It's just an equation. (I suppose a 12V car battery).

3s of starter, means 3*(900/12) C = 225C = 62.5mAh=0.0625Ah (900W is the
starter power).
Just add this to the loss of the battery.

Knowing that the alternator charges at 13.8V about 500W (500/(13.8-12)Â*
i.e. 200As=0.55Ah , it's easy.


Tom Del Rosso a écrit le 04/02/2019 Ã* 22:45Â*:
If you turn over an engine periodically to keep it charged, how long do
you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the
hospital.