Tom wrote:

Roy wrote:

On 15 Feb 2005 05:55:20 -0800, "Bob" wrote:

===The next splitter I build will have a 2 stage pump to speed the cycle
===time. Also the ram will be a 5 inch bore with a 4 inch rod to speed
===the retract time.
snip

A 4" rod in a 5" bore cylinder.........for what reason would this be
beneficial? With so much reduction on the retract side it would be
awfully low power and slow............A 2" rod is more than sufficient
for any splitter if the moveable slide with ram or wedge is
sufficiently sturdy.

LOL, a little knowledge can be erroneous..
Tom

Bit of a typo in the previous! :-(

A 4" rod would mean a fast retract as the volume per inch
of stroke required would be 7 odd cubic inches. With a 2" rod
it would be that much slower, as 16.5 cubic inches per inch of
stroke would be required.

5" bore = 19.635 square inches
4" rod = 12.566 " "
2" rod = 3.1416 " "

The maths are quite simple..

Tom