DeepDiver wrote:

"Tom Quackenbush" wrote in message
...

DeepDiver wrote:
snip

Less current draw through your wires means less power loss due to internal
wire resistance (which also means less wire heating = longer life).

P = (I * I) / R
Power loss in wiring = Current in wiring squared divided by Resistance of
wiring

snip

I think that should be P = I * I * R , or current squared times
resistance.



You're absolutely right. I should have proof-read my posting.


Simply a grammar or spelling issue - you used I before E. it was E^2 / R .

Martin

--
Martin Eastburn
@ home at Lion's Lair with our computer lionslair at consolidated dot net
NRA LOH, NRA Life
NRA Second Amendment Task Force Charter Founder

----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==----
http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups
----= East and West-Coast Server Farms - Total Privacy via Encryption =----