View Single Post
  #13   Report Post  
Don Foreman
 
Posts: n/a
Default

On Mon, 22 Aug 2005 10:32:53 +0200, (Nick Müller)
wrote:



with ...
rho(zinc) = 7 kg/dm^3 = 7000 kg/m^3
a = 3220 / 2 m/s^2 = 1610 m/s^2
h = 0.15 m

... I get:
p = h * rho * a
p = 0.15 * 7000 * 1610
p = 1690500 [Pa] = 16.9 bar = 245 PSI

This doesn't sound too frightening.
Or did I screw this one up too?

MathCAD agrees.