Small MOSFET input capacitance.
Does a source follower present lower apparent input capacitance?
I'm thinking in terms of 2N7000/BS170 sized devices. Thanks. |
Small MOSFET input capacitance.
On Wed, 1 Sep 2010 15:00:35 +0100, "ian field"
wrote: Does a source follower present lower apparent input capacitance? I'm thinking in terms of 2N7000/BS170 sized devices. Thanks. Yes. If the follower voltage gain is close to 1, the gate-source capacitance is bootstrapped and goes away. All that's left is drain-gate capacitance. You can bootstrap that, too, with another follower. John |
Small MOSFET input capacitance.
"John Larkin" wrote in message ... On Wed, 1 Sep 2010 15:00:35 +0100, "ian field" wrote: Does a source follower present lower apparent input capacitance? I'm thinking in terms of 2N7000/BS170 sized devices. Thanks. Yes. If the follower voltage gain is close to 1, the gate-source capacitance is bootstrapped and goes away. All that's left is drain-gate capacitance. You can bootstrap that, too, with another follower. John Thanks. Is there a cheat sheet anywhere on the web to estimate the % of Cin that disappears with various amounts of source degeneration? |
Small MOSFET input capacitance.
On Wed, 1 Sep 2010 16:17:08 +0100, "ian field"
wrote: "John Larkin" wrote in message .. . On Wed, 1 Sep 2010 15:00:35 +0100, "ian field" wrote: Does a source follower present lower apparent input capacitance? I'm thinking in terms of 2N7000/BS170 sized devices. Thanks. Yes. If the follower voltage gain is close to 1, the gate-source capacitance is bootstrapped and goes away. All that's left is drain-gate capacitance. You can bootstrap that, too, with another follower. John Thanks. Is there a cheat sheet anywhere on the web to estimate the % of Cin that disappears with various amounts of source degeneration? The small signal gain (gate-to-source) of an (R-loaded) MOS follower is ... (gm*R)/(1+gm*R) Take it from there ;-) ...Jim Thompson -- | James E.Thompson, CTO | mens | | Analog Innovations, Inc. | et | | Analog/Mixed-Signal ASIC's and Discrete Systems | manus | | Phoenix, Arizona 85048 Skype: Contacts Only | | | Voice:(480)460-2350 Fax: Available upon request | Brass Rat | | E-mail Icon at http://www.analog-innovations.com | 1962 | Democrats are best served up prepared as a hash Otherwise the dogs won't eat them :-) |
Small MOSFET input capacitance.
On Wed, 1 Sep 2010 16:17:08 +0100, "ian field"
wrote: "John Larkin" wrote in message .. . On Wed, 1 Sep 2010 15:00:35 +0100, "ian field" wrote: Does a source follower present lower apparent input capacitance? I'm thinking in terms of 2N7000/BS170 sized devices. Thanks. Yes. If the follower voltage gain is close to 1, the gate-source capacitance is bootstrapped and goes away. All that's left is drain-gate capacitance. You can bootstrap that, too, with another follower. John Thanks. Is there a cheat sheet anywhere on the web to estimate the % of Cin that disappears with various amounts of source degeneration? Well, the effective source resistance is 1/Gm. That makes a voltage divider with whatever impedance the follower drives, like the source resistor. So the gain might be, say, 0.9. That will reduce the charge pumped into Cgs to 1/10 of the original value, so Cgs drops by 10:1. There's a little additional error due to the slope of the drain curves, which makes the follower gain less than 1 for even an infinite source load, like a current sink. Again, you can also bootstrap the drain if every pF matters. Or use a dual-gate mosfet or a phemt. Or an opamp. John |
Small MOSFET input capacitance.
"John Larkin" wrote in message ... On Wed, 1 Sep 2010 15:00:35 +0100, "ian field" wrote: Does a source follower present lower apparent input capacitance? I'm thinking in terms of 2N7000/BS170 sized devices. Thanks. Yes. If the follower voltage gain is close to 1, the gate-source capacitance is bootstrapped and goes away. All that's left is drain-gate capacitance. You can bootstrap that, too, with another follower. Its proving difficult to get relevant hits on google - any hints on a suitable search string? |
Small MOSFET input capacitance.
On Wed, 1 Sep 2010 21:58:01 +0100, "ian field"
wrote: "John Larkin" wrote in message .. . On Wed, 1 Sep 2010 15:00:35 +0100, "ian field" wrote: Does a source follower present lower apparent input capacitance? I'm thinking in terms of 2N7000/BS170 sized devices. Thanks. Yes. If the follower voltage gain is close to 1, the gate-source capacitance is bootstrapped and goes away. All that's left is drain-gate capacitance. You can bootstrap that, too, with another follower. Its proving difficult to get relevant hits on google - any hints on a suitable search string? But I've just explained it all! John |
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