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Tzortzakakis Dimitrios
major in electrical engineering, freelance electrician
FH von Iraklion-Kreta, freiberuflicher Elektriker
dimtzort AT otenet DOT gr
Ο "Alexander" έγραψε στο μήνυμα
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"TimPerry" schreef in bericht
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"AllTel - Jim Hubbard" wrote in message
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I am curious about what would happen to an electrical current in 2
situations.....
Assume that you have 2 wires that, when joined, complete a closed
electrical
DC circuit with electrons flowing thusly.....
------------ ============
eeeeeeeeee eeeeeeeeeeeeeee
------------ ============
If you flattened out the end of each wire where they connect , would
the
resulting electron paths be more like figure A or Figure B?
neither ... research "skin effect"
Most of the times this just aplies to AC (high frequency) circuits
Or of line-to-line voltage equal or above 220 kV.Therefore transmission
lines of 400 kV are always designed with a double conductor, thus to reduce
the corona discharge due to skin effect.
Figure A
--- ===
--- ===
--- ===
--- ===
eeeeeeeee eeeeeeeeeeeeeeee
--- ===
--- ===
--- ===
--- ===
Figure B
--- e e ===
--- eee eeeeee ===
--- eeeee eeeeeeeeee ===
--- eeeeeee eeeeeeeeeeee ===
eeeeeeeeeee eeeeeeeeeeeeeeeee
--- eeeeeee eeeeeeeeeeeee ===
--- eeeee eeeeeeeee ===
--- eee eeeee ===
--- e e ===
(Please note that the vast # of "e"lectrons shown in Figure B is simply
to
show the path's of electrons. )
The second portion of my question is....If the flattened portions were
increases in mass (if each wire were connected to a metal cube and the
cubes
were brought together to complete the circuit) how would it effect
electron
flow where the cubes touch?
electron flow (or hole flow is you prefer to think that way) is
determined
by total circuit resistance. (and applied EMF as per ohms law)
decreasing
total resistance by increasing contact point surface area will result in
increased current flow if all other factors remain the same.
Thanks for your help.
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