On Mon, 11 Apr 2005 10:50:59 -0700, David wrote:

Jeff, I laid the ruler out again and it still looks like it's close to
85% or so. I place the ruler in front of me, on paper, and then pivot
it about the zero mark (at the left end). The I look to see how far
along the original line the 1" mark is and it looks to be over 85% along
that path, if I draw a line straight down from the 1" mark to the
original path line. The triangle that would result is an isosceles
triangle with 2ea 1 inch sides. But then I can't figure out how to
determine where a line between one of the equal angles and the opposite
equal length line, would intersect (that would give me the distance that
I'm looking for).

I'll admit, I'm having a little trouble following exactly what you are
describing, but are you looking for the standard trig formulas?

Sine = Opposite/Hypotenuse
Cosine = Adjacent/Hypotenuse
Tangent = Opposite/Adjacent

If you know what your angle between the two 1" lines is, you should be
able to get the appropriate angle value (Sin, Cos, or Tan) from a
decent scientific calculator or a Trig table, and then just use
standard algebra rules to solve for your missing dimention.
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