"Tom Quackenbush" wrote in message
...
DeepDiver wrote:
snip
Less current draw through your wires means less power loss due to internal
wire resistance (which also means less wire heating = longer life).

P = (I * I) / R
Power loss in wiring = Current in wiring squared divided by Resistance of
wiring
snip

I think that should be P = I * I * R , or current squared times
resistance.


You're absolutely right. I should have proof-read my posting.