On 15/09/2018 19:03, Roger Hayter wrote:
Tim Streater wrote:

In article , Andy Burns
wrote:

Fredxx wrote:

You could simply have said, "the diameter of each core excluding
insulation"

Except it's not a diameter of 1.5mm, it's a cross-section of 1.5mm^2

So it's a core diameter of just under 1.4mm.

So solve 2r = (pi)r^2 and you will know what wire has a diameter
numerically equal to its CSA. I can't be bothered. But I think trial
and error iteration to two decimal places would be quicker than
remembering the formula for quadratic equations.

It has a trivial solution:

r = 2/pi

In fact I would say assembling the equation was the more difficult part.

So 1.27mm dia has a CSA of 1.27mm^2

Or for oldies, very close to 50''' (thou)