4.0 V). The lamp lit up brightly and got warm, but from the significant voltage drop I conclude that the battery is basically dead. Correct? No, 1,25 ohm ESR (Equivalent Series Resistance) for a 9V battery is quite good. For a 1,5V "D" cell i would consider it too high. Interesting. I though a 44% voltage drop sounded like a lot, but as you and others have pointed out, the load resistance I've used is very low. What sort of resistance do I really need for this sort of test? If you've got lots of spare automobile parts there, perhaps "3W" panel indicator lamp would be more realistic or a 22 ohm resistor. Right. I measured the lamp's resistance with an ohmmeter, which of course puts very little current through it. But I took the measurements by clipping the voltmeter (actually it's the same meter) leads onto the battery terminals, reading the open-circuit voltage, then pressing the lamp's terminals against the battery terminals (the spacing was convenient --- that's where I got the idea from) and immediately reading the loaded voltage (before the lamp heated up). One thing you could do if the meter has a 10A range is put the meter in series with the lamp. then you can figure out the resistance of the lamp using ohms law. Bye. Jasen |
#2
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Posted to sci.electronics.basics,sci.electronics.repair
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On 2006-08-02, jasen wrote:
I recently tested a 9V alkaline battery by measuring its open-circuit voltage (9.0 V) and then measuring it with a car headlight lamp (R = 1 Ohm) across the terminals (4.0 V). The lamp lit up brightly and got warm, but from the significant voltage drop I conclude that the battery is basically dead. Correct? .... If you've got lots of spare automobile parts there, perhaps "3W" panel indicator lamp would be more realistic or a 22 ohm resistor. Perhaps I should mention that the only reason I did this test was that I happened to notice a used 9V battery and a headlamp lying near each other on my workbench, and curiosity drew me in! Right. I measured the lamp's resistance with an ohmmeter, which of course puts very little current through it. But I took the measurements by clipping the voltmeter (actually it's the same meter) leads onto the battery terminals, reading the open-circuit voltage, then pressing the lamp's terminals against the battery terminals (the spacing was convenient --- that's where I got the idea from) and immediately reading the loaded voltage (before the lamp heated up). I wrote those two paragraphs in the wrong order. I measured the voltage drop first and then (after letting the lamp cool) measured its resistance. If I'd seen the 1 Ohm value first, I wouldn't have used it for the voltage-drop test! |
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