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Stormin Mormon
 
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Default Figuring loads / block & tackle theory

Let me confuse you further. You want half the weight on the window sill, and
half on the rope?

How about if the rope is too long? Then all the weight is on the window (and
the rope is loose and droopy). How abut if the rope is too short? Then all
the weight is hanging, and the pot is up off the window sill.

I think you better think it out again.

--

Christopher A. Young
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"The Other Harry" wrote in message
...
During a recent trip to Mexico, I bought a pot that I
would like to hang in my front window. The problem is
that the pot is heavier than I thought it would be when I
was negotiating with the vendor. I haven't weighed it,
but I make it out to be about 25 pounds. Add the weight
of the plant, the water, the mix, etc, and it gets pretty
heavy.

So, I've been thinking. What if I distribute the weight?

I could hang it off a hook and anchor it to the window
sill. By my logic, half the weight would go to one place,
the other half would go to the other place.

Am I wrong?

I also don't know whether it makes any difference how high
the anchor is. I used to know these rules, but I have
forgotten them.

--
Harry