no, not correct - with a larger lathe you turn larger diameter, and take
larger cuts - If I put a 35 inch blank on my lathe and lean into a 5/8
glaser gouge, I can pull 1/4 inch thick shavings - that takes a fair amount
of power, and near the rim I can easily stall a 2 hp motor. Torque X RPM
gives you power, and the shaving thickness gives you pounds, so shaving
thickness/width times radius gives you torque.


"Dan Bollinger" wrote in message
news:ch3xd.217079$V41.10198@attbi_s52...
IMHO, motorsize is almost irrelevant, as long as it is 1/2 hp or more.

Bjarte

There is a certain logic to what Bjarte says. It's not like this is a
metal
lathe where the tools, tool feed and chips get larger as the lathe gets
larger, resulting in a larger requirement for Hp. As wood lathes get
larger
the gouges, feed and chips don't increase all that much. The power
required
to remove chips using a 1.5" gouge on a 8" bowl is about the same as the
same gouge removing chips on a 24" bowl. What needs to change is the
pulley
ratio so the tangential speed stays about the same. Since the pounds of
wood removed per hour stay about the same, then the Hp stays about the
same,
too. Dan