On Sat, 17 Jan 2004 19:16:09 UTC, "ripper"
wrote:

You are wrong, P=V*I according to ohms law.
Therefore, I= P/V

That part is true.

Power remains constant @ 9.5 kW

No, it doesn't. This is your fundamental error. The resistance of the
shower element is approximately constant during operation. Increased
voltage means increased current through the element, thus increased
power. The power rating on the element is purely nominal.

Do you see the reducing current with increasing voltage?

No.

Why do you think power is transmitted at such high voltages?
Well the two main reasons a
High voltage, low current. Smaller cable size, cheaper. And secondly,
voltage drop over long distances.

No argument with that....but it's a different topic.

--
Bob Eager
rde at tavi.co.uk
PC Server 325*4; PS/2s 9585, 8595, 9595*2, 8580*3,
P70...