Thread: Soldering T&E
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Dave Liquorice
 
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On Sun, 22 May 2005 09:23:04 +0000 (UTC), Brian wrote:

No, just one ring. I don't have friendly neighbours. A 50W iron
would (according to my calcs) require an extension cable of handling
around 5 amps. I don't have one of these.


eh? P = VI so the power from 5A is 230 * 5 = 1150W.

Rearranging the above formula gives P/V = I or 0.2 and a bit amps for
50W. I think you did V/P. B-)

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