On 6 Apr 2005 18:32:05 -0700, "monkers" wrote
something
.......and in reply I say!:

More ideas. They make hydro log splitters. I looked around and found
one that has a 9HP motor, which produces 16GPM. This will cycle a 24"
x 4" cylinder with a 2" rod. This is close to what you describe, and a
bit of math can work out the differences.

It claims 20 tons of force. At 2500 PSI and a 4" bore that seems a bit
optimistic,
#(2 ^2 * pi(3.14) = 12.6 in2 * 2500 PSI = 31500 lbs force / 2240
lbs/ton = 14 tons)

But some systems run at 3000 PSI. Even then I still get only 17 tons.
20 tons would need 3500 lbs.

Now it probably uses a double-speed pump. But without that, the cycle
time for _push_ would be:

4" * 24" capacity = 301 cu in = .175 cuft = 1.15 gals (imperial)

At 16 GPM, therefore I reckon about 5 seconds.

Then there is another 4-5 secs to come back again (the rod makes the
capacity smaller on the pull stroke).

If you use the 3.8 litre US "wet" gallon (I have never quite sat well
with all that wet and dry stuff G), the pump is actually only making
12GPM imperial, and the above times would be about 6.5 seconds push, 5
seconds pull.

Seems I screwed up again, it was the "rod" that I measured, and
incorrectly called the piston. I looked in a catalog at some cylinders
of the same orientation and looked at the rod size compared to the
bore, and it is very different. I think Im dealing with a 4" bore and
the other is probably 5 or 6" bore. All Im trying to do is find out
what GPM the pump should be. I tried finding the valves on Parkers site
and got errors. I tried searching for the mfg. company and nothing
turned up. Can you guys tell me how to figure GPM with the info I have?
I couldnt find anything telling me the force required to bend 1"
rebar. I have emailed some companys with no answers yet.
Thanks guys, sorry to be such a pain
Craig


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