Alistair
You are trying to find current from two known quantities, voltage and power.
Power remains constant, voltage varies.
P=V*I
P=9500 Watts
Voltage = 230
Therefore I = P/V which is 9500/230 = 41.3 Amps the shower will take at 9.5
kW.
Using the same power with a voltage of 240 Volts,
I = P/V which is 9500/240 = 39.6 Amps.
Now at 250 Volts, I = 9500/250 = 38 Amps.
And if you use 110 Volts, the amps now increase to 86.4 Amps

"Alistair Riddell" wrote in message
g.uk...
On Sat, 17 Jan 2004, ripper wrote:

You are a little wrong here, the supply voltage is allowed to fluctuate
between +10% and -6%.

Right enough

However, should your voltage be higher than the 230 Volts, the less
current
your load will draw.
This is a simple application of ohms law. The higher the voltage the
less
current the load will draw.

I'm afraid you have it back to front - ohm's law is V=IxR (or I=V/R)
therefore for a given resisitive load the current will increase
proprotionally with the voltage.

--
Alistair Riddell - BOFH
Microsoft - because god hates us