You gotta go that deep to see how much your IRS refund is.

Other than then, who cares for more than a silly millimeter?

--=20

PDQ
--
=20
"Oldun" wrote in message =
...
|=20
| "Doug Miller" wrote in message=20
| . ..
| In article , "PDQ"=20
| wrote:
| If you mean a miter cut, the length of the miter is
|
| the root of two times the square of the width of the board.
|
| Try again. Square root of 2 times the width of the board _not_ =
squared.
|
| If you mean a bevel cut, the length of the bevel is
|
| the root of two times the square of the thickness of the board.
|
| Try again. Square root of 2 times the thickness of the board _not_=20
| squared.
| Your formulas below are correct (even though given with an absurd =
degree=20
| of
| precision), but your descriptions above are wrong, and don't match =
the
| formulas.
|
| 1 inch wide =3D 1.4142135623730950488016887242097
| 2 inch wide =3D 2.8284271247461900976033774484194
| 3 inch wide =3D 4.24264068711928514640506617262909
| 4 inch wide =3D 5.65685424949238019520675489683879
|
| It appears the bevel/miter is proportional to the width by a factor =
of =3D
| ~1.41.
|
| Yes. Proportional to the width. Not to the square of the width.
|
| Or, the width/thickness is always =
70.7106781186547524400844362105198% of
| the bevel/miter.
|
| I find measuring to 20 decimal places is usually good enough for me.=20
| Although I only make things like garden furniture and planters etc.
|=20
| Oldun=20
|=20
|